I am thinking of appending something to each line in a text file with Java. I prefer not write a new file with content appended from the old one.That 'something' would probably be Time Stamp when the file is created (which is same for each line).I am not sure Java provide some easy way for it or not
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Say I have a text file like:
Code:
1
3
4
How would I use ksh to put the number '2' into the second line of that file?Okay it's not bash, it's ksh because this computer is OpenBSD
I am trying to append text to the beginning of a file. This is what I have so far.
Code:
date_default_timezone_set('America/Chicago');
$date=date("m-d-Y g:i:s a");
[code]....
So I have file which looks something like this:
cat .opera/operaprefs.ini
Code:
[User Prefs]
Language Files Directory=
[code]...
I have to delete a certain line of text from the a textfile via ubuntu's shell scripting.I have done research, and it seems that most people advocate the usage of sed /d option. sed makes does not edit the text file. Hence, most options I discovered involved the use of a temporary variable/textfile and then overwriting the old file with the temporary new file. Is there anyway whereby I can bypass the use of temporary storage containers? I hope there is any magical combination of commands to edit the file directly.
View 3 Replies View RelatedI have two txt files containing x and y coordinates: xcoord.txt & ycoord.txt. I need to open them; read them line by line to get each coordinate; then each time I need to update Xs and Ys parameters inside another file called "dc.in" with the grabbed values.
Finally each time I need to run two exe files ( dc_2002 and st_vac) and produce corresponding output for each Xs and Ys ( dc.in is an input file for this exe files)
I have written the following code but it does not work:
Was wondering if any perl guru's could help me with a quick log file adjustment. I have a text file that looks like so (tabs and newlines are revealed so you can see what separates the data):
There are maybe 100 lines of text in this file at any given time. I need to delete all duplicate lines only looking at the first bit of text prior to the first tab. It doesn't matter which one gets deleted as long as there are no two lines that begin with that same text at the beginning before the first tab. So in this example, either the fist line "1234" or the last line "1234" would need to be deleted. I already have code in my script that opens the files - I just need the code to read the text into an array and the part that would find matches based on the above criteria, and make the deletions.
If it would be easier, I can even do a system call and use SED (v4.1.5) and/or AWK (3.1.5) instead.
bash 3.1.17(2) I'm trying do write a shell script which must operate on each line of an ASCII text file. So, all the code must be inside a loop, and inside the loop, the first thing should be to read the next line from the file. I have the bash read command. But it reads from stdin. Any way to make read from a file?
View 6 Replies View Relateda sed command to add a text before line number in text file? I have text file with 500 lines, and i want to add 3 more lines with text after line 300, OR before line 302, isn't no problem.
View 16 Replies View RelatedThe s means substitute
The $ in this particular regex (regular expression) means end of the line.
The ; is what you're subbing. This works fine and well, but what if you want to append a / at the end of the line?
sed 's/$///' filename doesn't work.
What I am trying to achive is the editing of /etc/ssh/sshd_config I have the line
Code: AllowUsers usera userb
And I want to be able to append to the end of this line from a bash script.I have muddled together from other sites and got the following:-
Code: sed -e "s/^AllowUsers/� userc/" -i /etc/ssh/sshd_config
But this appears to add userc directly after AllowUsers and not after userb
I want to append some text to the file, files are mostly big, more then 100 mb. I found the cat command, so I can create a new txt file and then append it to the original file with it. Two questions:
1. Can I append text to the file instead of creating the new file and then appending it to the original file? eg:
Code:
cat file.avi "some text" > newfile.avi
2. cat takes several seconds to execute the merging files together, it seems that it is reading the original file first, is there a way skip the reading and just append the file?
I have a requirement like this..this just a sample script...
Code:
when i run this scipt...
Code:
Code:
It is appended in the same line...
I want it to be added to the next line.....
I want to do this by explitly using the filehandles in perl....and not with redirection operators in shell.
I have a text file called namelist.wps. In this file there is a line that reads:
Code:
start_date = '2010-12-26_12:00:00', '2010-12-26_12:00:00',
I have to automatically update the year, month, and day of month for this line without changing the rest of the file. Here is the script that I have:
[Code]....
I want to append a variable string to the end of a specific line. not like append the same string to each line. like in my file i have 4 columns, i want to add a string in 5th column in some fixed row.
View 4 Replies View RelatedHow do you append text to an entry in an existing file? For example, lets say I have a file called "env.logon" in /home/myself/bin that contains the following text:
PATH=/bin:/sbin If I wanted to add, via command line, ":/usr/bin:/usr/sbin" to the PATH= and I
used the "echo" command (echo "PATH=:/usr/bin:/usr/sbin) it would create a second entry and my file would look like:
PATH=/bin:/sbin
PATH=:/usr/bin:/usr/sbin
What I want is for it to look like:
PATH=/bin:/sbin:/usr/bin:/usr/sbin
Is there a way to get this result via command line?
I have a text file called namelist.wps. In this file there is a line that reads:Code: start_date = '2010-12-26_12:00:00', '2010-12-26_12:00:00', I have to automatically update the year, month, and day of month. I set values for the year, month, and day of month using the following code in a c-shell script:Code: set y1 = `date +%Y`set m1 = `date +%m`set d1 = `date +%d` After I do this, how do I update year, month, and day of month, without changing any of the other lines in the namelist.wps file?
View 2 Replies View RelatedI want to know how can I add something to a specific line.. the output would be something like:
abc
def 123
ghi
Search for string "def" and add something to that line.
I'm wondering how it is possible to read each line from a text file, and then store each line separately in a list, using C++?
View 2 Replies View RelatedAt the moment I got my md5sum checking working which I write to a text file and see below.
If the md5sum works it will write the output to check2.md5 test.txt: OK
If the md5sum fails it will write test.txt: FAILED
How do I write if statement to check the output whether or not the md5sum failed or not ?
check1="/home/ops/Desktop/test1/check1.md5"
check2="/home/ops/Desktop/test1/check2.md5"
cd /home/ops/Desktop/test1
md5sum test.txt > $check1
[Code]....
Using sed, I am trying to append four commas ',,,,' at the end of lines containing the pattern 'Response' in a text file with lines such as these:
6,Pulse,50,254968,14886,NA,,,,
7,Picture,8,265157,0,1,15045,2,0,15000
7,Response,1,271553,6396,1
7,Pulse,50,274969,9812,NA,,,,
8,Picture,1,290232,0,1,15045,2,0,15000
8,Pulse,50,294969,4737,NA,,,,
[Code].....
Here is the issue. I am reading in a outside text file and putting in the string on that line into a char array that is already allocated.
Code:
int main(int argc, char *argv[])
{
[code]....
im trying to output a list of running processes via a shell script. At the moment i got this which outputs the processes to a text file called out.
echo $(ps aux) >>out
The problem is though, the processes are all just one big block of text which makes it hard to read. Does anyone know how to sort the output to a text file so that it prints to the text file at 1 process per line? I know its probably simple but im very new to linux.
I have two files list1.cfg and list2.cfg both files contains differentrecords details like
List1.cfg
NAME1:25:C:NAME LINE1:
NAME2:25:C:NAME LINE2:
CITY:25:C:City:
[code]....
Now I want to append contents list2.cfg to list1.cfg(It ispposible using cat list2.cfg >>list1.cfg) but I want to check if content of (record) in list2.cfg is present in list1.cfg then dont append it otherwise append it.
where I'm trying to demonstrate the file locking concept through Perl/CGI.Here is the script which I tried.
Code:
#!/usr/bin/perl -w
use strict;
use warnings;
print "Content-type: text/html
[Code].....
I currently have 3 files with floating point data that I wish to have in a single file with the format:
Code:
F1 F1 F3 Output
a1 b1 c1 a1 b1 c1
a2 b2 c2 a2 b2 c2
a3 b3 c3 a3 b3 c3
a4 b4 c4 a4 b4 c4
may be an advanced question but I need to know how to do this. Here at work I am in charge of recruiting and we have about 1,000 resumes in already. All of the resumes are in a .pdf format. I need to rename every .pdf in the following format:{firstnameLastname}.pdfThe only way I know how to do this is to convert all the .pdf files to text, extract the name out of the first few lines of text, import into excel, and then use VBA to rename the files in mass:Here is my logic so far:~Deskop/a = houses all the .pdfresumesOpen terminal: Code: cd ~/Desktop/afor f in *.pdf; do pdftotext -raw $f; done That will convert all of the preceding resumes into text filesNow I would like to append the name of the text file into the last line of the text file. So, for example, for Resume1.txt, I want to append "Resume1.txt" to the last line within Resume1.txt. So after I run the command I open Resume1.txt and on the last line within I want to see "Resume1.txt" on the last line, at the end of the resume.How can I do this? I would like to use a loop and have the terminal append the filename to the body of the text file until all of the have been appended.
View 1 Replies View RelatedI'm a bit new to Python programming and hoped that someone might be able to help with a problem I'm having. What I essentially want to do is to combine two text files line for line. I know how to do this in a bash script so to give you a better idea here's the code for that:
Code:
This is basically for adding on values to the end of a CSV file that uses ';' as the delimiter. So say file1 said:
And file2 said:
Then running this command would create merged_file1_and_file2 which would be:
The code I'm using at the moment is:
Code:
As I'm sure any experienced python programmer will see, this prints out the first line of the file "csvraw" and then all of the lines of "stamps" and then the remainder of "csvraw".
What I'd like to do is something like: (pseudo code, I know it's not python ;-))
Code:
Is this possible? I've tried googling and my Python Pocket Reference hasn't been much help. I've looked at pickling but that doesn't seem appropriate.
I want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
View 1 Replies View RelatedI'm trying to add text to a file for a specific group of users, I'll need to do examples as I can't think of an easy way of explaining, my file is like this:
Code:
users{
user1
user2
[code]....
At the present my code lists all the available groups, how would I add a user to a specified group? (e.g add "members user3") to the end of group 1 for example. So the code ends up like this
Code:
members user2,user3
