I would like to grep two numbers out of a text file, and divide them.
Here is the script code...
It feels like grep saves a new line too? or what is happening? i simply can't divide them, as it handles the variables as they are empty (and prints the two numbers although they were not printed
I have two files :
FileA
prot1
prot5
prot9
prot15
[Code]....
What I need to do is to extract from fileB the fields containing only the strings in fileA.
I thought awk could do the job easily with :
Code:
awk 'BEGIN { RS = "###" } /'$variable'/' fileB > output
where variable would maybe be the output of grep from fileA. So can I store the output of grep in a variable to use it afterwards with awk ?
something like that:
Code:
result=`grep prot. fileA` ; awk 'BEGIN { RS = "###" } /'$result'/' fileB > output
but that doesn't work. I'm always getting the entire fileB.
The output of grep get stored in the variable, I verified that with echo. So there is something that I just don't get... It seems to me that the above line should work.
My script.
This is may script:
Code:
Problem: Output file doest not exclude the values in grep -av
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how can I pass this output to -exec command.
If I am not using grep command my script would be as
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How can I use -exec with grep and find.
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[Code]....
If I use cat somefile instead of ngrep at the start, everything works as expected.
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Im using this one
Code:
And I get an output similar to this one.
Code:
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Code:
semoi@darkstar:~$ cat rename4.sh
#!/bin/bash
INPUT="k3b_audio_0_04"
[code]...
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#!/bin/bash
a = `tail -1 new.txt|head -n 1`
echo $a
so i wrote myself a very simple hellworld program in c++
...the usual stuff
int main()
{
[code]...
I need to store the output of bitset() in a variable ... is it possible in c++?
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Code:
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Code:
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Code:
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Code:
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:~/bin$ echo $process
26736
:~/bin$
When I try to incorporate this into a shell script I get a blank.
Code:
:~/bin$ cat process_idesk
#!/bin/bash
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[code]....
The process_idesk script has been chmoded to be executable by the user. I'm sure there must be a silly omission on my behalf.
I've tried every combination of ' " that I have come across in similar threads on the forum but no luck.. I have 2 files
strings.txt: contains a list of numbers, 4 digits per line file.
txt: contains a lines that I want to grep for the strings.
for example:
>cat strings.txt
3214
8746
2411
[code]....
if I echo $i in the loop, I print out the contents of strings.txt If I put 3214 in place of grep "<$i>" file.txt I get "carls phone number is 3214"
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Code:
grep -r $SEARCHDIR --include="day_$YYYY-$MM-*" -h -o -e PATTERN
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I need to create a single line of output from multiple and variable lines of input in a Linux bash shell script.
My input file looks like this:
Where there may be any number of umsecondaryphonenumber lines; if there is not a umsecondaryphonenumber line for a telephonenumber, I don't want to write any output.
So, the output file should look like:
The script I have so far is:
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Why does grep not find the text, or at least why deos my script not check the grep output correctly?
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if [ -f /media/$id/file ]
then
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else
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