General :: Bash Script: Find, Grep If And Else Programing?
Oct 20, 2010
I am bussy with a litle bash script but i have now a problem.I have a file on the server with every time different text.Somewere in this text the is the following line:PHP Code:<BR><DIV CLASS='itemTotalsTitle'>2 Matching Service Entries Displayed</DIV> I want to make a bash script that replace this line when it says:"0 Matching Service Entries Displayed"To a other text like:"There a no knowing problem(s) on this moment."]If there is a other number than "0" than replace this line with:2 problems have been found on this moment, whe are bussy to fix this problem
I tried to tag late onto a question similar to mine on stackoverflow (Find Non-UTF8 Filenames on Linux File System) to elicit further replies, with no luck so far, so here goes again... I have the same problem as the OP in the link above and convmv is a great tool to fix one's own filesystem. My question is therefore academic, but I find it unsatisfactory (in fact I can't believe) that 'find' is not able to find non standard ascii characters.
Is there anyone out there that would know what combination of options to use to find filenames that contain non standard characters on what seems to be a unicode FS, in my case the characters seem to be 8bits extended ascii rather than unicode, the files come from a Windows machine (iso-8859-1) and I regularly need to fetch them. I'd love to see how find and/or grep can do the same as convmv.
I am trying to do a find/grep/wc command to find matching files, print the filename and then the word count of a specific pattern per file. Here is my best (non-working) attempt so far:
Right now i have some code to catch the inputs, using a variable "z":
Code:
Then:
Code:
I'm almost positive that the problem is in the bolded line above (for one thing, it always leaves off the initial "-e"). So basically i want a string that gives me "-e input" and concatenates as many times as necessary.
I have a server hosting 100+ websites. I need to quickly identify which websites are configured with a database. There are way too many to manually check every website for a PHP file with a database name. So, I created a list of all databases from MySQL and put them in a text file. I then exported the text file to a shell variable and used it in a for loop.
bash variable
Code: DBLIST=`cat dblist.txt` Example of $DBLIST
Code: db1 db_testing2 database_clientname production words4cheap for loop
Code: for db in $DBLIST; do find . -type "f" -iname "*.php" -exec grep -i $db '{}' ; -print; done Note: my find statement starts searching at . which is the directory that contains all of my websites and their data, each website is setup in a sub directory, identified by it's domain name.
Example: I'm in /var/www. Beneath /var/www are a list of directories:
[URL]
However, this is taking too long (it's been running most of the day) and I was wondering if there wasn't an easier way to accomplish what I'm trying to achieve?
I am looking for all the files that contain the text string 'moo.sql'. I ran the following:
find . -name '*.php' | grep -lir 'moo.sql' *
Unfortunately it seems to return non-php files in addition to php files. I thought the find portion of this would filter the file names so grep would only search php files.
For searching a file or directory i normally use grep command. kindly can you guide me the difference between grep and find command. I have used both but that are the difference between them ? are the same or grep is new as comapird to find command.
I'm trying to use grep to find the words in the dictionary that contain the letters "th" and the letter m.
I tried grep 'th m*.' Desktop/Dictionary/words(Thats where the destined dictionary word document is located)
grep 'th' Desktop/Dictionary/words works but only for the words with th. I have no idea of what expression to use to make it a unionized expression with m
I want to find files containing the "$" char (ascii 0x24). 'Grep -irl $ *' would output the names of every file in path *, of course, because it means end of line (EOL). So giving grep the string "$" won't do. So I tried 'grep -irl $ *'. But this doesn't work either and I do not understand why. Am I not escaping the dollar sign? grep should interpret it literally. Neither 'grep -irl "$" *' will work. Fortunately, there's LQ, besides grep's man page.
I am new to linux as well as awk, grep or sed. I need a find and replace command single liner or script that loops trough input file (file1) and find the particular input in file2 and add "!" in front of the found string.
Example: input file: file1 g+h=o+p a+b=c+d file2 (file that need to look for) a+b=c+d1e105 x+y=z+s5e105 g+h=o+pabcdefg t+r=w+qxvyderf
Output file (file3 should look like this) !a+b=c+d1e105 x+y=z+s5e105 !g+h=o+pabcdefg t+r=w+qxvyderf
I have tried many awk and sed method of find and replce but it did not work the way I wanted. This is mainly due to my lack of experience in awk and sed. The program should loop trough file1 and find in file2 and output in file3 for the 1st (g+h=o+p) set then repeat the same process again for set 2 (a+b=c+d).
When I used the find command, I almost always need to search the local drives. But, I almost always have super large network shares mounted and these are included in the search. Is there an easy way to exclude those in the find command, grep and other similar commands? Example:
I have some big files of logs that contain errors printed by an app. They are most of the time relevant, however most of them are similar. So i figured i could check what happened between a time interval with a find.
Im using this one
Code:
And I get an output similar to this one.
Code:
Is there a way to condensate the output lines to get only one or two, indicating the start and last occurrence of a block? Or I need to create a program to do so?
Because right now I get thousands of similar lines, but when I'm scrolling through them i sometimes miss relevant information that i would've otherwise noted if it wasn't all that spammy.
I'm trying to write a bash script and I'm having trouble with it.I have a list of DNS entires from a file called zoneExport.txt.Than I want to parse a log file to see if that DNS entry has been queried for. So I'm running a grep command and trying to save it into a variable. What I'm looking for is a variable ($varGrepQ) that has the number of matches for the grep query. I will then run this through an if statement and do some things from there..
But my problem right now is with this grep query. It keeps outputting '0' even when I know there are records in that file and when I run the same query on the command line I get the actual count. My thought is that the $record variable is not passing right.
# metadata_expire=90m # PUT YOUR REPOS HERE OR IN separate files named file.repo # in /etc/yum.repos.d [liveuser@localhost hd1]$ yum list installed bash grep Loaded plugins: langpacks, presto, refresh-packagekit Adding en_US to language list Installed Packages bash.x86_64 4.1.7-3.fc14 @fedora/$releasever grep.x86_64 2.7-1.fc14.1 @fedora/$releasever [liveuser@localhost hd1]$ sudo vi /etc/yum.conf [liveuser@localhost hd1]$ cat /etc/yum.conf [main]
# metadata_expire=90m # PUT YOUR REPOS HERE OR IN separate files named file.repo # in /etc/yum.repos.d [liveuser@localhost hd1]$ yum list installed bash grep Loaded plugins: langpacks, presto, refresh-packagekit Adding en_US to language list Error: No matching Packages to list
Basically when I comment out installroot it says grep and bash are installed but when I change installroot it says grep and bash are not installed?
I would like to know how I can get the ouput from the following dmidecode command in example 1 to look like example 2 without having to grep -v all the unwanted lines.Is there a way in awk or sed?Example 1
Code: Processor Information Socket Designation: Socket 1 CPU 1
How would I use a unix grep regular expression to find any two capital letters side by side and how would I find an expected comma in an expected spot?
I am facing problem with the following script. Could you please look into this.echo 'Enter Staging number' case $STGNUM in
1) for i in {'stg1-greg','stg1-marsha','stg1-peter','stg1-jan','stg2-greg','stg2-marsha','stg2-peter','stg2-jan'};do echo $i; ssh $i sudo -u dev /opt/usr/apps/workflow/stopwf.sh;done;
This should be a simple thing to accomplish, but I can seem to figure it out. Essentially, I want to have a bash alias or function that will let me recursively grep the current directory. A while back I added this to my .bashrc:
Code:
alias rg="grep -r --exclude=*/.svn/* --exclude=*.swp"
This works fine, (and also ignores any svn and vim swp files), and I can call it like:
Code:
rg foo *
However, 99.999% of the time, I am only interested in searching in the current directory, so the "*" is a bit redundant. Also, I would say 5-10% of the time, I am typing faster than thinking and forget the "*", so grep just sits there trying to read from stdin. It's a pretty minor thing, but ideally I'd like to be able to just type:
Code:
rg foo
I've tried creating a function to handle this:
Code:
function rg(){ grep -r --exclude=*/.svn/* --exclude=*.swp $1 * }
but it behaves exactly the same as the alias above. escaping the "*" with 's doesn't work, and neither does trying `pwd` (or even a hard-coded path) in its place.
I am looking for a powerful command line tool to send and receive data via socket I mean define IP , port and data other options for command to send and receive data from sender.(like a high level socket programming)
