Software :: Make Craig's List Ad Notifier In Bash?
Jan 7, 2010
I have OpenSuSE 11.2, and I am learning Bash scripting. I was wondering how I would make a bash program, That I could have it check multiple craigslist sites [western mass, worcester mass, etc], e.g. in the Free category, and/or enter keywords, and have it update every 5 minutes, and then post the results somewhere, to a file, or even upload it to a server, or if it's even possible? (Kind of like the program "Ad Notifier for Craigslist") Would I have to do this in C/C++? If it has to be done in C/C++ It would have to be windows compatible preferably.
I have a file witch I need to list 10 line by 10 lines with something like press enter to go on in between. Well, the problem is that i have absolutely no idea on how to implement this.
I am an uploader to a various hosts, so this tiny script me a lot. I make a rar archive and split files with 100mb. I could get 3-4 or even 76 parts of rar files and it would take me some time to paste all these urls to remote upload function of filehosting sites. For example:
Code:
server:/home/cober/downloads/teevee# ls -al total 358784 drwxrwxrwx 2 root root 4096 Dec 8 19:38 .
I have a file with joker character patterns: ./include/* ./src/* etc. From the current directory I would like to recursively get the list of files that do not match these patterns.
I'm writing a bash script to copy a list of files and do some stuff to them. Basically, I have the code written that does what it needs to do, but I can't quite understand why it works. I was hoping someone could clear up my understanding a bit.
Code:
The first line generates a list of files. I wrap each line in quotes because they usually have spaces in the directory names.
The second line changes IFS, and I understand what IFS itself does. What I don't quite get is what the separator becomes with that echo statement. If I'm reading that correctly, the backspace will remove the newline and essentially the result is nothing? I found this solution on a web page somewhere, but it was years old and there was no real explanation.
need a command or script to list all files recursive without directories one line per file, no extra lines like ls -AR1 should print file size and name eg.:
I have been using comm to compare two simple column lists, and suppress items that were contained in the second list (suppression list). This was extremely simple and basic, however now list1 has two columns, and I must compare the second column in list1 with my suppression list.
Basically I need to compare my user list and suppression list to suppress any users that exist in the suppression list, then remove the second column (md5).I wasn't sure the fastest way to make comparisons if there was a similar command like comm, or if I needed to create an array of users and see if any of them matched the suppression list one by one. This seemed like it would be pretty process intensive. Anyone have any less cumbersome ideas?
I'm trying to write a bash script that gets the list of files in a directory and puts them into a variable, then checks each entry and outputs them as follows:
item1 is a FILE item2 is a DIR item3 is a DIR etc etc.
I am able to get the list of files into a variable, but unsure how to get the output I want.
How to build a list of files under a directory that may have any permissible characters in the name, that is anything except NUL? The only possible (?) bash data structure to contain a list of such names is an array because NUL cannot be used as a list item separator so no X-separated list can safely be used; there is no "X" that might not be part of a file name. OK -- but how to populate such an array? Here's what I've tried.
Code:
#!/bin/bash # Set up test files dir=$(mktemp -d "/tmp/${0##*/}.XXXXXX") touch $dir/foo $dir/bar
I'm trying to use zenity in a bash script to display a .csv file using '--list' to allow the user to edit some of the values.I can display it fine but i'm unsure how to edit the data? all i can get is whichever line is highlited when hitting ok on the zenity dialog to print.the data in the csv is arranged:
AKA "zipping on the fly .. the slow-as-molasses way." The list includes full pathnames to each file, and they're all in subfolders of the same parent folder (which, unfortunately, is not the root folder of the drive or system on which the files reside). A cleaned-up and radio-ready portion of the list looks like
What I'd like to be able to do is zip all the files in the list into a single archive, to avoid the step of having to copy them to the same location (presumably another folder on the HD) and then zip that folder. I'm more inclined to make provisions about extracting to a single folder at some other time. Is this possible in BASH, or would I have to consider a faster, more robust scripting language such as python or perl?
I need to fgrep a list of things which are in a file. The file in which I will do the SEACHING is a large text file and I need fgrep to output each item from the list as a file with the item from the list as the file name.
how to make a list of all mp3 ogg or any other files in linux and save it as csv. Or, do somebody know a program or python script which allow you to do that by just pointing at the location with this files??
I'd like to turn the output of "yum list installed" into a file list I can use to setup other machines? Something similar to "yum -y install < listofinstalled.txt" or something?
I'm not sure if this is best done in Perl or Bash. I'm thinking surely someone else has created something close to what I'm looking for. The results of the script would be that someone would kick off "linux_hosts.sh" r whatever you want to call it, then a top "folder" of options (with hosts contained within each of these top menu choices), then, based on which number corresponds to that top level, they're presented with a set of linux hosts that are relevant to that top level name. Example:
$ linux_hosts.sh 1. VMware hosts 4. Private Domain 2. ESX servers 5. Red Hat boxes
I have a bit of a problem and the only solution I can think of at the moment is a very tedious one, so I was hoping there would be a better way. What I am trying to do is cross compile the PPPD program so that I can install it on an embedded system (this system does not have make/gcc on it). It was easy to cross compile it, but I can not run "make install" since I'm compiling on a secondary machine. I don't want to install PPPD on this secondary machine (I couldn't anyway, because it was compiled for a different architecture) and I can't run make install on the target machine because there is no make/build system for it.
So it seems like what I would have to do is to manually copy over each compiled file from the build machine to the appropriate location of the target machine. And the only way (that I know of) to figure out how to do this is to manually examine the Makefiles (yes, there are several for PPPD) and figure out which file should go where on the target system. This isn't trivial because it uses a hierarchy of makefiles and the probability of human error for this method is high.
Is it possible that I could run another command that would give me a list of all the commands that make install would perform? Or a list of all files and their target location for "make install"? Or possibly some other solution that I am completely unaware of that would make this task not so painful and error prone?
I need to, through a bash script, go through a given directory (given as argument 1) to list out the relative path in this directory (including $1) for eact subdirectory which contains files. Directories which only contain . .. and eventually only subdirectories SHALL NOT be listed. It is this last requirement that makes it difficult for me.
I have been using the tree command for now, but I have not found a way to ignore paths to directories which only contains other subdirs or nothing at all in any easy way. I may offcourse test each directory after they are listed but this gives an extra loop to go through and I beleive it should be possible to do it directly when creatring the list. I guess by using find or ls in conjuntion with the tree command or by itself it should be possible but I am not to conversant of nested script commands.
bash: how do you make the construct ${var%% *} work? I am trying to select the first word from a variable which contains many space-separated words. I am running Ubuntu 10.10 with GNU bash, version 4.1.5(1)-release (x86_64-pc-linux-gnu) and when I try to use this construct, the expression returns the complete variable with no removal of trailing anything.
Is there a way to make a dialog with zenity which would show an updating list? Zenity does it with progress, but I didn't figure out if it's possible to do it with the list. I.e. for example, I want to monitor something, and update the dialog with new list periodically. Is it even possible? zenity can wait for data from stdin, but it just adds stuff to the list. May be there are some control sequences which clear the list in the dialog?
I have a script from which i want to disable unwanted services. I wanted to have the list of unwanted services in the same script file. I tried the following, but it is not working...How do I mention list of services in the same file and still make the script work ?
Code: #/bin/bash #List of services, modify list between SERVICES tag service_list=$(cat <<SERVICES acpid apmd avahi-daemon
