How can I list the following with grep. I want to extract 2 lines fron a text file The fixed known part if it exists will static text and the text line after it will change.
A sample file
.
.
textline1
[code]....
If the fixed part does Not exist how can I return error code 1
I want to insert a line at a particular line number using sed or awk. where line number is not fixed and is in form of variable.
I want to use variable in sed or awk command.I tried something like below, but no luck.
I want to get the last term of an unknown-sized text line, by usig the awk command. Is there any variable which points to the last term of a text line ? (obviously, y can obtain that term if i knew how many terms does the line have... i.e. awk '{print $12}' ; if we are talking about a 12-terms text line) I wonder if there is an option like $?, to get the last term.
View 2 Replies View RelatedI have a dataset (see example below) that I would like to go through and copy all lines containing a certain string ("LGIG") plus the line immediately following that line to a new file. I have no problem grepping lines containing the string LGIG but I'm lost how to translate that to line number and shift up one line number for each instance of that string.
Example input file:
[code].....
I'm wondering how it is possible to read each line from a text file, and then store each line separately in a list, using C++?
View 2 Replies View RelatedI'm trying to make another file annotation script a little speedier than it has been by the up-until-now proven method of checking the last four characters in a filename before the "dot" (eg .jpg, .psd) against a list of known IPTC categories and Exiv2 command files. It occurred to me that if one script generated a list of files in directory foo, and the same or another script sorted that list by that four-letter tag,then that list could be used(instead of a for/do/done loop on the real files in the folder) by the command-file-matching script to "vomit out" which annotator file would go with file nastynewfile.jpg, f'r'instance. The script I had been using for this task looks like this:
Code:
while read 'line';
do
sp=$(echo $line)
vc=$(echo $sp | cut -d"," -f1)
cv=$(echo $sp | cut -d"," -f2)
[code]....
Where I seem to be stuck is with how to sort the lines in templist, which may be any number of different lengths, from back to front. sort -k looked promising, except it seems only to work the other way round. I thought of invoking a
Code:
q=$(expr length $line); echo $q
n=$[q-8]; echo $n
kind of thing, but that presented the problems of how to sort by those, how to tell sort where to find them (grep?) and how to "stitch them back in" to the original list, which is what I want to sort in the first place.
I currently have 3 files with floating point data that I wish to have in a single file with the format:
Code:
F1 F1 F3 Output
a1 b1 c1 a1 b1 c1
a2 b2 c2 a2 b2 c2
a3 b3 c3 a3 b3 c3
a4 b4 c4 a4 b4 c4
I have two txt files containing x and y coordinates: xcoord.txt & ycoord.txt. I need to open them; read them line by line to get each coordinate; then each time I need to update Xs and Ys parameters inside another file called "dc.in" with the grabbed values.
Finally each time I need to run two exe files ( dc_2002 and st_vac) and produce corresponding output for each Xs and Ys ( dc.in is an input file for this exe files)
I have written the following code but it does not work:
Was wondering if any perl guru's could help me with a quick log file adjustment. I have a text file that looks like so (tabs and newlines are revealed so you can see what separates the data):
There are maybe 100 lines of text in this file at any given time. I need to delete all duplicate lines only looking at the first bit of text prior to the first tab. It doesn't matter which one gets deleted as long as there are no two lines that begin with that same text at the beginning before the first tab. So in this example, either the fist line "1234" or the last line "1234" would need to be deleted. I already have code in my script that opens the files - I just need the code to read the text into an array and the part that would find matches based on the above criteria, and make the deletions.
If it would be easier, I can even do a system call and use SED (v4.1.5) and/or AWK (3.1.5) instead.
This solution works but is slow with large files. I am looking for a faster solution.
The 2 files contain filenames, one of them has associated data I want to append to the other file's matching filenames
file1:
file2:
I append file2 by matching the unique_filenames and appending them with the tag data and some formatting
appended file2:
Here is the SLOW code
while read inputline.
bash 3.1.17(2) I'm trying do write a shell script which must operate on each line of an ASCII text file. So, all the code must be inside a loop, and inside the loop, the first thing should be to read the next line from the file. I have the bash read command. But it reads from stdin. Any way to make read from a file?
View 6 Replies View RelatedI'm a bit new to Python programming and hoped that someone might be able to help with a problem I'm having. What I essentially want to do is to combine two text files line for line. I know how to do this in a bash script so to give you a better idea here's the code for that:
Code:
This is basically for adding on values to the end of a CSV file that uses ';' as the delimiter. So say file1 said:
And file2 said:
Then running this command would create merged_file1_and_file2 which would be:
The code I'm using at the moment is:
Code:
As I'm sure any experienced python programmer will see, this prints out the first line of the file "csvraw" and then all of the lines of "stamps" and then the remainder of "csvraw".
What I'd like to do is something like: (pseudo code, I know it's not python ;-))
Code:
Is this possible? I've tried googling and my Python Pocket Reference hasn't been much help. I've looked at pickling but that doesn't seem appropriate.
I'm trying to add text to a file for a specific group of users, I'll need to do examples as I can't think of an easy way of explaining, my file is like this:
Code:
users{
user1
user2
[code]....
At the present my code lists all the available groups, how would I add a user to a specified group? (e.g add "members user3") to the end of group 1 for example. So the code ends up like this
Code:
members user2,user3
I need to search a text file for a string of numbers which are different lengths, and always are between number=" and " like:
number="1234567890"
number="22390"
I need to grab those numbers and pipe each one to a line in a file. I've already tried something with awk and that didn't seem to work.
I have two files, file1.traj and file2.traj. Both these files contain identical data and the data are arranged in same format in them. The first line of both files is a comment.
At line 7843 of both files there is a cartesian coordinate X, Y and Z ( three digits ). And at line 15685 there is another three digits. The number of lines in between two cartesian coordinates are 7841. And there are few hundreds of thousands of lines in a file.
What I need to do is copy the X Y Z coordinate (three digits) from file1.traj at line 7843 and paste into file2.traj at the same line number as in file1.traj. The next line will be 15685 from file1.traj and replace at line 15685 at file2.traj. And I dont want other lines (data) in file2.traj get altered. This sequence shall be going on until the end of the file. Means copy and substitude the selected lines from file1.traj into file2.traj.
I tried to use paste command but I cant do for specified line alone.
Here i showed the data format in the file. I used the line number for clarity purpose.
Code:
I want to access a file, and check the length of every line.After, i want to check and replace all lines with length over 10 characters, with a message.Does anyone have a clue on that?
View 1 Replies View RelatedI am trying to get a word from a line using sed. Following is the line which I want to use.
inet addr:10.245.86.15 Bcast:10.245.87.255 Mask:255.255.254.0 inet6 addr: fe80::1031:3dff:fe01:55e1/64 Scope:Link
From the above line, I need the ip address like 10.245.86.15 only.
I want to add to the end of a line for a file that has the /usr/X11R6/bin/X in it. The /usr/X11R6/bin/X is not at the end of each line. I need to add "-nolisten tcp" to the end of each line containing the the /usr/X11R6/bin/X string.how can this be done in a script?
View 5 Replies View RelatedI need to simply replace a 2 lines, or one and I'll run each command separately, in a eps file. I know I can grep the line and pipe that into the sed but I would like to keep this in a sed command. I can use sed /s and get it if I copy the section out of the file and paste it. Really just trying to rewrite the boundingbox coord's in eps files.
sed -i 's/%%BoundingBox: 00 00 88 487/%%BoundingBox: 24 315 288 487/g;s/%%HiResBoundingBox: 00 00 88 487/%%HiResBoundingBox: 26 315 288 487/g' someeps.eps
I am trying to write a program in C which compares two files and prints the line that is equal.
Here file1.txt has
and file2.txt has
Note: file2.txt consist of only a single string where as file2.txt has multiple lines. Actually im comparing two files with md5sum values.
Here is the code but it compares only first line of files..but it should compare the whole file1..and sorry iam a beginner in C can any1 sujest some modification to this code so that..it can compare file2 with entire file1
Quote:
Ive seen some fixes for this but they all seem to be specific to the particular user's sources.list . . . ..
Code:
Here is Line 54
Code:
I tried to change the basic toolbar to cairo dock,a tutorial that i found told me to write in terminal gksu gedit /etc/apt/sources.list.d/winehq.listso i write it and a window opened,i couled not find the text that told me(the tutorial i mean)so i closed the window,after that i keep taiking the same error
E: Type �sudo� is not known on line 55 in source list /etc/apt/sources.list
E: The list of sources could not be read.
Go to the repository dialogue to correct the problem.
E: _cache->open() failed, please report.
now whene i got in the winehq.list the text has gone and i take this error in update manager,my software center doesn't work and my terminal whenever i type sudo commands says
E: Type �sudo� is not known on line 55 in source list /etc/apt/sources.list
I get this error message: E: Malformed line 57 in source list /etc/apt/sources.list (dist parse)
I am pretty new to Ubuntu and dont really understand computer
Here is the sources list (??) as well
don't know much, but when I tried to update I get this error:
E: Type 'sudo' is not known on line 52 in source list /etc/apt/sources.list E: The list of sources could not be read.
There is a problem with my source list (apparently) I'm running 11.04 if that helps.When I try to use apt-get install update for example, I get: "Malformed line 59 in source list etc/apt/sources.list"The same error occurs when trying to access synaptic package manager, it tells me there is a malformed line and the list of sources cannot be read.This error prevents me from apt-getting anything, updating and i suspect it is affecting the software center too.
View 6 Replies View Relatedcat filename| awk '{print $3}' | cut -c -3 | cut -c 2- | grep 66
this returns the lines containing "66" at 2nd 2 characters of 3rd column of a line, now i need complete lines for this, how can i do it?
Here's my current regular expression(used in sed):sed 's///!Start.*//!End//g' in > outThe only problem being that the wildcard . does not work across multiple lines,
View 1 Replies View RelatedI have to delete a certain line of text from the a textfile via ubuntu's shell scripting.I have done research, and it seems that most people advocate the usage of sed /d option. sed makes does not edit the text file. Hence, most options I discovered involved the use of a temporary variable/textfile and then overwriting the old file with the temporary new file. Is there anyway whereby I can bypass the use of temporary storage containers? I hope there is any magical combination of commands to edit the file directly.
View 3 Replies View RelatedThis has to also show the line count. I can get it to show the files but not the line count. What is the single command used to identify only the matching count of all lines within files under the /etc directory that contain the word „HOST? List only the files with matches and suppress any error messages.
View 4 Replies View Relatedremove a line starting with specific word with grep. Here is what I found
grep -v '^cc$' data.txt
Here I remove all lines with on 'cc' in that line. But I want the result write back to data.txt
I try several ways
grep -v '^cc$' data.txt > output.txt # works but to another file
echo `grep -v '^cc$' data.txt` > data.txt # didn't work, all carets gone, become one line
grep -v '^cc$' data.txt > data.txt # data.txt is empty after running this
How can I save the result of grep to the input file?