Programming :: Remove The Last Character From Variable
Jun 22, 2010
i have the following:
Quote:
echo %host%|sed "$s/.$//"
this would remove the Last character of the value assigned to the %host%. for example if my value is: abcd i get abc. but i am not able to assign the output. for example when i do
Quote:
set k=`echo %host%|sed "$s/.$//"`
after doing echo %k i get no output at the command prompt...!! whereas when i just type:
Quote:
echo abcd|sed "$s/.$//"
at the command prompt i get abc. maybe some other ways to Remove the Last character...?
I want to remove single quote from a variable. eg: Suppose I have a variable VAR='TEST' (including single quotes) How can I remove single quotes and make it TEST.
I am doing a mysql query with a bash shell script like: mysql translator -u root --password=******** -e "SELECT word FROM tagalog ORDER BY RAND() LIMIT 1" | while read line; do echo $line
So when I echo the value of $line I get: word magandang umaga "word" is the name of the row in the table and maganda umaga is a randomly selected choice from the row. Is there a way i can remove the name of the row from the variable $line. With a result that will allow me to echo $line and output only the randomly selected entry in from the row e.g. magandang umaga
I'm using sed to remove certain line in a text file based on a match with 2 variables from input. Here is how it looks like in file
Philip S:Odds:45:343 Mike Junior:Odds:3:56
I prompt for 2 inputs in variable form which is compared to the first 2 fields of the above text (: seperated). So say i enter Philip S and Odds then it should delete the entire first line.
I am writing a bash script to run everyday and output results to a file. When the same results are produced i want to overwrite the line from the previous day. (Or remove and add). So if the script finds a variable in a line. i want it to output the results to that line . sed -i did not work for me; sed: couldn't open temporary file ./sedTvOCEg: Permission denied
I'm looking for a script (bash, python, perl etc) or even a one liner (sed, awk etc) that can take a set of files and remove any line that has more than "x" instances of any character (case sensitive). I have been doing a lot of searching and can only come up with examples of how to remove blank lines, lines that start with a certain character or lines that contain a certain string. This will be used on a system running a Kubuntu derivative.
As a very poor and basic example, I would like to take files that contain lines like:
Code:
And end up with the files only containing the lines:
Code:
If I tell the script that 2 is the maximun number of times any character can appear in any line.
I know this must be possible, but for the life of me I cannot find even an example that will lead me in the right direction or better yet a piece of code I can use.
I want to match some filename in some text, but the filenames I have no control of, so "[" can "]" can appear in the filenames.so do I always have to use sed to addslashes to these variables before I have to grep them? and what other characters have I missed other than "[", "]", "."?
I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
my script has a variable which comes in the form +00.00 +0.00 -00.00 or -0.00 (the numbers can be any in that form) for any that have a + symbol I need to remove the +, but if it has a - symbol it needs to stay.
i need to make a new variable with the string from the old variable btut without any plus sign. I have tried a lot of different ways with no success, each thing I tried either left the + or removed the entire string. I think this should work but doesn't
I have got certain files which somehow contain abnormal character "Del" "0x7f" or 177 which represents Del. And this is causing SVN to reject these files and abruptly end the process. I need to remove those characters from the file names but am not able to. find or grep do not search the files. This is how the file looks like with ls or find code...
I want to be able to remove the first character of a line when I highlight multiple lines in gedit. Example:
%Example is %Commented Code %Uncomment using this shortcut
I would then highlight/select these lines, and remove the first character to make it look like this:
Example is Commented Code Uncomment using this shortcut
I'm pretty sure there is an actual shortcut for this. If there is another text editor on Linux that it would work in, it would be nice to know how to do it in that editor as well.
I am trying to copy a large number of files from a Linux server to a Windows file share. Unfortunately, all of the files and folders I have to copy have 10 numbers followed by 2 colons "::" in the name (example: 1234567890::WordDoc.doc) which of course is invalid in windows naming conventions. So now I'm trying to come up with a way to change the file and folder names on the fly to replace the colons with a dash "-" or space " ". I'm even willing delete the frist 12 characters in necessary. I have tried cp, mv, tr, and several -bash scripts but get no positive results.
I have model output data in ascii format. It contains thousands of lines. The output file contains multiple text lines with variable values. here I copy-paste some of it's contents.
I was reading Kernighan Ritchie book chapter 4 which deals with character pointers.I am not able to understand following different type of declarations
Code: char aname[][15] = { "Illegal month", "Jan", "Feb", "Mar" }; char amessage[] = "now is the time";
i am compiling the following program in linux. it's in c language. after the compilation with gcc when i run the executable file. it asks for input. but when i enter a name. i prints "Segmentation fault" and then terminate the program. can you please help me.
I have a file with one line. I want to check whether the first character is TAB or space, how can i do this.? using "cut" wont as it "bypasses the tab and space characters"
I am trying to check if the 9th character in a file on each line is a v and if so, then print the first word. I've tried a number of variations and am stuck !If it's possible to also check if character position 1 begins with a s in the same awk, that would make it cleaner instead of using egrep.
egrep '^s' file | nawk '{virtual=substr($0,9,1); if ($virtual=="v") {printf "%s", $1}}' nawk: illegal field $(e) input record number 1 source line number 1
I believe I have unwanted ' characters left in a 9 element character array that are causing subsequent operations with it to fail. I see wildly differing views on the web on the proper way to flush 'em. It's clearly not as simple as it would appear at first sight. What's currently the best (or else "least deprecated") method?
I am loading variables for cXtXdXsX disk names into a script, and at present I have only accounted for there being 3 characters from c to t. I need to change it to a variable recognition so that it can count any number of charcters such as c1t , c10t , or c100t.
I can then take that information and use it with the following string to strip off the lead characters so as to make the 3 in $substr either a variable or redirect to multiple occurrences of raw based on the count returned.
sub raw { $substr = substr ($_, 3); $raw1 = substr ($substr, 0, -4); $raw = lc($raw1); }
how to count from the c to the t inclusive so I get 3, 4, 5, etc ...
