if you execute :
#!/bin/bash
echo "some textstring" >> logfile.txt
then the string "some textstring " will be APPENDED to logfile.txt Is there a redirect way that in stead of appended, the string will be INSERTED at the top of the logfile.txt file ? If this cannot be done by redirecting, what would be the best way to insert the test-string at the top of the logfile ?
I'm just starting out with shell-scripting, but having a problem with making new text files with the touch or cat > commands.
What I've been doing is touch testfile1.txt
Also, I've tried cat > testfile1.txt (text)
Console reports "bash: text1.txt: No such file or directory. Consfusingly, it works fine in the home-directory. But if I move the file to where I want it, I can no longer view, edit, etc. it.
Just using shell scripting, how can I insert text into the middle of a file name. The file has a predictable pattern, let's say 3 letters and 3 numbers and I want to insert text in the middle of those 2 patterns. Say ABC123 is the file name. As a result, the file name should be ABC.blah.123
View 2 Replies View Relatedmay be an advanced question but I need to know how to do this. Here at work I am in charge of recruiting and we have about 1,000 resumes in already. All of the resumes are in a .pdf format. I need to rename every .pdf in the following format:{firstnameLastname}.pdfThe only way I know how to do this is to convert all the .pdf files to text, extract the name out of the first few lines of text, import into excel, and then use VBA to rename the files in mass:Here is my logic so far:~Deskop/a = houses all the .pdfresumesOpen terminal: Code: cd ~/Desktop/afor f in *.pdf; do pdftotext -raw $f; done That will convert all of the preceding resumes into text filesNow I would like to append the name of the text file into the last line of the text file. So, for example, for Resume1.txt, I want to append "Resume1.txt" to the last line within Resume1.txt. So after I run the command I open Resume1.txt and on the last line within I want to see "Resume1.txt" on the last line, at the end of the resume.How can I do this? I would like to use a loop and have the terminal append the filename to the body of the text file until all of the have been appended.
View 1 Replies View RelatedI'm writing a script to execute bash commands in the PHP CLI. I would like to suppress errors from bash and write my own error message if an error occurs. So far I have this (assuming log.txt doesn't exist!):
Code:
tac log.txt 2>/dev/null
Which works as expected, tac kicks up an error but the error is suppressed, but when I use this:
Code:
tac < log.txt 2>/dev/null
I get:
Code:
bash: log.txt: No such file or directory
The tac error is suppressed but bash still gives me a dirty error.
Is there a way to export a variable to parent shell in shell scripting ?
View 3 Replies View RelatedI am trying to create a shell script similar to ls, but which only lists directories. I have the first half working (no argument version), but trying to make it accept an argument, I am failing. My logic is sound I think, but I'm missing something on the syntax.
Code:
if [ $# -eq 0 ] ; then
d=`pwd`
for i in * ; do
if test -d $d/$i ; then
echo "$i:"
code....
I'm doing an assignment for school, and while we have not yet learned regular expressions, my teacher would like us to use AWK to append text to certain lines in a file. What we've had to do is creating a listing of all links and directories in the /etc folder and place them in a text file. From this, we were to cut the first field (Permissions) and the ninth field (filename) and create another text file. Now the part that I'm struggling with is this and I'm not sure if I should be using sed or awk. We're supposed to ADD the text "DIR" to the beginning of any line that is a directory, and "LNK" to any that is a link, like so:
DIRdrwxr-xr-x redhat-lsb
DIRdrwxr-xr-x rhgb
LNKlrwxrwxrwx rnDIRc.key
DIRdrwxr-xr-x rpm
Obviously, I realize that the first character in the permissions denotes what sort of file it is, hence when I created my text file I used
ls -l | grep "^d" > file.txt
and
ls -l | grep "^l" >> file.txt
I'd like to learn how to properly do this, but struggling through pages on the internet hasn't been helping, nor has the --help command. Therefore, while I would like the answer, I'd also like to know what the heck I'm doing For example, I know I could delete lines with regex using d/[STUFF I WANT TO DELETE]/g (To get rid of all occurences) and I can substitute using s/foo/bar But I'm unaware of anyway to ADD text upon certain occurences, let alone two different circumstances.
I want to append some text to the file, files are mostly big, more then 100 mb. I found the cat command, so I can create a new txt file and then append it to the original file with it. Two questions:
1. Can I append text to the file instead of creating the new file and then appending it to the original file? eg:
Code:
cat file.avi "some text" > newfile.avi
2. cat takes several seconds to execute the merging files together, it seems that it is reading the original file first, is there a way skip the reading and just append the file?
Say I have a text file like:
Code:
1
3
4
How would I use ksh to put the number '2' into the second line of that file?Okay it's not bash, it's ksh because this computer is OpenBSD
I am trying to append text to the beginning of a file. This is what I have so far.
Code:
date_default_timezone_set('America/Chicago');
$date=date("m-d-Y g:i:s a");
[code]....
How do you append text to an entry in an existing file? For example, lets say I have a file called "env.logon" in /home/myself/bin that contains the following text:
PATH=/bin:/sbin If I wanted to add, via command line, ":/usr/bin:/usr/sbin" to the PATH= and I
used the "echo" command (echo "PATH=:/usr/bin:/usr/sbin) it would create a second entry and my file would look like:
PATH=/bin:/sbin
PATH=:/usr/bin:/usr/sbin
What I want is for it to look like:
PATH=/bin:/sbin:/usr/bin:/usr/sbin
Is there a way to get this result via command line?
I am thinking of appending something to each line in a text file with Java. I prefer not write a new file with content appended from the old one.That 'something' would probably be Time Stamp when the file is created (which is same for each line).I am not sure Java provide some easy way for it or not
View 3 Replies View RelatedSo I have file which looks something like this:
cat .opera/operaprefs.ini
Code:
[User Prefs]
Language Files Directory=
[code]...
Using sed, I am trying to append four commas ',,,,' at the end of lines containing the pattern 'Response' in a text file with lines such as these:
6,Pulse,50,254968,14886,NA,,,,
7,Picture,8,265157,0,1,15045,2,0,15000
7,Response,1,271553,6396,1
7,Pulse,50,274969,9812,NA,,,,
8,Picture,1,290232,0,1,15045,2,0,15000
8,Pulse,50,294969,4737,NA,,,,
[Code].....
I have recently put together an install script to make my life a little easier.
The server is using lighttpd and I wish for the auth mod to be enabled.
For the line:
I require the script to call the servers external IP and insert it in place of 127.0.0.1
What is shell scripting? what is 'bash'?
View 14 Replies View RelatedCode:
sed -n '123p' file
that will print line 123 but how might I insert text to a specified line?
#!/bin/bash
str3=""
if [ -z $str3 ] ; then
echo " $? = $? "
fi
[code]....
output:-
$? = 0
$? = 0
why we get 0 for both conditions? I am using FC15.
Just give me any project on shell scripting .. to start working on it and practice my self ..
View 2 Replies View RelatedI am a bit confused with the first line while writing a shell script , if someone can please explain me the meaning of the first line " #!/bin/bash "the confusion for me is the # at the beginning , in shell scripting # means a comment. but in this case it loads the shell which the script must use,instead of commenting the line how is this possible. where is this defined , any particular file.
View 3 Replies View RelatedI'm using fedora 14...i would like to insert few texts to a file in shell prompt(may be useful in scripting for in the future)...for eg,
[root@ruby ~]# cat > hello
1
2
2
[code]....
so in the above file i need to add the line "new line added" near the number 4 in the above file ....how can be this done ...?
i need to add this line nameserver 208.67.122.221 from ISP before the first nameserver already exists in resolv.conf in all workstations i know
Code:
sed '/nameserver/ i
ameserver 208.67.122.221'
but that insert it on every line after nameserver not only before the first one
Code:
# blah blah
# blah blah
domain mydom.com
[code]....
i trying to add text messge in textarea and i got error in connection and i don't know if it correct syntax. and i wonder when i was install xamp server it no password required. but i dont know what password that i input in my php connection.?
PHP Code:
<?php
$con = mysql_connection("localhost","root","123");
if(!$con)
{
[code]....
PHP Code:
<textarea rows="3" cols="30" name="txtcomment" wrap="physical">Leave a Comment
How do i find out if a particular item is a file or a folder through the terminal ls -la gives 'd' before the permissions for every folder and '-' before every fileLike i want to write a script that backup data if it is a folder and deletes if it is a file
View 2 Replies View RelatedI am trying to learn more about global expressions and how it is needed in changing stuff in vi and in shell scipting in general.My question is basic:
How can I add a " # " pound sign at the beginning of every line in a file. So if I want to remark out every line in a file, what would be the global expression for that? Is there a global expression cheat sheet?
I am working on some homework, however i am not here to be spoon fed. I am trying to get the numerical modification date of each file in a folder. Ie lets say there is a file called bob and it was modified 2006-11-23. i want to get it into a variable as 20061123.
Now i currently have this code:
Code:
However for some reason my output is:
Quote:
See how the 2011 has been placed next to it? i ran it with -x and saw this:
Code:
However i do not know how to find a way around this?
I am working on a simple script that should take two command line arguments, a [number] and a [name]. The first thing the script should do is check to make sure that no more and no less than two command line arguments have been entered when calling the script - an error message should be delivered if the condition is not true.
If two args have been entered, then the message 'processing "scriptname"' should appear, where scriptname is the name of the script being called. The script should then write to the screen "Hi [name]!", and should write this phrase [number] of times. For example, the command $ myscript 2 joe would produce the output: I have read the manual many times looking for examples, and I am very close by virtue of my own efforts. Further, I have searched these forums and others for good examples, which have also gotten me very close. Still my script is not completing the objective, and I am wondering if someone could point me in the right direction. Script:
[Code]...
I am trying to learn shell scripting and came up with a lil first script that I could actually use.I have a basic shell script and all it does is run:
sudo apt-get update
sudo apt-get upgrade
So basically just a shell script that updates your packages. NOW, my question. I made another shell script that makse a bit of a menu and asks what you wanna do, 1 to UPDATE or 2, to CLOSE. How do I make it so when they enter 1 it runs my update.sh ?
I am new to shell scripting..I really need ur help or guidance here..I have a text file where i have to use dos2unix command.
Now the problem is how do i pass dos2unix command in the shell scripting after it had read the text file ??
And give out the new text file.
