General :: How To Find File With Name="php.ini" Using Grep Command
Jun 14, 2011How to find file with name="php.ini" on linux using grep command?
View 2 RepliesHow to find file with name="php.ini" on linux using grep command?
View 2 RepliesI am trying to do a find/grep/wc command to find matching files, print the filename and then the word count of a specific pattern per file. Here is my best (non-working) attempt so far:
wc `find . ( -name "*.as" -o -name "*.mxml" ) -exec grep -H HeightResizableList {}` ;
For searching a file or directory i normally use grep command. kindly can you guide me the difference between grep and find command. I have used both but that are the difference between them ? are the same or grep is new as comapird to find command.
View 2 Replies View RelatedWhen I used the find command, I almost always need to search the local drives. But, I almost always have super large network shares mounted and these are included in the search. Is there an easy way to exclude those in the find command, grep and other similar commands? Example:
find / -name .vimrc
Getting the list of files in the root directory that have changed less than 10 hours earlier, using grep, but without the directories.
View 1 Replies View Relatedam new to linux and trying to find a file in sub directories using find command as:find .-name *.jpg -type fBut I am unable to get the result as find command is not permitted by the server administrator.Is there any way to find files without using find command.
View 14 Replies View RelatedI want to write some code to search for a specific string in a text file, but without using grep command.
View 5 Replies View RelatedI have used diff command in past.I faced a situation to which I did not had a cluehere are some text strings (which can be stored in a file)Quote:
CONFIG_XEN=y
CONFIG_XEN_PVHVM=y
CONFIG_XEN_MAX_DOMAIN_MEMORY=128
[code]...
I want to know that is there any method to grep a particular data from a file without using the "cat --- | grep ' ' " command....I need to use a system call for this functionality.
View 1 Replies View RelatedI'm trying to math all class references in a C++ file using grep with regular expression. I'm trying to know if a specific include is usuless or not, so I have to know if there is a refence in cpp. I wrote this RE that searches for a reference from class ABCZ, but unfortunately it isn't working as I espected:
grep -E '^[^(/*)(//)].*[^a-zA-Z]ABCZ[]*[*(<:;,{& ]'
^[^(/*)(//)] don't math comments in the begging of the line ( // or /* )
.* followed by any character
[code]....
Well, I can get patterns like this:
class Test: public ABCZ{
class Test: public ABCZ {
class Test : public ABCZ<T>
[code]....
I want to search file excluding the NFS ...find / -mount -name 'filename' restricts the search only in the root disc partition,but the file can be in other partitions alsoIs there any way to exclude the NFS only.
View 2 Replies View RelatedI have an SQL dump, file.sql that has many references to a particular domain, d1.com. I would like to run a command that can replace every occurrence of d1.com with d2.com. I've tried looking into sed before but the man pages are quite daunting.
View 14 Replies View RelatedI have a server hosting 100+ websites. I need to quickly identify which websites are configured with a database. There are way too many to manually check every website for a PHP file with a database name. So, I created a list of all databases from MySQL and put them in a text file. I then exported the text file to a shell variable and used it in a for loop.
bash variable
Code:
DBLIST=`cat dblist.txt`
Example of $DBLIST
Code:
db1 db_testing2 database_clientname production words4cheap
for loop
Code:
for db in $DBLIST; do find . -type "f" -iname "*.php" -exec grep -i $db '{}' ; -print; done
Note: my find statement starts searching at . which is the directory that contains all of my websites and their data, each website is setup in a sub directory, identified by it's domain name.
Example: I'm in /var/www. Beneath /var/www are a list of directories:
[URL]
However, this is taking too long (it's been running most of the day) and I was wondering if there wasn't an easier way to accomplish what I'm trying to achieve?
I'm relatively experienced with UNIX and Linux, but this has me thrown for quite a loop, and it seemed like such a simple question. How would I go about finding the newest file in a file system? I thought something like:
Code:
ls -ltr `find /usr -type f`
would work, but I seem to be exceeding the argument maximum for ls:
ksh: 0403-029 There is not enough memory available now
I thought something involving xargs might work, but I really suck with that command.
find /var/spool/mqueue -group abc -exec rm -rf {} ;Using above command , I delete all the files belong to group abc.Now the problem i face is that the this command gives error that some files are missing . And this error occur because after creating list of files, it pass that list to rm -rf but till that time sendmail process queue and some of files disapper from /var/spool/mqueue.
View 5 Replies View RelatedI am looking for all the files that contain the text string 'moo.sql'. I ran the following:
find . -name '*.php' | grep -lir 'moo.sql' *
Unfortunately it seems to return non-php files in addition to php files. I thought the find portion of this would filter the file names so grep would only search php files.
I'm trying to use grep to find the words in the dictionary that contain the letters "th" and the letter m.
I tried grep 'th m*.' Desktop/Dictionary/words(Thats where the destined dictionary word document is located)
grep 'th' Desktop/Dictionary/words works but only for the words with th. I have no idea of what expression to use to make it a unionized expression with m
I want to find files containing the "$" char (ascii 0x24). 'Grep -irl $ *' would output the names of every file in path *, of course, because it means end of line (EOL). So giving grep the string "$" won't do. So I tried 'grep -irl $ *'. But this doesn't work either and I do not understand why. Am I not escaping the dollar sign? grep should interpret it literally. Neither 'grep -irl "$" *' will work. Fortunately, there's LQ, besides grep's man page.
View 9 Replies View RelatedI want to scan a particular directory recursively and run a particular command with each file as input. For this I am using "find /dir/path". I dont want to write any long script containing loop on the output of "find". I want a single command which will allow me to run a command on each file of the "find" command output.
View 3 Replies View RelatedWhat does this command mean? grep 'GET / HTTP.*Mozilla/5.0 (Windows; U; Windows NT 5.1; ru; rv:1.8.1.1) Gecko/20061204 Firefox/2.0.0.1' last10m |cut -d ' ' -f1 |sort -n |uniq -c|sort -n|tail
Whats the best way to figure out these commands in general? I have a lot of learning to do!
I am new to linux as well as awk, grep or sed. I need a find and replace command single liner or script that loops trough input file (file1) and find the particular input in file2 and add "!" in front of the found string.
Example:
input file: file1
g+h=o+p
a+b=c+d
file2 (file that need to look for)
a+b=c+d1e105
x+y=z+s5e105
g+h=o+pabcdefg
t+r=w+qxvyderf
Output file (file3 should look like this)
!a+b=c+d1e105
x+y=z+s5e105
!g+h=o+pabcdefg
t+r=w+qxvyderf
I have tried many awk and sed method of find and replce but it did not work the way I wanted. This is mainly due to my lack of experience in awk and sed. The program should loop trough file1 and find in file2 and output in file3 for the 1st (g+h=o+p) set then repeat the same process again for set 2 (a+b=c+d).
I am bussy with a litle bash script but i have now a problem.I have a file on the server with every time different text.Somewere in this text the is the following line:PHP Code:<BR><DIV CLASS='itemTotalsTitle'>2 Matching Service Entries Displayed</DIV> I want to make a bash script that replace this line when it says:"0 Matching Service Entries Displayed"To a other text like:"There a no knowing problem(s) on this moment."]If there is a other number than "0" than replace this line with:2 problems have been found on this moment, whe are bussy to fix this problem
View 3 Replies View Relatedwhen loggin as a normal user and search for a file passwd under /etc. i get few errors with permission denied.how to ignore this permission denied errors.
csh hostname 109 % find . -name passwd
find: ./lvm/backup: Permission denied
find: ./lvm/archive: Permission denied
[code]....
I have a requirement to find the files having its name as ack_reply. However, there are many other files in the same directory as these resides. Now I have to remove these files from the folder and retain others after 7 days. So I tried to write the below script with grep command.
find $directory -type f -mtime +7 | grep ack_reply
how can I pass this output to -exec command.
If I am not using grep command my script would be as
find $directory -type f -mtime +7 -exec remove.sh {}\;;
How can I use -exec with grep and find.
I am using grep to filter out directories I am not interested in like this:svn stat | grep -v data/charts | grep -v lib/model | grep -v web/picsIt seems a bit "hacky". Is there a better way to specify more than one string to ignore, so that I dont have to chain multiple grep commands?
View 3 Replies View Relatedcat filename| awk '{print $3}' | cut -c -3 | cut -c 2- | grep 66
this returns the lines containing "66" at 2nd 2 characters of 3rd column of a line, now i need complete lines for this, how can i do it?
I have some big files of logs that contain errors printed by an app. They are most of the time relevant, however most of them are similar. So i figured i could check what happened between a time interval with a find.
Im using this one
Code:
And I get an output similar to this one.
Code:
Is there a way to condensate the output lines to get only one or two, indicating the start and last occurrence of a block? Or I need to create a program to do so?
Because right now I get thousands of similar lines, but when I'm scrolling through them i sometimes miss relevant information that i would've otherwise noted if it wasn't all that spammy.
I need to kind of grep within grep. My input file would be something like:
[Code]....
and I need to find the first occurrence of hello before MY PATTERN (hello 9008 in this case), so the output should be:
[Code]....
After typing "grep some_word" on terminal 6, the system doesn't do a thing, just lets me type endlessly. I've tried "Esc", "q" , [CTRL] + x, "exit" and no luck. I bet I'll kick my ass when you tell me but at the moment I can't figure it out. Rebooting would probably solve the problem but there must be a better way.
View 5 Replies View RelatedCan someone please tell me how I can use grep to display all users running a particular command.
View 3 Replies View Related