After hours (literally) of searching the web and reading man pages, I think I've come up with the following:Code:find . -exec grep 'path/to/file' -print | xargs -0 -I new_path mv {this is where I get confused}So my code above is incomplete, obviously. In order to finish replacing the string, I need to mv the new file into the old file's spot. How do I do this, by incorporating it into my line of code?
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I am trying to replace a string (url) in 100s of files located in different directories. I found the sed command but cannoy get it to work. First I locate the files that have the string in them:
Code:
grep -ilr 'url' *
this works correctly and displayed the location of the files that have the string:
Code:
1/index.php
2/index.php
Now I need to replace the string so I combined it with sed:
[Code]...
Need to replace the following string :
By
In multiple .exp files and in sub directories.
Find and replace in multiple files in ssh?
View 1 Replies View RelatedBelow is extract of my file:
What I need is to replace "--destination-path=" with "--destination-path=/home/dest"
i.e. desired output is ----destination-path=/home/dest
I could achieve it with below command
$cat outgoing-xfer|grep destination-path|perl -pi -e "s/destination-path=/destination-path=/home/dest/g"
But the problem is that in this case i just wanted to append "/home/dest" for which I could easily escape "/" with just two "", but I wonder if i have a long path like "/a/b/c/d/e/f/g/h/i/j" I will have to escape so many /. Is there any other way by which I can avoid escaping forward slash.
I tried following:
But receiving follo error
Bareword found where operator expected at -e line 1, near "s/destination-path=/'destination-path=/home"
syntax error at -e line 1, near "s/destination-path=/'destination-path=/home"
Bad name after dest' at -e line 1. tried with enclosing in double quotes as well but in vain
I need to find this "TYPE=MyISAM;" and replace with "ENGINE=MyISAM;" in all .sql files in a directory. How can I do this with sed?
View 2 Replies View RelatedI'm pretty sure this is doable from the command line, but my CLI skills have degraded a lot since my pre-Y2K admin days. The goal is to search all the files in the directory for a very long string of text and replace it with another string of text. The text being searched for is my Google Adsense code (which will be stripped from my website) and it will be replaced with a placeholder so I can easily tack something else in there in the future.
Seeing how I have that long snip of code on about 100 pages, automating the process would make life easier.
If I was searching for a single word, I can see ways to do this.
If I paste the code I'm searching for into a text file, is there a way to:
find (contents of oldstring.txt) and replace with (contents of newstring.txt)?
Moving right along, I have a folder of MP3 files containing various Movie sound tracks and scores. I'm using Audio Tag Tool to tag all the files at once with an "Artist" of "Soundtrack", and to inherit the "Title" tag from the file name. After that, I will rename all the files (Using Audio Tag Tool -- awesome program, btw) with the format "<Artist> - <Title>.mp3"
The problem, is many of my files already contain the string "Soundtrack", which would be redundant. I happen to be a perfectionist, so I'm unable to ignore it and move on. Hence my question to you fine folk: I want to delete all instances of "soundtrack" (-i case irrelevant) in the filenames before I go through the above steps. But, its not quite that simple. This is a sample of some of the file names:
[Code]....
Hello, I need some help searching through multiple files, finding a line and replacing that line. The line I am searching for is:
password key ******* 1222554
ultimately I want to be able to delete the numbers after the asterisks . my thoughts are to create a script that will search for the line password key ******* and delete it then replace it with password key ******* my files are located in /opt and they are all txt files.
I want to replace a string of directory path in a string to empty:
Code:
But this doesnt seem to give me the desired thing:
Code:
This gives the desired outcome, but its specific, i need a variable in the sed not a string. And if I replace STRING="/mnt/sda1/record/$dd/" then I cant use it for something else, cause its has all the weird backslashes now.
I have the following problem:
CASE_FOLDER
----------->0_FOLDER
-------------------->ForceX ForceY ForceZ
[code]...
I wanted to find and replace a string from a perl file. I have written a script in bash which runs the following command.
perl -pi -e "s/$findstring/$replacestring/" testfile
where as $findstring = print F_WC_TMP"$line
";
and $replaceString = $line = join ' ', split ' ', $line; print F_WC_TMP"$line
";
But when I am running the above command, i think it is replacing the $findstring with the above mentioned string and hence it contains a $line, it is looking for the variable $line and not finding the exact string. I am confused about how to search for a string that contains $ in it and replace it with another $string.
I often use the rpl command to make changes to multiple html files at once. For example:
rpl -R '<br />' '<br /><br />' mydirectory However, I haven't been able to figure out how to change multiple lines. For example, let's say I want to change all occurrences of :
<br />
<br />
to:
<br />
I've tried
rpl -R '<br />
<br />' '<br />' mydirectory
but that didn't work. how to do this with rpl or some other way?
I have a many directories each with about 20 html files inside. All the files have .html ext. What I'm hoping is possible is from command line to find some text in each one and replace it with some other text.
Basically what I want to replace is;
/awstats/
with
awstats/
I can do this easily with dreamweaver or some other application but because I have 960 pages total to do I'm hoping to do it this way.
I used a command Code:
grep -r err_sys ./
its output is
Code:
./tcpclitime.c:err_sys("socket error");
./tcpclitime.c:err_sys("connect error");
./tcpclitime.c:err_sys("write error");
./tcpclitime.c:err_sys("shutdown error");
./tcpclitime.c:err_sys("read error, n = %d", n);
[Code].....
Is it possible some how to replace all the occurrences of word err_sys by printf.
I am new to linux as well as awk, grep or sed. I need a find and replace command single liner or script that loops trough input file (file1) and find the particular input in file2 and add "!" in front of the found string.
Example:
input file: file1
g+h=o+p
a+b=c+d
file2 (file that need to look for)
a+b=c+d1e105
x+y=z+s5e105
g+h=o+pabcdefg
t+r=w+qxvyderf
Output file (file3 should look like this)
!a+b=c+d1e105
x+y=z+s5e105
!g+h=o+pabcdefg
t+r=w+qxvyderf
I have tried many awk and sed method of find and replce but it did not work the way I wanted. This is mainly due to my lack of experience in awk and sed. The program should loop trough file1 and find in file2 and output in file3 for the 1st (g+h=o+p) set then repeat the same process again for set 2 (a+b=c+d).
Assumed y directory structure looks as follow:
Code:
--root
-- dir1
-- dir1-1
[code]....
And under each sub dir there are some log files ended with .log. Now I know how to list all these log files with:
Code:
find . -type f -name "*.log"
Assumed now there is a string called "Hello World" inside some of these files. How can I find out these files? I try followings but failed
Code:
grep "This is" | find . -mtime 0 -type f -name "*.log"
i use this script to get the time and date of back and fourth transactions for a particular execution id. I use a substr command on the 5th column to to cut the milli seconds off the time value. - otherwise the times would look like 08:30:04.235
grep <executionID> <auditfile> | awk '{ print $1, $2, $3, $4, substr($5,1,8}
FIX -> Mon 3/1/2010 08:30:04
FIX <- Mon 3/1/2010 08:32:36
FIX <- Mon 3/1/2010 08:35:08
[code].....
anyhow - i append two sed commands to further clarify the direction of the message.
awk '{ print $1, $2, $3, $4, substr($5,1,8} | sed -e 's/->/ ->IN/g' | sed -e 's/<-/<-OUT/g'
FIX -> IN Mon 3/1/2010 08:30:04
FIX <- OUT Mon 3/1/2010 08:32:36
[code]....
I tried using an awk gsub () command within the string instead of the two seds, but it did not work:
awk '{ print gsub(/<regex>/, <replace with>,$1), $2, $3, $4, substr($5,1,8}
the sed works ok, but it would be cooler to make the replacement within the awk command:
gsub(/->/,-> IN, $1)
Is there a way where i could replace the value of the $1 column in the awk print string?
I have a file with the following in it:
:0 local /usr/X11R6/bin/X -nobanner
:1 local /usr/X11R6/bin/X
I need to add "-nolisten tcp" to both of these lines and cannot figure out how to do it. I can get it to do the first one, but not the 2nd and so on. How do I search the file and loop though it to change them all?
I am looking for Windows Search equivalent looking for file name patterns (not file contents but file names)....
I am aware of "globbing" and wildcard recursive search functionality in ls but I am still not capable of finding files under directories.
for example: I want to find all files starting with a string lsnr* under root directory / and any sub-directories.....
ie I want to look for files like lsnr*.* anywhere under / and any sub-directories under / such as /dir1/dir2/dir4 and dir1/other/dir/someotherdir/sub-dir etc.
so if I have /dir1/lsnrcontrol and also have /dir1/dir/2/dir3/lsnr-tinit.dat then I want to list the files names etc.
how to do this using ls -R and wildcards.
I have a line in a text file that has 40 random characters within a tag and i want to change the characters to a new set of 40 random characters (alphanumeric a-z 0-9 etc)
The line in the text file looks like this:
Quote:
How would i go about doing that?
Also second question same as the above but how would i remove them instead of replacing them?
I need to replace ":" from multiple files names, since I am going to copy those files from a linux partition, which admit the ":" to a FAT32 partition, which does not.
Example:
original name: eg06_ana_21-05-06_09:21:03.JPG
wished name: eg06_ana_21-05-06_09-21-03.JPG
I have googled a lot but I have not been able to adapt the examples given by people to my aim.
It seems that rename command is what I should use, but I have no idea to build the correct pearl expression.
I have script that I'm working on that updates a username in all the files that are called blah.inc for my framework. since i host a bunch of these web apps i need to do it to all of them. so I need to figure out how to update these files automagically with out me watching it to call vim every time. heres what I have so far
Code:
This finds the files but now i need to figure out how to do s/bob/fred/g on those files.
If I have a word in a text file and I need to replace it by another word (for example, i need to replace abc by fff) so what is the command I can type it?
I am using vi editor.
I have a set of lines as ahown below:
Leon went to school
Leon came back from school..
Leon had dinner...
I have to replace the line containing "dinner" by a single string LUNCH...
I want to change some HTML in my files (80+ so I prefer not to do this by hand). I got a script to replace a string in files, however the HTML I want to replace contains an enter (and tab of 4 spaces) (explanation below) Does someone know how I could update my HTML by using a function in Linux?
I also found sed but don't know how to use it with the enter (linenumbers will not work because they variate)...
[Code].....
I'd like a sed command to replace all decimal values greater than 0.5 with nothing in a tab delimited text file.
EX:
There would be one tab before 0.301 and two tabs after it. This way when you paste the text into an excel spreadsheet, there are empty cells where you deleted values.
I thought the sed command would be something like:
But this will delete everything.
What I need is something that will start deleting when it sees 0.[5-9] and stop when it reaches a tab. I know you can use [^character]+ to do this, but it doesn't seem to work with a TAB as the character.
Another idea I had would be to have sed replace from 0.[5-9] to 0. and replace with a tab + 0. But I also cant get [^0.]+ to work as it only works with single characters.
I found this command that works great finding and replacing a simple string to another in files located in that folder and all sub-folders.
Code: find . -name '*.php' | xargs perl -pi -e 's/OldText/NewText/g'
The problem I have is that I need to replace a more complex string, like this: Old string: /mnt/stor6-wc2-dfw1/627896/982574/ New string: /mnt/stor8-wc2-dfw1/369587/302589/ There I don't know how to do it... since the / is what separates the old from the new strings, and the strings that I want to replace have / in it. Also, I would like to know how to specify under what folder replace the files, for example, I want that it search/replaces all files under /var/www/mysite/htdocs folder.
I want to replace a string "something1" to "something2" in some files in a directory. the files are:
a
a.raw
a.sd
b
[Code]....
but I don't know how can I tell him to open extensionless files (for example a, b and c) only. I don't want 'sed' to open .raw and .sd files.
I would like to find all the files that contains the strings I'm searching.
For example (it's just an example), I would like to search all the files in "/etc" that contains "eth0" and "us", whatever where are located those 2 strings, the important is that the 2 strings are in the files listed.
It would be something like a "grep -lr 'eth0' *" and "grep -lr 'us' *" but in one time/command, so that I don't have to make a comparison of the 2 list of files resulting from the 2 "grep" commands given higher.
