Ubuntu Servers :: HP Deskjet - Lp Output Three Lines Only (NOT Header Or Date)
Jan 13, 2011
10.10 Headless Server, CUPS queuing to HP Deskjet via socket correctly (?), but output regardless of file type only top three lines (NOT header or date or so)
I'm a complete linux beginner and currently have the following board that I am playing around with.the main chip onboard is an atmel arm9 core with a debian style distribution pre-installed. I have just updated the factory kernel to 2.6.30 as I was told this had an inbuilt GPIO driver? I am trying to interface the output pins on the header of the GESBC-9260 to the linux distribution. i.e. I would initially like to write a c file that did something like toggle an output pin, which I can then connect upto an led and see this flash. However I don't really have a clue where to start. Hopefully someone could point me in the right direction?
I just installed a OpenSuse 11.4 box. Now when I do a 'ls -l' I see the date format different than on all my other boxes even though I have identical regional settings. Is there a way (env var) to control this behaviour ?
In Windows's CMD when you execute a command and then start writing the next one (while still executing the former one) the characters remain in the buffer and they all come up nicely to the new line once the previous command has been executed. In Ubuntu when I do this the newly typed characters annoyingly get in the beginning of the previous command's output lines. I don't really understand why isn't the default method as in Windows's CMD. I mean otherwise almost _everything_ sucks with it when compared to Unix/Linux shells/terminals (commands are longer, syntax is annoying, etc.) So I'd like to know how to do this in both Bash and Zsh.
So I've got a rather vast database, one of the columns is date in the following format: DD/MM/YY HH:MM:SS. This is starting to cause problems with a php page I'm writing which asks the user for a 'start date'. Would it be better for me to split the date column into date and say time? Or is there a way of using distinct and masking the times.
Consider a situation in which you want to display only specific lines of contents from a file or of a command's output. Yes, we have head and tail commands. But, how to view all the lines of a file except the last one or vise versa when we don't know the count of lines in advance?
Here, I don't want the last line (in italic) to be included in the result since the last line is due to "grep bash" in the devised command "ps au | grep bash". Well, we can rewrite the devised command:
Quote:
"ps au | grep bash | head -n 2"
But, again, here we are specifying the count of lines to be included. But, in the presented problem we don't know any count in advance!
I have some big files of logs that contain errors printed by an app. They are most of the time relevant, however most of them are similar. So i figured i could check what happened between a time interval with a find.
Im using this one
Code:
And I get an output similar to this one.
Code:
Is there a way to condensate the output lines to get only one or two, indicating the start and last occurrence of a block? Or I need to create a program to do so?
Because right now I get thousands of similar lines, but when I'm scrolling through them i sometimes miss relevant information that i would've otherwise noted if it wasn't all that spammy.
i need to count the number of files and put the output into a variable. i used wc -l filename but i couldnt find an option to put the output to variable. example if the number o line is 5, i need the output of echo $x is 5.
I need to create a single line of output from multiple and variable lines of input in a Linux bash shell script.
My input file looks like this:
Where there may be any number of umsecondaryphonenumber lines; if there is not a umsecondaryphonenumber line for a telephonenumber, I don't want to write any output.
So, the output file should look like:
The script I have so far is:
My question is - how do print each of the elements of an array in one record - i.e. what do I put in place of howdoiprintarray?
im using postfix with amavis and spamassassin as spam/virus filtering and its working great.However, i get a "lot"(1-5/day) of "bad header" messages beeing quarantined by the server. And most of theese bad headers are false positives that i manually have to deliver to the correct mailbox.How can i make amavis/spamassassin deliver bad header messages to the correct mailbox and not place them in quarantine?Theese are my amavis settings. (which file is used, 20-debian or 21-ubuntu??)
Fairly new to Ubuntu server. Was curious about keeping a running system up to date. Can any harm come from running the following:
sudo apt-get update sudo apt-get upgrade
What I mean is, is it possible that doing the above could cause a perfectly healthy system to go foobar? If so, what's the best way to prepare a system for a recovery. The Server in question is a Hardy BIND server. In the past, I've seen some ugly things happen to Windows systems after running updates, so I'd like to err on the side of caution.
Let's suppose there are "n" number of servers in a Linux cluster / network environment. We want to make sure that "date" on all those servers are in sync. How can we log the output of "date" to a particular file (log file, let's name it /tmp/date.log on our local system from where we are executing our command or script) run on every server one by one so that we can have a log of all the servers and their corresponding date vales in the following format:
I am currently running multiple VPS's of which one is a Hardy based LAMP install with PLESK. I have just one gripe about running Hardy on this VPS: PHP 5.2 is horribly outdated!! It has 5.2.4 in the repos, whilst 5.2.14 was released a while ago. As an LTS server distro you would expect these kinds of packages to be updated to ensure security? Please don't tell me I can use Dotdeb, it was never meant for Ubuntu and I have had problems with it in the past.
Trying to take a UK formatted date (30/12/2010) and insert it into Mysql (2010-12-30) is just not going to plan. I have a feeling I'm getting close, however it's just not working out.
I think I miss something here(Ubuntu 9.10 server 64bit):
/etc/srg/srg.conf
Code:
##### SRG Example Configuration File ##### # Squid log file to process # Defaults to access.log in the srg directory. # e.g. log_file "/usr/local/squid/logs/access.log"
I recently formatted my HDD and installed Ubuntu Server 10.04 x64. This is actually the 4th install in the past week because I was testing some things. But I had this problem on at least the previous install which made me want to start fresh again. The problem I'm having is Ubuntu will not boot if I add any of my drives to fstab. If I leave it with the standard proc, /, and swap lines it works fine. As soon as I add a line for one of my RAID arrays or an NTFS formatted partition the system hangs on bootup. It doesn't matter if I have the extra drives operating or not.
The last thing I see before it hangs is: Code: /dev/sda1: clean, 69351/4358144 files, 583945/17401600 blocks Here is what the fstab currently looks like:
The other two lines which also made it hang included one which was almost exactly the same as the /dev/md0 line except it was md1 with a different mount point and another which used a UUID and was ntfs-3g. I know they work because all 3 of them were mounted by "mount -a" after putting them into fstab and they're pretty much the same as what I was using with 9.04 server.
I'm looking for a method for modifying some jpg photo files last modification date with the corresponding timestamp creation date of each file.The reason is that shotwell import pictures in folders according to last modification date which is stupid on my opinion.