I have grepped a log file to obtain every line that contains a word (let's call it 'blah'). I now want to only display a list of entries within that search result that feature the word 'host' anywhere in the line, and I also want to display the single word *after* 'host' (up until the next space). So, the end result will look like this:
[Code]....
I have a output file look like this:
{"test1" : "test2", "test3" : "test4"},
How can I read word by word in each line?This is not working code:
a=0
while read word
do a=$(($a+1));
[code]...
I am pretty new to bash scripting...I am trying to write a script that will take an input and read it word for word and then DO something with it like echo. I have been able to find how to read word for word from a file but I don't know how to do it with input.
I was looking for something like
Code:
exit 0 The input would be A-Z a-z 0-9 and have a single space between each word.
bash 3.1.17(2) I'm trying do write a shell script which must operate on each line of an ASCII text file. So, all the code must be inside a loop, and inside the loop, the first thing should be to read the next line from the file. I have the bash read command. But it reads from stdin. Any way to make read from a file?
View 6 Replies View RelatedI would like to delete a single line from a file that contains many lines passing through the same values as the two parameters. Again, I would like to delete a single line and not all those that contain parameters. How can I make bash?
View 14 Replies View RelatedBelow is the part of my bash script which uses awk to to fetch a line from a file. Choice is set by a case, and i know it is receiving a proper number because of the echo statement. The problem is with the syntax of the awk command it says the error is with one of the ', but when I run the command at the command line and replace "$choice" with a number it works properly. So I am not sure what is going on.
echo "announcing choice $choice"
command="awk 'NR = "$choice"' beerpong.txt | say"
$command
I've got a bash script I'm using to download a text file list of links via axel. What I'd like to do is automate the movement of completed links in the for loop when axel has successfully completed the download. This is what I've got. I can figure that I can just echo append the line to a new file, but what is the easiest way to delete the line with the link I just downloaded?
Code:
#!/bin/bash
for i in $( cat $1); do
axel --alternate --num-connections=6 $i
export RC=$?
[code]....
At the moment I got my md5sum checking working which I write to a text file and see below.
If the md5sum works it will write the output to check2.md5 test.txt: OK
If the md5sum fails it will write test.txt: FAILED
How do I write if statement to check the output whether or not the md5sum failed or not ?
check1="/home/ops/Desktop/test1/check1.md5"
check2="/home/ops/Desktop/test1/check2.md5"
cd /home/ops/Desktop/test1
md5sum test.txt > $check1
[Code]....
I'm having issue when trying to change a line in a file
[Code]....
I am trying to write a bash script that installs a program fully automated for me. I am stuck at the one part where i need to change a line in one config file. I have tried various syntax for sed and none have worked. Maybe someone can suggest how to go about this. Since the line appears in the middle of the file, I can't use echo or cat. Also the file will be diffrent lengths depending on the install.
The line I need changed is:
I need that changed to:
the last syntax i tried is:
Yes this is for PNP4Nagios on centos 5.6 64bit. If i can get this figured out. I will be willing to post the whole thing for others to use. it will be used to install PNP after a working nagios install is done.
I'm building a script for my place of employment. The next step in it is checking what the user input was. Determining if they added a part in there or not. The script prompts for a hostname. Hostnames are localhost.localdomain. Now, I want the script to check to see if they put localdomain and if they did, not to add the domain to the /etc/sysconfig/network, but just what they entered. So say the user inputs:
[Code]....
I have a file which a number at the end of each line. I need to change this number in the file to be correct, i.e. each time the number is 9 it needs to be 1, each time it is 233 it needs to be 2, etc... There is no pattern to the numbers currently in the list other than the same number appears only in a single line/group of lines, not throughout the file, but the replacements need to be sequential (but can be repeated an arbitrary number of times).
[Code]....
Want to search for ~ and delete it as well as to append the entire line to the above line. For Ex:
1111xxxx date Sandy area is ~around this area.3222xxx date There seems to ~left side of map, the colours are accurate (showing green areas)Even if I ~zoom in, the green parks, xxx3258 date The dammed up
~away, the "other" body of water varies ~blackNatural gas leaching.
IT MUST LOOK LIKE:
1111xxxx date Sandy area is around this area. 3222xxx date There seems to left side of map, the colours are accurate (showing green areas)Even if I zoom in, the green parks, xxx3258 date The dammed up away, the "other" body of water varies blackNatural gas leaching.
Using the latest version of Ubuntu desktop on an emachine t5062 if it matters. I have a text file of keywords that is one-three words line after line for like 5000 lines. How would I go about adding a word to each line.Aside from typing it in or copying and pasting.If it can`t be done with Gedit I am all for using another program.
View 8 Replies View RelatedI have to modify formsweb.cfg file in Oracle IAS.
Problem description
In formsweb.cfg file are two lines with labels archive_jini= and archive= at the beginning of line. After equal sign (=) is row of filenames of java archives delimited by coma(,). When I insert a new jar file in java directory, I have to append the very same name of jar file to both lines if that name is not yet present.
Example snippet from formsweb.cfg
I have a text file that contains a single word and I want to write a bash script that will read the word from the text file... The following is my incorrect attempt, as it assigns the name of the textfile to the variable as opposed to the word stored within the textfile:(assume I have a text file value.txt that has its contents a single word, say wordone)
Code:
#!/bin/sh
for f in value.txt
do
echo $f
done
so the output of the above script is value.txt, however I want it to be wordone.to summarise: how do I assign the value of the word contained within a textfile to a variable?
I have a file in the form below, and wish to replace each start line with an increasing number. So instead of:
Code:
start
content content
start
content content
start
[Code]....
After several searches and a bit of messing around, it's clear I'm missing something, so was wondering if anyone could offer any insight?
I currently have 3 files with floating point data that I wish to have in a single file with the format:
Code:
F1 F1 F3 Output
a1 b1 c1 a1 b1 c1
a2 b2 c2 a2 b2 c2
a3 b3 c3 a3 b3 c3
a4 b4 c4 a4 b4 c4
I would like to know how do I print the line # in a script. My requirement is, I have a script which is about ~5000 lines long. If there are any errors happen I just exit. And I would like to add the line # of the script where the error happened.
View 3 Replies View RelatedI have a set of files containing data that I need to re-arrange into one single property list.
The files that I have look like this:
Code:
# cat uk
<string>10</string>
<string>11</string>
...
<string>29</string>
[Code]....
So the lines in the files match up but I haven't found a way of reading several files line by line.
I'm trying to make another file annotation script a little speedier than it has been by the up-until-now proven method of checking the last four characters in a filename before the "dot" (eg .jpg, .psd) against a list of known IPTC categories and Exiv2 command files. It occurred to me that if one script generated a list of files in directory foo, and the same or another script sorted that list by that four-letter tag,then that list could be used(instead of a for/do/done loop on the real files in the folder) by the command-file-matching script to "vomit out" which annotator file would go with file nastynewfile.jpg, f'r'instance. The script I had been using for this task looks like this:
Code:
while read 'line';
do
sp=$(echo $line)
vc=$(echo $sp | cut -d"," -f1)
cv=$(echo $sp | cut -d"," -f2)
[code]....
Where I seem to be stuck is with how to sort the lines in templist, which may be any number of different lengths, from back to front. sort -k looked promising, except it seems only to work the other way round. I thought of invoking a
Code:
q=$(expr length $line); echo $q
n=$[q-8]; echo $n
kind of thing, but that presented the problems of how to sort by those, how to tell sort where to find them (grep?) and how to "stitch them back in" to the original list, which is what I want to sort in the first place.
I have a wrapper script called MAIN.sh that runs several other script. It looks like this:
Code:
#! /bin/sh
script1.sh
[code]...
I have a text file (myfile.txt) with columns a,b,c.
123 2 23
124 2 24
125 2 22
[code]...
I want to access a file, and check the length of every line.After, i want to check and replace all lines with length over 10 characters, with a message.Does anyone have a clue on that?
View 1 Replies View RelatedWell, I am facing one issue:How can i read two files word by word at a time using any loop as i need word by word comparision in shell script?Please let me know pseudo code.
View 14 Replies View Relatedso i have a file that has the following
file1.txt
ID1 age_11 dog_n3 parent_dog_n1
ID1 age_7 dog_n4 parent_dog_n3
ID1 dog_n5 age_4
ID1 dog_n6 age_4
[Code].....
As you can see i would like the output file to be just the dogs, not the otehr information. But because the information is mixed up how can i extract only the dogs? (i cant do and awk '{print }' because the dogs are found in colounm 2 or 3 or sometimes even 4.
I want to know that how can i search for a word in a file and then comment it or delete it. I know this command works.
sed 's/word/#word/'g inputfile > outputfile
But the lines in my input file are as under:
zone "abc.com" { ---- This line can be comment
type master; ----- This line repeat again and again in the file
file "abc.txt";
allow-query { any; }; -This line repeat again and again in the file
};
I want to know how can i comment a certain zone.
i have a text file like
abc abc abc abc
abc abc abc abc
--- --- --- ---
i want to add a string xyz to end of each line..
abc abc abc abc xyz
abc abc abc abc xyz
abc abc abc abc xyz
--- --- --- --- xyz
--- --- --- --- xyz
how do i do this in bash?
I have a project due for my Intro to C++ class and we are suppose to generate a file listing that will take an input of a C++ source code with .cpp extension and make a copy of it with a .lst extention that will have a line number preceding each and every line.
View 12 Replies View RelatedI wish to add information to one of my files based on matching IDs,
Here is an example
(the id is the 3 colunm)
(the ID is the 2 colunm)
And the output i wish to be
OUTPUT:
So as you can see the ones that do not match are still present, and the ones that do match just have the extra information from file2.txt added to them.
I thought about using join but that only seems to join the ones that match displays thoes only. i would like all the information in the output file.
