I tried to get a block of lines in awk, but unfortunately it returns output of one line only. I don't state the code here, because it's too short and too poor. What exactly I wanted to do: from file "/boot/grub/menu.lst" get blocks of lines, starting by title and ending by Now I have just
Code:
script="/boot/grub/menu.lst";
OLDIFS=$IFS; IFS=$'
';
[code]....
I want to get every block as one row of array.
I have a clump of text that needs to be broke up:gdbm Sat 07 Feb 2009 03:28:18 AM EST libattr Sat 07 Feb 2009 03:28:18 AM EST db4 Sat 07 Feb 2009 03:28:19 AM EST mktemp Sat 07 Feb 2009 03:28:19 AM EST keyutils Sat 07 Feb 2009 03:28:20 AM EST pcre Sat 07 Feb 2009 03:28:21 AM EST setserial Sat 07 Feb 2009 03:28:24 AM EST zlib Sat 07 Feb 2009 03:28:24 AM EST gawk Sat 07 Feb 2009 03:28:25 AM EST readline Sat 07 Feb 2009 03:28:26 AM EST rhpl Sat 07 Feb 2009 03:28:28 AM EST cracklib-dicts Sat 07 Feb 2009 03:28:37 AM EST setools Sat 07 Feb 2009 03:28:37 AM EST hal Sat 07 Feb 2009 03:28:38 AM EST which Sat 07 Feb 2009 03:28:39 AM EST Is there a way to get everything after the EDT in the text to be moved to a new line?
View 13 Replies View RelatedHow do you remove parts of strings using python? Such as, if I have something like:
Code:
erme1 sdifskenklsd
erme2 sdfjksliel
[code]....
I am having a file filled of blocks like (each is seperated with the <event> )
<event>
8 1 0.1118800E-04 0.1709000E+03 0.7546772E-02 0.1182204E+00
-1 -1 0 0 0 501 0.00000000000E+00 0.00000000000E+00 0.40846782627E+02 0.40846782627E+02 0.00000000000E+00 0. 1.
2 -1 0 0 501 0 0.00000000000E+00 0.00000000000E+00 -0.90202563950E+03 0.90202563950E+03 0.00000000000E+00 0. -1.
[code]....
how can I copy this block if for example find "13" in the first column and "-1" in the last ? Then, looping to the rest of the file doing the same all over again?
Consider a situation in which you want to display only specific lines of contents from a file or of a command's output. Yes, we have head and tail commands. But, how to view all the lines of a file except the last one or vise versa when we don't know the count of lines in advance?
Consider this output:
Code:
[root@localhost ~]# ps au | grep bash
root 6316 0.0 0.0 4672 1440 tty1 Ss+ Apr22 0:02 -bash
root 20847 0.2 0.0 4672 1432 pts/0 Ss Apr23 0:12 -bash
root 21167 0.0 0.0 3920 660 pts/0 S+ 01:00 0:00 grep bash
Here, I don't want the last line (in italic) to be included in the result since the last line is due to "grep bash" in the devised command "ps au | grep bash". Well, we can rewrite the devised command:
Quote:
"ps au | grep bash | head -n 2"
But, again, here we are specifying the count of lines to be included. But, in the presented problem we don't know any count in advance!
Is there a command which can be used to run some other command on a few lines from a file or an o/p of some file. (the kind of role that -exec option does for the find command). (I have solved the purpose using a bash loop but would like to know if there exists a command).
View 4 Replies View RelatedI do a logcat, i got lot of lines, that I filter with a grep, at end, I just got some lines like this:
Code:
I/ActivityManager( 1763): Config changed: { scale=1.0 imsi=732/123 loc=es_ES touch=3 keys=2/1/2 nav=2/1 orien=1 layout=17 uiMode=17 seq=15}
[code]...
How can I remove all lines which contain A,,,,,, I tried the following sed statements but no luck.
Code:
sed "/A,,,,,,/d file"
sed "/A,,,,,,/d file"
whichever source code I go through I find these three lines of code written what do they actually mean and what is their function?
[code]...
I have a large CSV file, tab-delimited with CRLF at the end of each line. Each line should contain 5 fields (i.e. NF == 5) However, there are rogue CRLF characters in the middle of some records, causing records to be split across two lines. I want to scan each line, check the field count and if it's !=5 then join that line to the following line. Example input might be;
Code:
one two three four five
six seven eight nine ten
eleven tw<CRLF>
elve thirteen fourteen fifteen
[code].....
I'm struggling myself with this problem: I have a file which contains a single column of data
2
.
.
.
45
[code]...
Is there a way to do it with awk?
I've got a website set up which has a section which is just a bunch of links on the side. But this section of links is on every page of the website. And when I expand and add more links I don't want to have to go to every page and add the new link. Is there a way that I could put all the links into something on CSS (or anything else) that I could just include one line in the HTML? So that when I add a link I'll only have to edit the one file and and then every page will be updated?
View 12 Replies View RelatedMy problem is like this I have to delete all lines between two pattern match example- suppose below is the content of the file then i have to delete all lines between text1 and text2
...
text1
abc
def
ghi
[Code]....
i jst want to delete a host entry from httpd.conf the entry for lal.com should be deleted!!
View 14 Replies View RelatedFor example, I have a file called "file" like this one:
type=strongsubj len=1 word=absolve pos=verb stemmed=y priorpolarity=positive
type=strongsubj len=1 word=unique pos=adj stemmed=n priorpolarity=neutral
type=strongsubj len=1 word=absolutely pos=adj stemmed=n priorpolarity=neutral
type=weaksubj len=1 word=taking pos=verb stemmed=y priorpolarity=positive
type=weaksubj len=1 word=friend pos=noun stemmed=n priorpolarity=positive
type=weaksubj len=1 word=usually pos=adverb stemmed=n priorpolarity=positive
type=strongsubj len=1 word=purecolor pos=anypos stemmed=n priorpolarity=negative
type=strongsubj len=1 word=accusingly pos=anypos stemmed=n priorpolarity=negative
I want to add the plural for the noun, for example if find this line:
type=weaksubj len=1 word=friend pos=noun stemmed=n priorpolarity=positive
will add one more line :
type=weaksubj len=1 word=friends pos=noun stemmed=n priorpolarity=positive
where we add "s" for the word friend
I did try to do like that:
<code>
cat file | while read LINE ; do
set -- ${line}
if [[ "${4#pos1=}" == "noun" ]];then
#I tried this line but it doesn't work properly:
v3==$(echo $line |sed 's/$3/$s') #I want to find the third word "word=friend" in that line and add "s" after that word
# I don't know what command to add this new line "$v3" to the file ???
done
</code>
Every now and then I have to indent the lines in my script to 4 space characters. I generally do it line by line. Is there an automated command in vi using which I can indent some set of lines to desired number of space characters in one go.
View 5 Replies View RelatedI have a file witch I need to list 10 line by 10 lines with something like press enter to go on in between.
Well, the problem is that i have absolutely no idea on how to implement this.
Can you give me some points?
I have a CDL netlist with 5630 lines. 512 of the lines are over 128 characters. The tool I am using to read in the CDL returns an error for each line over 128 characters.
If the line is too long I can fix it by adding a line continuation symbol, in this case a "/", somewhere prior to the 128th character then a line feed, obviously, and a "+" to the continuation.
example (pretend its a long line);
before;
this line is too long
after;
this line /
+ is too long
Part of the problem is that I can't use a constant point prior to the 128th character because I can't break up a term.
bad;
this line i /
+ s too long
If I can replace the last space before the 128th character with " / + " on all lines that are over 128 characters then I'm golden. I'm not sure if I need to escape the + or not. If so then the substitution is " / + ". And if I use sed then I'll escape the .
So For example I run this command:
Code:
But want to gerp / cut it in such a way that it only displays
Code:
Now the thing is that these 3 lines are not static.. there can be N number of lines there.. the only thing is that I want the command / output NOT to display the first line but the rest of the n lines ..
I'm trying to find the correct sed syntax to match from a given pattern to the end of the file and then append that pattern to the end of the file.
I was trying:
But that prints each line right after its original occurrence. I want to match the block and then append it to the end of the file.
I have one password text file: username<tab>password, I want to wrote any bash script to check if certain user exist at this file, if did exist print out the password. I get stocked at password value to AWK if block:
#!/bin/bash
FILE="$1"
if [ ! -e "$FILE" ]
then
[code]....
it not work , but if I change toassword=$(awk < $FILE -F\t '{ if (test $1=="JIMMY2") print $2;}') it works, anything wrong $1==$user_name? $FILE is the password file, -F\t is use tab as delimiter.
I need to grep a pattern which can be present in one line or could be split in 2 lines.Normal grep wont work in this case. Can anyone please help on this?There are 100's of files in which i need to search for this pattern so time is also a constrain.
View 5 Replies View RelatedI have a plain text file with 360 lines of varying length text. How do I add a comma or other symbol to the end of each line so that I can convert the file to csv format that I can open in a spreadsheet (45 rows, 8 columns). That means each 8 lines of text forms 8 columns, with 45 rows.
View 9 Replies View Relatedi have a sorted file with many repeated lines like this:
1ujw
1ujw
1ul1
1us7
[code].....
i need to calculated haw many times each line is repeated, for ex
1ujw 2
1ul1 1
1us7 5
etc.
Using awk I pull the first field of a random line from my datafile.myvar1=`awk -F" " 'NR=='$randline' {printf "%s", $1}' myfileThis works fine. The problem is there will be empty lines at the end of the file. Rather than using awkto filter out blank lines I would like to figure this out first.So I test $myvar1 for a blank string after setting $randline to one that I know is blank:test -z "$myvar1" && echo "true" || echo "false"But, this returns "false"? So the string is not zero length. Why? It's a tab-separated file. Is awk storing the tab with the $1 field or something.This is where I get headache. I try to echo my variable to see what it looks like.
echo "$myvar1"
outputs: nothing
echo "My variable is [$myvar1]"
outputs: [y variable is [
Why is the closing bracket at the beginning? What character could be stored in $myvar1 that would do such a thing and how did it get there?
there is a way to add line spaces when asking for user interaction in a script. For example:
Code:
SPACE
Hello what is your name?
SPACE
SPACE
So this is asking a question but has a space/empty line at the top of the screen and 2 spaces/empty lines below. I've seen it done in a bash script using for each line/space needed
Code:
echo ""
So what does perl use?
I have a file, and I have to display all the lines from the beginning of the file till a matching string is found.
I know grep with "-a", "-b" as option does exist, but it needs the number of lines to be printed in advance. eg grep -b 10 "search_string" file so it will print 10 lines before a match is found.
Is there a convenient method to find a text pattern that extends over several lines? In this case:
Empty line
LineConsistingOfSingleWord
Preferably to return the line number where the pattern occurs to determine the first such after a known line number. In other words, in order to extract a block of text from within a file.
I would like to know how I can get the ouput from the following dmidecode command in example 1 to look like example 2 without having to grep -v all the unwanted lines.Is there a way in awk or sed?Example 1
Code:
Processor Information
Socket Designation: Socket 1 CPU 1
[code]...
I have such a file(test.txt) as below:
[code]...
I want to use grep to fetch the lines contain 'AB_001'.
[code]...
get the first 2 lines, not the 'AB_0011/10/105'.