General :: Error Executing The Script?
Jun 16, 2011Running following script for checking root ssh login status.
Code:
Flag=`cat /etc/ssh/sshd_config | grep "^PermitRootLogin"`
if [ -z "$Flag" ]
then
[Code].....
Running following script for checking root ssh login status.
Code:
Flag=`cat /etc/ssh/sshd_config | grep "^PermitRootLogin"`
if [ -z "$Flag" ]
then
[Code].....
I am writing a script which will fetch data from different machines and display it on single terminal. I have created a file named SERVERNAMES containing ip address of machines I need to monitor. Then for every IP I am issuing ssh command to get date on that machine. However When I am trying it on the script it is just giving me output of first server and it is ignoring rest servers mentioned in file. ssh works fine without password for all machines mentioned in SERVERNAMES.
Code:
# cat SERVERNAMES
10.180.45.231
10.180.45.235
10.180.45.238
10.180.45.211
Script
Code:
#!/bin/bash
while read line
do
#Calculate Load on remote machine.
Date=`ssh -T -q $line date`
echo "Date on $line is:$Date"
done < SERVERNAMES
Code:
output.
Date on 10.180.8.231 is:Wed Jul 14 10:48:46 IST 2010
I am not getting the output for .
Code:
10.180.45.235
10.180.45.238
10.180.45.211
Is there anything wrong in ssh?
I am wondering why running this file:
Code:
-rwxrwxrwx 1 root root 1247 2010-04-21 18:25 autorun.sh
by issueing this command:
Code:
./autorun.sh
results in this message:
Code:
-bash: ./autorun.sh: Permission denied
I'm logged in as root and prior to the above I did a chown root:root on the file.
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[code]....
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Code:
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Code:
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Code:
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Code:
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Code:
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BEGIN{ FS=":"}
{
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[code]....
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i just want to know whether we can execute the commands in invisible mode in linux. i.e.the command we typed must be executed but should not be visible.is it possible.
if not,then how the password we are typing is not visible in linux,while creating or entering password for users.
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i have n files and each file has 5-6 .sql files.Now I need to wrie a shell script that executes all the n files in parellel and for each n file the .sql files sequentially.eg
CRM_File CM_file AP_file
crm_file_1425.sql
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[code]....
run CRM_File CM_file AP_file in parellel and each file under CRM_File,CM_file,AP_file sequentially.