I am new to shell scripting..I really need ur help or guidance here..I have a text file where i have to use dos2unix command.
Now the problem is how do i pass dos2unix command in the shell scripting after it had read the text file ??
And give out the new text file.
I am very new to shell scripting.How does one pass a command-line parameter to a shell script?for the below program
#/bin/bash
mount -t cifs -o user=ramkannan,password=Linux123@ //10.200.1.125/ramkannan /MT
cd /MT/test
date=`/bin/date "+\%Y-\%m-\%d-\%H-\%M-\%S"`
mysqldump -uroot -pram2@ employeedb > $date.sql
gzip $date.sql
I want to pass parameter for everything,i tried in google and did but iam getting error while passing parameter to all
#/bin/bash
mount -t cifs -o user=$1,password=$2 //10.200.1.125/ramkannan /MT
cd /MT/test
date=`/bin/date "+\%Y-\%m-\%d-\%H-\%M-\%S"`
mysqldump -uroot -pram2@ employeedb > $date.sql
gzip $date.sql
i was getting error while passing parameter to all.
How do i find out if a particular item is a file or a folder through the terminal ls -la gives 'd' before the permissions for every folder and '-' before every fileLike i want to write a script that backup data if it is a folder and deletes if it is a file
View 2 Replies View Relatedmyscript [-a a-arg] [-c c-arg] [-b] [-e] somedirectory
Given that I want my shell script be invoked at the command line using the above parameters - where [these brackets] denote that they are optional - what is the best method to parse them?
I have written the following script in my linux server to add users for LDAP database.But i can't able to run this.
The script is as following
#!/bin/bash
echo "Mention the username which you want to convert LDIF format"
read username
if ["$username" -e "/ldiffile/passwd"]; then
echo "Username already exists"
else
cat /etc/passwd | grep -i "$username" >> /ldiffile/passwd
fi
The output which i got :
. ldapadd.sh
Mention the username which you want to convert LDIF format
yal2361
-bash: [yal2361: command not found
please let me know where need to change and what
I have a new machine with LINUX Red Hat 5 installed. As I try to use command dos2unix I got:
Code:
-bash: dos2unix: command not found
How can I install this command?
I've been doing Finite Element simulations with the Ansys software for several years now, and recently I have been allowed to use a cluster running on Linux (it's a Sun Grid Engine, or SGE). Since I am quite newbie to this thing, I have read a lot on the internet to get more familiar with the Unix language. I found some example codes which are supposed to launch Ansys and read input files, but it does not work for me. Actually, what I want to do is simple:
1- I need to use Ansys 12.1 in batch mode, with the Academic Research license (which is called "aa_r");
2- The software should then read my input file (which is an APDL command file (in case you are familiar with it..)) and save the database and results in my working directory on the server.
The software is located in the following path:
/ansys_inc/v121/ansys/bin/ansys121
My working directory:
/home/myusername/
From what I've found on the web, I have to write a shell script that calls the software and specifies the details (batch mode, license name, input file, ...). Then I have to call this script by using the command "qsub".
Script: myjob.sh
Code:
#!/bin/bash
nohup /ansys_inc/v121/ansys/bin/ansys121 -b nolist -p aa_r -j jobname -i jobname.inp -o jobname.out 2>&1 &
vi /etc/samba/smb.conf
[samba test]
comment = client
path = /opt/apps/deploy/websites
public = no
writable = yes
[Code]...
Using the bash shell script the above given samba configuration,the script should automatically add these above given entries in the /etc/samba/smb.conf.can any one help me how to edit the file add entries in the config file using shell script.
delete a file on a remote server using shell scripting.
View 14 Replies View RelatedWhat options should I use when I'm using the sort command to sort the top 5 CPU processes (ps -eo user,pid,ppid,%cpu,%mem,fname | sort ??? | head -5) showing max to min usage?
View 2 Replies View RelatedIs there a way to export a variable to parent shell in shell scripting ?
View 3 Replies View RelatedI am trying to create a shell script similar to ls, but which only lists directories. I have the first half working (no argument version), but trying to make it accept an argument, I am failing. My logic is sound I think, but I'm missing something on the syntax.
Code:
if [ $# -eq 0 ] ; then
d=`pwd`
for i in * ; do
if test -d $d/$i ; then
echo "$i:"
code....
I have recently put together an install script to make my life a little easier.
The server is using lighttpd and I wish for the auth mod to be enabled.
For the line:
I require the script to call the servers external IP and insert it in place of 127.0.0.1
What is shell scripting? what is 'bash'?
View 14 Replies View Related#!/bin/bash
str3=""
if [ -z $str3 ] ; then
echo " $? = $? "
fi
[code]....
output:-
$? = 0
$? = 0
why we get 0 for both conditions? I am using FC15.
Just give me any project on shell scripting .. to start working on it and practice my self ..
View 2 Replies View RelatedI am a bit confused with the first line while writing a shell script , if someone can please explain me the meaning of the first line " #!/bin/bash "the confusion for me is the # at the beginning , in shell scripting # means a comment. but in this case it loads the shell which the script must use,instead of commenting the line how is this possible. where is this defined , any particular file.
View 3 Replies View RelatedI am trying to learn more about global expressions and how it is needed in changing stuff in vi and in shell scipting in general.My question is basic:
How can I add a " # " pound sign at the beginning of every line in a file. So if I want to remark out every line in a file, what would be the global expression for that? Is there a global expression cheat sheet?
I am working on some homework, however i am not here to be spoon fed. I am trying to get the numerical modification date of each file in a folder. Ie lets say there is a file called bob and it was modified 2006-11-23. i want to get it into a variable as 20061123.
Now i currently have this code:
Code:
However for some reason my output is:
Quote:
See how the 2011 has been placed next to it? i ran it with -x and saw this:
Code:
However i do not know how to find a way around this?
I am working on a simple script that should take two command line arguments, a [number] and a [name]. The first thing the script should do is check to make sure that no more and no less than two command line arguments have been entered when calling the script - an error message should be delivered if the condition is not true.
If two args have been entered, then the message 'processing "scriptname"' should appear, where scriptname is the name of the script being called. The script should then write to the screen "Hi [name]!", and should write this phrase [number] of times. For example, the command $ myscript 2 joe would produce the output: I have read the manual many times looking for examples, and I am very close by virtue of my own efforts. Further, I have searched these forums and others for good examples, which have also gotten me very close. Still my script is not completing the objective, and I am wondering if someone could point me in the right direction. Script:
[Code]...
I am trying to learn shell scripting and came up with a lil first script that I could actually use.I have a basic shell script and all it does is run:
sudo apt-get update
sudo apt-get upgrade
So basically just a shell script that updates your packages. NOW, my question. I made another shell script that makse a bit of a menu and asks what you wanna do, 1 to UPDATE or 2, to CLOSE. How do I make it so when they enter 1 it runs my update.sh ?
I am trying to read the fields of a file and manipulate them, record by record. Lets say using awk :
awk -F":" `{print $1 $2 $3 $4 $5}' TrackMsgFile.0806`
This prints my fields on screen.But I dont want to print these fields while reading the records instead store them in some variable and manipulate them as per my logic. Does "awk" or some other shell command provides something for this ?
I made a little rsync script for log transfer.
Code:
SERVERS=(SERVER1 SERVER2 SERVER3)
SERVER1_SERV=(web ftp mail)
SERVER2_SERV=(web transcoding)
SERVER3_SERV=(web ftp mail)
for SERVER in ${SERVERS[@]}
do
echo "Starting tranfer for server $SERVER"
for SERVICE in ${$SERVER_$SERVICE[@]}
do
something_to_be_done
fi
done
But when I run it I get ${$SERVER_$SERVICE[@]}: bad substitution
How do I create a user account in a shell script? I know this may sound n00bish to you, but I know it's more than just mkdir-ing the home directory and subdirectories.
View 7 Replies View RelatedI need to part a string into separate integers ....like "0x0-0xffffffff,0x20000" into 3 integers 0x0 and 0xfffffff and 0x20000.... i can't use any other high-level languages ..
View 3 Replies View Relatedch[1]=0; ch[2]=0; ch[3]=0; ch[4]=0; ch[5]=0; ch[6]=0; ch[7]=0; ch[8]=0; ch[9]=0; ch[10]=0;ch[11]=0; ch[12]=0; ch[13]=0; ch[14]=0; ch[15]=0 ch[16]=0; ch[17]=0; ch[18]=0; ch[19]=10; ch[20]=0;
I have an array ch and I want to increment each element in my array for the following if statement. I'm not sure I have the right array increment syntax but I have tried it in different ways ant it doesn't seem to work.
I tried ch[$1]++, ch[$1]+1, ch[$1++], ch[$1]+=1, ch[$1]=ch[$1]+1 none of these seem to work.
# while loop reading from read.txt for check list 1 - 15
for i in `seq 15`
do
a=`grep "${cl[$i]}" $file`
status=$?
if [[ $status = 0 ]];
then
echo -n -e "1 "
let ch[$i+1]
let k++
else
echo -n -e "0 "
fi
done
for l in `seq 20`
do
echo -n -e "${ch[$l]} "
done
I do not know how to write either PYTHON or Bash Shell Scripting. I am to learn one for Linux Administration purpose. Which one will you recommend for a Linux Admin/Eng environment?
View 4 Replies View RelatedThere are five folders in a folder and I want to select one randomly. I used this command:
Code:
rand1="${loc[RANDOM % ${#loc[@]}]}"
but it selects files too. I have no idea about this code even. I found it on a forum.
I'm just starting out with shell-scripting, but having a problem with making new text files with the touch or cat > commands.
What I've been doing is touch testfile1.txt
Also, I've tried cat > testfile1.txt (text)
Console reports "bash: text1.txt: No such file or directory. Consfusingly, it works fine in the home-directory. But if I move the file to where I want it, I can no longer view, edit, etc. it.
I got two cgi shell scripting files. Is it possible when i am in file 1, to call a function from file 2?
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