General :: Grep And Store Two Lines In Other File
Feb 16, 2011I have following contents
I want to grep "#2" and want the output as
How to using shell script?
I have following contents
I want to grep "#2" and want the output as
How to using shell script?
I have a list of words that I want to grep in many files to see which ones have it and which ones dont. in the text file I have all the words listed line by line, ex: list.txt:
check
try this
word1
word2
open space
list ..
I want to grep each line one by one. like I want it to
grep "check" *.log
grep "try this" *.log
grep "word1" *.log .. etc how can I do this?
and maybe write the output to a file.
I know how to use grep to output a line that matches a string. But what if I also want to output one line above every line containing a matching string, how do I do that?
View 1 Replies View RelatedDoes anyone know why something like:
echo lowercase | grep [A-Z]
Would still return the lowercase line even tho there is no match?
Using --color will show there is no match but the line is still returned.
I am still new but from what i've learned this should not work like that. ubuntu 10.10
I have a large file in which each line has three or more blank-delimited words. I'd like to code a grep to keep only those lines which have the letter M in the last word. the M (if present) will be the first character in the last word.
View 14 Replies View RelatedI have a file that goes like this:
I need to grep the lines between pattern 1 and pattern 2 and not the lines following pattern 2. Cannot use grep -A(num), as there are varying number of lines following pattern 1. Also, used awk one-liners, but results are erroneous.
I have done this before but i cant really recall now
I have a text file and i want to grep the word "interface" and 10 lines following it. I think there was some switch like grep -A or something ?
I have some big files of logs that contain errors printed by an app. They are most of the time relevant, however most of them are similar. So i figured i could check what happened between a time interval with a find.
Im using this one
Code:
And I get an output similar to this one.
Code:
Is there a way to condensate the output lines to get only one or two, indicating the start and last occurrence of a block? Or I need to create a program to do so?
Because right now I get thousands of similar lines, but when I'm scrolling through them i sometimes miss relevant information that i would've otherwise noted if it wasn't all that spammy.
I have this massive table file with some data in it and I want to replace some lines that are wrong with the correct ones that are in another table file of the same format. The wrong lines are not all together in a block but randomly distributed so I need to make a loop checking if the line is in the other file and if it is, replace it. I want to try and do it with sed or awk but I don't really know how to....
View 12 Replies View RelatedWas trying to write a shell script that has if conditional statements to decide different arguments for a command.Basically:
Code:
if [ "$1" = 1 ]
then
[code]...
I have this script:
Code:
a=awk'{print $8}' f1.txt
How can I make it store lines in $a ? In the way above it creates one big line.
So For example I run this command:
Code:
But want to gerp / cut it in such a way that it only displays
Code:
Now the thing is that these 3 lines are not static.. there can be N number of lines there.. the only thing is that I want the command / output NOT to display the first line but the rest of the n lines ..
I have a dataset (see example below) that I would like to go through and copy all lines containing a certain string ("LGIG") plus the line immediately following that line to a new file. I have no problem grepping lines containing the string LGIG but I'm lost how to translate that to line number and shift up one line number for each instance of that string.
Example input file:
[code].....
I need to grep a pattern which can be present in one line or could be split in 2 lines.Normal grep wont work in this case. Can anyone please help on this?There are 100's of files in which i need to search for this pattern so time is also a constrain.
View 5 Replies View RelatedI would like to know how I can get the ouput from the following dmidecode command in example 1 to look like example 2 without having to grep -v all the unwanted lines.Is there a way in awk or sed?Example 1
Code:
Processor Information
Socket Designation: Socket 1 CPU 1
[code]...
I have such a file(test.txt) as below:
[code]...
I want to use grep to fetch the lines contain 'AB_001'.
[code]...
get the first 2 lines, not the 'AB_0011/10/105'.
I need to kind of grep within grep. My input file would be something like:
[Code]....
and I need to find the first occurrence of hello before MY PATTERN (hello 9008 in this case), so the output should be:
[Code]....
I have two students whose windows laptops are riddled with malware and not working properly. They want me to help them install Linux (which we use in school), but they are concerned about their iTunes.
Having avoided iPods as "defective by design", I know nothing about iTunes whatsoever. However I remember reading about DRM locking and such problems that have me concerned that I won't be able to do it.
Where does iTunes store its stuff?
Can I copy its data store to an external drive, and then into a linux home?
Then will it work on wine, or can another manager (rhythmbox etc) access the itunes data?
Alternatively, if I partition the drive and install linux, can rythmbox/wine/something access itunes data on the win partition?
Supposing they are buying music through iTunes, what will happen to that account?
Finally, one of them has an iphone. Does that work with linux?
Ironic that an apple application is blocking migration away from windows.
I'm using a command in Linux which generates an eight character random password. the problem is when i execute the command, the generated password have shown and isn't store anywhere i can use.How can I store this password into a file or pipe the command to save the password into desired file directly?
[code]...
Im trying to use a DBMS to store rpms for been reach by YUM, what I need to know is how to generate the repomd.xml and make it point to my dbms using href like [URL]...
View 1 Replies View RelatedI have a file which contains a line like this:SERVER=10.205.110.19 How can I cut out the IP and assign it to a variable?
View 4 Replies View Relatedsomeone once told me that use can pass a file to grep and use that to search the contents of another file. if that is the case I'm not entirely sure why the following isn't working for me.
Code:
[root@LCENT01:~]#grep -i id_rsa.pub .ssh/authorized_keys
[root@LCENT01:~]#cat id_rsa.pub >> .ssh/authorized_keys
[root@LCENT01:~]#grep -i id_rsa.pub .ssh/authorized_keys
I'm looking for a way to insert the number of lines in a file to the start of the aformentioned file. This should be simple but as I am not used to scripts in Linux, I am finding it tough going. I can find the number of lines in a file easily enough via
filesize=$(awk 'END {print NR}' $1)
but as for inserting this into the first line, i'm failing to do so. I've tried some of the other approaches on these forums but none so far have been able to do so.
I've tried:
sed '1i$filesize' $1
but sed i requires a string, not a variable so no go I've also tried:
mv "$1" "${1}.bak" 2>/dev/null || touch "${1}.bak"
cat $filesize "${1}.bak" >"$1"
but again with no luck as cat seems to need an input stream Just to recap, i want to insert a line at the start of a given file that holds the number of lines the original file has.
ie the file:
a
b
c
d
e
should become:
5
a
b
c
[code].....
I am trying to watch a command and try to log it into a file. I tried
watch -t -n 10 "(date '+TIME:%H:%M:%S'
; ps aux | grep "pattern" | wc -l)" >>
logfile
and am expecting a result like
TIME: 10:32:30 12
TIME: 10:32:40 18
TIME: 10:32:50 2
to be stored in logfile. However, when the logfile has unprintable characters in in. How do I get this kind of output from the command li
I am using RHEL 5.I have a very large test file which cannot be opened in vi.The content of the file has some 8000 lines.I need to view ten lines between 5680 to 5690.How can i view these particular lines in a large file.what is command and option i need to use.
View 1 Replies View RelatedLet me *try* and explain what I'm trying to do, and keep in mind aside from a little command line stuff I'm a beginner to any of what I'm asking about.
I have a directory structure something like this:
Code:
/usr/local/chatlogs/
webserver1/
1.chatlog
2.chatlog
[Code]....
So that whatever was captured in the () in the first part of the statement would be used in the 1 in the back part of the statement for every n.chatlog that might be in any of the /webserver directories at that time.
I have collection my routers configuration through rancid. Now i want to do the following,
Display all the files that contain the following words
C1841 AND HWIC-4ESW
I want to display all the files that contains both these words.
I'm trying to create a backup script. For my second version, I want to make a GUI that will ask the user three things:
1. which folders should be excluded
2. where to store the backup
3. the user's email
I need to store this input, and later input the values into variables in my script. How do I go about doings this?
I'm storing a list of strings in a file and would like to read the file and pipe each line returned to grep which in turn searches a directory for files containing the string.However this is not returning any output.
View 2 Replies View RelatedI am searching for Class declaration on a site with hundreds of PHP files, how can I do this in the current folder and subfolders using GREP?
I tested cding to the folder and then something like
grep -r 'class MyClass' *.php