Ubuntu Security :: Testing Shell Codes In 10.10

I am learning exploit development and learning some stuff about shellcodes now! The shellcode is absolutely right and have tested it. I am using the following code...(created by me) to run my shellcode..

Code:
// #include<stdio.h> we will not be needing this as we are not using any functions from the C library...Just basic logic of Pointers..
char shellcode[] = "x31xc0xb0x01x31xdbxb3x07xcdx80"; // basic exit shellcode
int main()
{ int *ret; // a simple integer pointer pointing a address
ret = (int *)&ret + 2; // change the address pointed by
(*ret) = (int)shellcode; }

Compiling :-
Code:
aneesh@aneesh-laptop:~/articles/C$ gcc test.c -o test -fno-stack-protector
Compiling gives no errors as expected..

Now the problem I am facing is that As I run the program :-
Code:
aneesh@aneesh-laptop:~/articles/C$ ./test
Segmentation fault

Strace output :-
Code:
aneesh@aneesh-laptop:~/articles/C$ strace ./test
execve("./test", ["./test"], [/* 37 vars */]) = 0 .....
set_thread_area({entry_number:-1 -> 6, base_addr:0xb78016c0, limit:1048575, seg_32bit:1, contents:0, read_exec_only:0, limit_in_pages:1, seg_not_present:0, useable:1}) = 0
mprotect(0xf5e000, 8192, PROT_READ) = 0
mprotect(0x8049000, 4096, PROT_READ) = 0
mprotect(0x15c000, 4096, PROT_READ) = 0
munmap(0xb7802000, 81274) = 0
--- SIGSEGV (Segmentation fault) @ 0 (0) ---
+++ killed by SIGSEGV +++
Segmentation fault

I have some feeling that its because the program has no access to the memory containing the shellcode (May be???)..