Programming :: Bash Search Line And Replace Hex To Binary?
Jul 7, 2011
I need a command to search a string in a file and then to convert the next string in the same line from hexadecimal to binary. I was able to put everything in capitals. The original file can be as such:
E 2
C 1 794
T ffff
E 2
C 1 787
It is not always FFFF! I am trying to do this in a file at once, not reading line by line (using while).
i need to change a binary file, let's say to find and replace username:
find string: "/home/name/bla-bla-bla/ " new string: "/home/anewname/bla-bla-bla/ "
i can do it, for example, in emacs (hexl-mode), but interesting in writing a script instead. it will be much more better for me if i could do it automatically. is there an analog of: sed 's/string1/string2/g' ? P.S. the best way is to recompile the binary files i have, but there are no sources available.
I want to search a file for a particular pattern and if pattern found replace the line with new text. i am using awk 'match($0,"pattern") != 0 {print $0} ' filename to check if the pattern exists.how do i get the line number of the pattern and delete that line and replace the line with my new text?
Hello, I need some help searching through multiple files, finding a line and replacing that line. The line I am searching for is:
password key ******* 1222554
ultimately I want to be able to delete the numbers after the asterisks . my thoughts are to create a script that will search for the line password key ******* and delete it then replace it with password key ******* my files are located in /opt and they are all txt files.
I've got a bit of an obscure question for you to test your brains a wee bit. I'm trying to implement a search program to find areas of high density in a binary string.
Where density is the number of 1's / number of digits with a maximum number of digits being the current number in a buffer (in this example 50). So for the example the density for the whole buffer is 15/50. But the density of Buffer[14..20]=[1110001]=4/7. So if looking for areas of density = 1/3 it would find the longest sequences of density over 1/3.So in the example. Buffer[4..9]=[100101]=3/6=1/2 which is above 1/3 but it is within the Buffer[4..48]=[100101000011100010000001000100100001001011001]=15/45=1/3
I'm trying to use sed to search and replace backwards. The problem is that I have a shell script that is required to put commas into big numbers. For example
9999999 as 9,999,999
I've tried a few things, but none seem to work:
Code:
$ echo 9999999 | sed -e 's/([0-9]{3})/,1/g' ,999,9999 $ echo 9999999 | sed -e 's/([0-9]{3})$/1,/g' -e 's/([0-9]{3})/1,/g' 999,999,9, $ echo 9999999 | sed -e 's/([0-9]{3})$/1,/g' -e 's/([0-9]{3})/,1/g'
[ode]....
It would be much easier if I could search backwards! For example Bash parameter substitution style:
At the moment I have a flat file which is being used by a few people. I want a script to remotely change the file, so I can start logging who is doing what.At this point here is one requirement I am trying to develop. We have text blocks who pretty much look like.I hope this is somewhat clear. I try to find $param for the right $workflow and change that. Can you help me to find $$var3 and change that?
I'm wanting to mod some PHP files across a hierarchy and thought I'd drive it with find + grep + xargs
I built up a command line which I was confident would do the job, but now can't save the results.
First I tried this:
Code: find . -name *.php | xargs grep serialize | cut -d: -f1| sort -u | xargs sed -i s/serialize/serialise/g but that didn't work: Code: sed: illegal option -- i so I thought I'd try using Code:
As indicated in the subject, I want to search a text. If the text is present I want to replace it. But if the text is not present, I want to insert it after first line and before last line.
Something very handy to do in a Linux shell, is manipulating files and strings - essentially parsing data. Write a utility which will scan in a text file and search and replace strings. We also want to keep track of how many strings we've replaced.
I know that my command would look like this: <utility name> <filename> <stringToSearchFor> <stringToReplaceWith> Code: #!/bin/bash
I would like to know how do I print the line # in a script. My requirement is, I have a script which is about ~5000 lines long. If there are any errors happen I just exit. And I would like to add the line # of the script where the error happened.
bash 3.1.17(2) I'm trying do write a shell script which must operate on each line of an ASCII text file. So, all the code must be inside a loop, and inside the loop, the first thing should be to read the next line from the file. I have the bash read command. But it reads from stdin. Any way to make read from a file?
I'm trying to make another file annotation script a little speedier than it has been by the up-until-now proven method of checking the last four characters in a filename before the "dot" (eg .jpg, .psd) against a list of known IPTC categories and Exiv2 command files. It occurred to me that if one script generated a list of files in directory foo, and the same or another script sorted that list by that four-letter tag,then that list could be used(instead of a for/do/done loop on the real files in the folder) by the command-file-matching script to "vomit out" which annotator file would go with file nastynewfile.jpg, f'r'instance. The script I had been using for this task looks like this:
Code:
while read 'line'; do sp=$(echo $line) vc=$(echo $sp | cut -d"," -f1) cv=$(echo $sp | cut -d"," -f2)
[code]....
Where I seem to be stuck is with how to sort the lines in templist, which may be any number of different lengths, from back to front. sort -k looked promising, except it seems only to work the other way round. I thought of invoking a
Code:
q=$(expr length $line); echo $q n=$[q-8]; echo $n
kind of thing, but that presented the problems of how to sort by those, how to tell sort where to find them (grep?) and how to "stitch them back in" to the original list, which is what I want to sort in the first place.
Im looking for assistance to create a script to find and replace files.Probably best if I give you the background Our server uses a specific application which stores user data, each user data account (a folder on the server) has a file called 'Profile.xml' this file gets updated and replaced about every 30 mins similar to the fashion logrotate works i.e. Profile.xml.1 Profile.xml.2 -> .10
What we experience is that if the application crashes unexpectedly while it is doing its user profile refresh task we end up with sometimes a few hundred Profile.xml files which end up 0kb(should be around 4kb) , and our server see's these as corrupted profiles and will not see them. Our fix is to go back thru and rename the Profile.xml.1 to be Profile.xml (or sometimes up to Profile.xml.5 to Profile.xml) We want a script we can manually run to automate this process The server tree is
I need to replace a line in the lvm.conf file from: filter = [ "r|/dev/.*/by-path/.*|", "r|/dev/.*/by-id/.*|", "a/.*/" ] to: filter = [ "a|/dev/cciss/c0d0.*|", "a|/dev/disk/by-id/.*|", "r|.*|" ] And I was hoping there was a way to use sed or awk to do this in a script (as I need to repeat this on several machines).
All of the examples I've found don't see to work with all of the special characters in the line that I need to replace. Then I need to add a line after the above edit like this: types = [ "device-mapper", 253 ]
I would like to have a script that will do a search in an XML file for a specific block of XML code and replace it with a different block of XML code using the Windows build of GNU Sed 4.1.5.
Here's the text I want to find:
Code:
And here's what I want to replace it with:
Code:
There is however a lot of stuff in there that would mess up sed, and the one example from the sed FAQ (from the Sourceforge site) that looked promising and easy enough to figure out (4.23.3. Try to use a block of "literal strings") fails with this error message: sed: file blockrep.sed line 18: unterminated `s' command
Anyone got any ideas, or even an alternate program that can do this? (Preferably one that I can automate.)
Here's the actual line of code, which exists in a bash script:
Code:
I want to replace instances like this:
Code:
with this:
Code:
Using this:
Code:
Which works great when there's only ONE of the pattern on the line. But in a case like the "actual line" I posted first, where there are two patterns, separated by a slash, only ONE gets replaced
Watch:
Code:
Why? There must be (among many other things) something I'm not knowing about sed, that's causing this.
-- I'm currently using the ~ (tilde) as the separator in the sed command. It doesn't matter, I've used / ~ and % with no difference.
-- As a test, I tried putting a different character(s) in the middle of the original pattern instead of the / but that made no difference.
-- I've come up with various similar but slightly different regexs that will do this replacement, but they all have had this same result.
-- I tried the sed single-quoted, double-quoted, and unquoted; the latter fails to execute, and the formers both work as described here: wrong.
I am bouncing a file across platforms (windows->solaris->mainframe), and the file is starting out with a "special" character (the registered trademark "circle R") in some of the records. This character is not in the EBCDIC character set on the MF, so it is unrecognizable. The MF developer I am working with asked if it is possible to replace the character with a specific hex value (AF) before it gets to the MF.
I was putzing around with sed, tr, etc. on the ksh command line, hoping to find an easy way to get one of them to substitute hex instead of ASCII. I have found that the usual shell utilities recognize the trademark character, so homing in on what to replace is solved. But I cannot get anything to actually substitute in the hex sequence I want. E.g. I was thinking something like...
>cat special_file | sed 's/R/AF/g'
But my version of sed does not seem to have hex "editing" capability.
Does any one know what syntax i could use to allow me to replace all instances at the beginning of a line with ones.
Before :
Code: ---------------------------------------------------------------------- Logical device information ---------------------------------------------------------------------- Logical device number 0 Logical device name : RAID1Mirror RAID level : 1 Status of logical device : Optimal
After
Code: ---------------------------------------------------------------------- Logical device information ---------------------------------------------------------------------- Logical device number 0 111Logical device name : RAID1Mirror 1111RAID level : 1 11111Status of logical device : Optimal
I am beginner in this business of shell script and I have no idea how to do the following: I would like to replace the lines of my file that contains 'CFL=' by 'CFL=0.5'. Note that I want to replace the full line meaning
I wanted to find and replace a string from a perl file. I have written a script in bash which runs the following command.
perl -pi -e "s/$findstring/$replacestring/" testfile where as $findstring = print F_WC_TMP"$line "; and $replaceString = $line = join ' ', split ' ', $line; print F_WC_TMP"$line ";
But when I am running the above command, i think it is replacing the $findstring with the above mentioned string and hence it contains a $line, it is looking for the variable $line and not finding the exact string. I am confused about how to search for a string that contains $ in it and replace it with another $string.