How would i calculate following values.Initial file
10 3
20 4
How would i calculate 3rd column which should be addition of value in 1 and 2nd column.File after calculation
10 3 13
20 4 24
i've been using a awk script to calculate my data... i have 3 files:
file a1.txt:
2
3
4
[code]....
the results were (3.5, 6 and 3) which is pretty easy.. now i want to combine all this into 1 file and each have different columns and called it avg.txt which have something like this in the end:
3.5 6 3
i use this script to get the time and date of back and fourth transactions for a particular execution id. I use a substr command on the 5th column to to cut the milli seconds off the time value. - otherwise the times would look like 08:30:04.235
grep <executionID> <auditfile> | awk '{ print $1, $2, $3, $4, substr($5,1,8}
FIX -> Mon 3/1/2010 08:30:04
FIX <- Mon 3/1/2010 08:32:36
FIX <- Mon 3/1/2010 08:35:08
[code].....
anyhow - i append two sed commands to further clarify the direction of the message.
awk '{ print $1, $2, $3, $4, substr($5,1,8} | sed -e 's/->/ ->IN/g' | sed -e 's/<-/<-OUT/g'
FIX -> IN Mon 3/1/2010 08:30:04
FIX <- OUT Mon 3/1/2010 08:32:36
[code]....
I tried using an awk gsub () command within the string instead of the two seds, but it did not work:
awk '{ print gsub(/<regex>/, <replace with>,$1), $2, $3, $4, substr($5,1,8}
the sed works ok, but it would be cooler to make the replacement within the awk command:
gsub(/->/,-> IN, $1)
Is there a way where i could replace the value of the $1 column in the awk print string?
I have a multicolumn datas, like
a1 b1 ... f1
a2 b2 ... f2
. . ... .
[code]...
I would like to make a file with all these data in one column, like
a1
a2
.
.
[code]....
Can it be done with awk or some other command? Also, is it possible then do add another column in front of this one with numbers of the lines (for every previous column), like
1 a1
2 a2
. .
. .
[code].....
I have a two column file and I need to create a new column in between the first and second but the new column adds a value to the first. E.g.code...
I thought I had figured out how to do it with the following but it just hangs:
awk -F '{print $0,$0+25,$1}' file_in > file_out
Also tried the following to no avail:
awk -F,-v OFS,'{print $0,$0+25,$1}' file_in > file_out
I can add the new column with the added value to the last column easy ( awk '{print $0,$0+25}' file_in > file_out).
I have not defined a user vimrc, OS is redhat 4.6 and after a search and replace the first column in the editor is highlighted yellow and it stays that way as I close and open vim. This is the /etc/vimrc that came on the system. anyone see a bug or a reason it would do that?
if v:lang =~ "utf8$" || v:lang =~ "UTF-8$"
set fileencodings=utf-8,latin1
endif
set nocompatible " Use Vim defaults (much better!)
[Code]....
1. when we run od command it displays octal values. But the first column will be always 000000. after that the actual file contents are displayed. Can anyone tell the meaning of that.
2. When we run ls -l command, in the first line of the output, we can see some integer value. What is the significance of that value.
I have some series of files, which actually named bellow
<day_month_yr>_<hh:mm:ss>.<host_name>.<IP.ip.ip.ip>.<log_name>.txt
I want to show this file name below the column may be
Date Time Host_Name IP_address Login_Name
----- ---- --------- ---------- ----------
<day_month_yr> <hh:mm:ss> host_name x.x.x.x log_name
...
Im trying to use awk to do matching in only a specific column
example.txt:
www.google.com www.example.com
www.google.com/search www.example2.com
i used:
awk '{ (if $1 == "http://www.google.com") print $2}' example.txt
this awk statement only returns the first line, and i cant seems to make it perform in a way to match based on keywords like GREP. Is there any way to make display the other lines which contains "google" also?
It is very important for my research work. For example mydata.txt:
id type x y z
1 6 0.474611 0.227223 0.583947
2 4 0.422894 0.22726 0.536791
3 5 0.448963 0.200148 0.560336
4 3 0.386478 0.207721 0.515293
5 6 0.371617 0.22361 0.582206
6 4 0.32123 0.222999 0.534782
How to change second column (type) whose values are 4 and 3 to value 1, so that mydata.text file become:
id type x y z
1 6 0.474611 0.227223 0.583947
2 1 0.422894 0.22726 0.536791
3 5 0.448963 0.200148 0.560336
4 1 0.386478 0.207721 0.515293
5 6 0.371617 0.22361 0.582206
6 1 0.32123 0.222999 0.534782
I have a basic question of awk.
Code:
var=/test/build/create/sls
echo $var | awk '{ FS = ":" ; print $NF }'
/test/build/create/sls
I am trying to extract last column from the above awk one liner.
I want to use awk to modify file like this
origin:
A[]A[][]A[]A
modified:
A[]a[][]A[]A
but when I use
awk '{$2="a"; print $0}' inputfile
the output is
A[]a[]A[]A
where the [] means space. This is not what i want. I guess that is because the OFS is one space by default, but i really don't know how to solve this.
I need to replace a value in a file. For example the content of data.txt file is:
1 1 23
2 1 42
3 2 52
4 2 62
5 1 77
6 1 88
7 2 99
8 1 100
Could I substitute 2 in second column with 3 using awk and or sed or other command so that the data will be change as follow?
1 1 23
2 1 42
3 3 52
4 3 62
5 1 77
6 1 88
7 3 99
8 1 100
How do I sort the output of du by its first column. I issue the command this way:$ du.Is there a way?
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On a text file, .txt, it is possible to high-light and copy a row on a table. But how to high-light and copy a column.
I was trying to redirect the output of two variables to different columns of a .csv file in MS excel like this,
Code:
echo "$a $b" > abc.csv
But I am getting both $a and $b in the same column, is there anything I can use instead of to move the value of $b to the next column? Or is there a good different approach to do it?
I have this piece of code with some template strings.
Code:
Big_L: $Big_L
$Big_R
$Lambda_tf
$Epsilon_1
$mu
$n_0
$ms
$Delta_R
$Epsilon_2
$Lambda_d
$Epsilon_3
$Small_N
$Small_Q
How can I insert exactly the same template strings in front of each string, but just without the '$' sign (see the first line for an example)?
I have a text file and I need to replace the 3rd column of that file from row 3 to the end of the file with a column which I have stored in the different text file. For e.g the original file is like given below:
a.txt nobla 6 gadf 72.500 1.600 1.800 .850 5.250 8.540
A# rad ang ht prf bk sd dia type blade
1 0.3081 9.00 1.9235 -17.50 18.00 -3.00 0.6250 1613 1
2 0.6509 194.00 2.0316 -17.50 18.00 -3.00 0.6250 1613 4
3 1.0128 8.00 2.1457 -17.50 18.00 -3.00 0.6250 1616 1
4 1.3748 192.00 2.2598 -17.50 18.00 -3.00 0.6250 1616 4
5 1.6986 7.00 2.3619 -17.50 18.00 -3.00 0.6250 1616 1
6 1.9347 120.00 2.4364 -17.51 18.00 -3.00 0.6250 1616 5
7 2.1327 190.00 2.4988 -17.34 18.00 -3.00 0.6250 1616 4
So lets say I wanna replace column 3 from row 3 to row 7 with a data from another file which is given below:
54.00
239.00
53.00
237.00
52.00
165.00
235.0
So the final output file should be like this:
a.txt nobla 6 gadf 72.500 1.600 1.800 .850 5.250 8.540
A# rad ang ht prf bk sd dia type blade
1 0.3081 54.00 1.9235 -17.50 18.00 -3.00 0.6250 1613 1
2 0.6509 239.00 2.0316 -17.50 18.00 -3.00 0.6250 1613 4
3 1.0128 53.00 2.1457 -17.50 18.00 -3.00 0.6250 1616 1
4 1.3748 237.00 2.2598 -17.50 18.00 -3.00 0.6250 1616 4
5 1.6986 52.00 2.3619 -17.50 18.00 -3.00 0.6250 1616 1
6 1.9347 165.00 2.4364 -17.51 18.00 -3.00 0.6250 1616 5
7 2.1327 235.00 2.4988 -17.34 18.00 -3.00 0.6250 1616 4
And I will post the code whatever i have tried soon. I started with awk and cut commands..but never got it to work and also tried PASTE command too.
What I need to do is to extract one complete column (file size) from the output of ls -lS but while doing so in some rows I have a single space but in some other rows I have 2 or 3 spaces like some file sizes are different with 30 bytes 400 bytes and some 4000 bytes. So when I extract the output of ls using | cut -d ' ' -f5 i get the value which has only one space i.e. I get 4000 as output because 400 has 2 spaces seperated and 30 is 3 spaces separated. So how to get the file size column from the ls output?
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it should be something like this but i cant get it right
Sort -u +1 -3 results
the file is called results
I have a file like:
ER- V67
ER+ V68
ER- V69
ER+ V70
[Code]....
I am using the code:
sort -k1
but it prints it by sorting the second column.
I have 2 large text files , one looks like this:
<contact type="1">blahblah@hotmail.com</contact>
<contact type="1">blahblah2@hotmail.com</contact>
<contact type="1">blahblah3@hotmail.com</contact>
The other is a list of emails in single column format like this:
emailaddy@hotmail.com
emailaddy2@hotmail.com
emailaddy3@hotmail.com , etc
Is there a command to delete all the blahblah emails from text file 1 and replace them with the ones from text file 2?
Or maybe a linux version of 'Csved' which has the ability to add,remove,insert columns?
I'm newbie to awk scripting. Need your great help to convert the irregular lines into column using awk (Sorting based on "Pri Number" column)
Input files is as follows:
Partition Name OA
Partition UID: 88:93:22:AE:B3:42:DF:11:A8:64:00:60:16:36:04:02
HBA/SP Pairs:
[Code]...
I have two files: one is like
preface
Introduction
chapter 1
the other is like
1
2
3
I was wondering how to column-wise combine the two files into one:
preface 1
Introduction 2
chapter 1 3
by using some utilities, such as awk, sed, available in Ubuntu?
I have a file that stores employee login IDs, names, types, and permissions. Our software reads the information based on byte-columns, so it reads a column as any ASCII character (spaces, letters, numbers, punctuation, etc.). I want to create a web-interface for adding and removing users, and storing the data in a MySQL database. However, if I am creating the files from the MySQL output, I need a way to write to specific column locations in the file ...
User ID: Columns 1-4
User Name: Columns 6-30
Type: 32-40
Permissions: 42-45
I want to use a scripting language, preferably C-Shell, to call MySQL for the data and write the data to the correct columns of the file. I wrote a script that takes the data from the file, and dumps it into the MySQL table, so maybe I can pad the remaining space in the table column to fill with spaces ...
I have a lot of files with thousands of rows and usually two columns of data. Column 1 is a coordinate, column 2 is a score. I want to delete rows that have a value in column 2 over, in this case, 50.
For example, here's a clip from a file:
2999898 39
2999899 40.9
2999900 42.7
2999901 44.7
2999902 46.7
2999903 48.9
2999904 51.1
2999905 53.3
2999906 55.7
I want the output to be this:
2999904 51.1
2999905 53.3
2999906 55.7
I know how to use sed for very basic things like deleting rows or ranges of rows but I can't figure out this ostensibly easy command.
I have this .txt file
3183630 R
3574216 W
5264994 M
2656889 A
I want to sort it by the numerical order of column. After sort, I wish to get output like
2656889 A
3183630 R
3574216 W
5264994 M
anyone knows how to use sort to do that? or any other command?
I have two files one having some transaction IDs only and sample content as follows:
Code:
SDP-DM-100755485
SDP-DM-100755504
SDP-DM-100755508
SDP-DM-100755716
[Code]....
