General :: Parsing File With Multiple Delimiters?

I am using nessus to scan systems, and it generates the report file without any specific delimiter. Shown below is how a typical line in the file reads (It might show up as a very long line.

Code:

xx.xx.xx.xx|cpq-wbem (2301/tcp)|49272|REPORT|Synopsis :;;The remote web server is affected by multiple vulnerabilities.;;Description :;;According to its self-reported version number, the HP System;Management Homepage install on the remote host is earlier than 6.2. ;Such versions are reportedly affected by the following ;vulnerabilities :;; - Session renegotiations are not handled properly, which; could be exploited to insert

[code]....

The field of interest (for me) are IP ADDRESS, Synopsys, Description, Solution and Risk Factor. I tried the following command to parse this:

Code:

sed s/:;;/|/g report.nsr | grep Risk Factor |High | awk 'BEGIN {FS = "[:][;][;]"} {printf("%s|%s|%s|%s",$1, $6, $7, $10)}'

But this would not give desired results as ':;;' is not a standard delimiter and hence gives incorrect results. how to grab everything that occurs between the strings 'Synopsys', 'Description', 'Solution' & 'Risk factor' in the above example? In other words i may be asking to use multiple delimiters.. in the order of occurance.. is there a tool that supports multiple delimiters?