I am going to separate records with the string, "[J.System Info]" in awk command.
Both of the following expressions don't work well.
Code:
RS = "[J.System Info]"
(or)
RS = "[J.System Info]"
suppose i store the history number of a command say :
1004 cat file
Then now i want to run it like : !1004 but by using a variable.
command=1004
!$command
i am getting errors like :
command=1004command
Any relatively easy user guide for the built in command line ftp program?
View 10 Replies View Related(1) I'm wondering if there is a way to have abcde play the songs while it is encoding? I understand that this would be a lot slower.
(2) Is it possible to have abcde start playing right after it finishes ripping the first track and then have it add on the other tracks to the playlist as it rips them.
Is there anyway to do one or both of these from the command line or with abcde's built-in options?
i'm trying to execute a shell script, i'm trying to use the values in an array for use in a sed command:
sed -n '/Sales ID: ${array[$i]}/,/Totals:/p'
that command creates empty files. so my guess is that its not recognizing the array as an array but as text?
how would i be able to utilize the array in the command? i got it, didnt think that if i doubled up the single quotes that it would work, but this worked:
sed -n '/Sales ID: '${array[$i]'}/,/Totals:/p'
I can print a specific line of a file with:$ sed -n '20p' myFileHow can I store it in a variable (in a shell script)?(I wasn't successful with "myVar=sed -n '20p' myFile" for example)
View 2 Replies View RelatedI need to create a zip file of jpg and bmp files. The zip file is named after the first file it finds which ends with .dat. Here is my script:
Code:
DAT_FILE= `find . -maxdepth 1 -iname "*.dat" | head -1 | sed 's/..(.*)..../1/'`
(cd pics; find . ( -name "*.bmp" -o -name "*.jpg" ) -print | zip ../$DAT_FILE -@ )
BTW my sed command cut off the first two chars and last four chars since find will return the filename is the form of "./filename.dat" and I just want to extract filename. When I run this script, it creates a zip file named ".zip". How do I fix this so the zip file is named after my dat file?
Code:
ls Again the command can be stored in a variable and then executed. Like
Code:
var=ls
&var
The above two codes are the same. The problem occurs when we try to pipeline it. Consider the following problem:
Code:
ls | grep *
works fine...but when we try to store it in a variable and run the command there is an error.
Code:
var="ls|grep *"
$var
how to store this kind of commands in a variable?
I tried to install JRE to my remote Suse 11 SP1 linux.After i finished with files i typed like
export PATH=<my jre path>
now i have no bash commands - typing ls causes
-bash: ls: command not found
i think that i should re-export my PATH to the right value but i don't know what it should be. I tried differend values
/etc/profile
/usr/bin
I was reading that if I want to do a one time scheduled command, I should use at, which I've never done, as opposed to cron, which i'm kinda familiar with. But what I want to do is reboot my server at 3am tomorrow and force it to check the file systems with a shutdown -rF. For this do I even need to use "at" or could I just say shutdown -rF 3:00.Will that also know that I mean 3am tomorrow and not say in 3 minutes from now or 3pm?
View 14 Replies View RelatedI tried using the tail command in my shell script and storing that value in a variable a but an error keeps coming. Is there any other way to store the output of a command into a variable. Cannot Read text from text file and store it in a variable using shell script. The thing is I need a number from the file new.txt and use that number in my script
#!/bin/bash
a = `tail -1 new.txt|head -n 1`
echo $a
I want to store the result of wc -l as a variable so I can use it later in my script...so far unsuccessfully.
I have tried this:
set `echo awk '{ print $1, $6}' | wc -l` | echo $1
but it is far from working.
I want to display 4 options using the case command and refresh the screen when options 1 and 2 are chosen (no changes to the options and you get asked again to chose option), but give a message for option 3 and exit on option 4. I set this up with the script below, but choosing option 1 works and choosing option 2 exits the script.
Code:
#!/bin/bash
#testing options
Option="0"
[code]....
I have the following code :
Code:
E_BADARGS=65
if [ $# -ne 2 ] ; then
[code]...
I have the following script:
Code:
#!/bin/bash
for HOSTS in server01 server02 server03
do
echo "Connecting to $HOSTS"
echo "Resetting Password"
echo ""
[Code]...
done When I run the script I get an error message on the hosts that says: pass=test command not found. Any ideas why is not taking it as a variable?
I am having all sorts of trouble trying to assign a variable within an awk script with the system command. I know there is a lot of ways around this problem, but for efficiency reasons, I would like to, within my awk script, do something like
system(x=3)
or
system(x=NR)
and, latter on the shell script which calls the awk script, use the variable $x. But nothing is passed to x. I have already tried things like
command = "x=3"
system(command)
and also used a pipeline within the system to pipe it to /bin/sh In fact tried a lot of stuff like that, using $(( )) etc etc etc I can create directories e write to files (yes, i could write to a file and read from there, but I dont think it is efficient, plus I am puzzled).
When I run this command from shell, it runs ok
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
However when I save it into a file called test.sh (of course, I chmod it with +x), I got error "export: 2: bad variable name"
Here is the file:
#!/bin/bash
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
I am using ubuntu.
For example, when using bash you can use
Code:
to execute the previous command or
Code:
!<number> to execute the Nth command(use history to see the list). Or you can use
Code:
cd !-2:1
to cd into the value in the first field that was executed 2 commands ago Anyhow, say I run a command and the output is a path. Any way to cd and then some variable where OUTPUT of the previous command was stored? A variable that always stores the OUTPUT of the last command.
I do this:
Code:
a@b:~$ export A=hi
a@b:~$ echo $A
hi
a@b:~$ bash -c "export A=blah; echo $A"
hi
a@b:~$
Why doesn't the bash command print the new value of $A? Is there a way to make it do so?
I am using CentOS5.5 & everytime it is showing command not found. If I export the path as below it will be working fine until a reboot. Again same error i.e command not found if I open new terminal. Every time I am exporting as below:
#export PATH=/sbin/:$PATH
#export PATH=/usr/sbin/:$PATH
#export PATH=/usr/bin/:$PATH
#export PATH=/bin/:$PATH
How can I set these permanently as that the paths should automatically be exported for everyone user whenever the system boots. And command completion also should happen for eg. #fdi (press tab), then it should show available options such as fdisk, etc.
I want to use PROMPT_COMMAND variable to build a history of all the commands i execute. So Basically i want to append the last executed command to my own command log file. How can i find the last executed command ?
I want to add PROMPT_COMMAND="echo $last_executed_command >> my_command_log" But I am not sure how to find the last executed command
I would like to put a variable in the $PS1 prompt that will change each time a command is run. I want the color of the $PS1 prompt to change each time a command is run.I know that I can do this:
Code:
PS1="h@w # "
## "#" is changes every time a command is run
[code]....
Suppose I want to account number of files beginning with abc , I can use "ls 'abc* | grep abc | wc -l", this will return me a number.
I want to store this number in a variable, say var1, so I tried
1. "ls 'abc* | grep abc | wc -l |read var1", but this didn't work as var1 has no value somehow.
2. var1='ls 'abc* | grep abc | wc -l', this just assign the entire string "ls 'abc* | grep abc | wc -l" to var1, which is not I wanted.
I don't want to store the value to a temporary file and then read the value from that file. I think there should be a direct way to get the value, but don't know how. I know in tcsh, one can just use set var1='ls 'abc* | grep abc | wc -l', but it also doesn't work in bash. Can anyone give any clue about this?
I'm trying to create a program that would locate the oldest file of a certain type on a server. Here's the commands:
OLDEST_PATH=`find -L / -depth -maxdepth 6 -mindepth 6 -type d | sort -f | head -1`
OLDEST_FILE=`find -L $OLDEST_PATH | grep .mp3 | sort -f | head -1`
ls -al $OLDEST_FILE
I'm writing this all in expect but I'm having problems. The main problem I have is whenever I try to run the first command, I can't seem to isolate the result of the OLDEST_PATH so that the 2nd command will work. There always seems to be a newline in the variable and the result is only "find -L" command running and it bypasses the variable. If I can just figure out how to get the 1st and 2nd command to work, then I can figure out the 3rd. Here's some code:
Code:
send "find -L / -depth -maxdepth 6 -mindepth 6 -type d | sort -f | head -1
"
sleep 20
expect -re "(.*)
[Code]....
I know there is a better way to write this. I've tried multiple ways and this just happens to be the last way I've tried it. If you try running this, you'll notice that there is still carriage returns after the result of OLDEST_PATH and it prevents the 2nd "find" command from working properly.
Was trying to write a shell script that has if conditional statements to decide different arguments for a command.Basically:
Code:
if [ "$1" = 1 ]
then
[code]...
I have the following TCL code:
if{ [catch {sqlite3 db /path/to/db/file} result] } {
puts stderr $result
} else {
do something
}
What I want is to use a variable for the file name/path. When I put in a variable instead of the absolute path, I get an error: "missing close-brace: possible unbalanced brace in comment while executing"
This is weird because when I run the code with the fully qualified pathname, it works fine. I substitute out the pathname for a variable containing the pathname ($variable) and I get this error.
I want to modify my $LS_COLORS variable to colorize documents on a ls command. What color would be standard or most logical to the average user?The files I want to colorize are: *.doc *.xls *.ppt *.odt *.ods *.txt *.csv *.html ...I think these files should stand out in a terminal ls output. mp3's and jpg's do, why not business files (documents, spreadsheets, presentations, etc.)
View 1 Replies View RelatedI have added an application launcher to my desktop and it works fine. However, I want to be able to feed parameters to the launcher before I launch the application. So, for instance, if the command is normally "/usr/bin/foo something" I want to be able to add the "something" parameter dynamically after clicking the launcher but before the application launches. Is this possible in Fedora?
View 2 Replies View RelatedI'm trying to execute the following command within a bash script:
Code:
tac /var/log/system.log | head -1
The script I wrote is:
[code]...
Ive been using linux for a while but I am just getting into shell scripting, im currently trying to get a simple script for finding and copying files powered by the command:
Code:
This works fine from the command line but when put in a script such as:
Code:
Code:
with the keyboard inputs for $fc1 and $fc2 being *.doc and ~/test respectivly. The only problem i can see is the xargs -ivar "var" part possibly needing $var to be defined?