Is there a way to extract the last field? Specifying the field number is causing problems using awk or cut as the input log file has the output specified in different lines at different places/fields. The only thing constant is the 'pathname' which always occurs at the end.
View 3 RepliesI'm trying to display fields from flat files where the first 8 fields are always the same. Fields 9 - n are varied but will contain specific patterns I'm after. I'm using this so far because "mySearch" is on each line I want to examine.
Code:
How would you pattern match and include 2 additional fields above field $9 but change field position from line to line?
I have a file with variable length lines containing fields separated by colons:
Code:
path/to/file0.c:4150:109:4151:142:4153:275
path/to/file1.c:4040:109
path/to/file2.c:4605:72:4606:109
path/to/file3.c:4380:54
The first field identifies the file name, the second is the search key, and the third is the line number of the file that the search key points to. Any subsequent fields are other key/line number pairs.
As an example, I can search for 4151 (key) from my bash script to identify the file I will have to access, but I also need to capture the line (142) as well, and I can't figure out how to do that using grep, awk or sed (or anything else).
I've had a very colorful morning learning the innerparts of Linux's sort command, and have come across yet another issue that I can't seem to find an answer for in the documentation. I'm currently using -t, to indicate that my fields are split by the comma character, but I'm finding that in some of my files, the comma is used (between double-quotes) within values:
Jonathan Sampson,,foo@bar.com,0987654321
"Foobar CEO,","CEO,",ceo@foobar.com,,
How can I use a comma to terminate my fields, but ignore the occurences of it within values? Is this fairly simple, or do I need to re-export all of my data using a more-foreign field-terminator? (Unfortunately, I do not have any control over declaring a different terminator with this particular project).
The thing is that the command for sed resembles the following
[code]...
Now if I want to place another command like grep or cut in the address field how do I do it. Actually I don't know the line number. The user has to give it as an input. How shall I do that?
How can print the, let's say 5nd field to the last field of every record (let's say we have 10 fields)?
I mean: I cant avoid to have to do:
print '{$5 $6 $7 $8 $9 $10}'
I am creating a game with random variables. In the game I have created a dialogue exchange to players. I have set up a table with various returns and I inserted {$fields} to represent various random variables. When I call on the requested fields, I only see the field text and my field names. Am I supposed to parse something and call it back another way?
ie: myfield is: "You have won {$random1} silver! <br />{$wi['gender'] majesty rewards you well." the code I am using to call that field is:
I just recently learned about the wonderful little lpr command- and using man -t (bash command) to beautifully print man pages for reference- but is there a way to print both sides of the paper using a printer so equipped?
View 2 Replies View RelatedI have a debian system installed on my pc . I have just saved a text file on my desktop . Please let me know how can i print the file through comand prompt ? I need to learn the printing the file thru comamnd line .
View 1 Replies View RelatedI am trying to understand the join command. I wish to join two files:
Code:
$ cat test1
a 0
b 2.51
c 19.85
$ cat test2
a 0
b 2.51
[Code]...
this is great but I do not understand why join ignores the -e flag and fails to insert FOO in the empty field.
i have a file : file.dat with following data
Code:
STORAGE PERCENTAGE FLAG:
/storage_01 64% 0
/storage_02 17% 1
/storage_03 10% 0
/storage_04 50% 1
I need to get the value of PERCENTAGE in a variable for a value of storage passed as variable i have tried the following without success like :
Code:
percentage='awk -vx="$defaultStorage" '{FS=OFS=" "}$1==x{print $2}1' file.dat
I am trying to find a way to print PDFs from the command line. I was using "cups-pdf', but I want to be able to specify the output folder from the command line. Is there a way to do this? I guess what I am trying to do is the Gnome "Print to file" option in the terminal so I can easily print off a batch of file to whatever directory I wanted.
View 4 Replies View RelatedI am trying to write a program that monitors when an lp or basically any sort of print command is issued. If a print command is detected I want to pause that job and ask the user if he / she wants to continue.
This program would run in the background all the time so it can't sit and eat up a lot of cpu. I tried a simple while loop that continuously monitored "ps" and that obviously boosted my cpu to 100%.
I am creating a script to sync my important documents between two system. I want my script to generate a log file for the last action. can you suggest me a way to achieve this.Question: If I execute the rsync command with -v flag, it will print a lot of messages on the console. Is there any way. So, I can redirect these logs to a file?
View 4 Replies View RelatedI am looking for a way to print the timestamp of a directory using find command. I can do that for a file, but for a directory, it is printing the contents of the directory as well. Lets say there is a directory called doc, and there are more than one occurrences of that directory.
find . -name "doc" -type d -exec ls -l {} ;
This is printing the contents of all the files under doc directory as well.
I am using an awk command to print a line from a cvs file.the awk command includes an if statement that filter the output-lets say i want to print all the lines that the price field is greater than 30.i have it working when i put the parameters myself.. but when i try to send them with vars it wont work..i am sending the sign of the if statement - can only be: == , < , >it looks like this:
cat file.csv | awk -v sign=">" -v field="2000" '{if($3 sign field) printf "%-12s%-12s%-12s%-12s
",$1,$2,$3,$4}' FS=,
the bold part is the problem , because when i put the sign parameter myself t works great.. i guess its a chars issue but i cant spot it
When running certain programs (i.e. Nedit or Gourmet Recipe Manager) asking to print will give the following message: Enter print command:
Am using 13.1 32 bit with cups. Everything works properly and prints properly I just don't know what to enter for a 'print command'.
Have tried entering lpr and cups.
1. lp file_with_english_chinese2. lp -ozh_CN.utf8 file_with_english_chineseThe normal ascii characer prints ok but the chinese character are blank.
View 4 Replies View Relatedhow to use multiple linux cut comman to display on same line ?
e.g ls -il | cut -f6 d:
ls - il cut -f9 -d:
The linux script output is
filename
123
How to use cut to display on same line ?
I am writing an expect script and I want to send the command for the print-screen function. So, what is the command? Alternatively, is there some terminal application which may be well suited to take screen-shots via commands from the terminal or automation scripts?
View 2 Replies View RelatedI'm hoping this is the right category. Is there a terminal command to display what network you're currently connected to?
Example:
My home network's name is (in this example) "home".When connected to it, I want a command that, when run, would give me the output 'home'. Does such a command exist?
I am just trying to print the timestamp. which is not working.
#!/bin/bash
TSTAMP= date '+%d.%m.%y-%H:%M:%S'
echo "${TSTAMP}"
It is not displaying anything. What is wrong with the above commands.
This pretend to be a script for rename a lot of files automatically. So I put the list of files in an array named @lista. But, as you can see, at the end of the command I use a sed filter to print out a backslash for those files that have spaces in their names, so the path for those files could be rightly interpreted.
But there's no way I could print a backslash. It works well when I use the Perl's sed substitution s///, but I need every path in the array to be fixed.
I'd like to add that the bash command works perfectly well alone. I mean outside the Perl script.
This is de command line with the sed filter:
Code:
And this is what it brings:
Code:
I work at The University of Alabama as a sysadmin on various HPC resources and also provide support for faculty using Unix systems. I've run into one problem that is affecting two different desktop systems running CentOS 5.3.oth of these systems have the latest updates. These machines have standard network-attached printers. One is an HP LaserJet 3250 and the other is a model that is pretty close to that one.Previously these users were able to print from graphical applications such as Firefox, but now when the print dialog is opened on ANY graphical application, it causes a hard freeze on that particular app.Printing from the commandline via `lpr` gives no issues and test pages from the Printer Admin interface also succeed.This problem has me stumped, so I'm looking for any insight as to what could have changed. I do not know what changed between the time when the printers worked graphically and when they stopped, but the users assure that they have changed no settings. The only thing I can suspect is a rogue update since this is affecting separate users on separate machines with separate printers.
View 4 Replies View RelatedI loaded FED 13 and running kernel 2.6.34.6-47 fc13, Now back from holiday, I'm trying without success to sort out a few problems. 1 can not print. the printer sets up OK epson R285, but can't print test pages or from any app, or from CLI with lpr command. Cups log shows this:-
[Code]....
I want to print Landscape and I would normally use Code: lp -ddestination -olandscape However this isn't working, it could be another problem (I am passing to a windows print spooler) but I would like to know if I have got the command right.
View 1 Replies View RelatedIs it possible to print the permission in octal format for a directory recursively?Code:
stat -c "%a" /etcIt prints the permission for /etc directory only.
How to print a sequence of line say line number 10 to 20 of a 50 line file ?
View 6 Replies View RelatedLet's say I am pinging a host, and want to output to a file each reply and its timestamp of when this started.
I know that it can be done with a loop and a shell script. Something like this
DO
echo "$(date)" >> results.txt ###includes the time and outputs results to txt###
ping -c 4 HOST >> results.txt ###a total of 4 pings at a rate of 1 per second###
REPEAT UNTIL USER PRESSES CTRL-C
Now, my first issue is that I need to be able to see results real-time as well.
Is there a way one can print to BOTH a screen and output? If one uses the ">>" command, it is essentially sending everything to the file. Running another ping command in parallel is not an option.
I have a requirement to print images (two to be precise) from the command line of a given size and without losing too much quality.
So, I may have two images, a.jpg and b.jpg which may be 4x4" and 6x4" respectively (the sizes may vary). I need to be able to print both these on a single sheet of paper (one under the other) at a given size for each - so a may be 2x2" and b may be 3x2" - the aspect ratio will always be maintained (or as near as possible!)
I am currently doing this a very messy way (because I don't know any other way!!) - basically I am converting the picture to a given size using a set density using convert and then concatenating the two using montage.
Here is part of my script:
Code:
Don't worry too much about the case statement at the end - that is just to be able to select to print either A, B or A and B.
The issue with this is that is doesn't work great if the aspect ratio is not maintained perfectly and also, it loses quite a lot of quality on the print.
I have a very old windows app which I wrote years back in VB (o dear! ) which does the same thing and the quality is fine (I am running it through wine). I want it to be command line though because I want to run it as part of other scripts etc.