Trying to do a simple bash script, and having some issues. I am relatively new to bash, and did my best to search, but idk what exactly to search for.
Doesn't work code...
Can I pass javascript variables to bash script? If possible in bash script what code should I insert to receive javascript variables.
View 14 Replies View Relatedi am trying to write scripts to pass 2 different variables to find command.
find . -name $var1 -exec grep -H $var2
find . -name CDR_2010-07-21 -exec grep -H 9892614477 {} ;
1st variable CDR_2010-07-21(passed by var1) is the file name inside which i am trying to search string 9892614477(passed by var2). i have tried following script
[code]...
I'm using perl script from php. I wanted to pass parameters to perl script from php and also return value from perl script to php. I don't no how to do it.
View 14 Replies View RelatedI'm trying to write a bash script and I'm having trouble with it.I have a list of DNS entires from a file called zoneExport.txt.Than I want to parse a log file to see if that DNS entry has been queried for. So I'm running a grep command and trying to save it into a variable. What I'm looking for is a variable ($varGrepQ) that has the number of matches for the grep query. I will then run this through an if statement and do some things from there..
But my problem right now is with this grep query. It keeps outputting '0' even when I know there are records in that file and when I run the same query on the command line I get the actual count. My thought is that the $record variable is not passing right.
If I read in variables entered by the user, how can I check to make sure the correct number of variables were entered? For example, after reading in a data file and making it into an array, I have:echo "To check the data, enter the first element number, last element number and step size as x y z:"read x y z.It then goes on to start a loop, but what I would like now (before the loop) is a check to see if three variables have been entered, before the rest of the script continues.
I've tried specifying the variables as $1, $2 and $3, but if I echo $#, the value comes out as zero, so it's obviously not working.
I need to find the value of:
Code:
$Namenumber
My script asks for the name you want to look up and I want it to return the value of $Namenumber
I was thinking:
Code:
number=$"$name"number
but this returns
Code:
$Namenumber
but does not actually resolve what the variable $Namenumber is equal to.
My hosting server does not allow exec() or system() calls, for security reasons. I can call a cgi process in two ways. From a .shtml page, i can issue a directive like code...
View 11 Replies View RelatedIs there a way to count the number of errors- an exit variable $? from one function?
The output from the exit variable (either erroneous or correct (1) or (0)) is it possible to add the erroneous one ups?
I'm playing around with a bash script to pass files to a program (such as VLC). I thought something like this would work:
vlc $( ls | sed 's/ /\ /g' | tr '
' ' ' )
ls shows the files in the current directory, then sed changes spaces to " " (to escape them) and finally tr removes the line breaks. I end up changing:
01 - Music Track.mp3
02 - Another Track.mp3
to
01 - Music Track.mp3 02 - Another Track.mp3
"vlc 01 - Music Track.mp3 02 - Another Track.mp3" works if I type it manually but my script reports a problem with `-'
It seems it's not escaping the spaces.
I wrote a C++ program that uses two different parsers. The first parser is reading program arguments from command line:./mybin arg1 arg2 ...then during program execution there's an interactive prompt asking for more parameters:
...
>> (second bunch of arguments here)
...
I'd like to run my program inside a bash script, but I don't know how to give the second level arguments.
I'm trying to do a shell script which are suppose to run a program as a specific user at system boot up. The problem is that I don't know for sure how to make the script add the users password to the prompt when it's necessary.
Basically the program would be run like this:
sudo -u extrema program_name -r /srv/program_name -d
and in this example the password is, "hidden".
How would I make this script run this program as user extrema with the password "hidden" at boot-up? I know how to put the script in the rc.X directory and so on, its more the syntax of the code.
I have a problem with snmp answers being empty or having spaces.
What I already have:
#get all interface indexes (if you wonder - I'm working for a cable company and different cablemodems have different number and types of interfaces):
The problem is the physical address which is sometimes empty and the description which has spaces. So I'm doing 2 snmpgets which is slower than 1 snmpget (sometimes I have up to 18 interfaces).
I'm trying to explain it a bit simpler.
Interface 5 gives me back the following lines:
Ethernet CPE Interface
Now the first line should go into variable ifadm,
2nd line should go into variable ifoper,
3rd line should go into variable ifspeed,
4th line should go into variable iftype,
5th line (which is empty) should go into variable ifphys and finally
6th line (which has spaces) should go into variable ifdescr
I have a bash variable where the content looks like this where ;f1; and ;f2; are delimiters:
;f1;field1value1;f2;field2 value1 ;f1;field1value2;f2;field2 value2 ;f1;field1value3;f2;field2 value3
So what I need is to extract and put into variables each combination of f1 and f2 in a loop to something like that:
#first pass of the loop I need:
f1=field1value1
f2=field2 value1
#second pass of the loop I need:
f1=field1value2
f2=field2 value2
# third pass of the loop I need:
f1=field1value3
f2=field2 value3
mkvmerge -o <filename without extension>_TV.mkv -S <filename> && mkvextract tracks <filename> 3:<filename without extension>.*** && perl /home/brian/Desktop/ass2srt.pl <filename without extension>.*** && rm <filename without extension>.***
Doing these commands for multiple command line file inputs is the goal. So I can just type ./script.sh *.mkv in my terminal.This is what I have so far, but it doesn't work whatsoever.
I will have to code this. However I am lacking of time since I have too much to do. make a short code bash/dash to prompt the country with Zenity, then, get the PLS or m3u url and prompt with another zenity which radio to play. http://www.listenlive.eu/index.html
My code to get url's radio country.htm is:
Code:
I'm trying to use system to call echo and pass variables to it. That was a success. The problem is the variables inside the while-loop i wrote cannot be manipulated. what I'm doing wrong here? here's the code:
Code:
#include <iostream>
#include <stdlib.h>
#include <string>
#include <sstream>
[Code]....
I'm trying to write a bash script that helps me building C program then run the C program but I don't know how to make it run.I did like this
Code:
#!/bin/sh
# assuming I've built C program '$output' successfully
[code]....
I have for example the following IP addresses:
24.172.220.218
41.239.36.19
63.215.202.234
66.176.124.22
[code]....
How can I sort those IP addresses? I want to sort them using the first 3 numbers I also want to count the number of times that address is repeated This is a batch program.
We are trying to create a message forwarder program that receive a message on Port A and pass it on t Port B. Also receive a message from Port C and Pass it on to Port D as follows.
[Code]...
I'm trying to write a bash script program in the Linux command terminal that will write to a fellow user and then continue reading down the program. this is what i have (kind of explains the idea too):
#!/bin/sh
clear
echo "this is before the write command"
write jcummins
this message should go to jerry
echo "the message didn't send and this string will not appear"
echo "it appears it has stopped at the write command"
I am trying to write a bash script that installs a program fully automated for me. I am stuck at the one part where i need to change a line in one config file. I have tried various syntax for sed and none have worked. Maybe someone can suggest how to go about this. Since the line appears in the middle of the file, I can't use echo or cat. Also the file will be diffrent lengths depending on the install.
The line I need changed is:
I need that changed to:
the last syntax i tried is:
Yes this is for PNP4Nagios on centos 5.6 64bit. If i can get this figured out. I will be willing to post the whole thing for others to use. it will be used to install PNP after a working nagios install is done.
Everyone knows that it is like impossible to use mplayer to watch an *.html file. OK.
For instance here is a cool example of lot of streaming for firefox
http://watchtvlivestreaming.com/tvlive/b5499
Code...
Anyone is there a talented bright coder, coming from hell -because it is really difficult, to make such console program ?
I frequently use wget to download tarballs and zip files from the web, then either untar then or gunzip them. I do:
Is there a way for me to automatically pass the zip file to tar or unzip WHILE wget-ting?
In pseudocode: wget google.com/somfile.zip && unzip
How do I pass file names as parameters to the shell through a script? I have installed 'wipe' from the repos and it is a shell based app. so I made a shellscript and put it in my script folder.
the normal usage of wipe is 'wipe -q /path/to/file' so if I were to make a shell script, right click on the file in question, and run the script on it, how to I permit the shell to wipe that file only, in other words pass it as a parameter. I think on windows it was the use of %1, such as. 'wipe -q %1' for example, which was simple enough. how to I achieve this with bash?
I am not parsing on a webserver so is it possible to have both
#! /usr/bin/php &
#!/bin/bash
in the same script? Alternatively, I have a current bash script that I need to get some variables from mysql and not sure how to get mysql results in bash:
Quote:
mysql -h server.net -u username1 -paaa -e "USE squid; SELECT email, usern FROM TABLE WHERE blah blah;"
emailadd="resultfrom above"
usern="resultfromabove"
Is there a difference when variables are referred to as $variableName and ${variableName} in bash?
View 1 Replies View RelatedI have $db and $DATE set in my bash script, then I need to join them like this: mysqldump --user=usr --password=pss --databases $db | gzip > /backups/sqlNew/$db_$DATE.sql.gz;
Unfortunately, that doesn't work. How do I properly join those 2 variables into a filename?
I'm trying to write a bash script, and for some reason Bash doesn't seem to like any of my variables _except_ the one used in a loop.What's going on? The same problem with MYS occurs regardless of its name, whether it is declared or referenced before, after, or inside the loop, and whether it is a string, integer, or floating-point number. Also, as far as I can tell, everything related to Bash is up to date.
View 7 Replies View RelatedI am trying to use the following bash alias:
I've been able to get this working under mac and solaris.
I've also tried not escaping the vars.
Anyone know if this is doable with ubuntu's bash shell? (or any meaningful workaround other than writing a script for this?)