General :: Possible To Pass JavaScript Variables To Bash?
Apr 18, 2011Can I pass javascript variables to bash script? If possible in bash script what code should I insert to receive javascript variables.
View 14 RepliesCan I pass javascript variables to bash script? If possible in bash script what code should I insert to receive javascript variables.
View 14 RepliesTrying to do a simple bash script, and having some issues. I am relatively new to bash, and did my best to search, but idk what exactly to search for.
Doesn't work code...
mkvmerge -o <filename without extension>_TV.mkv -S <filename> && mkvextract tracks <filename> 3:<filename without extension>.*** && perl /home/brian/Desktop/ass2srt.pl <filename without extension>.*** && rm <filename without extension>.***
Doing these commands for multiple command line file inputs is the goal. So I can just type ./script.sh *.mkv in my terminal.This is what I have so far, but it doesn't work whatsoever.
I'm trying to use system to call echo and pass variables to it. That was a success. The problem is the variables inside the while-loop i wrote cannot be manipulated. what I'm doing wrong here? here's the code:
Code:
#include <iostream>
#include <stdlib.h>
#include <string>
#include <sstream>
[Code]....
Is there a difference when variables are referred to as $variableName and ${variableName} in bash?
View 1 Replies View RelatedI frequently use wget to download tarballs and zip files from the web, then either untar then or gunzip them. I do:
Is there a way for me to automatically pass the zip file to tar or unzip WHILE wget-ting?
In pseudocode: wget google.com/somfile.zip && unzip
i am trying to write scripts to pass 2 different variables to find command.
find . -name $var1 -exec grep -H $var2
find . -name CDR_2010-07-21 -exec grep -H 9892614477 {} ;
1st variable CDR_2010-07-21(passed by var1) is the file name inside which i am trying to search string 9892614477(passed by var2). i have tried following script
[code]...
I have $db and $DATE set in my bash script, then I need to join them like this: mysqldump --user=usr --password=pss --databases $db | gzip > /backups/sqlNew/$db_$DATE.sql.gz;
Unfortunately, that doesn't work. How do I properly join those 2 variables into a filename?
I have a problem with a very big script I wrote in bash, and now I need to modulirize it in at least four smaller scripts. The problem is, that most of the variables I have will need to be shared by all scripts.
My question is: is there a way to declare global variables in bash? So that I can use and change them in any of the scripts and every change in the variable can be "seen" by the other scripts later.
I've created a script that put in dynamic variables the value HELLO 1, HELLO 2 HELLO 5. And I put the values of this variables in the file text.txt. Here's the script:
Code:
for i in $(seq 1 5); do eval ${i}=$(cat << EOF "HELLO" $i EOF); done
cat > text.txt << EOF
$1
$2
[Code]...
I would like to run a bunch of SQL commands from mysql client in bash. However, I would like to store the output in different variables. E.g.
Code:
var1=`mysql -u[user] -p[pass] -D[dbname] -e "Query1"`
var2=`mysql -u[user] -p[pass] -D[dbname] -e "Query2"`
[code]...
How do I concatenate two environment variables in bash?
View 3 Replies View RelatedI've been writing a bunch of bash scripts to make possible non-interactive, secure, cron-based SVN checkouts with CollabNet's SVN client and GNOME Keyring Daemon (aka GKD) and one of the scripts was designed to start GKD, harvest its output, essentially a couple of environment variables, and export those variables in shell of a user the script is run as. All upon user login by sourcing a bash script in ~/.bashrc.The problem is that those environment variables will not be exported, because the script is being run in a sub-shell that exits upon it completion and environment variables get unset for good.Well, the question is how can those variables be set permanently, meaning they're exported and kept untouched even across login-logout sessions?
View 1 Replies View RelatedI am using Linux some years, but since I built a LFS, I feel noobish again. Now with the help of BLFS I am setting up my environment and somewhere I incidentally read, that not every variable is inherited by a child Bash shell. As for the $PS1 and $PS2 variables I know, that they are not inherited by non-interactive Bash shells (and there is no reason why they should in my opinion). Well, as for my first thread I hope the title gives enough information on what I want to know. But anyways: Which environment variables are not inherited by Bash shells?
View 1 Replies View RelatedFor example, if I'm in csh, I can use `setenv VARNAME varVALUE` while I can use export in Bash. Given that the environmental variables are created, can BASH read env vars from csh and vice versa?
View 2 Replies View RelatedI have a user that has been used for long time now that runs o C Shell... now there is a need to change it to Bash Shell? Can I cause a problem changing his shell from C to bash? I mean apps or variables?
View 2 Replies View RelatedI've written myself a linux program "program" that does something with a regular expression. I want to call the program in the bash shell and pass that regular expression as a command line argument to the program(there are also other command line arguments). A typical regular expression looks like "[abc]_[x|y]".Unfortunately the characters [, ], and | are special characters in bash. Thus, calling "program [abc]_[x|y] anotheragument" doesn't work. Is there a way to pass the expression by using some sort of escape characters or quotation marks etc.?
(Calling program "[abc]_[x|y] anotheragument" isn't working either, because it interprets the two arguments as one.)
I've written myself a linux program "program" that does something with a regular expression. I want to call the program in the bash shell and pass that regular expression as a command line argument to the program (there are also other command line arguments). A typical regular expression looks like "[abc]_[x|y]". Unfortunately the characters [, ], and | are special characters in bash. Thus, calling "program [abc]_[x|y] anotheragument" doesn't work. Is there a way to pass the expression by using some sort of escape characters or quotation marks etc.? (Calling program "[abc]_[x|y] anotheragument" isn't working either, because it interprets the two arguments as one.)
View 8 Replies View RelatedI have made a simple bash script through which i can add, del, edit user from certain file using different CASE variables. like
case
1. adduser
2. del user
3. edit user
Now i want to add a exit CASE like
1. adduser
2. del user
3. edit user
4. exit
Now i want to make a script such a way that, if user input is 4 then only script quit. I used with exit function also but it didn't work. if user press ENTER or other keys then also it quit the program.
First, i have no experience with javascript. I came across an interesting site and I'm curious if I could make a private webpage to call some shell commands or just open a terminal.Yes, i know this could potentially be malicious and possibly illegal. Again it's for my own private usage.
View 1 Replies View RelatedI'm using perl script from php. I wanted to pass parameters to perl script from php and also return value from perl script to php. I don't no how to do it.
View 14 Replies View RelatedHow do I pass file names as parameters to the shell through a script? I have installed 'wipe' from the repos and it is a shell based app. so I made a shellscript and put it in my script folder.
the normal usage of wipe is 'wipe -q /path/to/file' so if I were to make a shell script, right click on the file in question, and run the script on it, how to I permit the shell to wipe that file only, in other words pass it as a parameter. I think on windows it was the use of %1, such as. 'wipe -q %1' for example, which was simple enough. how to I achieve this with bash?
I am not parsing on a webserver so is it possible to have both
#! /usr/bin/php &
#!/bin/bash
in the same script? Alternatively, I have a current bash script that I need to get some variables from mysql and not sure how to get mysql results in bash:
Quote:
mysql -h server.net -u username1 -paaa -e "USE squid; SELECT email, usern FROM TABLE WHERE blah blah;"
emailadd="resultfrom above"
usern="resultfromabove"
I'm trying to write a bash script, and for some reason Bash doesn't seem to like any of my variables _except_ the one used in a loop.What's going on? The same problem with MYS occurs regardless of its name, whether it is declared or referenced before, after, or inside the loop, and whether it is a string, integer, or floating-point number. Also, as far as I can tell, everything related to Bash is up to date.
View 7 Replies View RelatedI am trying to use the following bash alias:
I've been able to get this working under mac and solaris.
I've also tried not escaping the vars.
Anyone know if this is doable with ubuntu's bash shell? (or any meaningful workaround other than writing a script for this?)
I'm trying to write a bash script and I'm having trouble with it.I have a list of DNS entires from a file called zoneExport.txt.Than I want to parse a log file to see if that DNS entry has been queried for. So I'm running a grep command and trying to save it into a variable. What I'm looking for is a variable ($varGrepQ) that has the number of matches for the grep query. I will then run this through an if statement and do some things from there..
But my problem right now is with this grep query. It keeps outputting '0' even when I know there are records in that file and when I run the same query on the command line I get the actual count. My thought is that the $record variable is not passing right.
If I read in variables entered by the user, how can I check to make sure the correct number of variables were entered? For example, after reading in a data file and making it into an array, I have:echo "To check the data, enter the first element number, last element number and step size as x y z:"read x y z.It then goes on to start a loop, but what I would like now (before the loop) is a check to see if three variables have been entered, before the rest of the script continues.
I've tried specifying the variables as $1, $2 and $3, but if I echo $#, the value comes out as zero, so it's obviously not working.
Are there numerical variables (like type int in C) in the shell script language of bash? Say I want a counter to increment each time a loop is traversed.
View 1 Replies View RelatedI need to find the value of:
Code:
$Namenumber
My script asks for the name you want to look up and I want it to return the value of $Namenumber
I was thinking:
Code:
number=$"$name"number
but this returns
Code:
$Namenumber
but does not actually resolve what the variable $Namenumber is equal to.
I wrote a C++ program that uses two different parsers. The first parser is reading program arguments from command line:./mybin arg1 arg2 ...then during program execution there's an interactive prompt asking for more parameters:
...
>> (second bunch of arguments here)
...
I'd like to run my program inside a bash script, but I don't know how to give the second level arguments.