Programming :: Awk/bash - "current Dir" - Script On A File In A Subfolder
Apr 25, 2011
I have a script (bash) that do some editing and stats on different logs (syslog) and output a file (html format). If i want to run the script on a file in a subfolder as the script where in that folder how do i do that?
Code:
makes a file called index.html with some stats from the syslog file.
if i run the script on a file in a subfolder
Code:
the script makes a output in the base folder, i want it to print the file to the test folder. There are multiple subolder and i want a index.html in each of them.
I've got some bash scripts that I'm testing which operate on different screen sessions under different usernames. In order to check the status of them, however, I have to attach the screen sessions to my current terminal.
I run into problems, though; I only allow SSH to my machine from one username; the others shouldn't need SSH access. So, I log in as one user, and su into whichever user I need. Without performing a chmod o+rw on the terminal before I su into a different user, screen complains that it can't reattach to my terminal, because the user trying to make it attach doesn't have the permissions to do so.
Seeing as I forget to do this a lot, I wanted to make a script that I'd run on log-in to do this for me. Unfortunately, I don't know if there's a bash variable that refers to the current terminal - I can't always guarantee that I'll be logging in to /dev/pts/0, especially if my internet connection gets cut and I leave a hanging terminal...
Is there a variable for that or a way to refer to it in a script? If not, how do I work around that?
why I cannot upload local files to subfolder in my home folder on FTP server? Say, i wanna upload files to /home/haolh/trial/occ/src/occ, but following error msg were given...
commandput "C:Proj rialoccsrcocc" "occ" error/home/haolh/trial/occ/src/occ: open for write: permission denied
After google this prob, i've tried commands as below but it still failed
how i can use the cal command so it displays the current month and the next month, i know you can use cal -3 9 2007 to show the previous current and next but i just want to display the current and next.
and I have share1 and its subfolder " subshare " the thing i have to do is that, i have 2 assign user1 and user2 to share1 that means user1 and user2 can only access share1 through password and user3 can access only its subfolder "subshare" i have done this upto first level permission of share1 not able to do for its subfolder "subshare"
What's the easiest way for me to make a program that requests a file location and then tar balls it. I basically want to start making a simple method of using pv with tar (lzma).
#!/bin/bash ls -lhGg | while read line; do echo "$line"; done | awk ' { print $3" "$6 } '
what i want to do is be able to print column 3 and every column greater then 5. Has to be to the end of the line, since different filenames can have different amounts of words in them and the blank space is the separator. my current code works just fine if the file has no blank space.
How do I use bash to open a file, (file name as first parameter) cut n char from begin of each line, and write shortened lines to new file (outputfile name as the second parameter, n as the third parameter)
I have a laptop that I am in through SSH. The laptop does not have an Xwindow system so I am using the program fbi to open an image on my laptop screen from my SSH connection:
fbi -T 8 picture.jpg #this opens the image on the laptops tty8 terminal
I've found that making a for loop does not work with files that contain a space in the name. Something to due with a bug that they call a "feature" that stops the first variable at the first whitespace.
Using a "while" loop is not exactly what i require either seeing as I want to be able to view each image in the directory on screen and tag it accordingly, before it jumps off to the next image, and I'm not sure how to add a pause to a while loop.
How do I make a Bash script and loop Variables handle files like "files that contain spaces.jpg"
I would like to delete a single line from a file that contains many lines passing through the same values ​​as the two parameters. Again, I would like to delete a single line and not all those that contain parameters. How can I make bash?
Using awk I pull the first field of a random line from my datafile.myvar1=`awk -F" " 'NR=='$randline' {printf "%s", $1}' myfileThis works fine. The problem is there will be empty lines at the end of the file. Rather than using awkto filter out blank lines I would like to figure this out first.So I test $myvar1 for a blank string after setting $randline to one that I know is blank:test -z "$myvar1" && echo "true" || echo "false"But, this returns "false"? So the string is not zero length. Why? It's a tab-separated file. Is awk storing the tab with the $1 field or something.This is where I get headache. I try to echo my variable to see what it looks like.
echo "$myvar1" outputs: nothing echo "My variable is [$myvar1]" outputs: [y variable is [
Why is the closing bracket at the beginning? What character could be stored in $myvar1 that would do such a thing and how did it get there?
This code uses ping to check connectivity to a remote location and logs it to a .html file which is then stylized by css..
Code:
#! /bin/bash path="$HOME/Desktop/IP_Monitor" #Path to write out files ALT="0" #For styling alternative row
[code]....
I need to add a feature such that instead of hardcoding the ip address .. it takes them from a list and makes new files for each ip address for logging.. And also when log files are completed , They should be compressed using tar. How should i go about adding both these.. This is my first bash script.
I have a script that reads part of a line, delimited between the first and second intended part by a colon. Then it "chops" the part after the colon, which are words offset by commas (counting them beforehand so as to catch every word in the string's second part), like this:
Code:
"COLORS.JPG:red,orange,yellow,green," (Returning) red
[code]....
single script that parses/breaks both parts of a line like this "COLORS.JPG:red,orange,yellow,green;blue,indigo,violet," so that the two parts, separated into single words (or two and three words, sometimes with spaces) can be used as single-line annotations and written to JPEG files using Exiv2. So far, I haven't been able to come up with a script that does this without one part of the total string(usually that part after the colon) becoming the first word in the second array. In other words, I look for this:
KEYWORDS:
[ ]red [ ]orange [ ]yellow
[code]....
Or vice-versa (ie, the second array winds up as a single-line "member" of the first). I think it's because I'm using a single while read loop to read the text file in which the filenames and substrings happen to be. If there's some way of reading a file once and going back to the beginning to read it again in another while loop, I haven't found it.
I am struggling with Bash scripting at the moment (I can't seem how anyone can write scripts with this language!!!) I have a need at home to have a cron job execute daily to lookup my downloads.txt file, read each url (per line) and download content from that url. Then that entry needs to be removed (well I keep all urls in memory and clear the file afterwards). If an error occurred during the download process, then the url is written to a downloads.err file. I got all the above working except for properly reading the url from the text file without including newline characters. I am using the following to read:
while read url; do --Do whatever here-- done < downloads.txt
How can I get it not to let the url variable have newline characters?
I have a file called list.txt with on word on each line that changes in length. I'd like to make a menu, each line being its own choice. I pieced together most of it the only thing missing is a failsafe for typing a number out of range
I need to Read a path of a file witch is written in Text file i used this
Code:
FILENAME=$1 while read line do echo $line done < $FILENAME
it worked and showed me the Line witch was written in my file but now my problem is how am gonna use that line as a path i mean for example if am gonna execute a linux command on that file like dpkg -i /path/to/the/file how am gonna export it from The $Line variable and use it after the command.
This script simply deletes files older than a certain age (in this case 7 days) from a certain location; I use it to purge old backups nightly, and it works as expected:
# delete backups older than 7 days find /mnt/backup/* -mtime +7 -exec rm -Rf {} ;
The problem is, every morning I get an email with an error message something like this:
find: `/mnt/backup/subfolder': No such file or directory
I'm new to bash scripting and I've searched around the forums and Internet for this but haven't had any luck. I've found similar things but not what I need. What I need to do is write a simple script that uses what the user inputs to locate and display where a file is. I would prefer to use locate instead of find since I know that the person I am writing this for has locate on her machine (my mom, who is just beginning with Linux).I'm writing the script to make things easier for her while she learns In this particular part of the script I would like to be able to have the script prompt to enter the file she is searching for, read the her input and then display for her where the file is. I realize it would in most cases be much simpler just to teach her how to use locate, but she is very impatient and this is just a part of the script I will be writing, but I can't figure out how to do this.
I have got a script with an outer and inner loop. The inner loop issues loads of echo's which need to be redirected to a log file determined by the outer loop. The obvious solution is to redirect every echo to >$LOG and set LOG in the outer loop.
Code:
for f in $FILES ; do LOG=<logfile> for l in $LINES ; do
[code]....
it is possible to map stdout to $LOG in the outer loop without having to redirect every subsequent individual command output?
Im writing my first bash script. Its function is to move files to the trash can and write a log file in the same format that the system does to allow for file restoration. The problem is that in bash, everything works fine, but in the OpenBox window session, the files are named after the source directory, not the original name. Heres the script:
Code: #!/bin/bash # trash - Script to move file or folder to the trash can and create a log file ##### Functions ##### err_output () # Writes error message { echo "$0: cannot stat `$1': No such file or directory" echo "USAGE: $0 SOURCE DEST" exit 1 } >&2
if [ -e "${DEST}/${FILE}" ]; then max=0 DIR="$(pwd)" cd "$DEST" shopt -s nullglob for backup in "${FILE}."; do nr=${backup#${FILE}.} if [[ "$nr" =~ ^[0-9]+$ ]]; then if (( nr>max )); then max="$nr" fi fi done cd "$DIR" max=$(( max + 1 )) write_log_numbered mv -- "$SOURCE" "${DEST}/${FILE}.$max" else write_log_unique mv -- "$SOURCE" "$DEST/${FILE}" fi
So I run the script with the test file "Junk". In bash, it moves over and its named correctly. Code: ~/.local/share/Trash/files$ ls file file.1 Files Files.1 Junk The log file is also named correctly
Code: ~/.local/share/Trash/info$ ls file.1.trashinfo Files.1.trashinfo Files.trashinfo file.trashinfo Junk.trashinfo
But, when I go to view the trash can in the file manager in Openbox, the file is called "Testing" which is the name of the source directory. However, if I go to the trashcan via its full path (going to .local/, then share/) all the files are named correctly. Whats going on here? Is there some way to get the trash can to read the correct file name?
This script that I found online does the job it promises. it does convert the files to mp3 without an issue. What I need to include now is an if statement that says If $file.mp3 exists then delete $file.wav
Code: #!/bin/sh # name of this script: wav2mp3.sh # wav to mp3 # Credit to the script creator (Nikesh Jauhari):
[Code]...
After that I'm stumped as to how to do the if statement
Below is the part of my bash script which uses awk to to fetch a line from a file. Choice is set by a case, and i know it is receiving a proper number because of the echo statement. The problem is with the syntax of the awk command it says the error is with one of the ', but when I run the command at the command line and replace "$choice" with a number it works properly. So I am not sure what is going on.
