Bash 3.1.7
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I think read A1 A2 makes A1, A2 string variables. Then, when A2 gets the value 01, '01' should be a string. But for some reason bash takes it as numeric. I know there are no types in bash.
I have a program that loops over each word in a sentence. I need to append a constant to the beginning and end of each word. It works up until the last word on the line.
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Output:
Here is the code:
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How ever when I run this script I get the following error
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I just don't get it, I have racked my brain trying to figure out every combination of how I should write this if statement and I can't get it to work.
how do i ask in a query for any numeric or string field? It may not have any meaning, but i need it to fill a toplink DataReadQuery in java....Something like " select * from table where table.fieldA='?'
View 2 Replies View RelatedI need to check whether a shell script variable contains non-zero numeric data to proceed. The variable should contain numeric values, but may in fact contain zeroes, blank space or nothing. So far, I have tried various combinations of:
Code:
if test $variable
then
if test $variable -gt 0
then
echo "good data exists"
else "no good data exists"
fi
fi
It partially works, but I get either "too many arguments" or "integer expression expected".
my script has a variable which comes in the form +00.00 +0.00 -00.00 or -0.00 (the numbers can be any in that form) for any that have a + symbol I need to remove the +, but if it has a - symbol it needs to stay.
i need to make a new variable with the string from the old variable btut without any plus sign. I have tried a lot of different ways with no success, each thing I tried either left the + or removed the entire string. I think this should work but doesn't
foo=+12.40
bar=${foo#+}
I do this:
Code:
a@b:~$ export A=hi
a@b:~$ echo $A
hi
a@b:~$ bash -c "export A=blah; echo $A"
hi
a@b:~$
Why doesn't the bash command print the new value of $A? Is there a way to make it do so?
I have a file (.tmpfile) and inside it is a string which i only know part of, the rest being a random group of characters... I would like to know how to pull the whole string out of the file and into a variable.
View 13 Replies View Related(variable substitution?)
(parameter expansion?)
Code:
run_repeatedly()
{
NUM=0
while [ <irrelevant stuff here> ]
[Code]....
run_repeatedly "programX -o "./messy/path/output-$NUM.txt"" The echo inside the loop prints "...-$NUM.txt"; obviously I'm aiming to have bash substitute the iteration number so that I end up with many output files not 1.
I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
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Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
I want my bash file to read from "input.dat" the two values emin emax. My input file looks like that:
#cat input.dat
!Energies
emin 10.00 !minimum energy
emax 30.00 !maximum energy
Now this seems to be not so hard with the command awk
#!/bin/bash
awk '{FS=" "}/emin/{print $2}' input.dat
awk '{FS=" "}/emax/{print $2}' input.dat
[code]....
So far so good. Now, I want to define two variables (e.g. e1,e2) in the bash file, so that their values would correspond to 00.00 and 30.00, as read from the input file. This one I have not found yet, thus asking for your advice. At the end, writing echo $e1 $e2, I should get 10.00 30.00 This is even harder to me: I want to replace the values emin,emax in a new file "modify.dat" which looks like that:
...
c---- energy interval
emin = 1.00
emax = 2.00
...
with the values e1 and e2 I have in my bash file. In other words, I want to call "modify.dat", find these two lines and replace the numeric values with the e1 and e2. At the end, my file should be like:
...
c---- energy interval
emin = 10.00
emax = 30.00
...
How to change string variable in awk? for example, I parse with awk script text file named some_name_with_extension.txt
I want to print only some_name in my script
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....
varCompName = FILENAME
print varCompName
How to put not all symbols from FILENAME to variable?
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I'm trying to pass a path as a string to an array, but its evaluating it as a command instead. I want to take the literal string "/mnt/accounts/user/temp/*.jpg" and assign it to an array{1}, but when i echo the array variable, it displays it as
pic1.jpg
pic2.jpg
pic3.jpg
[code]....
I just want it to be the actual text "/mnt/accounts/user/temp/*.jpg" which i will be combining with other text to create a longer path elsewhere in the code.
The script produces 2 empty lines and I don't know why.
View 1 Replies View RelatedI have a config file that contains:
my.config:
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Now in my bash script, I want to get the output /home/user instead of $HOME once read. So far, I have managed to get the $HOME variable but I can't get it to echo the variable. All I get is the output $HOME.
Here is my parse_cmd script:
Code:
I want to append a variable string to the end of a specific line. not like append the same string to each line. like in my file i have 4 columns, i want to add a string in 5th column in some fixed row.
View 4 Replies View Relatedhow do you include a string variable as part of a regex in Perl?
View 5 Replies View RelatedI have beat this enough and don't get what should have been a very simple thing to do. I build a variable;
Code:
CLIST=java,lua,python,php,perl,ruby,tcl
CLIST will be used by another bash script but I need to replace the commas with a space. I
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I have a text file with content that look like this..
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1,3927,"AIS"
1,6928,"AIS"
[code]...
Just a simple BASH for loop to read the file path from a text file (clean.txt) echo the variable for debug purposes, and scp it to a server I have using port 50 for SSH.
I've already formatted the entries in clean.txt to handle spaces correctly, using sed replacement.
Example from the clean.txt file:
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/MP3/NAS000000001/Barenaked Ladies/Barenaked Ladies - Barenaked For The Holidays/20 Auld Lang Syne.mp3
/MP3/NAS000000001/Barenaked Ladies/Barenaked Ladies - Barenaked For The Holidays/14 Deck the Stills.mp3
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I want to write a c program with some shell scripts.Now For a simple C program. I am Setting a variable called val2 in bash, now I want to use bash variable val2 in C code. How do I do that?The above doesn't work (coz its spawning a different memory space and when shell script ends the variable dies with it as per my research but how do I keep them in same memory space)Also Is there any Good reference where they teach how to integrate C and Bash Together?
View 5 Replies View Relatedi've just started to learn about functions in Bash scripting. I'm able to set the functions and execute the commands correctly. However, if my_var is set in the first function and then later in the script in the script the 2nd function is called, it doesn't seem to remember my_var and quits (at least i suspect this is the problem).
Here's my code (it requires yad available via webupd8. org). My specific problem seems to lay in line #27 where if we view the changelog and then exit that window, it returns to the "main" function but any subsequent commands cause a crash. Is this because of the get command on line #29? It's presumably now out of scope after calling menu on line #25?
I have a file with around 1000 IP addresses in it and I need to be able to ssh into each one of them, run a single command, and then exit. I already know the ssh command I want to run and it looks like this:
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shpass -p [password] ssh -p 10022 -o StrictHostKeyChecking=no root@[ip variable] 'reboot'
(I know shpass is not good to use and keys are the correct way but I don't have any other options in this scenario.) if these ip addresses were in a .csv file, by themselves with no other information, how would I create a script to do the above command to each ip until the end of the file?
I cannot for the life of me get this little (simple) script I wrote to work. Here is the entire script:
Code:
#!/bin/bash
ASPECT=`mediainfo $1 |grep "Display aspect ratio" |cut -d : -f 2`
HEIGHT=`echo "320 / $ASPECT" |bc`
SIZE=`echo 320x$HEIGHT`
[code]......
An input filename ($1) is fed into mediainfo, which by the use of grep and cut spits out a single number which is the aspect ratio. This is then divided by bc into 320, which gives the desired height dimension for the file that I want ffmpeg to create for me. Finally, ffmpeg runs using the calculated dimensions... Basically, it's the passing of the $ASPECT variable to bc that seems to fail. It looks like bc won't read the output from the mediainfo line... It always crashes out with:
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(standard_in) 1: illegal character: ^M I've tried doing something even simpler like this to debug by just trying it to display the calculation on the screen:
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#!/bin/bash
ASPECT=`mediainfo $1 |grep "Display aspect ratio" |cut -d : -f 2`
HEIGHT=`echo "320 / $ASPECT" |bc`
echo $HEIGHT
and it does the same, so it's definitely bc that won't accept the output from mediainfo.
I am killing myself with this, please someone come to the rescue...
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#!/bin/sh
IFILE=$@
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I am using gnu bash 3.2I need to split the string into array like
a=this_is_whole_world.file # split [_.]
I need to split this on _ and . some thing like this
a[0]=this
a[1]=is
a[2]=whole
a[3]=world
a[4]=file
preferable using bash regex. if not sed is also ok.
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g echo ${mm[$j]}
4 BashNotes
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I am trying to remove everything before my string code...
View 9 Replies View RelatedI have the following function that does not iterate through the array I want to be able to do some manipulation on each element in the array[@].it appears the below array has only one item in the array whereas i want the array to have 3 items hence the loop three times printing the message Any ideas why this is not happening ?
function foo() {
name =$1
array=( "$2" )
[code]...
I was wondering if possible in bash for a variable to take the value of a function, I mean the function returns a value and a variable will take it. example:
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