I would like to know how to change the uname -a result in my server, i mean if the attacker upload a phpshell in any website for my customer, how could i have a fake uname -a for him?
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I want to change my servers node name which is the output of "#uname -n"Server is CentOS 5I searched but couldn't find. There was some search results about /etc/nodename but I don't have a file at that path. Also some said uname -S which doesn't work.
View 8 Replies View Related# mkinitrd -v /boot/initrd-$(uname -r).img $(uname -r) what does it [$(uname -r).img $(uname -r) mean?
View 2 Replies View RelatedI got this message after a update some weeks ago and am now on a permissive opening.
Fedora 11
gnome 2.26.3
You know, I thought I had my Broadcom issues all figured out, I have a simple list of installing the RPM Fusion repos do a yum update and yum install kmod-wl and everything works.However, this time it didn't work. I am installing a new fedora 14 for a friend who is totally fed up with windows and I get this error: (Yes I have searched the internet and Fedora forums for an answer)
[code]...
I have tried the two yum suggestions and they don't work I have tried updating the kernel and have installed kernel-devel-'uname -r' (suggested by another site) I have tried installing broadcom-wl and b43-openfwwf which only knocked out the card entirely
I installed Ubuntu Server and want to change the default user name to increase the difficulty of accessing the server.Is it possible to do this? If not, can I effect the same change by creating a new user and transferring over permissions, files, and etc.?
View 7 Replies View Relatedi try to copy file music .oog .wav from Music folder to /usr/share/sounds/freedesktop/stereo but i can't and in folder /stereo i can't manage rename ,cut ,move to trash for all file .ogg when i right click at file to look Properties > at permissions i saw owner : root can not change these permissions
that 's i not understand about owner . and how i can change these permissions ?
I want to change the password complexity how do i do this?
View 9 Replies View RelatedDear Friends, For Upload a Web Site in my Local Fedora using Apache I need to use the /var/www/html folder.But I cant add/edit anything on html folder
View 3 Replies View RelatedRecently I was going through some chmod manipulations and found the umask values to be 0002 by default in Fedora 11 distro. What I knew about the default values to be 022. I don't know whether this is a kernel modification in this distro or my system is in compromise(I doubt for the latter option, but not confirmed).
View 4 Replies View RelatedI'm trying to change that:
Code:
modprobe ipt_recent ip_list_tot=500
But it's not work Can I change menually in /sys/module/xt_recent/parameters/ip_list_tot Or there is other way
How to change the passphrase for crypted partitions in F14?
View 1 Replies View RelatedI have a problem with my fedora workstation.I am trying to change my ldap user password through passwd command.When I first create the user on ldap server, I use md5 and create the user password.This is the entry:
Code:
dn: uid=boo,ou=People,dc=linux,dc=gettolandia,dc=org
uid: boo
[code]....
Fedora 11 update released today creates a dependency issue in my x86-64 system: Processing Dependency: kernel-uname-r = 2.6.29.5-191.fc11.x86_64 for package: kmod-wl-2.6.29.5-191.fc11.x86_64-5.10.91.9-3.fc11.1.x86_64 # yum info kernel-uname-r produces "no matching packages to list" the yum info pack tells me kmod-wl is: Metapackage which tracks in wl kernel module for newest kernel so it seems important to have it up to date. What should I do?
View 5 Replies View RelatedI receive messages such as the below:
SELinux is preventing /usr/sbin/httpd from using potentially mislabeled filesjk-runtime-status. SELinux has denied the httpd access to potentially mislabeled filesjk-runtime-status. This means that SELinux will not allow httpd to use these files. If httpd should be allowed this access to these files you should change the file context to one of the following types, httpd_tmp_t,
I know how to change the owner of a file and the permissions but what does it mean to change the file context?
I need to write program (preffer Python) to change range for users. Does anyone know some library which can help me to do that? Maybe someone has written program like that?
View 5 Replies View RelatedI've got a samba share on a linux server, connecting to it with a windows 2k3 server via tools > map network drive. The goal is to be able to use windows to change the security of the samba share. The good news is it works! The bad news is it's not QUITE perfect:
The share is called /company. I started with the following to give everyone access to everything, set the owner of the share to administrator (my domain admin on the Windows domain), and set the group owner to domain users (group that everyone on the domain is part of):
Code:
chmod -R 777 /company
chown -R administrator /company
chgrp -R domain users /company
I then mapped the drive as a regular user, and of course, can access/modify/delete/rename/create anything I want. Then I picked a folder to lock down. Let's call it /company/myFolder. I did this on the Windows server by mapping the drive as administrator (the owner), right click > properties > security tab > advanced > highlight "domain users" and "everyone" and click edit > clear all (i.e. remove all access). Go back to Linux and
[Code]..
The only issue that remains is that I am able to rename/delete "myFolder" as a regular user. I thought this was coming from the "acl map full control = true" parameter in smb.conf, but I changed it to false and verified the change and it still happens. If I remove group and world write access to /company, I am no longer allowed to rename/delete myFolder, but then I can't create a new folder. If I add group write access back in I can create files but can also rename/delete folders within /company that have --- specified for group access. Any ideas what I need to tweak to make this right?
I have read that to improve security in Ubuntu a good fix is to make the /home folder tree non-executable by default. This would mean that malware could not run in the /home tree without changing the setup.Is this a viable change, or is it just icing on the cake, any one any thoughts on this.
View 9 Replies View RelatedSome instructions say to put 'uname -r' into terminal commands. Is this supposed to be automatically converted by the system to something else? It doesn't get converted to anything on my system. uname -r only works by itself but not as a program argument.
View 1 Replies View RelatedWe are trying to define an appliance based on Suse for an application server and Web server Apache, so we would like to know configuration best practices for network and security, is there any paper/doc about best practices?
View 3 Replies View Relatedany one knows the difference between the uname -m, -p and -i?
Code:
uname -m
i686
uname -p
i686
uname -i
i386
[Code]...
i gt this from man. does it mean that the machine is a i686 machine that is running on a i386 OS?
How would I prevent printing the kernel version after logging in? I cannot find any relevant setting in login.defs
View 4 Replies View RelatedI use Debian testing and when I run this
Code: Select alluname -a
I see these
Code: Select allLinux debian-mfaridi 4.2.0-1-amd64 #1 SMP Debian 4.2.1-2 (2015-09-27) x86_64 GNU/Linux
I run the uname -m command and the output is i686.What does it mean ???
View 3 Replies View RelatedI am having issues trying to compile the alsa-linuxtant module and I am getting errors about not being able to find some files and the source needing to be reconfigured. Anyway the developers told me to try compiling on a pristine source to see if I could compile that way. When I went looking at kernel.org I did not find a 2.6.32-5 version. So I did some checking and to see just what version I have.
$ uname -r
2.6.32-5-amd64
$ dpkg --list | grep linux-image
ii linux-image-2.6-amd 64 2.6.32+27 Linux 2.6 for 64-bit PCs (meta-package)
ii linux-image-2.6.26-2-amd64 2.6.26-24 Linux 2.6.26 image on AMD64
ii linux-image-2.6.32-5-amd64 2.6.32-15 Linux 2.6.32 for 64-bit PCs
So the actual package that is installed is 2.6.32-15 but uname -r reports 2.6.32-5 as the kernel version.
I am writing a script inside i need to get the values of uname -n like... var = uname -n. how to do it in shell script ?
View 1 Replies View Relatedpam_auth_radius - Change the "Password:" prompt.Im currently working on getting a two-factor supplier working with my servers.Ive installed the pam_auth_radius.so and it works fine.HOWEVER.When I SSH to the server , I get this:
warning: Need basic cursor movement capability, using vt100
Keyboard-interactive:
Password:
[code]....
I am an openSuSE user for many years. My current installation is openSuSE 11.2. However, my first was SuSE 6.4 and I have been _constantly_ upgrading since then until reaching the current openSuSE 11.2. The technical issue I have been facing lately is with the kernel version of my current system: although it should be 2.6.31.5-0.1-desktop, as this is the one I have chosen via the online update mechanism and the yast2 system boot-loader procedure, grub shows it as preselected, the boot procedure in the end greets me mentioning this very kernel version, _but_ when I issue the command: uname -a in a command prompt, I am informed of using linux kernel version: 2.6.18.2-34-default #1 SMP PREEMPT
I am really quite puzzled, since I _cannot_ find any such vmlinuz file under /boot/ ! Could it be that my system properly runs with the expected kernel version, but uname mistakes it with a different one? Is there a way to determine the actual version of the linux kernel that my system currently runs with? If it's a problem with uname, have you got any suggestions that could potentially shed some light towards the origin/cause of the reported issue?
I did apply the updates on 11.1 32bit and upgraded the kernel from 2.6.27.45 to 2.6.27.56.
Now:
Code:
> uname -a
Linux myhost 2.6.27.45-0.1-default #1 SMP 2010-12-01 16:57:58 +0100 i686 i686 i386 GNU/Linux
but:
Code:
> cat /proc/version
Linux version 2.6.27.56-0.1-pae (geeko@buildhost) (gcc version 4.3.2 [gcc-4_3-branch revision 141291] (SUSE Linux) ) #1 SMP 2010-12-01 16:57:58 +0100
I am creating an FTP server using VSFTP. It will be in the wild, initially at least only functioning as an FTP server. I have the iptables config from the previous box I set up 3-4 years ago. I have also got private/public key authentication running with SSH to eliminate brute force attacks.
Here is where is my specific question. On the old server I set up something that allowed my clients to log in using accounts that were not system accounts but would translate to a single system account that was limited to FTP. I remember setting up a passwd account that had username / password pairs that FTP used for authentication.
What app is this? Is it just part of VSFTP or maybe SELInux? I really want to utilize this.
