I need to write program (preffer Python) to change range for users. Does anyone know some library which can help me to do that? Maybe someone has written program like that?
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I am using squid + dansguardian for web and content filtering. And it is working fine. I am forcing users to use proxy through browser configuration. Now I am planning to add another layer to controlling access using ncsa_auth program. I know it is not the most secured but I am fine with it. Plain passwords are fine with me.
I will be giving users some default passwords but I want some program for allowing users to change the passwords for the respective users if they want. Is there any perl script or something web based for the purpose that anyone is using or know of?
How to allow users to change their password in chrooted ssh as long as the modifications in the shadow file in the chrooted environment will not be applied on the system itself ?
View 2 Replies View RelatedI'm assuming that the following should block the complete 178.123.xxx.xxx address range.
Code:
iptables -I INPUT -s 178.123.0.0/24 -j DROP
Then I believe that I need to save this change.
Code:
service iptables save
iptables: Saving firewall rules to /etc/sysconfig/iptables:[ OK ]
However, I'm not so sure that it is actually working based on the fact that there continues to be access to my wiki from that address range. The following is after I made the firewall change.
Quote:
178.123.177.61 - - [31/Dec/2010:04:24:40 -0500] "GET /mywiki/Opera%20Web%20Browser?action=edit&editor=text HTTP/1.1" 200 6346 "-" "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1)"
code....
Let me state that I'm new at this iptables thing. I did some reading and decided that I need to make the above change to the firewall but it doesn't seem to make a difference.
I am working with NS-2, I am facing a situation where I need to re align the transmission range of a particular node. Can I do this by modifying the protocol's source code? I should not change the default value from 250, only few nodes who satisfy a particular criterion should be reset to some other range like 200 or 300. How can I do this?
View 1 Replies View RelatedHaving a bit of an issue with Python while trying to write a script to download every rar file on a webpage. The script successfully downloads any link that doesn't contain any spaces, etc. But when it hits a url like: [URL] (Classical Spelling).rar. It fails...I'm sure this is something simple, but I'm so new to python I'm not sure what to do!
Code:
import urllib2
import os
os.system("curl [URL] -i rar|cut -d '"' -f 2 > temp.out ")
infile =open('temp.out', 'r')
for url in infile:
print url
#url = "[URL]"
#url = target
file_name = url.split('/')[-1]
u = urllib2.urlopen(url)
f = open(file_name, 'w')
meta = u.info()
file_size = int(meta.getheaders("Content-Length")[0])
print "Downloading: %s Bytes: %s" % (file_name, file_size)
file_size_dl = 0
block_sz = 8192
while True:
buffer = u.read(block_sz)
if not buffer:
break
file_size_dl += block_sz
f.write(buffer)
status = r"%10d [%3.2f%%]" % (file_size_dl, file_size_dl * 100. / file_size)
status = status + chr(8)*(len(status)+1)
print status,
f.close()
I'm tring to run AMDOverdriveCtrl, since they don't have an RPM file for Fedora i tried to compile from source i followed the instruction in the readme files run the make command
Code:
% make
g++ -mwindows -s -pthread -lwx_gtk2u_richtext-2.8 -lwx_gtk2u_aui-2.8 -lwx_gtk2u_xrc-2.8 -lwx_gtk2u_qa-2.8 -lwx_gtk2u_html-2.8 -lwx_gtk2u_adv-2.8 -lwx_gtk2u_core-2.8 -lwx_baseu_xml-2.8 -lwx_baseu_net-2.8 -lwx_baseu-2.8 -ldl -o./Release/AMDOverdriveCtrl ./src/CFanSpeedPanel.o ./src/COvdrSettingsPanel.o ./src/CFanControlPanel.o ./src/CColorTempPanel.o ./src/BezierMath.o ./src/Color.o
[code]....
and tried to run the application, and i get this error message
Code:
$ AMDOverdriveCtrl
Fatal Error: Mismatch between the program and library build versions detected.
The library used 2.8 (no debug,Unicode,compiler with C++ ABI 1002,wx containers,compatible with 2.4,compatible with 2.6), and your program used 2.8 (no debug,Unicode,compiler with C++ ABI 1002,wx containers,compatible with 2.6).
I am developing a program that uses libusb-1.0 on a FC14 x64 system. I solved the compile and link issues, but I now have a problem with user privileges when I try to get device handles. The problem appears to be in the mounting of the usbfs. Is the an accepted fix to giving users read/write privileges for all usb devices?
View 4 Replies View RelatedI created 3 partitions on my usb stick, one is vfat, one ist ntfs and one is ext4.And i formated them like this:
Code:
mkfs.vfat -F32 /dev/sdg1
mkfs.ext4 /dev/sdg2
[code]....
I have written a shared library and successfully used debhelper 9 to create a Debian package from source using a Makefile generated by cmake. I then went about writing a python wrapper to that library and wish to package that wrapper in with the library so I can have a single distributable rather than 2 separate ones.
All of my attempts so far have me placing my python source and a setup.py file in the same directory as the makefile at the time where I call debuild.
From here I have tried a couple different configurations to my debian/rules file as seen below:
Attempt 1:
# -*- makefile -*-
%:
dh $@ --with-python2 --buildsystem=python_distutils
This try seemed to package up the python stuff nicely but proceeded to ignore my makefile for the shared library and therefore ultimately failed.
Attempt 2:
# -*- makefile -*-
%:
dh $@ --with-python2
This try ran make, but completely ignored the python stuff. From some research I have gathered that the --buildsystem flag tells debuild to ignore any makefiles in the directory, which obviously causes a problem in my case.
Another attempt was to modify the build dependency to first run make and then call the python build process that file looked like this
Attempt 3:
# -*- makefile -*-
build:
dh $@
dh $@ --with-python2 --buildsystem=python_distutils
%:
dh $@ --with-python2 --buildsystem=python_distutils
This appears to somewhat work as both processes do build, but a few of the python files are still not getting installed.
Is this the way I should be going about doing this? I've noticed that most python wrappers tend to package themselves individually and then make that package dependent on the library it is attempting to wrap.
The whole day was more or less spent reinstalling a basic Gnome Ubuntu system. Everything went swimmingly until I started with the XBMC part of the installation. After wrestling with PPAs and apt-get for hours I finally got it installed, but then it all turned awkward in a hurry. It simply refused to start up. I clicked the icon and nothing happened for a good few seconds. The screen then flickered black for an instant, but after that nothing. I started from a terminal and it showed an error message saying it couldn't import Python's os and shutil modules. I found that mighty strange since both modules are part of the Python Standard Library.
Finally, in a bizarre twist, it turns out this doesn't seem to be a XBMC problem, suddenly apt-get started complaining too. TL,DR: I (nor the system) can't import any Standard Library modules in Python in Ubuntu! Is this a path problem? Or have I actually managed to uninstall some vital python packages, if so which ones? I am running Ubuntu 10.10, but I don't think this is necessarily a Ubuntu specific problem. Here are some dumps to show the error messages: (I forgot to copy the XBMC error message, but it looked exactly the same as these below, i.e., it couldn't import the os module) First from apt-get:
Code:
tv@tv:/usr/lib$ sudo apt-get autoremove
[sudo] password for tv:
Reading package lists... Done
Building dependency tree
[code]....
one of the coolest features of Fedora imho is sandbox -X, which I used extensively in F12. However, in F13 I yum install /usr/sbin/seunshare prints:
Code:
[...]--> Processing Dependency: policycoreutils-python = 2.0.82-13.fc13 for package: policycoreutils-sandbox-2.0.82-13.fc13.x86_64
--> Finished Dependency Resolution
Error: Package: policycoreutils-sandbox-2.0.82-13.fc13.x86_64 (fedora)
Requires: policycoreutils-python = 2.0.82-13.fc13
[Code]....
I recently got a nice, lightly used IBM Thinkpad laptop. It has wireless capability for the Internet. Linux is the only OS in the laptop. At home, I don't have wireless-- I have a wired DSL connection for my laptop and for my IBM desktop (which also only has Linux as OS).
When I took the laptop to the public library, wireless is provided there for free and I had no trouble connecting to the system there. But since I'm new to wireless, what do I need to have installed to have a secure laptop when in the public library (or when I'm anywhere else that offers free wifi) using the wireless connection? [I use Firestarter as my firewall in the laptop and in the desktop.] Do I have to install some software to make sure my laptop is secured from spying and invasions when in the library or is the Firestarter enough? If Firestarter is not enough, what is that wifi security software by name?
[My OS is MEPIS 8.5, a Debian-based distro.]
I have a new server with Fedora 10. The root user can log in by SSH using an RSA key but for any other user the RSA key is ignored and a password required.Ultimately I wish to access an SVN server over SSH and would like to to have to keep entering a password. I have Googled this issue and found nothing.If I log on as root the /var/log/secure file shows that the key is accepted, for any other user no message is added and the password is requested.I have checked all the config files and as far as I can see they are all correct so I am at a complete loss as to why SSH will not use the users RSA key.
View 13 Replies View RelatedSo I have just set up my cryptsetup.I can open/mount it by either "crypsetup luksOpen" or just clicking on the partition from the "Places" tab and it will ask me for a password and all.
The only problem is that I can't read or write to it at all. Everything is probably root, which isn't useful to me.
So how can I change it so that when I do either of those 2 methods for opening it, I can just fully use it, read and write and everything? As my user.
I want to write a shell script contains python one. So,the result of python one is flv file. I want the path of this is copied into a enviroment variable that i have to pass as a flag argument of another program (to convert into mp3). To individuate the result of python script I thought to use (in PWD)
Code:
ls | grep -E '^.*mp3$'
But my question is: How can I copy this result into enviroment variable?
Right i did a clean install of Fc15 and used a custom layout with separate /home partition. when it all installed It had created /home in the /root partition. so I then moved the /home directory to the partition I intended, added the relevant fstab entries and re granted permissions etc to the relevant files. All done with a live cd.
the problem is when i rebooted all settings worked as the partitions mounted with all the /home directories and all my user settings are in tact but when i click home in KDE's kick off it tried to open root? So all im wondering is how could i change the default /home back to my user account? as all i seem to find online is how to specify a /home with useradd
I need to create a number of internal Linux users for admin purposes. I do not want these users to appear on the initial console login page just after Fedora boots up, as users who can attempt to log in, and I do not want to allow these users to log in directly. I merely want these users to be accessed via su, just like the root user.
View 2 Replies View RelatedI do not know how to write either PYTHON or Bash Shell Scripting. I am to learn one for Linux Administration purpose. Which one will you recommend for a Linux Admin/Eng environment?
View 4 Replies View RelatedWe are trying to set up a classroom training environment where our SIG can hold classes for prospective converts from Microsoft/Mac. The ten machines will have /home/student01..10 and /home/linsig01..10 as users. We want /home/student01 to be able to explore and sudo so they can learn to administer their personal machines at home. We don't want them to be able to modify (sudo) /home/linsig01. I've seen the tutorial on Access Control Lists but I'd like other input so we get it right the first time.
View 3 Replies View RelatedIs it possible in Linux to restrict POP3 or IMAP for particular users.I need a confirmation on this, that it is possible or not in Linux.
View 3 Replies View RelatedI have my own dedicated server box running (using it for game servers). I access it via ssh and I have root control of it. It has FEDORA Operating System. I wanna give FTP control of different directories to different users. Right now there are no other FTP users except root. I have installed vsftpd and dont know what should I do next? How do I add users (who can read/write/delete files) and How do I restrict them to their home directory?
Here is what I want:
username:client1
password:12345
home directory: home/server1
username:client2
password:12345
home directory: home/server2
When I'm logged into my account, I can't shut down the computer if someone else is also logged in unless I supply the root password. However, if I log out, I can shut down from GDM without being challenged, even though another person is logged in, which could cause problems if that person is in the middle of some work. Is there a way to password-protect the gdm shutdown function if people are logged in?
View 2 Replies View RelatedMost kernels are written in low level programming languages such as C and Assembly. Would it be possible to write a kernel in a high level language such as Python? Many high-level languages are themselves written in C.
View 5 Replies View RelatedI have squid server running FC7. i have created a ncsa authentication for windows user to use internet through squid proxy.
My problem is that the each created user should be able to change their password.
- Is there a way, using NCSA authentication, to allow users to change their passwords?
- Is there a way to use windows AD password for squid authentication. if so how?
I am running Fedora 13 - 64-bit variety and using KDE as the gui. No real issues asides from machine not exactly flying, but then this is a mere core 2 duo 1.6 with 2 gigs of ram, so not unexpected...
When I run top I see 3 users indicated - which worries me somewhat... I am the only user on this machine.
I come from a Debian / Ubuntu /Gentoo knowledge-base and this laptop is a fresh install, encrypted partitions, temp has own partition (encrypted too) and obviously the firewall is on, with ssh service turned off and ssh access removed in the firewall....
is this 3 users in top normal, or have i managed to be hacked in the 3 - 4 days since I started the install ? In all this time I have been sitting behind a router when on the net.
Am I looking at a fresh install, or are there valid reasons for the extra users?
I just ran "users" in terminal and I show up 3 times - I have only logged in once, through the GUI and no extra access routes
we want to send from 1 to 4 via the path 1-2-3-4 but aodv sends it directly from 1-4 we want to restrict the range how to do so
View 1 Replies View RelatedI have a box that's used as an SFTP server. All users have restricted shell so they can only use SFTP to send and receive files. But it makes it hard to have them change their passwords. I thought that if we had a web page set up where the user could enter their username, old password, new password and confirmed new password, that this would be the easiest solution.
View 1 Replies View RelatedI was unable to compile a program that used libicu42 on Ubuntu 11.04, because Ubuntu 11.04 has only libicu44 and does not have libicu42 installed. So during compile time I used g++ prog.c -L mylib/ to compile the program. mylib had libicu42 (This library is a shared library and has the .so extension). The program compiled successfully, but when I tried to run it, it failed and complained that it did not find libicu42. So I had to manually install libicu42 in /usr/lib. Then the program worked.'ldd prog' revealed that it looked for libicu42 in /usr/libWhat was the point of specifying the library path using -L, if the compiled program looked for the library in /usr/lib? It's almost like it was just to satisfy the compiler.
View 3 Replies View RelatedI've created 3 files: swap.h and swap.c then make static library from it
Code:
Then I write 2 program to test this library: test_swap.c and test_swap.cpp
I compile
Code:
What's wrong with this in C++? And how can I make a library that can work both for any C and C++ program?
Here the source code
Code:
Code:
Code:
