I have 2 files to compare and then print out information that match a certain pattern. I know basic scripting and was heading down the path of merging the 2 files together but this is the wrong approach. Would really appreciate a script that can do what is required:
file 1 contains dates, times and ID's:
2010-10-28 10:42 5939697357
2010-10-28 11:56 5919543491
[code]...
What is the best and simplest way to compare two directory structures without actually comparing the data in files. This works fine:
diff -qr dir1 dir2
But it's really slow because it's comparing files too. Is there a switch for diff or another simple cli tool to do this?
I have some data ( seperated by semicolon ) with close to 240 rows in a text file temp1. temp2.txt stores 204 rows of data ( seperated by semicolon ). I want to : Sort the data in both files by field1.i.e first data field in every row. compare the data in both files and print out the rows that are not equal in seperate files. I was trying to do this with excel using vlookup, without a great deal of success. hence, i'm exploring the shell script option.
Code:
temp1.txt
1000xyz400100xyzA00680xyz0;19722.83;19565.7;157.13;11;2.74;11.00
1000xyz400100xyzA00682xyz0;7210.68;4111.53;3099.15;216.95;1.21;216.94
1000xyz430200xyzA00651xyz0;146.70;0.00;0.00;0.00;0.00;0.00
[code]....
I want to have a script that pull db from remote server to my local. Beside that the filename should contain current date the time the db was dumped.
Ex: getdb databaseName
Then the filename should be like this:
So basically I have an archive of DB. Similar to this I need also a script that pull directory from remote to my local.
Ex: getdir htdocs
Then the filename should be like this:
file 1 :
DB_NAME FIRST_ACTIVE_LOG DBPARTITIONNUM
-------- -------------------- --------------
BP1 279231 0
BP1 12735 1
BP1 12734 2
BP1 12735 3
BP1 12616 4
[Code]...
I want to compare two files in perl, I have two files file1.txt & file2.txt. if column1 on file2.txt match column1 on file1.txt then I want my result on file3.txt (column1 column2 file1.txt + column1 column2 column3 file2.txt). this problem was solved with "awk" but I want to do in perl.
file1.txt
---------
column1 column2
------- -------
linux-2049 1
linux-2817 1
[code]....
i have file1 and file2.
[Code]...
Here i want to compare these two files with diff command and need to take the common things in a separate file. File contents are 7 strings in length and everything will start with the character e. File 3 contents should be
[Code]...
I need to compare two binary files and get output in form
for every different byte. So if file1.bin is code...
what is the easiest way to accomplish the goal? Standard tool? Some 3rd party tool?
How to compare files on ftp-server and in a folder in Linux?
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example:
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line_1
[code]...
How can I use diff to compare the files of similar directories on to diferent linux boxes.
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View 11 Replies View RelatedI'm working with Radiotap headers right now. I want to get the RSSI data. I came through a problem that I can't figure out right now.The value that I need to get is:
Code:
s8 IEEE80211_RADIOTAP_DBM_ANTSIGNAL
now, when I printf it:
[code]...
I have this program:
#! /usr/bin/perl
use DBI ;
use strict ;
[code]....
and I get this error simply running the program from the command line: DBD::mysql::st execute failed: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 at ./submit.cgi line 24.
is this the right syntax to use, both, for this line:
my (@param) = $cgi->param("firstname","lastname","type") ;
as well as this one:
$sth=$dbh->prepare ("SELECT firstname,lastname,type FROM dts WHERE firstname LIKE $param[0] AND lastname LIKE $param[1] and type LIKE $param[2]" );
or should there be quotes around the $param[0] or something? (also is it $param[0] or $param(0)?)
I am using the diff command with the -r option, to compare a large number of files and files in subdirectories. My main interest is to find out which files have been changed, and not what the actual changes are, and since a lot of files has been changed, it would be a lot easier to view the file names only. Is there and option for diff that might do this, or does there exist a similar tool/command that could do the job?
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I am trying to figure out a way to pull http links out of text files and then output the results in a log. The text files are in folders like this inside a source directory.
/source
./folder1
...folder1.txt
./folder2
...folder1.txt
[Code]....
I have two files (not sorted) and need to compare line by line (i.e. first line of file1 to be compared to all the lines of file2 and so as for the rest of file1). Output will be an array of length of file2. Any suggestion in BASH other than a grep inside two read line loops ( which is time consuming for files ~1000s of lines).
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View 2 Replies View RelatedI have to write a script that accepts two directory names (JIIT, JUIT) as positional parameters and checks which files are identical in both directories and files having same contents are also considered as identical in same directory. I tried using diff:
#both directories contain three files...file1, file2, file3
echo "Enter the directories:"
read d1
read d2
cd $d1
if diff file1.sh file2.sh > /dev/null
then echo same 1,2
else echo different
fi
if diff file1.sh file3.sh > /dev/null
then echo same 1,3
else echo different
fi
if diff file2.sh file3.sh > /dev/null
then echo same 3,2
else echo different
fi
cd ../
cd $d2
.....
I used the same code in the other directory for the three files. This is not running. I also want to know what to do when I need to compare files from different directories. i.e., JIIT, JUIT..
Dear expertsI have files like
ABD : 5869 events, relative ratio : 1.173800E-01 , sum of ratios : 1.173800E-01
VBD : 12147 events, relative ratio : 2.429400E-01 , sum of ratios : 3.603200E-01
SDF : 17000 events, relative ratio : 3.400000E-01 , sum of ratios : 7.003200E-01
[code]....
I have two files with user DN's that exported from two different LDAP directories. I wanted to write a script that reads(checks) users (cn=user1) in file Ack to see if users(cn=user1) exists in file B and give me nice output with what users are missing in file B.I have around 30k users in file A with following format..Quote:
cn=user1,ou=some,o=org
cn=user2,ou=some,o=org
cn=user3,ou=some,o=org
[code]...
I would like to compare two md5sum outputs to see if the files match. in my script I have
Code:
ORG_FILE="/path/to/org/file.zip"
NEW_FILE="path/to/new/file.zip"
MD5_ORIG=$(md5sum -b "$ORG_FILE")
[code]....
How do I get just the MD5 hash and not the */.... stuff so I can compare them. i tried Code: JUST_HASH=${$MD5_ORIG:0:32} but All I get is
dir_mon_notify.sh: line 79: ${$MD5_ORIG:0:32}: bad substitution
I want to compare the following two tab-delimited .txt files (both were subsets of the original files) by comparing Columns 3 and 4 simultaneously. It is easy to compare C3 because both C3s are just numbers. But how to compare C4s?Basically, in File1, "G,G" = G in File2, "C,C" = C in File2, "A,A" = A in File2, "T,T"= T in File2.In File2, A/T in Column4 just equals "A,T" or "T,A" in Column4 of File1. C/T in Column4 just equals "C,T" or "T,C" in Column4 of File1, and etc.
File1:
C1C2 C3C4
ih509rs12345467244750"G,G"
ih499rs6049687244911"C,C"
ih508- 7244977"A,A"
[code]....
I need to create a script that will compare the differences between two folders and then to copy only the updated and new files only to another directory. I know I need to use rsync here, I can write scripts so really it not how to create a script it is how do I accomplish the transfer of only new or changes files between two folders to a new file. Do I need to link these two folders first and then use the "--compare-dest" switch.
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