I used a command Code:
grep -r err_sys ./
its output is
Code:
./tcpclitime.c:err_sys("socket error");
./tcpclitime.c:err_sys("connect error");
./tcpclitime.c:err_sys("write error");
./tcpclitime.c:err_sys("shutdown error");
./tcpclitime.c:err_sys("read error, n = %d", n);
[Code].....
Is it possible some how to replace all the occurrences of word err_sys by printf.
I know how to replace a particular instance (say 3rd one) of a word in a line using sed based on the sed one-liners. However I would like to replace a particular instance of a word in the entire file.
For example, here is a file:
Code:
John
Betty
Jack
Ron
Jack
Paul
So now I would like to replace the second instance of Jack (in red color) with "Rob" (for example). Not quite sure how to do that? I tried couple of things from here but they did not work.
How do I count the number of occurrence characters in a string in an efficeint way ?
How do I reverse the words in a string with out using temp variables if possible . (if not possible use temp variables ?
Why do I specify dependedcies for header files in the Makefile ?
I wanted to find and replace a string from a perl file. I have written a script in bash which runs the following command.
perl -pi -e "s/$findstring/$replacestring/" testfile
where as $findstring = print F_WC_TMP"$line
";
and $replaceString = $line = join ' ', split ' ', $line; print F_WC_TMP"$line
";
But when I am running the above command, i think it is replacing the $findstring with the above mentioned string and hence it contains a $line, it is looking for the variable $line and not finding the exact string. I am confused about how to search for a string that contains $ in it and replace it with another $string.
I have a set of lines as ahown below:
Leon went to school
Leon came back from school..
Leon had dinner...
I have to replace the line containing "dinner" by a single string LUNCH...
I found this command that works great finding and replacing a simple string to another in files located in that folder and all sub-folders.
Code: find . -name '*.php' | xargs perl -pi -e 's/OldText/NewText/g'
The problem I have is that I need to replace a more complex string, like this: Old string: /mnt/stor6-wc2-dfw1/627896/982574/ New string: /mnt/stor8-wc2-dfw1/369587/302589/ There I don't know how to do it... since the / is what separates the old from the new strings, and the strings that I want to replace have / in it. Also, I would like to know how to specify under what folder replace the files, for example, I want that it search/replaces all files under /var/www/mysite/htdocs folder.
Any solution using awk/sed/regexp or other standard linux utility (this is for a mix of RH versions)? I am dealing with some very large application log files. I want to see everything that has been written to the log since the last application restart.
For an example take a log file like this:
Code:
# cat test.log
1 msg
2 msg
3 restart 1
4 msg
5 restart 2
6 msg
The following command is close to what I want:
Code:
# awk '/restart/,G' test.log
3 restart 1
4 msg
5 restart 2
6 msg
But the awk command grabs the first restart not the last. If it was working the way I wanted I would see something like this:
Code:
# awk '/restart/,G' test.log
5 restart 2
6 msg
So, I need something in that search pattern that says look for the last occurrence. I know how to do this with a pipe line - I could reverse the file and then do a similar awk and reverse back, or I could find the number associated with the last restart and then use that in the awk search. But these just take too long because the file is too big.
i use this script to get the time and date of back and fourth transactions for a particular execution id. I use a substr command on the 5th column to to cut the milli seconds off the time value. - otherwise the times would look like 08:30:04.235
grep <executionID> <auditfile> | awk '{ print $1, $2, $3, $4, substr($5,1,8}
FIX -> Mon 3/1/2010 08:30:04
FIX <- Mon 3/1/2010 08:32:36
FIX <- Mon 3/1/2010 08:35:08
[code].....
anyhow - i append two sed commands to further clarify the direction of the message.
awk '{ print $1, $2, $3, $4, substr($5,1,8} | sed -e 's/->/ ->IN/g' | sed -e 's/<-/<-OUT/g'
FIX -> IN Mon 3/1/2010 08:30:04
FIX <- OUT Mon 3/1/2010 08:32:36
[code]....
I tried using an awk gsub () command within the string instead of the two seds, but it did not work:
awk '{ print gsub(/<regex>/, <replace with>,$1), $2, $3, $4, substr($5,1,8}
the sed works ok, but it would be cooler to make the replacement within the awk command:
gsub(/->/,-> IN, $1)
Is there a way where i could replace the value of the $1 column in the awk print string?
I am web developer I have this command find . -exec grep "Improve your score" '{}' ; -print for searching through files . I found this command but now i would like to tweak it to gain more out of it.
View 2 Replies View RelatedMoving right along, I have a folder of MP3 files containing various Movie sound tracks and scores. I'm using Audio Tag Tool to tag all the files at once with an "Artist" of "Soundtrack", and to inherit the "Title" tag from the file name. After that, I will rename all the files (Using Audio Tag Tool -- awesome program, btw) with the format "<Artist> - <Title>.mp3"
The problem, is many of my files already contain the string "Soundtrack", which would be redundant. I happen to be a perfectionist, so I'm unable to ignore it and move on. Hence my question to you fine folk: I want to delete all instances of "soundtrack" (-i case irrelevant) in the filenames before I go through the above steps. But, its not quite that simple. This is a sample of some of the file names:
[Code]....
how to replace last character string. For example
$>export T1=abcde
$>export T2=xyz
how to get result abcdxyz?
I've found some scripts that replaces a string in a file but it's not quite working for me.
And I'm trying to replace a tag in an xml file that looks like this
So I ran a command line like this perl -w -i -p -e "s/xmlns="'http://mydomain.org/replacethese.xsd'">/>/g" testfile.xml
And I get a error output
Search pattern not terminated at -e line 1.
Found the script from this blog [url]
I want to know the Perl command to replace a string by pointing the line number. I know how to replace a string without pointing a line number but I am in need to replace only the two matching string in a file
View 6 Replies View RelatedI am trying to replace a string (url) in 100s of files located in different directories. I found the sed command but cannoy get it to work. First I locate the files that have the string in them:
Code:
grep -ilr 'url' *
this works correctly and displayed the location of the files that have the string:
Code:
1/index.php
2/index.php
Now I need to replace the string so I combined it with sed:
[Code]...
I've been trying to understand pthread in C a little better. So I made a simple program that takes in a string from the command line and creates a thread to print the string. I've looked online and copied the basic concepts but there are something things I'm confused about. The programs works just fine, but I have questions. Here's what I have so far.
[Code]....
One thing I'd like to know is why the 3rd argument in the pthread_create function which is my SendMessage function needs to be typecasted to a void pointer and then send the address of the function. Also as for the 4th argument, I would see typecasting to void pointer in some of the pthread examples I saw online, but in my case I'm passing a char pointer, would this be correct? In which case would I ever want to pass a void pointer?
Do I need a pthread_exit(NULL) in my main and in the SendMessage function? If so, why? I added the sleep() function so that I could let the pthread_exit function in my SendMessage function execute first. I simply saw that the online examples on pthread had pthread_exit() in both locations.
I am trying to replacee all digits with a symbol (say, big U here) in a string by
[code]...
The result become 'UsUoUmUeUtUhUiUnUgU' instead of 'somethingUUU' as expected. Looks like my string contains some 'hidden digits' in between the letters. Does anyone have an idea about that?
I have question about replacing a string in a file.
How can I replace the printerb's 10.1.1.1 to something else(10.1.1.2, for example) without replace printera's 10.1.1.1 accidentally?
I have tried perl -e -pi "s/10.1.1.1/10.1.1.2/g" /etc/hosts. but, perl replace both 10.1.1.1 to 10.1.1.2.
Say I have a file as
[code]....
It would be great, if i could issue a command (Vi/Bash/awk, ...) in order to obtain
[Code]...
So, the "replace string" should be replaced by another string containing the counter of replacement.
After hours (literally) of searching the web and reading man pages, I think I've come up with the following:Code:find . -exec grep 'path/to/file' -print | xargs -0 -I new_path mv {this is where I get confused}So my code above is incomplete, obviously. In order to finish replacing the string, I need to mv the new file into the old file's spot. How do I do this, by incorporating it into my line of code?
View 14 Replies View RelatedI want to use SED to do the following: In a text file replace any occurrences of the three character string ZZZ with a quotation mark "and. replace all occurrences of a comma with a semi-colon. It is the S/ / / command which is stumping me on the first issue...inparticular how to get the replace string to be quote.
View 9 Replies View RelatedI have a line in a text file that has 40 random characters within a tag and i want to change the characters to a new set of 40 random characters (alphanumeric a-z 0-9 etc)
The line in the text file looks like this:
Quote:
How would i go about doing that?
Also second question same as the above but how would i remove them instead of replacing them?
If I have a word in a text file and I need to replace it by another word (for example, i need to replace abc by fff) so what is the command I can type it?
I am using vi editor.
I want to replace a string of directory path in a string to empty:
Code:
But this doesnt seem to give me the desired thing:
Code:
This gives the desired outcome, but its specific, i need a variable in the sed not a string. And if I replace STRING="/mnt/sda1/record/$dd/" then I cant use it for something else, cause its has all the weird backslashes now.
I have script that I'm working on that updates a username in all the files that are called blah.inc for my framework. since i host a bunch of these web apps i need to do it to all of them. so I need to figure out how to update these files automagically with out me watching it to call vim every time. heres what I have so far
Code:
This finds the files but now i need to figure out how to do s/bob/fred/g on those files.
copy string a to string b and change string b with toupper() and count the chars
View 3 Replies View RelatedI have a tab delimited file. I need to replace the 7th tab with a new line.
I tried the following command (but it does not work):
The above simply spits out the original file.
If I write the next command, it replaces the first tab in each line with a newline. How can I make it replace the 7th tab in each line?
I have found this from a site [url]
Code:
But it does not work for me, segfault.
how to search for those files which contain word "AM_COLLECTION=22". I need to know all the files with this string. ( I know the grep command can do it but either
View 4 Replies View RelatedI am trying following script can I do this or is there a way to do find and replace the replacing word is dynamic input by user
echo -n "Enter name:"
read RP_USER
sed 's/text1/$RP_USER/' /home/user/file1 > /home/user/file2
Here's the actual line of code, which exists in a bash script:
Code:
I want to replace instances like this:
Code:
with this:
Code:
Using this:
Code:
Which works great when there's only ONE of the pattern on the line. But in a case like the "actual line" I posted first, where there are two patterns, separated by a slash, only ONE gets replaced
Watch:
Code:
Why? There must be (among many other things) something I'm not knowing about sed, that's causing this.
-- I'm currently using the ~ (tilde) as the separator in the sed command. It doesn't matter, I've used / ~ and % with no difference.
-- As a test, I tried putting a different character(s) in the middle of the original pattern instead of the / but that made no difference.
-- I've come up with various similar but slightly different regexs that will do this replacement, but they all have had this same result.
-- I tried the sed single-quoted, double-quoted, and unquoted; the latter fails to execute, and the formers both work as described here: wrong.
