For example, if I'm in csh, I can use `setenv VARNAME varVALUE` while I can use export in Bash. Given that the environmental variables are created, can BASH read env vars from csh and vice versa?
View 2 RepliesI am using Linux some years, but since I built a LFS, I feel noobish again. Now with the help of BLFS I am setting up my environment and somewhere I incidentally read, that not every variable is inherited by a child Bash shell. As for the $PS1 and $PS2 variables I know, that they are not inherited by non-interactive Bash shells (and there is no reason why they should in my opinion). Well, as for my first thread I hope the title gives enough information on what I want to know. But anyways: Which environment variables are not inherited by Bash shells?
View 1 Replies View RelatedMy question has to do with how environmental variables are passed from parent to child processes at the BASH SOURCE CODE level. I have a need to add an environmental variable that has the complete invocation line so that the child process can see it via ENVP.I have been studying the source for a quite a while and can't seem to find how to make the variable pass to the child. In EXECUTE_CMD.c I found a good place to set the variable: I made a routine similar to PUT_COMMAND_NAME_INTO_ENV called PUT_COMMAND_LINE_INTO_ENV which would add "?=THE FULL INVOCATION LINE" as an environmental variable but it doesn't make it to the child. (I've tried names other than '?' but they don't work either.
I'm thinking that there is either a LIST or a attribute associated with those environmental variables that should be passed to the child but I can't find it.
I installed Java on a server and anytime I have to start or stop a service that requires the $JAVA_HOME variable I have to manually set it with the export command such as: Code: export JAVA_HOME=/usr/java-jdk1.6.0_21 How can I permanently set this variable?
View 3 Replies View RelatedI have installed ubuntu10.04 LTS in VirtualBox in my home computer(i forgot to tell you i am very new to linux-though i am studying a lot, but....-maybe because of my age "45" i am going slow. LOL. I hope i dont have a heart attack before i finish what i am trying to do in the server). Back to my issue: What i want is to have in the server some enviromental variables running not only for the root user but for all the users,when the server is open and not having to type the following commands every single time i open the terminal. Here are the commands:
export JAVA_HOME=/opt/java
export PATH=$JAVA_HOME/bin:$PATH
export M2_HOME=/opt/maven/maven
export PATH=$M2_HOME/bin:$PATH
[code]....
(where java, maven, tomcat are symbolic links for java jdk, maven and apache-tomcat 5.5.31). Please (LOL) save me from the heart attack, give me the chance to enjoy the holidays with my family!
I am new in Using Ubuntu, I need to set up environmental variables in Ubuntu, I do the following:
Code:
export JAVA_HOME=/path/to/Java
export PATH=$JAVA_HOME:$PATH
it work fine, but every time I restart the system I have to reset it again Is that the right way to it, or I do something wrong
I am trying to figure out where variables are set for interactive shells? In particular, I am trying to have LS_OPTIONS inherited by interactive shells as it is by login shells. I understand LS_OPTIONS is set in /etc/profile, and this may not be processed by interactive shells but by login shells. However, I also note other variables such as PATH and INPUTRC are set correctly in interactive shells, and these are also set in /etc/profile from what I understand. So how is it determined which variables are inherited by all shells, and which are just for login shells?
View 16 Replies View RelatedI do this:
Code:
a@b:~$ export A=hi
a@b:~$ echo $A
hi
a@b:~$ bash -c "export A=blah; echo $A"
hi
a@b:~$
Why doesn't the bash command print the new value of $A? Is there a way to make it do so?
mkvmerge -o <filename without extension>_TV.mkv -S <filename> && mkvextract tracks <filename> 3:<filename without extension>.*** && perl /home/brian/Desktop/ass2srt.pl <filename without extension>.*** && rm <filename without extension>.***
Doing these commands for multiple command line file inputs is the goal. So I can just type ./script.sh *.mkv in my terminal.This is what I have so far, but it doesn't work whatsoever.
Let's say that I have a customized Bash prompt stored as a PS1 variable. My variable gets read every time I invoke a login shell, i.e., when logging in in one of the standard virtual terminal or by invoking xterm with the -ls parameter.
However, when I just invoke the terminal without specifying that it is a login shell, I just get something like: bash-XXX$ as a prompt.
where should I place my PS1 variable so that it could get read even on non-login shells?
Is there a difference when variables are referred to as $variableName and ${variableName} in bash?
View 1 Replies View RelatedI have $db and $DATE set in my bash script, then I need to join them like this: mysqldump --user=usr --password=pss --databases $db | gzip > /backups/sqlNew/$db_$DATE.sql.gz;
Unfortunately, that doesn't work. How do I properly join those 2 variables into a filename?
I have a problem with a very big script I wrote in bash, and now I need to modulirize it in at least four smaller scripts. The problem is, that most of the variables I have will need to be shared by all scripts.
My question is: is there a way to declare global variables in bash? So that I can use and change them in any of the scripts and every change in the variable can be "seen" by the other scripts later.
I've created a script that put in dynamic variables the value HELLO 1, HELLO 2 HELLO 5. And I put the values of this variables in the file text.txt. Here's the script:
Code:
for i in $(seq 1 5); do eval ${i}=$(cat << EOF "HELLO" $i EOF); done
cat > text.txt << EOF
$1
$2
[Code]...
Can I pass javascript variables to bash script? If possible in bash script what code should I insert to receive javascript variables.
View 14 Replies View RelatedI would like to run a bunch of SQL commands from mysql client in bash. However, I would like to store the output in different variables. E.g.
Code:
var1=`mysql -u[user] -p[pass] -D[dbname] -e "Query1"`
var2=`mysql -u[user] -p[pass] -D[dbname] -e "Query2"`
[code]...
How do I concatenate two environment variables in bash?
View 3 Replies View RelatedI've been writing a bunch of bash scripts to make possible non-interactive, secure, cron-based SVN checkouts with CollabNet's SVN client and GNOME Keyring Daemon (aka GKD) and one of the scripts was designed to start GKD, harvest its output, essentially a couple of environment variables, and export those variables in shell of a user the script is run as. All upon user login by sourcing a bash script in ~/.bashrc.The problem is that those environment variables will not be exported, because the script is being run in a sub-shell that exits upon it completion and environment variables get unset for good.Well, the question is how can those variables be set permanently, meaning they're exported and kept untouched even across login-logout sessions?
View 1 Replies View RelatedI have a user that has been used for long time now that runs o C Shell... now there is a need to change it to Bash Shell? Can I cause a problem changing his shell from C to bash? I mean apps or variables?
View 2 Replies View RelatedI have made a simple bash script through which i can add, del, edit user from certain file using different CASE variables. like
case
1. adduser
2. del user
3. edit user
Now i want to add a exit CASE like
1. adduser
2. del user
3. edit user
4. exit
Now i want to make a script such a way that, if user input is 4 then only script quit. I used with exit function also but it didn't work. if user press ENTER or other keys then also it quit the program.
I need a bash script that can read from a MySQL database field and insert the read information into a variable. I need it to read from a field in the database which will list if somone is using Linux or Windows. Once its done that the code will continue as follows:
Code:
if [ "$var" = "linux" ] ; then
OTHER CODE HERE
else
[code]....
simple bash code:
Code:
#!/bin/bash
trap "echo 'you got me'" SIGINT SIGTERM # to trap ctrl+c
echo "Press ctrl+c during 5 sec loop"
for ((i=0;i<5;i++)); do
[Code]...
How come code behaves normally and stops when ctrl+c signal is caught and resumes, but after I use at least one timeout read in the code it looks like, if signal is caught again it doesn't pause the execution but skips the loop. If you remove -t (timeout) option from the read, both loops look the same!
I'm trying to write a bash script, and for some reason Bash doesn't seem to like any of my variables _except_ the one used in a loop.What's going on? The same problem with MYS occurs regardless of its name, whether it is declared or referenced before, after, or inside the loop, and whether it is a string, integer, or floating-point number. Also, as far as I can tell, everything related to Bash is up to date.
View 7 Replies View RelatedI am trying to use the following bash alias:
I've been able to get this working under mac and solaris.
I've also tried not escaping the vars.
Anyone know if this is doable with ubuntu's bash shell? (or any meaningful workaround other than writing a script for this?)
I'm trying to write a bash script and I'm having trouble with it.I have a list of DNS entires from a file called zoneExport.txt.Than I want to parse a log file to see if that DNS entry has been queried for. So I'm running a grep command and trying to save it into a variable. What I'm looking for is a variable ($varGrepQ) that has the number of matches for the grep query. I will then run this through an if statement and do some things from there..
But my problem right now is with this grep query. It keeps outputting '0' even when I know there are records in that file and when I run the same query on the command line I get the actual count. My thought is that the $record variable is not passing right.
If I read in variables entered by the user, how can I check to make sure the correct number of variables were entered? For example, after reading in a data file and making it into an array, I have:echo "To check the data, enter the first element number, last element number and step size as x y z:"read x y z.It then goes on to start a loop, but what I would like now (before the loop) is a check to see if three variables have been entered, before the rest of the script continues.
I've tried specifying the variables as $1, $2 and $3, but if I echo $#, the value comes out as zero, so it's obviously not working.
Are there numerical variables (like type int in C) in the shell script language of bash? Say I want a counter to increment each time a loop is traversed.
View 1 Replies View RelatedI need to find the value of:
Code:
$Namenumber
My script asks for the name you want to look up and I want it to return the value of $Namenumber
I was thinking:
Code:
number=$"$name"number
but this returns
Code:
$Namenumber
but does not actually resolve what the variable $Namenumber is equal to.
I have many files with name in order of number. e.g)
u0101.asc
u0102.asc
u0103.asc
[code]...
I am trying to read file using for loop.
for ((date=01; date<=31; date++))
do
echo ${date}
done
but '01' is read(print) as '1' How can I make it read from '1' to '01'?
I am trying to create scripts to move files over from one directory to an ftp server and there is this one file with spaces that bash is see each word as being a file, here is the variable i am trying to use:
Code: Select allLOCL = '/mnt/cifs/"File name with spaces"/'
cd $LOCL
ls -l