General :: Pass All Arguments To A Function?

I've got a sticky little problem with a bash script. Please consider the following code:

Code:
#! /bin/bash
processArgs() {
echo "Count = $#"
while [[ $# -ne 0 ]]; do
echo $1
shift
done
}

processArgs $* If I call this script with Code: ./script first second third it'll print each of the argument on a new line - exactly what I would expect. However if I call it with

Code: ./script "Single Argument" "Second-Argument" it splits the first argument in two using the space as a delimitor. The problem appears to be the call to processArgs, where $* doesn't honour the quotes around the variables sent to the script.