In a c program the value of an integer variable is changing rapidly. I have to get the value of that variable at a particular instant from another program. How can i do it without using a file?
When i tried with extern variable as
I execute the both .c file from 2 terminals but got only value 0 printed for both var_a and var_b all the time .
If I have a variable, say xvar, which can take both string and integer value and I want to perform an operation in following 2 conditions:1. Either xvar is null2. xvar equals 2[ -z "$xvar" ] || [ $xvar -eq 2 ] && <some-code>Doesn't seem to work if xvar takes string valuesI know that since I have no restriction on xvar, I can get away with string comparison in second test too, ie[ -z "$xvar" ] || [ "$xvar" = "2" ] && <some-code>
But, 'Sams teach yourself shell script in 24 hrs' says that [ expr1 -eq expr2 ], if either is string, it assumes 0 valueIs it true
I'm trying to write a simple program that lists a menu and then asks you for your decision, and you can answer with a number or the name. However, I don't know how to add the second options (name).
View 14 Replies View RelatedI have a function that take char* I call this function in an array, and I need to pass the following:-i+" binomial" to be like "2 binomial" or whatever value of i value (i is an integer) it is pretty easy to be done in java, but how to concatenate an integer with a string and get char* or string to pass to a new function.If you missed me i just need to get the following :string =integer + string
View 5 Replies View RelatedI am trying to write a bash script that installs a program fully automated for me. I am stuck at the one part where i need to change a line in one config file. I have tried various syntax for sed and none have worked. Maybe someone can suggest how to go about this. Since the line appears in the middle of the file, I can't use echo or cat. Also the file will be diffrent lengths depending on the install.
The line I need changed is:
I need that changed to:
the last syntax i tried is:
Yes this is for PNP4Nagios on centos 5.6 64bit. If i can get this figured out. I will be willing to post the whole thing for others to use. it will be used to install PNP after a working nagios install is done.
I have C++ source code(*.cpp) files that expects it's header files in System's include folder which is/usr/include.The cpp files has include lines like this:
Code:
#include <some.h>
#include <another.h>
[code]...
I have a file in which contains one line with a lot floating points.In the very first place and some times in the downstream, there are a few integers, surrounded by blank spaces.1 1.02-4 1.03-5 544 1.04-1 65 2.98-1 5.78-10 3.45-2 etc etc.I aim to split the file in more files each of them containing an integer and the following floatings until the next integer.
View 1 Replies View RelatedI have a java compiler and Im using a double intiger called Experience and when compiled and run the double intiger does not hold intiger values that are mathameticle. Like 1.5 - 1.4 will equal .100000000000000000009 and 5/3 will equal 1.0. and 1.5x 1.4 doesnt equal 2.1. Is there something I am doing wrong with double intigers? Is it the compilers fault? Could it be something thats wrong with my computer and the compilers I am using are not tat fault? Anyways double 1.5 + 1.4 does equal 2.9 so.
View 4 Replies View RelatedI've got a strange bug that I cannot figure out how to solve. Here is the function.
Code:
int getnexttab(char input[], int index, int length)
{
[code]....
I need to convert an integer to a byte array of size 2 and vice versa. The code shown below works well for positive values but not for negative values. Also, using an array of size four makes the conversion works. However, I am limited to an array of size 2.
View 5 Replies View RelatedIt it safe to read a shared integer while another thread is writing to it on a multicore system?
View 3 Replies View RelatedI want to print a single digit integer on to the screen using the int 0x80. I have loaded the number in the ecx(=5, say), size in edx (=4, lenght) and eax (=4) ebx (=1). I've added 48 to the contents of ecx, and then calling int 0x80, I thought should print 5 on the screen.
However it does not print anything. also gives no errors. I checked the contents of the ecx reg (gdb), it has 53.
A snippet showing the this will be great. I've seen snippets using the c library (printf), but I want to see how it is done using int 0x80.
I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
my script has a variable which comes in the form +00.00 +0.00 -00.00 or -0.00 (the numbers can be any in that form) for any that have a + symbol I need to remove the +, but if it has a - symbol it needs to stay.
i need to make a new variable with the string from the old variable btut without any plus sign. I have tried a lot of different ways with no success, each thing I tried either left the + or removed the entire string. I think this should work but doesn't
foo=+12.40
bar=${foo#+}
how I can search within a variable and assign the results to a new variable. I'll use the following as an example -
cars="Audi BMW Cadillac Chevy Dodge Ferrari Ford Mercedes"
list=`echo ${cars} | egrep -o '<A?+|<C+'`
with the echo command I get the following output assigned to list -
A
C
C
What I'd like to get for output is -
Audi
Cadillac
Chevy
how I could do this regardless of upper/lower case letters?
included shell script inside c program, and i wanted to assign the value of c variable to shell variable..Can any one please suggest me how to do it?
View 8 Replies View RelatedI changed shells for a user from bash to tcsh using this command... chsh user -s /bin/tcsh but when logging on via ssh under that user I get a "Illegal variable name" error. I type, echo $shell and it says, /bin/tcsh. I am curious what that Illegal variable name could be.
View 3 Replies View RelatedI want to make change to environment PATH system wide. Because I have program called "md5". I want to execute it from anywhere (i.e any directory).
My md5 program is located at "/home/ahuq/MappingServer/md5_program". So what I did was to put: "export PATH=$PATH:/home/ahuq/MappingServer/md5_program" in the running SHELL.
This only makes temporary changes and lets me run the "md5" program from anywhere temporarily.
But I want to make this change permanent. So what I did was to put the "PATH=$PATH:/home/ahuq/MappingServer/md5_program" line into the "/etc/environment" file.
This screwed everything up and then for a while I couldn't execute anything from SHELL. I knew the absolute path of "nano" editor and used it to modify the file (i.e. /etc/environment) back to its original condition.
This fixed the problem and now I can run programs like "ls" from the SHELL.
But still I need a way to permanently add the path of "md5" to the environment. How can I do this in Ubuntu 10.10? Which file needs to edited?
Do I just logout or do I have to restart the system to make the changes active?
This loop is part of a bash script which takes multiple arguments.
Code:
for ((i=1;i<=$number;++i)) ; do
offset=$(($i+5))
[code]...
Code:
The error is:
Code:
What I want to do is take input of ip4 as a string, convert it to an integer to add 1 to it, then reconvert it back to a string. Its not working.
My full code is:
Code:
'readonly HISTFILE'
but the user could tamper with the histfile itself. Like:
rm -f $HISTFILE;
rm -f $HISTFILE; mkdir $HISTFILE;
rm -f $HISTFILE; ln -s /dev/null $HISTFILE;
I'm experimenting with PROMPT_COMMAND to execute a command each time the user executes a command and so log it somewhere else.This post was pruned from the 2009 Is there a way to prevent users from changing or unset their HISTFILE variable? thread. Please do not resurrect old threads but instead create your own (and maybe provide a link to the old one).
I'm not sure if I should post the whole script here (60 lines) but the script has a variable that occurs only three times, once when it's set and twice when it's referenced/read/expanded (not sure of the correct terminology)Anyway if I change the name of this variable from "maxdepth" to "findopts" the script throws the following error:
find: unknown predicate `-maxdepth 1'
But if I change the variable name to "maxIdepth" it still works? Here are the lines that this variable appears in:
maxidepth=('-maxdepth 1');
.
# other code, etc
[code]....
I have been using Slackware64 newly installed to an external USB drive to get used to KDE4 and whatnot as I currently run Slackware 12.0. It's been very good and I now feel a little alienated when I reboot to Slackware 12 and KDE 3. There is an ongoing problem though. My machine has a front mounted jack socket for headphones which cuts off the feed to my external speakers as it should. When ever I plug in my headphones the volume coming through them rapidly drops off to nothing, If I then unplug them no sound comes back out through the external speakers. It could be that they are being reinstated when I unplug the headphones but the sound level has dropped to zero - as it has in the headphones. The machine has an on board Intel sound device reported like this :
[Code]....
This is a real pain and the only solution seems to be to reboot. This not only happens when in KDE but also if I run "speaker-test" as a test from the CLI as well.
I have tried to learn how 64bit asm (nasm in my case) works and found, among the many disparate pieces of info on the net, a few vague inferences that floating point registers can be used for other purposes than what they are intended for, example: "64-bit Linux allows up to fourteen parameters to be transferred in registers (6 integer and 8 floating point)." This would be fantastic for string operations/manipulation (I have never used asm for floating-point operations), can anyone shed a bit of light?
View 8 Replies View Relatedso i wrote myself a very simple hellworld program in c++
...the usual stuff
int main()
{
[code]...
Running Squid version 2.6.STABLE21 on CentOS5 release 5.5 (Final) in non transparent mode. All the browsers are configured to connect to the squid on the said port. And that is working fine in conjunction with dansguardian.I want to integrate ncsa_auth basic authentication mechanism into squid. And the error is what is mentioned in the thread title.
Here is cache.out file contents:
Code:
2011/01/12 18:16:14| Starting Squid Cache version 2.6.STABLE21 for i686-redhat-linux-gnu...
2011/01/12 18:16:14| Process ID 29318
2011/01/12 18:16:14| With 1024 file descriptors available
2011/01/12 18:16:14| Using epoll for the IO loop
2011/01/12 18:16:14| DNS Socket created at 0.0.0.0, port 52054, FD 6
[code]....
i want to pass variable in mysql qyery in c programming
View 1 Replies View RelatedI am running fedora 14,
have 456.2 MB RAM
59.9 GB disk space
Kernel 2.6.35.13-91.fc14.i686
Intel Pentium 4 CPU 2.00Ghz
SIS motherboard
Unknown brand sound card
Have tried tried the following music apps
-Amarok
-Audacity
-Banshee
-Rhythymbox
-Kaffiene
-Movie Player
Have played
-mp3
-m4a
-wav
Used several diff speakers and heaphones
What is the problem?
I will have to code this. However I am lacking of time since I have too much to do. make a short code bash/dash to prompt the country with Zenity, then, get the PLS or m3u url and prompt with another zenity which radio to play. http://www.listenlive.eu/index.html
My code to get url's radio country.htm is:
Code:
Ok so Basically i have 2 questions
1. i know how to create a file with c++ using but is there a way to save it to a specific location on your computer with windows and linux
Code:
2. i need to know how to run/execute/open a file in a c++ program im using and its not working
Code: