Programming :: Three Lines Of Code - What Do They Actually Mean
Feb 23, 2011whichever source code I go through I find these three lines of code written what do they actually mean and what is their function?
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whichever source code I go through I find these three lines of code written what do they actually mean and what is their function?
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How do you remove parts of strings using python? Such as, if I have something like:
Code:
erme1 sdifskenklsd
erme2 sdfjksliel
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A tiny Linux kernel patch that makes the desktop incredibly more responsive: [URL]...
View 14 Replies View RelatedI need to rewrite the selenium java code into its equivalent php code.
View 5 Replies View RelatedIs there a command which can be used to run some other command on a few lines from a file or an o/p of some file. (the kind of role that -exec option does for the find command). (I have solved the purpose using a bash loop but would like to know if there exists a command).
View 4 Replies View RelatedI tried to get a block of lines in awk, but unfortunately it returns output of one line only. I don't state the code here, because it's too short and too poor. What exactly I wanted to do: from file "/boot/grub/menu.lst" get blocks of lines, starting by title and ending by Now I have just
Code:
script="/boot/grub/menu.lst";
OLDIFS=$IFS; IFS=$'
';
[code]....
I want to get every block as one row of array.
I do a logcat, i got lot of lines, that I filter with a grep, at end, I just got some lines like this:
Code:
I/ActivityManager( 1763): Config changed: { scale=1.0 imsi=732/123 loc=es_ES touch=3 keys=2/1/2 nav=2/1 orien=1 layout=17 uiMode=17 seq=15}
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How can I remove all lines which contain A,,,,,, I tried the following sed statements but no luck.
Code:
sed "/A,,,,,,/d file"
sed "/A,,,,,,/d file"
I have a large CSV file, tab-delimited with CRLF at the end of each line. Each line should contain 5 fields (i.e. NF == 5) However, there are rogue CRLF characters in the middle of some records, causing records to be split across two lines. I want to scan each line, check the field count and if it's !=5 then join that line to the following line. Example input might be;
Code:
one two three four five
six seven eight nine ten
eleven tw<CRLF>
elve thirteen fourteen fifteen
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I'm struggling myself with this problem: I have a file which contains a single column of data
2
.
.
.
45
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Is there a way to do it with awk?
I've got a website set up which has a section which is just a bunch of links on the side. But this section of links is on every page of the website. And when I expand and add more links I don't want to have to go to every page and add the new link. Is there a way that I could put all the links into something on CSS (or anything else) that I could just include one line in the HTML? So that when I add a link I'll only have to edit the one file and and then every page will be updated?
View 12 Replies View RelatedMy problem is like this I have to delete all lines between two pattern match example- suppose below is the content of the file then i have to delete all lines between text1 and text2
...
text1
abc
def
ghi
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i jst want to delete a host entry from httpd.conf the entry for lal.com should be deleted!!
View 14 Replies View RelatedFor example, I have a file called "file" like this one:
type=strongsubj len=1 word=absolve pos=verb stemmed=y priorpolarity=positive
type=strongsubj len=1 word=unique pos=adj stemmed=n priorpolarity=neutral
type=strongsubj len=1 word=absolutely pos=adj stemmed=n priorpolarity=neutral
type=weaksubj len=1 word=taking pos=verb stemmed=y priorpolarity=positive
type=weaksubj len=1 word=friend pos=noun stemmed=n priorpolarity=positive
type=weaksubj len=1 word=usually pos=adverb stemmed=n priorpolarity=positive
type=strongsubj len=1 word=purecolor pos=anypos stemmed=n priorpolarity=negative
type=strongsubj len=1 word=accusingly pos=anypos stemmed=n priorpolarity=negative
I want to add the plural for the noun, for example if find this line:
type=weaksubj len=1 word=friend pos=noun stemmed=n priorpolarity=positive
will add one more line :
type=weaksubj len=1 word=friends pos=noun stemmed=n priorpolarity=positive
where we add "s" for the word friend
I did try to do like that:
<code>
cat file | while read LINE ; do
set -- ${line}
if [[ "${4#pos1=}" == "noun" ]];then
#I tried this line but it doesn't work properly:
v3==$(echo $line |sed 's/$3/$s') #I want to find the third word "word=friend" in that line and add "s" after that word
# I don't know what command to add this new line "$v3" to the file ???
done
</code>
Every now and then I have to indent the lines in my script to 4 space characters. I generally do it line by line. Is there an automated command in vi using which I can indent some set of lines to desired number of space characters in one go.
View 5 Replies View RelatedI have a file witch I need to list 10 line by 10 lines with something like press enter to go on in between.
Well, the problem is that i have absolutely no idea on how to implement this.
Can you give me some points?
I have a CDL netlist with 5630 lines. 512 of the lines are over 128 characters. The tool I am using to read in the CDL returns an error for each line over 128 characters.
If the line is too long I can fix it by adding a line continuation symbol, in this case a "/", somewhere prior to the 128th character then a line feed, obviously, and a "+" to the continuation.
example (pretend its a long line);
before;
this line is too long
after;
this line /
+ is too long
Part of the problem is that I can't use a constant point prior to the 128th character because I can't break up a term.
bad;
this line i /
+ s too long
If I can replace the last space before the 128th character with " / + " on all lines that are over 128 characters then I'm golden. I'm not sure if I need to escape the + or not. If so then the substitution is " / + ". And if I use sed then I'll escape the .
So For example I run this command:
Code:
But want to gerp / cut it in such a way that it only displays
Code:
Now the thing is that these 3 lines are not static.. there can be N number of lines there.. the only thing is that I want the command / output NOT to display the first line but the rest of the n lines ..
I'm trying to find the correct sed syntax to match from a given pattern to the end of the file and then append that pattern to the end of the file.
I was trying:
But that prints each line right after its original occurrence. I want to match the block and then append it to the end of the file.
I need to grep a pattern which can be present in one line or could be split in 2 lines.Normal grep wont work in this case. Can anyone please help on this?There are 100's of files in which i need to search for this pattern so time is also a constrain.
View 5 Replies View RelatedI have a plain text file with 360 lines of varying length text. How do I add a comma or other symbol to the end of each line so that I can convert the file to csv format that I can open in a spreadsheet (45 rows, 8 columns). That means each 8 lines of text forms 8 columns, with 45 rows.
View 9 Replies View Relatedi have a sorted file with many repeated lines like this:
1ujw
1ujw
1ul1
1us7
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i need to calculated haw many times each line is repeated, for ex
1ujw 2
1ul1 1
1us7 5
etc.
Using awk I pull the first field of a random line from my datafile.myvar1=`awk -F" " 'NR=='$randline' {printf "%s", $1}' myfileThis works fine. The problem is there will be empty lines at the end of the file. Rather than using awkto filter out blank lines I would like to figure this out first.So I test $myvar1 for a blank string after setting $randline to one that I know is blank:test -z "$myvar1" && echo "true" || echo "false"But, this returns "false"? So the string is not zero length. Why? It's a tab-separated file. Is awk storing the tab with the $1 field or something.This is where I get headache. I try to echo my variable to see what it looks like.
echo "$myvar1"
outputs: nothing
echo "My variable is [$myvar1]"
outputs: [y variable is [
Why is the closing bracket at the beginning? What character could be stored in $myvar1 that would do such a thing and how did it get there?
there is a way to add line spaces when asking for user interaction in a script. For example:
Code:
SPACE
Hello what is your name?
SPACE
SPACE
So this is asking a question but has a space/empty line at the top of the screen and 2 spaces/empty lines below. I've seen it done in a bash script using for each line/space needed
Code:
echo ""
So what does perl use?
I have a file, and I have to display all the lines from the beginning of the file till a matching string is found.
I know grep with "-a", "-b" as option does exist, but it needs the number of lines to be printed in advance. eg grep -b 10 "search_string" file so it will print 10 lines before a match is found.
Is there a convenient method to find a text pattern that extends over several lines? In this case:
Empty line
LineConsistingOfSingleWord
Preferably to return the line number where the pattern occurs to determine the first such after a known line number. In other words, in order to extract a block of text from within a file.
I would like to know how I can get the ouput from the following dmidecode command in example 1 to look like example 2 without having to grep -v all the unwanted lines.Is there a way in awk or sed?Example 1
Code:
Processor Information
Socket Designation: Socket 1 CPU 1
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I have such a file(test.txt) as below:
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I want to use grep to fetch the lines contain 'AB_001'.
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get the first 2 lines, not the 'AB_0011/10/105'.
I need to replace part of a line in a file with multiple lines, however need to separate each line with a newline is this possible?
Example, need to remove line 2
And insert line similar to below:
If the multiple lines were part of a text file, would inserting a text file automatically include newline characters?
I tried, of course:
Code:
awk '/^./ {print}' FILE.TXT
That does not work, I just get an empty output, even if FILE.TXT contains lines which fit the desired regexp I've searched but did not found my way. I'd like to do it with awk, as I want my program to rely only on awk, nothing else such as sed, grep, etc.