Software :: Grep Not Working Right With Colortail?
Jun 10, 2011Put simply, this command won't work:
Code:
colortail /var/log/auth.log |grep -a "sshd"
However, these commands work perfectly:
[code]...
Put simply, this command won't work:
Code:
colortail /var/log/auth.log |grep -a "sshd"
However, these commands work perfectly:
[code]...
I am trying to grep for A records in a bind zone file but I am failing.I am trying: grep "s+As+" db.domain.comBut there are no results.
View 12 Replies View Relatedworks fine on a FAT32 dsk:
Code:
fgrep -iRn -C 2 'print' *.txt
---also recurses one level and displays all kinds of data
---------------------------------------------------------------
in root / ext4 directory:
Code:
fgrep -iRn -C 2 'print' *.* or fgrep -iRn -C 2 'print' *.txt
---displays msgs:
fgrep: *.*: No such file or directory
and
fgrep: *.txt: No such file or directory
I am probably missing something very basic.recursive does not seem to work from root directory.Is this (as they used to say) a feature? This is on an 11.2 system, upgraded to 11.3 (ran zypper verify to verify. According to it.. all is well).
I'm trying a recursive search -- only PHP files -- and yet grep is searching SQL files too.
Code:
sneakyimp@Ubuntu-64bit:/var/www/site$ grep -irl --include='*.php' 'car_images' *
2011_02_11_dump.sql
car_images_pending.sql
client/search_results.php
[Code]....
I need to kind of grep within grep. My input file would be something like:
[Code]....
and I need to find the first occurrence of hello before MY PATTERN (hello 9008 in this case), so the output should be:
[Code]....
I need to find file from ls - l by using grep and certain regexp.
In particular I need greep to see certain file ending, like let's say .txt but only using regex.
So it should be something like
ls -l | grep '^.+.txt$'
But that doesn't seem to work for me.
I'd to extract data from a log file and move those strings into a CSV.
Log File:
Code:
...
File = foo.bat
Date = 11/11/11
User = Foo Man
[Code]....
I need to grep a dictionary file.Only the words that contain 2 or more z's and only 1 b needs to be listed.
View 1 Replies View RelatedToday, i checking my error log of Apache. I have look many IP brute scan URLo, i collect, export that to ip.txt and i need grep IP with connection >=8I don't know command to solve that. Example ip.txtQuote:
101 210.13.73.30
161 58.210.77.98
164 115.168.71.87
[code]....
I have a file which contains a line like this:SERVER=10.205.110.19 How can I cut out the IP and assign it to a variable?
View 4 Replies View RelatedHow can I use grep expressions so that i can find strings like the ones bellow:
New York, NY
Virginia, VA
Oregon, OR
As you can see each city starts with capital letter then it follows up with a comma, and then with the Abbreviation of the city. I used :
Code: grep -w '[A-Z].*[a-z][,][' '][A-Z][A-Z]' filename But i get no results.
I have on my desktop around five java files. I also created a java file in directory Viti, located in desktop.
Since all java files contain string "class", I practice my usage of grep with the following:
And this works fine. However, when I type the following:
I expect to be shown the file that's located in my Viti directory, too, but it won't show it.
I searched and I found a few threads on this but none answered my question really.I'm using:
Code:
curl www.foo.com | grep '<h2>.*.</h2>'
Basically I want to extract all instances of
Code:
<h2>Blah blah blah</h2>
from the page source, but it's not giving me that, it gives me <h2>.. followed by a loads of other stuff that I don't want. I haven't used wildcards with grep before so I don't really know whether I'm doing it right or not.
I am trying to monitor how long an ldap search takes and maybe notify or something that a search takes longer than say 10 seconds.
Code:
tail -n 1000 /var/log/ldap.log
for SRCH in $( cat monitorldap.log |grep 'SRCH'); do
echo search string is
echo $SRCH
[Code]....
ok, so to start off with it doesn't appear to get the whole line, just a piece "Aug". How can I get the whole line into a variable so I can then cut it up into the pieces I need?
I'm using Zabbix on which I can use give bash command to the agent.This 1-liner will give me all the interfaces with their IPv4 addresses.I have a 2nd expression which returns a checksum so I can detect a difference whenever someone deletes/adds/changes an ipv4 interface.This is the output on my Ubuntu-server:
Code:
~# ifconfig | grep -B1 ' inet ' | grep -oE '(^[a-z0-9:]*|addr:[0-9]+.[0-9]+.[0-9]+.[0-9]+)'
eth0
[code]....
How can i use grep (or any other command) to check for lines that begin with N number.
E.g. I want to print out commands (from history), but only from the command number 50 until #200.
This one doesn't work:
Code:
history | grep "^[50-200]"
Should print out something like:
Code:
50 cd ~/Desktop
[Code].....
ii gtk2-engines1:2.20.1-1theme engines for GTK+ 2.x
ii hicolor-icon-theme0.11-1 default fallback theme for FreeDesktop.org icon themes
ii libobrender21 3.4.11.1-1 rendering library for openbox themes
[code]....
Let me *try* and explain what I'm trying to do, and keep in mind aside from a little command line stuff I'm a beginner to any of what I'm asking about.
I have a directory structure something like this:
Code:
/usr/local/chatlogs/
webserver1/
1.chatlog
2.chatlog
[Code]....
So that whatever was captured in the () in the first part of the statement would be used in the 1 in the back part of the statement for every n.chatlog that might be in any of the /webserver directories at that time.
I want to grep a a file for each '#' character that starts a line, the thing is the file is utf-8 and it starts with some some characters 'ef bb bf' is there a way to have grep to work with utf-8 files ?
[Code]....
Here's a silly question: suppose I want to "grep" an entire directory. Real life example: we reconfigured our mail server to a different IP address, so I needed to search for each occurrence of the original to make sure they'd all been changed.
A simple
Code:
grep -i -l -r "192.168.1.200" *
... works great until it hits a socket. This particular mail server has sockets scattered at random through the directory. When grep hits one of these, it hangs.
I've tried every command line option I can think of it to force it to ignore these sockets, but to no avail. Any of you Grep Gurus out there want to give me a hand?
any way we can change the delimiter that uses grep?
I think, by default, grep uses as the delimiter.
I forgot a lot of my command line. I am doing cat file | grep "error" and i would like it to show everything to the right of G:/ including G:/ if possible. I figure its an awk command but i dont know what. I tried awk '{print $8+}' but + does not work like i hoped and guessed.
View 2 Replies View RelatedWhen using the grep plugin to VIM, I can search the current directory for all occurrences of a string within a set of files, like this::grep Ryan *.txtThis outputs something like this:
file1.txt:3:Ryan was here
file2.txt:10:Ryan likes VIM
file3.txt:5:superuser.com is a fav of Ryan
[code]....
I'm wondering if it's POSIX + ASCII or something else is mixed in?
View 1 Replies View Relatedi want to search some key words in some pdf files grep myword ~/test.pdf that command can't work! grep command can't search pdf file??
View 1 Replies View Relatedso i have a data file of a couple thousand lines. for example, my file will look like this (condensed of course):
Code:
something something 100 something 1 2 3
something something 101 something 4 5 6
[code]....
How would I use cut or grep to take this line :
Code:
Load......................... 198 Watt(22 %)
and make it into this information, in a text file :
Code:
198 Watts
If you don't mind, please explain the process, as I have been trying to figure this command out, and I must be missing something.
1) I need to search a field value to check for exact 0. If the number is 0, it should throw error.
The line to be searched looks like as below. "Output Rows [1], Affected Rows [1], Applied Rows [1], Rejected Rows [0]"
Here I have to search whether the affected rows is 0. But the code below picks up other values also (lie 10, 20.. etc). How do we write to get an exact match for 0? Code: affected=`echo ${line} | cut -f6 -d" " `
affectedcount='echo ${affected} |grep 0 ` 2) Also, I need to check whether the rejected rows > 0
Code: rejected=`echo ${line} | cut -f12 -d" " `
rejectedcount='echo {rejected} |grep [1-9]`
3)Can we combine these two statements in a better way to get the desired results?
I have a file:
979798707
787862348
766428634
I want to see if all the records in the file are present in the contents of the files of a particular directory.
Basically I want to say if grep doesn't return anything, then report.
For example in /tmp dir I have 4 files and flast 2 values (787862348 and 766428634) are present in the files of /tmp dir, but first one (979798707) is not. I want to echo that in a reporting file.
something like:
while read line
do
# if ! grep -rl $line /tmp
echo $line >> are_not_present
done < "myFile"
How do I achieve " if ! grep -rl $line /tmp"? That is, if the line is found by grep, then grep will print the output, but if grep does'nt find it, it will print nothing. How can I check if grep didn't find it (i.e. printed nothing)?
Can you find an alternative for Code: wc -l using grep?
View 1 Replies View Related