I want to store the result of wc -l as a variable so I can use it later in my script...so far unsuccessfully.
I have tried this:
set `echo awk '{ print $1, $6}' | wc -l` | echo $1
but it is far from working.
I tried using the tail command in my shell script and storing that value in a variable a but an error keeps coming. Is there any other way to store the output of a command into a variable. Cannot Read text from text file and store it in a variable using shell script. The thing is I need a number from the file new.txt and use that number in my script
#!/bin/bash
a = `tail -1 new.txt|head -n 1`
echo $a
I'm trying to create a program that would locate the oldest file of a certain type on a server. Here's the commands:
OLDEST_PATH=`find -L / -depth -maxdepth 6 -mindepth 6 -type d | sort -f | head -1`
OLDEST_FILE=`find -L $OLDEST_PATH | grep .mp3 | sort -f | head -1`
ls -al $OLDEST_FILE
I'm writing this all in expect but I'm having problems. The main problem I have is whenever I try to run the first command, I can't seem to isolate the result of the OLDEST_PATH so that the 2nd command will work. There always seems to be a newline in the variable and the result is only "find -L" command running and it bypasses the variable. If I can just figure out how to get the 1st and 2nd command to work, then I can figure out the 3rd. Here's some code:
Code:
send "find -L / -depth -maxdepth 6 -mindepth 6 -type d | sort -f | head -1
"
sleep 20
expect -re "(.*)
[Code]....
I know there is a better way to write this. I've tried multiple ways and this just happens to be the last way I've tried it. If you try running this, you'll notice that there is still carriage returns after the result of OLDEST_PATH and it prevents the 2nd "find" command from working properly.
Code:
ls Again the command can be stored in a variable and then executed. Like
Code:
var=ls
&var
The above two codes are the same. The problem occurs when we try to pipeline it. Consider the following problem:
Code:
ls | grep *
works fine...but when we try to store it in a variable and run the command there is an error.
Code:
var="ls|grep *"
$var
how to store this kind of commands in a variable?
Suppose I want to account number of files beginning with abc , I can use "ls 'abc* | grep abc | wc -l", this will return me a number.
I want to store this number in a variable, say var1, so I tried
1. "ls 'abc* | grep abc | wc -l |read var1", but this didn't work as var1 has no value somehow.
2. var1='ls 'abc* | grep abc | wc -l', this just assign the entire string "ls 'abc* | grep abc | wc -l" to var1, which is not I wanted.
I don't want to store the value to a temporary file and then read the value from that file. I think there should be a direct way to get the value, but don't know how. I know in tcsh, one can just use set var1='ls 'abc* | grep abc | wc -l', but it also doesn't work in bash. Can anyone give any clue about this?
Was trying to write a shell script that has if conditional statements to decide different arguments for a command.Basically:
Code:
if [ "$1" = 1 ]
then
[code]...
I am connecting to MySQL DataBase using shellscript and writing a select statement like select attachmentid from attachments where pageid=10175 I want to store the output of the select statement into a shellvariable or a file. How can i do it using shellscript.
View 4 Replies View RelatedIf I want to use that result to be saved in a variable, which type would it be in script? For clearing: let variable x and destination path is y/z
in prog.sh:
x=du -hb /y/z
echo $x
Q1: What type of x?
Q2: What option instead of -hb to presedent the size in kib?
I need to store the output of bitset() in a variable ... is it possible in c++?
View 1 Replies View Related#!/bin/shLOOK_FOR="NTLMAuthenticationFilter"for i in `find ./ -name "*jar"`doecho "Looking in $i ..."grepjar -e $LOOK_FOR $idoneI wrote the script above, and try to find if there any file name LOOK_FOR exist in those jar,my quest is: grepjar -e $LOOK_FOR $ihere how can I check if there are any successful result , and output them ?
View 2 Replies View RelatedEvery time I need to find a file and then open it, I have to use :
find ./ -name **.properties. , then copy the result, and then vi "paste the result here" .
If I need to use a mouse, it can be a little trouble. So is there any better way to do this?
I am frustrated by running a script on the Fedora 14 computer as a cron job. I paste the code:
Code:
#!/bin/bash
#a backup script to copy data from sda to sdc
ROOTVOL=`blkid -U ea210a08-6212-4dc8-be1c-23fce3b965bc`
[code]....
So when I run this as root, for example:
Code:
# /root/myscript
the result is what I expect:
Code:
Jul 1 13:41:16 svn root: ADMIN: Executing backup-svn
Jul 1 13:41:16 svn root: using blkid ea210a08-6212-4dc8-be1c-23fce3b965bc as /dev/mapper/vg_svn_backup-lv_root
[code]....
I am working at a client who has a project where code is a mixture of different source control systems. So a layout might be like this
project/a/.svn
/a/subfolder/.svn
/b/.hg
/c/subproject/.svn
/d/.hg
So I am trying to put together a simple command that when executed from the project folder will run the appropriate hg/svn command in each project i.e:
[Code]...
Since the client has many such projects, Instead I am looking for a solution similar to find -exec where the svn/hg commands are automatically executed on each first level of match (i.e. svn up is run in the project/a folder but not in project/a/subfolder). How can such a command be constructed ?.
I have the following commande /sbin/fuser -f -u /u/DT01/F010107 1>/tmp/null 2>/tmp/seausr.T0069 when executing as root 'su' this give me all user using the file. but when tried with 'sudo' i am asked with 'user password'. Is ther anyway to simply get the result without having to supply a password and to see all user not only me. (i have the file open also).
View 1 Replies View RelatedI came across this reult of the type command (hashed) in another post. (see below).
Code:
fraespappp8:/data/apps > type topic_file_publish.sh
topic_file_publish.sh is hashed (/data/apps/pnbgstk/publication/topic_file_publish.sh)
This (result = hashed) is new to me.
I wonder which kernel/distro/shell it is from.
I have this script:
Code:
a=awk'{print $8}' f1.txt
How can I make it store lines in $a ? In the way above it creates one big line.
I am not able to execute a multiple sed statement using pipe filters in a variable. i am trying to extract a path from a file and then working on that path to change a few letters within the path by going through another sed statement.
the code looks like this code...
I am trying to watch a command and try to log it into a file. I tried
watch -t -n 10 "(date '+TIME:%H:%M:%S'
; ps aux | grep "pattern" | wc -l)" >>
logfile
and am expecting a result like
TIME: 10:32:30 12
TIME: 10:32:40 18
TIME: 10:32:50 2
to be stored in logfile. However, when the logfile has unprintable characters in in. How do I get this kind of output from the command li
I have two students whose windows laptops are riddled with malware and not working properly. They want me to help them install Linux (which we use in school), but they are concerned about their iTunes.
Having avoided iPods as "defective by design", I know nothing about iTunes whatsoever. However I remember reading about DRM locking and such problems that have me concerned that I won't be able to do it.
Where does iTunes store its stuff?
Can I copy its data store to an external drive, and then into a linux home?
Then will it work on wine, or can another manager (rhythmbox etc) access the itunes data?
Alternatively, if I partition the drive and install linux, can rythmbox/wine/something access itunes data on the win partition?
Supposing they are buying music through iTunes, what will happen to that account?
Finally, one of them has an iphone. Does that work with linux?
Ironic that an apple application is blocking migration away from windows.
I was reading that if I want to do a one time scheduled command, I should use at, which I've never done, as opposed to cron, which i'm kinda familiar with. But what I want to do is reboot my server at 3am tomorrow and force it to check the file systems with a shutdown -rF. For this do I even need to use "at" or could I just say shutdown -rF 3:00.Will that also know that I mean 3am tomorrow and not say in 3 minutes from now or 3pm?
View 14 Replies View RelatedWhen I run this command from shell, it runs ok
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
However when I save it into a file called test.sh (of course, I chmod it with +x), I got error "export: 2: bad variable name"
Here is the file:
#!/bin/bash
export REVS=`svn info svn+ssh://svn.myone.ca/var/svn/story/trunk/lib |grep 'Last Changed Rev:'| awk -F: '{print $2}'`
I am using ubuntu.
For example, when using bash you can use
Code:
to execute the previous command or
Code:
!<number> to execute the Nth command(use history to see the list). Or you can use
Code:
cd !-2:1
to cd into the value in the first field that was executed 2 commands ago Anyhow, say I run a command and the output is a path. Any way to cd and then some variable where OUTPUT of the previous command was stored? A variable that always stores the OUTPUT of the last command.
I do this:
Code:
a@b:~$ export A=hi
a@b:~$ echo $A
hi
a@b:~$ bash -c "export A=blah; echo $A"
hi
a@b:~$
Why doesn't the bash command print the new value of $A? Is there a way to make it do so?
I am using CentOS5.5 & everytime it is showing command not found. If I export the path as below it will be working fine until a reboot. Again same error i.e command not found if I open new terminal. Every time I am exporting as below:
#export PATH=/sbin/:$PATH
#export PATH=/usr/sbin/:$PATH
#export PATH=/usr/bin/:$PATH
#export PATH=/bin/:$PATH
How can I set these permanently as that the paths should automatically be exported for everyone user whenever the system boots. And command completion also should happen for eg. #fdi (press tab), then it should show available options such as fdisk, etc.
I want to use PROMPT_COMMAND variable to build a history of all the commands i execute. So Basically i want to append the last executed command to my own command log file. How can i find the last executed command ?
I want to add PROMPT_COMMAND="echo $last_executed_command >> my_command_log" But I am not sure how to find the last executed command
Ive been using linux for a while but I am just getting into shell scripting, im currently trying to get a simple script for finding and copying files powered by the command:
Code:
This works fine from the command line but when put in a script such as:
Code:
Code:
with the keyboard inputs for $fc1 and $fc2 being *.doc and ~/test respectivly. The only problem i can see is the xargs -ivar "var" part possibly needing $var to be defined?
suppose i store the history number of a command say :
1004 cat file
Then now i want to run it like : !1004 but by using a variable.
command=1004
!$command
i am getting errors like :
command=1004command
I need to find one RUNNING word in latest created logs.
and as soon as i will get RUNNING WORD , i have to execute another Unix Command.
I wrote following script code...
how to assign a local variable value to a global variable....
View 2 Replies View RelatedI am supposed to create an environment variable with the PRINTER variable, which should resolve to the word sales. Would the command be like this?: env PRINTER - NAME=SALES (is this the command to create that variable with resolving the word sales to it?)
View 3 Replies View Related
