Programming :: Check That The Same File Exists Within Two Different Directories Using A Filename As A Variable?
Apr 30, 2010
I am in need of a way to check that the same file exists within two different directories using a filename as a variable. Here is the process which requires it: The script is reaches out (via ftp) and pulls down a file(s) and delete it afterwards. This is halfhazard because in the instance it doesnt pull down the file, yet still deletes it, we are up a creek. I am looking to pull it down to a temp location and then verify that file exists in the location in which it needs to be present to process before deleting it, adding a little extra layer for security. The script itself is finished.If I put a file name in manually it works perfect. I just need a way to pump the filename into the variable.
I have a directory called /data In this directory I have some files like abcejb.jar,12_ab_ejb.jar, shejb.jar, test I need a shell script like... 1st I want to check if there is any ejb file exists in the directory using some condition If ejb files exists I want to redirect the ejb files list to a file called list. Now I want to copy all the files in the list file to some remote system.
This script that I found online does the job it promises. it does convert the files to mp3 without an issue. What I need to include now is an if statement that says If $file.mp3 exists then delete $file.wav
Code: #!/bin/sh # name of this script: wav2mp3.sh # wav to mp3 # Credit to the script creator (Nikesh Jauhari):
[Code]...
After that I'm stumped as to how to do the if statement
I need a script that dose the following checks if files exists by read input from a file then compares them to the files listed in the directory if they don’t exists the script would report back which file dose not exists. I also need to format the output so that files are grouped in different groups, group A, B, and C and etc based on file name. I would like the output of that do not exists files to be sorted based on second number in the file name than group according. I understand some of the basics of bash scripting something along of the lines of a loop and if statements might do the trick. Below is what I have so far. I don’t car so much about the script reporting back the file exists I prefer to only know if the file is missing and is less than 3 days old. Problem is if a file dose not exists in the reports file the test compares against the wrong file.
I have scenrio where i have to check first whether the files exists or not then count of records should not be equal to zero and file should be of current day not the previous day then only process my next task.There are three files totally.please let me know how to write script to achieve the same.
I am trying to write some small script file that will check if a USB stick is connected to my pc or not. I can't seem to get it to work, but I am sure it is a very simple fix.
I am running on Fedora core 10.Can anyone help me figure out what the problem is?If I run these lines through console it works fine (meaning, I type the commands in this file straight in the command line/console).
I am new to scripting, would like to have a script that tests whether a directory exists on remote host & display the message accordingly. The remote hostname can be provided by means of file containing list of hostnames. Can use rsh for connecting to remote host.I tried with couple of scripts by searching google but didn't get desired result. Please help me, below is my efforts, $file contains list of hostnames.
Is it possible to set up a udev rule that will check if a file exists on a USB drive?
I've got a few ubuntu servers in environments with some very not-techy peoples. Im hoping to get to the point where I can give them a few USB sticks with scripts on them, and if they plus one of these sticks in it will be mounted in, say, /media/special (rather than /media/usb0..7) and then the script would be run. But if a usb drive without special.sh is inserted, it should be mounted to /media/usb0..7 as normal.
I've been googeling for udev rules, and it seems simple enough to specify a mount point based on brand/model/serialnumber/etc... but i havent been able to find anything about checking for the existance of a file.
Tho the more i think about it, the more im starting to think its not going to be that straight forward. Can udev check for a file on a drive before that drive is mounted? Is it going to be a case of mounting every drive to /media/usb0..7 then having a script run that will check for the file, and if its there change the mount point before running special.sh?
I need to find if, in a folder any directories exist, except a certain one named "mes croquis".What I am trying to say, is that the re already is a directory named "my croquis", which I have to ignore. IF any other directory appears, I have to archive them.I got everything so far, except the starting condition.In other terms , I am lookign for something like this:
IF anyDir EXIST AND name != "mes croquis" do something else
I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
My employer issues pdf files with everyones work schedules. I copy the content and save it as plain text in a file called unformatted (hope to be able to automate this step someday). Im working on a SED script that reduces unformatted to only display what I want to see and saves the result in a file Iïve named formatted. After that I have to manually copy formatted and save it with that days date as a filename e.g. 2011-02-25 or whatever day is scheduled in the pdf, for use on a mobile device (Nokia N900). I noticed that the date occurs on certain lines in the file so I added a line like:
sed -n 's/^Date: (201[1-9])/([0-1][0-9])/([0-3][0-9]).*/1-2-3/p' < unformatted >theDate That creates a file theDate with the date in it that I wish to use as the filename for this particular instance. So I would like to skip the file formatted all together and have the sed- script write to a new file using the content of the Date as a filename, but how do I make that happen? And of course it would be more elegant if I could skip the intermediate theDate file as well.
I'm running CentOS 5.3 64bit and from the get go I've had problems with the Apache serverMore specifically, on what seems to be a random occurance, the apache server stops to respond.The process is still running, but nothing happens with it, and it is not responding.The /var/logs/httpd/error_log is blank for the occurance and only shows an entry after I give it a restartSo I'm a bit confused about what is going on.With that said, I need to make sure the httpd is working one way or another.I don't want to force a restart service every 10 minutes as this seems a bit too much.However, I do want to have the following:run a crond every minute to do:
rm -Rf /root/testarea/* wget http://ip/work.gif then check if work.gif exists.
I am trying to strip the .wav file extension from a file name so that I can pass the result to lame encoder. I started to write a BASH script that looks like this:
Code:
for f in /home/user/wavfiles*; do FILE=basename $f .wav; lame $FILE; done
It doesn't work very well though. For the life of me I can't seem to discover how to use basename in a suitable way for a script like this.
How can we convert a dynamic library (filename.so) to a static library (filename.a) using gnu gcc . Can we get a static library form a dynamic library . I saw a few post in which the conversion form a static library to a dynamic library is mentioned but, unfortunately, not the other way.
I'm having problems figuring out the process to find directories that DO NOT contain a certain file. I have a mp3 collection that all the album art is name "folder.jpg". Not all the albums have images. I need a way to find the albums/directories that do not contain "folder.jpg". I can find the ones that do contain "folder.jpg" with
There is the Archive::Zip I think I can use with Perl 5.10 but I don't know how. I don't want to read or write any files, just zip something in memory, with best compression, like
$text = "this is a test"; $zippedtext = &Zip($text); sub Zip {
instead of importing a file I would like to use the variable $x I tried using pipes, but with no luck. My goal is to read one line at a time, but not have to export my data to another file, I would like to keep it all within one script.
At my wit's end I can't find anything that I understand well enough to use. This is for a Unix class, we are working with shell scripting. File1 has 5 in it and File2 has 100 in it.The teacher wants us to read the values then do the math. This is what I have so far:#!/bin/bashvar1='cat File1'var2='cat File2'var3=`echo "scale=4; $var1 / $var2" | bc`echo The final result is: $var3
This is what I have right now. Well, I thought I knew sed, and apparently I don't... I tried writing this for someone else, and this has given me trouble, so since the user pretty much figured it out on his own, here it goes. Say VARR=1, so VARX and VARY contain the above text, appended by 1. What I am trying to do is replace the text "defaults.ctl.card 0" by VARX and "defaults.pcm.card 0" by VARY. The contents of FILE1 is the file being used to search for both text fields, and FILE2 is the output file. I tried using single quotes, double quotes, and a mixture of both, and no go whatsoever. So my question... What is the proper way of searching for text within a file and replacing with a variable?
I am trying to think of a logic where my file contains some data I had to read and do some processing. Issue is that file contains data multiple times. For example:
::::::::::: var1=value1 var2=value2
[code].....
I have to read first paragraph of variables and do some processing and then move on until the end of file. Variable names are same in whole file but for each paragraph the value is different. I can't think of a logic to attain this task. How can I do it? It should be a simple bash script, but I am not able to work out.
