CentOS 5 :: Pass Shell As Command Line Argument When I Ssh To An Account
Jan 25, 2011
I want to have a choice or more preferable pass shell as command line argument when I ssh to an linux account.i.e. If John logs in to account "zzz" on server "abc", by default definition of account "zzz" n server "abc" he get csh.But Sally desires that when she logs in to account "zzz" on server "abc", she needs the login shell to be ksh,and Rick wants bash when he logs in to account "zzz" on server "abc".What is the most non-intrusive / easiest way to achieve this? Each user can set their preference on ssh command line or create a simple alias by each shell, but not sure how to do this.
Trying to create a small script that will read user's input, test if user entered some input and if not display some message or display a text using user's input.
The script is the following but i get an error saying "[: 6: =: argument expected"
when I am running the script below,it performs on whatever logfile u type ,i.e, ./scriptname logfilename.But how do I convert it into a function and then call it from another script.I mean how do I prompt the user to enter a logname and then capture the name in the function and when calling this function from another script how do I pass the parameter.
I need to write a script that will take 1 command line argument. The argument will be a username. The script will determine if the user exists on the system and will print an error if it does not. If the user does exist it will determine if the user is currently logged in, if the user is not logged in it will determine the last time the user logged in and display the file in the users home directory that was most recently modified.
I've written myself a linux program "program" that does something with a regular expression. I want to call the program in the bash shell and pass that regular expression as a command line argument to the program(there are also other command line arguments). A typical regular expression looks like "[abc]_[x|y]".Unfortunately the characters [, ], and | are special characters in bash. Thus, calling "program [abc]_[x|y] anotheragument" doesn't work. Is there a way to pass the expression by using some sort of escape characters or quotation marks etc.?
(Calling program "[abc]_[x|y] anotheragument" isn't working either, because it interprets the two arguments as one.)
I've written myself a linux program "program" that does something with a regular expression. I want to call the program in the bash shell and pass that regular expression as a command line argument to the program (there are also other command line arguments). A typical regular expression looks like "[abc]_[x|y]". Unfortunately the characters [, ], and | are special characters in bash. Thus, calling "program [abc]_[x|y] anotheragument" doesn't work. Is there a way to pass the expression by using some sort of escape characters or quotation marks etc.? (Calling program "[abc]_[x|y] anotheragument" isn't working either, because it interprets the two arguments as one.)
The university I go to uses a WPA2 wireless network that requires a netID and password to connect too. I installed wicd but I can't seem to connect to this network, is there a way to add this functionality to wicd, and if so, how do I do that (links to a how-to or guide would be nice, I've yet to find one).
Also, I spend most of my time on campus in the command line, so I'd like to know if there is a way to use command line utilities to connect to this network (again, a guide or how-to would be nice)
I can get online through my fedora live USB just fine (w/ network manager) but I'd rather get on directly from slackware.
The ide has xp and I installed debian on the sata, the duel boot worked fine and still does. I then installed unbuntu on the sata along with debian but can't access unbuntu. when I tryed to install grub it error'd out so I bypassed that and finished the install. It told me I would need to pass a kernel argument to load ubuntu but I'm clueless about what that means.
I am attempting to script some tasks I have to do, but I have no control over one of the scripts I have to use... and they output all kinds of useless things on the screen. My goal is simple: Capture all output from their scripts, and create a progress line that only shows the most recent output from their stuff. So, here was my first solution; a file I called "spin":
To use it, you pass it a process ID and a file that contains the output from that process. As the process continues, a kurby dances on the screen (To let you know that the process has not hanged), and the tail of the output is shown (To let you know what it is doing). When the process ends, the kurby stops dancing and the time it took is displayed.
And here is the file I call "noise": Code: #!/bin/bash while [ i -lt 100 ];do i=1 echo "Look at me count!$" sleep 1 let "i=$i+1" done
This does nothing but create random output, for testing. It counts from 1 to 99 on the screen. To run my test, I do the following: Code: (noise) &>tmp.txt & spin $! tmp.txt
It works relatively well, but it is messy. I don't like creating a temp file, and I don't like the messy syntax for calling my program. I decided that I would rather move everything into the spin program, to make using it less messy: Code: #Spin Psuedo code #$1 = command I am about to run (exec $1) &>tmp.txt & spinX $! tmp.txt
By executing the process inside of the spin code, I can get rid of the tmp file later on without changing a lot of scripts (Or move it, or whatever). I can also call it by passing the command to the script, which I find more elegant.
So here is what I would like to know: 1) If possible, I would love to get rid of the tmp file all together, and store the most recent line of output from script 1 into a variable that script 2 can print out instead... is it possible? 2) How can I run a random command that is passed as an argument? Basic ones work fine, but anything with a pipe fails me.
Example of a script: Code: #!/bin/bash #myEcho.sh echo;echo "Recieved command: ";echo $1;echo; echo "Attempting to run command: ";echo exec $1
Example code for passing commands to script: > myEcho.sh "ls -al" #works > myEcho.sh 'ls -al' #works > myEcho.sh "ls -al|grep *.sh" #fail # Output: #ls: invalid option -- | #Try 'ls --help' for more information. > myEcho.sh "ls -al|grep "*.sh"" #fail # Output: #ls: invalid option -- | #Try ls --help' for more information. > myEcho.sh 'ls -al|grep *.sh' #fail # Output: #ls: invalid option -- | #Try 'ls --help' for more information.
i am working on a neat little bash script, and i want the output to be mailed to my email account. So far i have tried installing sendmail then running: mail -s Test myemail@gmail.com But that hasn't worked; and i did check my spam folder. Am i missing something or is there a better technique all together?
Is there a non-root shell command that can tell me if a user's account is disabled or not? note that there is a fine distinction between LOCKING and DISABLED:
LOCKING is where you prepend ! or * or !! to the password field of the /etc/passwd file. On Linux systems that shadow the passwords, this marker flag may be placed in /etc/shadow instead of /etc/passwd. Password locking can be done (at a shell prompt) via password -l username (as root) to lock the account of username, and the use of the option -u will unlock it.
DISABLING an account is done by setting the expiration time of the user account to some point in the past. This can be done with chage -E 0 username, which sets the expiration date to 0 days after the Unix epoch. Setting it to -1 will disable the use of the expiration date.
The effect of locking to to prevent the login process from using a supplied password to hash correctly against the saved hash (by virtue of the fact that the pre-pended marker character(s) are not valid output character(s) for the hash, thus no possible input can ever be used to generate a hash that would match it). The effect of disabling is to prevent any process from using an account because the expiration date of the account has already passed.For my situation, the use of locking is not sufficient because a user might still be able to login, e.g. using ssh authentication tokens, and processes under that user can still spawn other processes. Thus, we have accounts that are enabled or disabled, not just locked. We already know how to disable and enable the account - it requires root access and the use of chage, as shown above.To repeat my question: is there a shell command which can be run without root privileges which can output the status of this account expiration info for a given user? this is intended for use on a Red Hat Enterprise 5.4 system.The output is being returned to a java process which can then parse the output as needed, or make use of the return code.
I want to pass ip address,port address and some parameters from command line using python script.The ip address and port address for establishing socket connection and remaining parameters to execute different connection.
Given that I want my shell script be invoked at the command line using the above parameters - where [these brackets] denote that they are optional - what is the best method to parse them?
I am looking for a powerful command line tool to send and receive data via socket I mean define IP , port and data other options for command to send and receive data from sender.(like a high level socket programming)
If say, I want to read the input given by user at the command prompt and write a code to execute the cmd given then which commands do i use to implement this ( Im writing the code in C )?
Does anyone know a method of being able to process the complete and literal command line passed to a shell script ? I want to have the command line parameters with ALL characters (including meta characters e.g. $ literally).
So as if there was no shell to substitute or expand parameters nor applying it quoting rules.
I am very new to shell scripting.How does one pass a command-line parameter to a shell script?for the below program #/bin/bash mount -t cifs -o user=ramkannan,password=Linux123@ //10.200.1.125/ramkannan /MT cd /MT/test date=`/bin/date "+\%Y-\%m-\%d-\%H-\%M-\%S"` mysqldump -uroot -pram2@ employeedb > $date.sql gzip $date.sql
I want to pass parameter for everything,i tried in google and did but iam getting error while passing parameter to all
#/bin/bash mount -t cifs -o user=$1,password=$2 //10.200.1.125/ramkannan /MT cd /MT/test date=`/bin/date "+\%Y-\%m-\%d-\%H-\%M-\%S"` mysqldump -uroot -pram2@ employeedb > $date.sql gzip $date.sql
i was getting error while passing parameter to all.
I'd like to say I'm very impressed with Fedora 11. I'm a long time Linux user and I've tried many distros. But, I usually keep only the best on my laptop. For a long time that was Ubuntu but, I think Fedora 11 has made some key improvements over Ubuntu and I'm eager to switch. The problem is: I haven't been able to run Fedora as anything other than on the Live CD. Everything works perfectly and it installs but, when I reboot, Grub begins. Instead of booting, however, Grub drops into its minimal shell and gives me a command line.
I've tried installing it a number of ways now and have read much about the problems with Ext4 on Grub and took special care to see that Grub has its own, separate, /boot ext3 partition. Even then, no luck. My hardware should work fine. I've got an HP DV-5 with 4GB RAM, AMD Turion 64-bit dual-core @ 2 Ghz, and an IDE 250GB hard drive. I'm working with the 64-bit Fedora 11 Live disc with KDE as the Gui.
I wonder if there is anyway to make a user-defined bash shell function global, meaning the function can be use in any bash shell scripts, interactively or not. This is what I attempted:
Anyone know why my fresh installation of centOS server is so slow? Seems like it takes over a minute to execute a command, im not doing anything complicated either. Secondly, how come at times when I type reboot the machine starts to beep, one long loud annoying beep.
Feel free to just link to another thread where this is (pre)solved; I can't search the forum for the word "for," because it's too short (or maybe the search engine dislikes prepositions).
Is there a way to give the 'for' command a range? Here's what I mean:
Code: #for i in (1-5); do echo $i; done Certainly, meat space user; I understand exactly what you're thinking. 1 2 3 4 5 True, I realize I could use
Code: COUNT=1 ; while [ $COUNT -lt 6 ]...
...but if I can avoid the extra preparatory step I'd prefer to do so.
Examples: Code: $ ./test.sh -a -c 2 operator is -gt remcount is ^ value missing!
Code: $ ./test.sh -b -c 2 operator is -lt remcount is ^ value missing!
Yet when "-c" is the first argument, its value is present: Code: $ ./test.sh -c 2 -b operator is -lt remcount is 2 What could I do to ensure the value of "-c" is picked up regardless of the argument order?
read a files's specific line but return as argument only part of it ie
...
value # this is mass
value2 # this is force
so, how can I get / use the $value and $value2 as arguments for some other file and skip the rest of the line(s) ? of course, the values are different everytime, but the comment always the same, as well as the position of the lines in the file
