I've got a 'nested' for loop which has a grep in it, if the grep fails there's no output - however the error code is still $0 and the second for loop is still entered, there's also a grep in the second for loop.I guess ultimately what i need to know is whether there's a way of making grep generate an error code. when no results are found?
View 14 RepliesI have written the following script in my linux server to add users for LDAP database.But i can't able to run this.
The script is as following
#!/bin/bash
echo "Mention the username which you want to convert LDIF format"
read username
if ["$username" -e "/ldiffile/passwd"]; then
echo "Username already exists"
else
cat /etc/passwd | grep -i "$username" >> /ldiffile/passwd
fi
The output which i got :
. ldapadd.sh
Mention the username which you want to convert LDIF format
yal2361
-bash: [yal2361: command not found
please let me know where need to change and what
I think I put this in the wrong place
View 1 Replies View RelatedI have downloaded whole linux source codes of fedora in a dvd. There are several rpm packages and lots of directories in it. I want to load all source codes to version control system (svn or cvs) which is loacated in a server and develop it step by step .During this time I want to build my own distribution. So I need to know how to build all these packages at once. Is there anyone who can explain "how to do" to me
View 1 Replies View RelatedI wrote a c++ program but for security reasons I need to make sure that no one can read my codes by my ".out" files. I did everything I could. But everyone can see it by "strings Alpha.cpp".I heard that g++ has some options to do so.
View 7 Replies View RelatedI got some problems and need your help.
In school, my codes are writeen under UNIX system (Solaris10/SUN), now I need to transfer those codes to Linux (Redhat5). But after I directly copy to Linux, it shows many errors and warnings.
Does anyone know which codes I need to modify to specifily suit for UNIX? I am not familiar with those systems and hope to get your kind help.
I am a student taking part in a comptition. We have a set of questions to complete within today. Can anyone please help me out with it. I have a custom written "echo" program in C, running on port number "1220" which echoes back the first 16 characters of whatever is given as the first command line argument. But somehow, my brother had got unauthorized remote root access. The program is given below. How did he do it? Please give the exploit code and explain how it works.
#include
#include
void echo(char* input) {
[code]....
I wish to implement some part of my codes to use the GPU of my graphic card but I have no idea whether GNU as already implemented it (as for OpenMP). I mean, there are PGI Fortran compiler which embedded CUDA but I figure it's not free. I also wonder if that works only with ATI graphic cards or if for instance I can use my Intel Corporation Mobile GM965/GL960 Integrated Graphics Controller.
View 4 Replies View RelatedOne of the feature in my application involve changing of hardware setting. This require the user to be root or have administrative right.Before my application enable that feature, I want it to check whether the user is "root" or not, or whether user use "sudo" command to run the application or not, or whether the user has administrative rights or not.What are the codes or library that can do this?
NOTE: Sometimes, advanced linux user may set the user id of root to something else other than 0. So, getuid() may not be helpful in this case.
I need a script that can print some series of strings in colors based in the information of a file, for simplicity let's say it only does:
Code:
#!/bin/bash
printf "e[1;31;32m%-10se[00m" "OK"
When you execute this in the command line it prints a bold green 'OK'. So far so good.
Now, I need to check the output of the script over time using the command watch. The problem then arises. watch seems to ignore the escape codes and just prints:
Code:
[1;31;32mOK [00m
Is there any way to fix this?
If not, how can I check inside the script if it is being executed from a command? (watch in this case) So I can print without color for those cases.
im trying to install aircrack and i keep getting this error code. I am completely new at this. I have ubuantu 10.10 or the latest edition.
View 3 Replies View RelatedI need to rename the resulted searched files from a loopI have the following code:
find . -name DOC* | while read i
do
find $i -type f -name '*.txt'
done
basically, I am searching for all txt files inside any folder starting with DOC name.this code is working fine with me.I need to rename those .txt files to .txtOLDOS: Ubuntu 10.4Bash shell
i can not figure out why my program does not terminate if i type n when i read loop unless it is the last if statement in my program ?
while [ "$loop" = y ] ; do
echo "what does baket mean: " ; read word
if [ "$word" = why ]
[code]....
Here is my code
Code:
I just cant seem to understand loops. i havent put the loop in yet but what i would like is the user only to have 3 tries at guessing number then exit if wrong or it says "correct if right" tbh i dont even know if the above code is correct. i have tried several ways and position of the loops but each time is comes out wrong
I have a directory file capturing script, the variable is fine with in the loop but gone after the loop is done:
Code:
DIR="/usb/sdb1/media/music/"
i=1
[code]...
I am about to move my scripts to the next generation level, so I need some help I am stuck in varying my variable names in a loop. For example:
for user in ben dorothy mike pat
do
[ -r /home/$user ] && let "$user"check=1 || let "$user"check=0
[code]...
I am trying to do some shell programs. I tried some sites regarding the while loop, they give the structure as:
Code:
while [ n1 -lt 500 ]
do
echo $((n1+100))
done
But the below code also worked for me:
Code:
while ((n1 > 500))
do
echo $((n1+100))
done
By using (( )) I could use while, for. But the documentations didnt follow this way. I mainly use this for datastructure programming.
In the code segment below is a for loop I am having some considerable difficulty with. It just keeps iterating endlessly and totally ignores the 70 times limit specified. I can't ever remember having this problem before and am absolutely Clueless.
Code:
for ( x = 0; x < 70; x++ )
{
fputs ("CSN00", target);
fprintf (target, "%d", userid);
[Code].....
I want to loop through the records in the below file (homedir.temp)
/home/user1
/home/user2
/home/user3
I want to do the following activities with each record1. du -s - to get the total usage for that directory (my variable name is SIZE)2. divide SIZE by du -c for /home to get the percentage of usage. (my variable name is PER)3. write the directory, SIZE, PER to a filePROBLEMI am using the below for loop: for record in homedir.tempthe mentioned activitiesdonehe above is not looping through the records. It does the first record perfectly and exits the loop.
ITT and am just lurning about scripting and need to read a file and output the file to the screen. We need to do this with a while loop.
View 5 Replies View Related./test.sh: line 3: syntax error near unexpected token `cd'
./test.sh: line 3: `cd $f'
--------------------------------
[code]....
I need to flash my BIOS to get rid of an error: "Intel uCode loading error". On [URL] I have found a tutorial, that looks to be fine. I can even see in the comments, that somebody have done this with success from Ubuntu 9.04, the very same system, that I use. Nevertheless I cannot make this bootCD with my Ubuntu 9.04, as it doesn't know the loop option to mount the image.
In the tutorial it says: "Requirements for this step is that you have support for the vfat and loop file systems in the kernel. Or you can have those features compiled as modules. In the latter case you can load the modules before the next step, like this:
modprobe vfat
modprobe loop"
loop doesn't seem to be present in my system, and the command modprobe loop returns an error that the module is not available. I tried to follow the tutorial anyway, but with no success. How can I get the module lopp? I also want to use it to make iso images bootsble from the harddisk.
When I deal with an array in a function I con not access to the content of array in a for loop, but out of a for loop I can access to them! for example
[code]...
In a function when I send as parameter, in a for loop it prints the content of array and out of a for loop it prints the address of arr[i]
I'm writing a mass snmp toner check which polls any toners available to be snmp polled, however when using a loop statement I get the results on different lines; which sounds good, however the tool I use to check with (nagios) ignores the new lines.
Is there any way I can get the output on one line? Also, I need to raise a fault if any of the toners are below a specific level (with nagios you raise faults with the exit code) - any way I can do this without exiting the loop. Code below with bits and bobs commented out.
Code:
check_ink_levels ()
{
for ID in $INKS
do
[Code].....
#!/usr/bin/perl -w
use strict;
my @files = `ls -1`;
[code]...
I have a 50 file name NSSAVE0001.vtk to NSSAVE0050.vtk.Do I have to manually type individually command to open each file or can I have a loop to open file?
View 3 Replies View Relatedso far I have this
list = open('list.txt')
for x in list:
list.read(x)
I need to pass a large number of arguments to a function which takes variable number of arguments, such as gtk_list_store_new. But it doesn't look nice if i write something like gtk_list_store_new(NUM,TYPE_A,TYPE_B,TYPE_C,...,TYPE_OMEGA); because of large number of arguments. And, it will be a trouble to change number of columns because of need to manually change arguments to large number of such functions. So, how can i pass all the arguments to a function using a loop? Something like
Code:
for(i=0;i<NUM;i++)
{
push_arg(args[i]);
}
call_function(func);
?
Of course, i could just use asm code for this, but is there a portable way of doing so?
P.S. i mean C language.
I have images in jpg format
Code:
CIMG0100.jpg
...
...
CIMG0131.jpg
I used imagemagick to convert the files to gif with the following command
Code:
for i in {100..131}; do convert CIMG0$i.jpg CIMG0$i.gif; done # works
This worked like expected, but when afterwards I wanted to scale the images
Code:
for i in {100..131}; do convert -scale 25% CIMG00$i.gif CIMG00$i_scaled.gif; done # works not it seems the system is working for about half a minute, but I get no output. The single command
Code:
convert -scale 25% CIMG100.gif CIMG100_scaled.gif # works
works as expected and gives me a scaled image. What does the convert command do in the second case? is the for-loop wrong?
I'm learning c but then when i tried looping as i follow a tutorial, the numbers are wierd that it seems not right..
This is the example.
Quote:
When i run it, it outputs this.
Quote:
why?