I need to create a script that returns a list of the users who have never changed their password from /etc/shadow. As I know on linux there is a command "chage" used for find last password change.
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I need to create a script that returns a list of the users who have never changed their password from /etc/shadow.
As I know on linux there is a command "chage" used for find last password change. Any idea about solaris command?
I've compiled the latest version of shadow (without PAM and selinux support), but I can't create new users or groups. I don't even get a error.
It's just like:
bash-4.1# useradd -d DIR -u NUMBER USER
bash-4.1#
but if i take a look at the /etc/passwd or /etc/shadow file there's no entry.
How would I list 4 users ID numbered 10, 11, 12 and 13 from my users list and output them to a file busers where their names are numbered by ascending order? How would I accomplish that on a one line command?
View 4 Replies View RelatedI need to see who all the Samba users are. Some other distros keep that in /etc/samba/smbpassword file but I don't have that file here.
Using Slackware 13.1 (64)
I'm working in a school and we have a Apple server, we have many problem with it. So, I would install a linux server instead.
Anyway, there is just one big problem (or I miss a simple tip to do it )
We have 1300 students. If I must create them one by one, that will take a lot of time. Actually with the apple server, we can go on a web interface & import an excel list with theses columns :
"Name", "Login", "Password", "Class", "Group", "HDD Space", "Print quota", "Internet access or not", etc ...
Due to this tool, I can upload an excel files with my 1300 students & a couple hours after, they have an account with a personal space & a shared space with their class.
My question is : This tool exist on Debian/Linux world ?
I want to use samba in ubuntu.For samba users i make a user in my linux box like
# useradd smith
# useradd jone
These users can also login into my ubuntu system if they want. For samba I want to know that, is there any way to create separate valid list of samba users so that they may access files from windows xp.
It is possible to check who logged in with "who" command. If we are also logged in to that linux pc.
But, is there any possibility to check without our login?(not even by ssh)
Our logging in to find that pc, will be wasting the cpu resources. And may disturb the user who is working on the x-session.
I have a file with 5000 lines. it is a list of books authors, series and titles. all lines start with the author names, than there is a dash (-) than the series name, a dash again and the title of the book.
The problem I encounter is that sometime there is a series, sometime not, and as I try to enter this list in a database, I wanted to create a cvs file to import into mysql.
ex:
The best would be to be able to add in the second line, a "space dash space" just after the author name, but how to make sure it does not do it to the first line as well.
If I could separate all line with 2 dash, (grep ?) then I would be able to do a simple replace, and change the single dash into two.
I need do a small interfaz, it works under bash. I read the user name and password from the terminal then i need validate this data.
My principal dude is:
how look in the /etc/passwd file a user and passwd?
The problem is the password is encrypted and i need compare with the data I read.
Only I can use BASH because it is school homework.
I want to create a webpage where users can change their samba password and before I jump to PHP code i want to write perl code that can be called in php code.I have created two file 1. main.pl - this script actually switch user and call passwd.pl2. passwd.pl - this is actually changes the password {main.pl}
#!/usr/bin/perl
my $username = $ARGV[0];
my $oldpass = $ARGV[1];
[code]....
I came across this script a while back that i found. What i want to do is edit the script to create a default web page in /var/www/html a new user is added through the script.What the script does now is adds a user and sets a password for the user. What possible way (either through a combination of python or c or some other language) could i add to the shell script to do this? I've tried just dointhe command to touch index.html /var/www/html but it puts it on the desktop. Here's the script....
Code:
#!/bin/bash
# Script to add a user to Linux system
[code]...
I am trying to create an array that will allow me to print a list after selection such as:
1) Location A
2) Location B
3) Location C
Would you like to print selected locations? Print I have no idea how to approach this problem and don't know whether Perl, Bash or shell script would be the most useful in this particular situation.
I wrote a program to create a link list
Code:
#include <stdio.h>
#include <stdlib.h>
struct node {
[Code].....
how to dynamically create a list within a dictionary using Python.
Code:
dates = defaultdict(int)
array = []
...
dates[m.group(3)] = array.append(date)
dates[m.group(3)] = [array.append(date)]
dates[m.group(3)].append(date)
None of the above works and I've tried everything I can think of.
I am moving my Linux server from Suse 10 to Ubuntu 9.04 and I moved the significant parts of /etc/shadow, /etc/passwd, and /etc/group over to Ubuntu 9.04. I am not able to login into the computer with the old accounts. The only problem I see is that the old accounts use Blowfish and DES to encrypt the passwords in /etc/shadow, and Ubuntu uses SHA512. If I change the passwords, the accounts will work. However; I have about 300 accounts to move, and I don't want to do that to all of them. I have tired Ubuntu Forums and talked to every linux expert I know, and no one has an answer.
View 7 Replies View RelatedToday i was going through some of security guides written on linux .Under shadow file security following points were mentioned.1)The encrypted password stored under /etc/shadow file should have more than 14-25 characters.2)Usernames in shadow file must satisfy to all the same rules as usernames in /etc/passwd.3)password for application Username should display * if username is not locked.4)If a user is locked it should be displayed as ! as the first character in second field of shadow file.
Confusion for point 1 and 2:Now i m confused as why the encrypted password should be more than 14-25 characters.Also what rules to satisfy How to check it?Confusion for point 3 and 4:There are lot of users with * as second field i guess they are not locked but according to 4th point there are lot of users with ! as first characters.How would i check whether they are actually locked or not.I m posting the output of /etc/shadow and /etc/passwd files for the account.
The /etc/shadow file contains an id of $1$, $2$, $5$ or $6$ to show the encryption method used.A salt follows this,followed by the password hash.When a user is created and a password is set, a hash is RANDOMLY generated and used as the salt to the password hash. Everytime that user logs in, login checks /etc/shadow for the $id$ and salt and runs the password given by the user through the hash mechanism ($id$) using the salt in /etc/shadow.So basically does login look at /etc/shadow for the $id$ and salt to create a hash with which to compare to the /etc/shadow hash?question 2 - If my $id$ was $5$, which is sha256, how would i go about changing this? Like is there a shadow.conf or crypt.conf or something? Can i change it per user?
View 2 Replies View RelatedI need to manually convert an string ( like with echo ) to a DES crypt format to be inserted inside a /etc/shadow file, does anybody knows how can I do that?
Maybe there are some little tool that could handle that operation, well.. I don't know, hope someone can give me a hint on that.
I noticed that our /etc/shadow file is readable on a patch I released for one of our in house linux boxes a while back ago. Could they use it to gain access the root account etc? Our passwords are all MD5 encrypted.
View 5 Replies View RelatedHow to create the password hash exactly the same as in shadow file (from the command line)?
The command
openssl passwd -crypt
returns something different.
I would like to grep all values other than encrypted password from /etc/shadow fileFor example,each line consists of 8 fields separated with :/The only thing that I want not to print out is the contents between first : and second : (encrypted password)
View 7 Replies View RelatedI am working on building a customized ISO image of a server based on linux. The thing is after the server is installed and run for the first time, three users have to be created for the various services to run properly. I want this to be automated. To achieve this what is was thinking is automatically enter the user entries in the /etc/passwd and /etc/shadow files through init scripts when the server starts for the first time after the installation. I tried creating user and assigning password in one of my machine, and the /etc/passwd and the /etc/shadow entries of this user I copied it into the other machine and tried login in on the other machine and everything worked fine. How I am trying to achieve this.
View 1 Replies View RelatedI want to know, how does changes happened in the encrypted password in /etc/shadow file , when user changing password . because user doesnot have access on that file
View 1 Replies View RelatedI am trying to write a remote access module. Is there any function in linux where I can give string (password entered by user) and compare it with the actual user password stored in /etc/shadow. Since the password is stored encrypted in /etc/shadow I cannot parse and compare. So I want some method to compare if my user entered the correct password..Is there any function for that..
View 6 Replies View RelatedI am bulding my own image based on 2.6.32 kernel, I wish to add a guest user:
In a script thats invoked by the makefile, I use 'useradd' command & this updates the shadow, passwd files under /etc on the host, is it possible to tell the command to create the shadow / password under some other folder on the host? may be /tmp?
I'm trying to write a script that will prompt the user for a username/password, then create that user/password in the right groups on all my machines. I know this is kind of a long way around to avoid a NIS server, but I like making my life more difficult.
This is what I have so far:
Code:
the script has 2 problems: The "if" functions return an error and do not compare the strings successfully. whatever password is entered does get applied properly and the user is unable to login
create a tar file from a list? My script returns the error: AttributeError: 'list' object has no attribute 'startswith' I want to create a compressed tar file containing the directory /usr/lib and the files in the list assigned to variable b.
code:
import tarfile
tar = tarfile.open("backup.gz", "w:gz")
[code]....
I've been trying to write php or perl code to generate the sha-512 password hashes in fedora. I've been unable to do the hashing which is encoded in the shadow file on fedora core 11. Does anyone have php or perl code which provides the hashing algorithm. (All of my attempts result in the encrypted hashing being longer than 86 character -- the length that crypt says the sha-512 should be)
View 3 Replies View RelatedI'm getting these entries in my auth.log file. What is it and why it is returning passwords?
Code:
May 26 12:57:50 infecticide dovecot-auth: pam_unix(dovecot:auth): authentication failure; logname= uid=0 euid=0 tty=dovecot ruser=david rhost=88.148.51.170
[code]....
