I have a script that that is supposed to send me an e-mail when a host is not responding to ping:
The script works fine when I execute it directly but when cron executes it, the ping error is never picked up by the script so the if statement is ignored.
*I'm using Ubuntu 10.10
My issue is I can't handle the files with spaces in their name, I've donde the below script to print each file found inside folder and subbfolders with "find".
I would like to "ls" to each file found with its complete path and with its basename too.
Code:
files=$(find . -type f)
for each in "$files"
do
ls -l "$each" # 1rst option I've tried to list with full path
ls -l "$(/bin/echo "$each")" # 2nd option I've tried to list with full path
ls -l "$(/bin/echo $(basename "$each"))" # 1nd option I've tried to list with it basename
[Code].....
How can I list "ls -l" in both cases (with full path and with basename) when there are files with spaces in their name?
I have an rsync script I wrote that I have tested and it works perfectly when I run it manually. Now I am working on a server setup script and I have gotten my setup script to create the rsync script in /etc/cron.hourly and restart crond. To spite the fact that the script is in /etc/cron.hourly and I have restarted crond, the script does not run. With that said, how can I script adding the rsync script to run hourly as a cron job?
View 9 Replies View RelatedI have a function in perl which I want to use trap all errors a script ocurs which the script does not explicitly handle. These errors are then logged to various places. So I tried to use a eval block but the problem I have is sometimes if you put a die statement in the evaled script it doesn't get handled. What I have so far is:
[Code]....
Script programming question for the experts. I have written a bash script that works fine if I execute from the shell interactively. However, once I schedule it to be executed via cron, it just wouldn't work. I believe this has to do with cron running in a different environment than the one I am in when I putty in.
The bash shell script does refer to environment variables in the .cshrc file. I guess these aren't available to the cron? How can I load them into the script if I want them to be available to the cron locally within the script?
I have this project which I've been working on essentially nonstop for the past three days and due to work I am running low on time. I'm new to Linux/Unix and my Teacher has assigned us a scripting project, due for Monday. I have All the functions for the project in a separate file which run as a daemon process when I log in. It has no syntax errors but my Script can not run the functions (I'm not sure where they go before or after the body) and I have one function I'd like you guys to take a look at. It has a Second menu leading to a case statement but it does not run after the Search. I'm Kinda tired of looking at the CLI but I have to finish this.
phoneEdi() {
directory=~/phonepro/directory
loop="y"
clear
tput cup 4 4; echo "Record Editor" .....
i have a script where i need to pass an argument "1234:-)"if i run this as ./shell.sh 1234:-)it wont work because invalid character. i need to handle this with expect utility so if i pass it as ./shell.sh "1234:-)"no issue in bash but expect does not recognize this.
View 7 Replies View RelatedI'm running CentOS 5.4.In the last three days I've started to get various cron errors:
/bin/sh: line 1: 7066 Segmentation fault /usr/local/scripts/cron.email.sshd.access/cron.email.sshd.access.pl
/bin/sh: line 1: 4822 Floating point exceptionsudo -u mobile getmail --quiet
Can't load '/usr/lib/perl5/vendor_perl/5.8.8/i386-linux-thread-multi/auto/RRDs/RRDs.so'
[code]...
Then yesterday I rebooted, and all the other errors seemed to have disappeared for now, but, I am now getting:
/bin/sh: line 1: 23600 Segmentation fault sudo -u mobile getmail --quiet
I have setup cron to call getmail once every 3 minutes, and I get this error about 4-6 times an hour.
I am running Valgrind on my program. It shows me two errors but mentions only addresses against them and not actual code even on a debug build.
The output is
==23002== Memcheck, a memory error detector.
==23002== Copyright (C) 2002-2005, and GNU GPL'd, by Julian Seward et al.
==23002== Using LibVEX rev 1575, a library for dynamic binary translation.
[code]....
I've got a bash script that uses rsync via SSH to back up data from a remote webserver.
This script works fine when I run it myself but when it runs as a cron job I get the following error:
Code:
2010/02/20 08:15:01 [6786] Unexpected remote arg: user@www.server.com:~/www
2010/02/20 08:15:01 [6786] rsync error: syntax or usage error (code 1) at main.c(1219)
[code]....
I have a script that pops up a jpg file several times a day as a reminder. The script is called up by crontab and it works perfectly.The issue is that I want the script to also perform a system "beep" in addition to popping up the jpg file. When I test it on the command line everything works but when I run it in cron the jpg file pops up but the beep doesn't beep. I'm thinking the problem is in the "echo -e \a" part. I must be missing something.Here is my script:
#!/bin/bash
echo -e \a
sleep01; echo -e \a
[code]....
Code:
#!/bin/sh
chown -Rc steven:users "/home/steven"
I have more lines in the script but each line does the same error. This is run in a cron job but it always returns.
Code:
chown: cannot access `/home/steven
': No such file or directory
But it is a valid directory I have even tried adding an / and even a space on the end and still same error.
I have a personal server and a dynamic IP address, so I wrote a script to check the currently assigned IP address and compare it to the one stored in a file from the last check, and visit the update URL if it's different.
View 4 Replies View RelatedI'm really running into a wall trying to figure this out. I have a Bash script and narrowed down the one command that doesn't seem to work via cron and it's my pgp decrypting line. Works fine if I run the command via terminal but if I run it via cron it doesn't output anything.crontab -e shows the cronjob and it runs, creates the log file with no output. Is there maybe something I need to run as well? Permissions look set, unless the cron is running as a different user(was under the assumption if it showed up under crontab while logged into that user, then it would run as that user.
View 14 Replies View RelatedI am frustrated by running a script on the Fedora 14 computer as a cron job. I paste the code:
Code:
#!/bin/bash
#a backup script to copy data from sda to sdc
ROOTVOL=`blkid -U ea210a08-6212-4dc8-be1c-23fce3b965bc`
[code]....
So when I run this as root, for example:
Code:
# /root/myscript
the result is what I expect:
Code:
Jul 1 13:41:16 svn root: ADMIN: Executing backup-svn
Jul 1 13:41:16 svn root: using blkid ea210a08-6212-4dc8-be1c-23fce3b965bc as /dev/mapper/vg_svn_backup-lv_root
[code]....
Sometimes the variables will be 0 and sometimes not, and of course the output may also be 0%...What is the best method to handle division by zero errors in awk.
View 2 Replies View RelatedI have script which does file locking via flock and then writing it's pid into that file. It perfectly works being run by hand in terminal, running under cron on Debian, but somehow fails being run under cron on Centos 5.6. Script part and straced outputs are below.
bash code:
#setting lock
mylog "setting lockfile $LOCKFILE"
exec 200<> $LOCKFILE
[code]....
I would like to make program that reads a *.TXT file and searches for last line and constatly refreshing the search. So last line would look something like this:Mike Had A 100.0 Pound Shark.So there are multplie category of "fish"(Shark, Dolphin, etc.) and each of them have allowed weight (ie. minimum 70.0 Pound Shark, 50.0 Pound Dolphin). If in the found sentence Shark or Dolphin doesn't meet requierments than program named False.exe should be started. I dont know how to make it my self so any help is much appreciated. My knowledge on programming is very low but I'm opend for learning.
View 1 Replies View RelatedI'm trying to get cron to run a bash script every 15 minutes to change my desktop background
running crontab -e I added
Code:
*/15 * * * * sh /home/ME/Documents/scripts/background.sh
(at first i didnt have the sh before the path of the script but read somewhere i needed that) But it doesnt seem to be running my script works fine if ran straight from the terminal so Dont think thats the problem.
I want to write simple firefox extension / script or anything to change URLs from HTTP to HTTPS for selected websites (e.g. facebook). That thing is actually bypassing some security checks in my network.
Can anyone tell me how to proceed? I can deal with language as far its C++ or Python (something else would just take more time that's all )
I'm new to php and need some pointers to worth while documentation 'cause I'm getting nowhere I want to make a simple html form that allows me to submit a csv file so that I can work on it.The problem seems to be that if the file is not in the root of the (web) application it won't work.The form doesn't seem to send the path with it so I am unable to (1) know where the file is, I just get the name of the file and (2) I couldn't access the file anyway as it's outside of the apache environment.Is there a way to up the file to memory? How would you do this
View 3 Replies View RelatedI need to make a daemon which listens to port 81 for messages like [URL] So far I made a daemon which serves as a simple stream server: I set up a socket to listen to a non-reserved port (like 9999), but I don't know how to read the query strings.
Linux distro: Kubuntu 9.04
Language: C
I have a file with 200 000 lines and I want to append the fields of each line based on matching first field. The resulting file should have 70 000 columns but has "only" 18 000. The command I'm using is working perfectly with a smaller file, wich lead to 14 000 columns. Could there be a limit in number of fields that awk can handle ? Here's my awk command :
Code:
awk -F, 'END { for (k in _) print _[k] } { _[$1] = $1 in _ ? _[$1] FS $4 : $1","$4 } ' file > out
Also, this command writes ^M (windows line break) after each columns. Removing them is easy but where do they come from ? Working on Ubuntu 10.10
I'm learning Signals, and I have a question:
Is possible to make a handle when I press any of the keyboard buttons?
The SIGINT handles the Ctrl-C combination, but I want to handle if any keyboard button was pressed.
Need to handle SIGSEGV error when pbuf size is less than size. inside lib.:
for (i = 0; i < size; i++)
pbuf[i] = i;
A question of ODBC correctness - maybe someone knows.
Code:
// statement handle is sth, connection handle is dbch
SQLExecDirect(sth, ...);
// ... bind var, fetch results ...
SQLFreeHandle(SQL_HANDLE_STMT, sth); // free statement handle
SQLEndTran(SQLHANDLE_DBC, dbch, SQL_COMMIT);
(error checking removed for clarity).
To my mind this seems wrong - surely the statement handle should be free'd only after the commit is done? Or maybe not. I theorize about the ODBC library like this: a whole set of statements can be created, run, executed in one transaction (which is held at the connection level), and only after all that is a commit/rollback done. So maybe it's OK. Even so it still feels weird. What is written above works, but there are rare and very difficult to replicate problems with this code, and I wonder if a premature free might be the cause...?
I am using Fedora 14 and when I am executing a file:
#!/bin/bash
asd #assuming this command does not exist
I am getting following error:
/path/to/file: line 2: asd: command not found
I want to format it so it outputs error in same way as it would when it was executed from terminal:
$ asd
bash: asd: command not found
how to handle non argument error while adding two alphabets using 'expr' (not bc).
View 1 Replies View RelatedI would like to know how do I print the line # in a script. My requirement is, I have a script which is about ~5000 lines long. If there are any errors happen I just exit. And I would like to add the line # of the script where the error happened.
View 3 Replies View Relatedsimple bash code:
Code:
#!/bin/bash
trap "echo 'you got me'" SIGINT SIGTERM # to trap ctrl+c
echo "Press ctrl+c during 5 sec loop"
for ((i=0;i<5;i++)); do
[Code]...
How come code behaves normally and stops when ctrl+c signal is caught and resumes, but after I use at least one timeout read in the code it looks like, if signal is caught again it doesn't pause the execution but skips the loop. If you remove -t (timeout) option from the read, both loops look the same!