General :: Pass Multiline Output Of A Command Into 'date?
Mar 3, 2011I am doing some NSCA log parsing and I want to get an output like this:
2011-Feb-18:11:00:07
2011-Feb-18:11:00:07
2011-Feb-18:11:00:07
[code]...
I am doing some NSCA log parsing and I want to get an output like this:
2011-Feb-18:11:00:07
2011-Feb-18:11:00:07
2011-Feb-18:11:00:07
[code]...
I am doing some NSCA log parsing and I want to get an output like this:
2011-Feb-18:11:00:07
2011-Feb-18:11:00:07
2011-Feb-18:11:00:07
2011-Feb-18:11:00:08
2011-Feb-18:11:00:08
[Code]....
I have tried this, but it treats the entire output as a single line, then plops a timestamp on the end (I think):
Code:
sort -b -k4.9,4.12 -k4.5b,4.7Mb -k4.2,4.3 -k4.14,4 foo.log| date -j -f "%Y-%b-%d:%T" "+%s" "`awk -F '[ [/:]' '{print $7"-"$6"-"$5":"$8":"$9":"$10}'`"
I need to pipe the output of date command, to form a command like this:
mycommand -f 20110721
where 20110721 is current YearMonthDay.
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watch -t -n 10 "(date '+TIME:%H:%M:%S'
; ps aux | grep "pattern" | wc -l)" >>
logfile
and am expecting a result like
TIME: 10:32:30 12
TIME: 10:32:40 18
TIME: 10:32:50 2
to be stored in logfile. However, when the logfile has unprintable characters in in. How do I get this kind of output from the command li
I'm putting together a small bash script which uses diff in a sub shell.
RESULT=$(diff file1 file2)
This is the first time I've tried to return multiline output from a subshell - how can I get this to display as multiple lines instead of one?
How can format the date command to output the following format 08-Dec-2010.
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Under UNIX I have a folder where files will be placed frequently and I need to upload those files to Oracle, what I need is a UNIX script that can do the following
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[code]....
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