I am trying to use the time command to measure the execution time of a small program. The problem is that the command has three outputs. They look like this:
Code:
$ time ./a.out
real0m51.935s
user0m51.060s
sys0m0.040s
Should the execution time be the sum of the user and the sys time? sys time is really small.
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$ time ./foo > /dev/null >> output_from_time_command.txt
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In windows, you could do a dir | more to scroll one page a time.How does one do this in Linux?
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Code:
ls -l | grep 'date/time range' | mv /folder
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the elapsed real time between
invocation and termination,
the user CPU time (the sum of the
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View 2 Replies View Relatedtime a.out
106.130u 0.000s 1:46.28 99.8% 0+0k 0+0io 83pf+0w
As per my understanding of the man page:
the first value is the time since the code execution started and ended,
the second values is the time spent in usermode
the third one being in kernel mode
Is the 99.8% indicating time spent in kernel mode?
Also, what does this indicate?
0+0k 0+0io 83pf+0w .
The program definitely takes more than a minute to execute - then why is the first value so small?