I want to write the date & time and a text string to a file from crontab.The following line works fine in the CL:echo $(/bin/date +"%F %T")" Some text" >> /home/me/foo.txtI installed in crontab and no text appears in the file that it is redirected to.The crontab entry looks like:* * * * * echo $(/bin/date +"%F %T")" Some text" >> /home/me/foo.txtTried a version to just write to stdout....* * * * * echo $(/bin/date +"%F %T")" Some text"No date, time or text appears at the command line
I'm writing a Bash script to take IPTC keywords from a text file and write them, via Exiv2, to several (first batch is 100) JPEG files in a single directory. The script has one while loop inside another while loop, both terminated, but I'm pretty sure that's not my problem. I think it's how I'm incrementing the "counter" variable, although it could also be the method of parsing the text lines from the file (using cut with delimiters that have worked fine in simpler scripts).
Here's the code as I've worked it up to this point.
Code:
And yes, "keywords" checks out in Crimson Editor, Emacs GUI and nano as an ASCII file with UNIX line endings. No issues on that score.
Feeding each line consecutively into a terminal (excepting the exiv2 command) works fine: each variable echoes with the part of the text line used as a variable value as it should, even when the b variable is incremented the quick&dirty way (up arrow three commands and hit enter).
Running the above script in eval mode (sh -x) stalls after setting the b variable to one and reading in the first line of text. I'd like to know why. I'd also like some advice on another reliable method of parsing the read-in lines.
Writing script to create backup of file by adding datetime to file name. Basically test for file presence if there, cp with datetime then rm original cp works fine from command line but get cannot stat `full path to file': No such file or directory
Code:
Here are the errors: cp: cannot stat `~/html/CVP_dadamail/.dada_files/.logs/errors.txt': No such file or directory rm: cannot remove `...': No such file or directory
The for statement is a placeholder as I have same file to backup out of several directories. using "bash -x scriptname" -OR- inserting echos, I can see I've constructed the strings properly. Believing it might be related to the hidden directories, I tried setting the shopt "glob" options to no avail.
Ultimately I'll add the other directories to the for loop and then run this from a cron job, so if you see potential pitfalls knowing I'm headed in that direction...believe construct would be
I had to make for work a collectd based network monitoring system which displays data for each server in a fullscreen conky on different compiz viewports. I have to switch viewports automatically when the machine isn't operated (sorta screensaver) and also if i had to call attention in the case something bad happens, autoswitching should stop and the relevant viewport be showed up.This requires an interface to talk dynamically to the WM, which i've implemented in bash with support of the widely available "wmctrl" program.
Having an odd problem running a mysqldump via crontab. I have the script running on other servers and they work fine, so not sure how to actually troubleshoot, but the script looks like the following;
If I run it as a cronjob as root, it finishes in a second and a 20k file is there. If I run it from the command line as root it does the backup (takes a few minutes) but does complete the backup and can be unzipped and read successfully.
I use crontab to execute a bash script every minute and the output is redirected to a log file.In that bash script there is a screen command to start a screen session.When I execute the script manually it works perfect, but with crontab, the screen command is not executed, but the echo's are. Because they are written in the log file...Here's my script:Script removed for violation of LQ Ruleso the script runs perfect when I do it manually, but not with cron...Here's my crontab (sudo crontab -e)
# m h dom mon dow command */1 * * * * sudo /home/laurent/Games/Cod4/StartCod4.sh | egrep 'running|started' >> /home/laurent/Games/Cod4/Serverlog.log
I am using Linux 64 bit Redhat Linux. I am trying to setup simple crontab as follow...1. Edited crontab file using crontab -e2. Listed the file once to verify it using crontab -l. This will display as.. 18 5 * * 2-3 ksh $HOME/testScript.sh > $HOME/testscript.out3. Logged in a root and restarted cron deamon using "/etc/init.d/crond restart"As per my understanding now my testScript should start running at 5:18 am Thuesday
As root, I use crontab to run mirrordir to backup directories. Everything gets copied over properly, but owner information isn't preserved and root is the owner of all the backed up files. I can deal with that, but crontab reports tons and tons of chown/chgrp errors for mirrordir every time I do back ups--which is every day--and the multiple emails to root of thousands of chown/chgrp errors is very annoying. The error is "Operation not permitted," but that doesn't make sense to me because the job runs as root (right?) and clearly the job is permitted to create the backup files, so why would it fail to chown and chgrp?
I've had the exact same setup on another server for years, and crontab has always run mirrordir without error. Any suggestions how to clear the errors on my new server?
I have written a simple backup script, and added it to CronTab, but it doesnt execute at all. Here is my script: [URL]...And my CronTab entry: 0 */2 * * * root /home/server/Scripts/backup.sh
i want to create a crontab job by bash scripts:test1 cat /opt/shell/test1crontab on.but i do not want to use this command line ( crontab -e )to add this job.
is it possible disabling a crontab job without deleting the crontab description entry (by crontab -e)?I could also accept to change the entry itself. Now it's:0 0 * * 0-6 /home/me/cron/script.csh
I would like to know how do I print the line # in a script. My requirement is, I have a script which is about ~5000 lines long. If there are any errors happen I just exit. And I would like to add the line # of the script where the error happened.
Code: #!/bin/bash trap "echo 'you got me'" SIGINT SIGTERM # to trap ctrl+c echo "Press ctrl+c during 5 sec loop" for ((i=0;i<5;i++)); do
[Code]...
How come code behaves normally and stops when ctrl+c signal is caught and resumes, but after I use at least one timeout read in the code it looks like, if signal is caught again it doesn't pause the execution but skips the loop. If you remove -t (timeout) option from the read, both loops look the same!
I don't quite understand how pipes work in bash. I know that it takes an output from one command as the input in another command. What an output is I can get because it's what the command prints out to the screen. But how do I know what input a command will take? Here is an example I thought would work:
Which gem | rm Unfortunately it didn't. Which gem prints out "/usr/bin/gem" so that must be the output right? I thought that was given to rm so it would be "rm /usr/bin/gem" but I was wrong. How do I know what input a command takes?
Now in my bash script, I want to get the output /home/user instead of $HOME once read. So far, I have managed to get the $HOME variable but I can't get it to echo the variable. All I get is the output $HOME.
I have written quite a few separate bash & scripts and php scripts that up to now I have run from cron jobs. However I have to estimate how long each takes to run, before running the next and so it probably takes much longer than necessary to run them all. They have to run in order.
Now there are so many I am thinking it would be better to have a master bash script that would run one after the other, but I am not sure how to get the master script to wait before starting to run the next script. Is this possible and is there a command that will make the script wait between bash and php scripts , for them to finish, before running the next?
I have a script that pops up a jpg file several times a day as a reminder. The script is called up by crontab and it works perfectly.The issue is that I want the script to also perform a system "beep" in addition to popping up the jpg file. When I test it on the command line everything works but when I run it in cron the jpg file pops up but the beep doesn't beep. I'm thinking the problem is in the "echo -e \a" part. I must be missing something.Here is my script:
I have a PGP script that for whatever reason if I let linux's cron run it automatically, it sends out the final email with attachment with a blank file. If I come in and run in manually everything works fine and the file is populated in the file. So the only real difference is that i'm running it manually through cron, rather than letting cron run it at a set time.Below is a sumary of my script.
I'm really running into a wall trying to figure this out. I have a Bash script and narrowed down the one command that doesn't seem to work via cron and it's my pgp decrypting line. Works fine if I run the command via terminal but if I run it via cron it doesn't output anything.crontab -e shows the cronjob and it runs, creates the log file with no output. Is there maybe something I need to run as well? Permissions look set, unless the cron is running as a different user(was under the assumption if it showed up under crontab while logged into that user, then it would run as that user.
I think it would be better to count the len and remove 3 chars to right to get the extension, but it can be macintosh filenames with have 4 chars for extensions.
I have a question about using crontab with /etc/crontab...
I had a cron job that I needed to run as root. At the time I thought that sticking it in /etc/crontab would be a good idea. However, I used the crontab command to edit /etc/crontab, which I guess is not standard procedure? Specifically, I configured /etc/crontab as my local user's crontab (i.e. sudo crontab /etc/crontab) then added my cron job as I would a local user crontab (i.e. sudo crontab -e).
Originally, my cron job looked like this:
30 * * * * root /my/batch/script &> /dev/null
After adding the new cron job I started seeing errors. Something to the effect of "can't find command root" or something similar. So I removed the 'root' user definition from the cron job and the job started running fine. However, because this is /etc/crontab, there are other system related cron jobs that have been defined to run under the root account (e.g. "17 * * * * root cd / && run-parts --report /etc/cron.hourly" runs as root, etc.). So these pre-existing system cron jobs, which up until now have been running smoothly, are now generating "can't find command root" errors. But I think that the system cron jobs _are_ successfully being run someplace because logrotate seems to be working.
So what I _think_ is happening is that /etc/crontab is being run twice: once as the system crontab, and once as my sudoed local user's crontab. When I run crontab -l I see nothing, but when I run sudo crontab -l I can see the contents of /etc/crontab. I am reluctant to delete my sudoed local user's crontab, because then in the process I would be deleting the system crontab, and I do not know how I should restore the system crontab's contents. (I am still not sure as to the most appropriate way to edit the system crontab).
How can I get out of this mess? I want /etc/crontab to go back to the way it was before--running _once_ as the system crontab. As for my new cron job, I'm willing to reconfigure it anywhere so long as I am still able to run it as root. Any ideas? (I am using Ubuntu 8.04 Server LTE)
I have installed an application manager(monitoring application) on my linux server. Now, i need to have backup schedule for my application. The application itself has executive file to backup database.But when i put this file in my crontab to schedule the backup program it wont run!50 09 * * * root /opt/ME/AppManager9/bin/BackupMysqlDB.sh
I need to rename the resulted searched files from a loopI have the following code:
find . -name DOC* | while read i do find $i -type f -name '*.txt' done
basically, I am searching for all txt files inside any folder starting with DOC name.this code is working fine with me.I need to rename those .txt files to .txtOLDOS: Ubuntu 10.4Bash shell
I tried searching and couldn't find a good explanation on how UTF-8 and UTF-16 works. Could someone explain it or provide a link to a good explanation?
I am trying to write a bash script that sources another bash script. Essentially, I need a few lines to check to see if a certain variable is set. If not, I set it manually, and then source a scripts with that variable in the path. I wrote a test script to try it, but for some reason the last line does not work. Here is what I wrote:
#!/bin/sh source ~setupdir/setup.shrc #just a test, this line works echo ${#SETUP} # prints 0 if setup is not set, which it isn't if [ ${#SETUP} -eq 0 ] then SETUP="~setupdir" fi echo $SETUP # prints ~setupdir
want to get a text file and use sed commands on it to make it more manageable.(because I don't know how in python) Then take each line based on what it starts with and send it to the proper lcdnumber.display. I need an adjustable "pause" to allowing slowing down of the entire process equally but I think the way I'm using the time.sleep is messing things up as only 1 in 10 value sets make it to the lcd and sometimes some of the segments don't get drawn. Also the x digit and the y digit are now being sent to one lcd how can I grab just the first half of the double value xy up to the space as x and then grab the remainder as y so all three xyz values go to three separate lcd displays? I attached 2 files one before and one after the formating.
