I am trying to make a simple alias for find command that acceps a variable.
alias myfind="find $@ -type d -exec chmod 777 -fv {} ;"
this alias tells me that "find:paths must precede expression"
I want to build on the code from /etc/apt/apt.conf.d/05etckeeper to work with Snapper, the new-in btrfs (et al) snapshot package.
Code: Select allDPkg::Pre-Invoke    { "if [ -x /usr/bin/etckeeper ]; then etckeeper pre-install; fi"; };
DPkg::Post-Invoke   { "if [ -x /usr/bin/etckeeper ]; then etckeeper post-install; fi"; };
The etckeeper code will work well as a template, but I need to pass a parameter between the pre- and post- instances. The parameter is obtained from the pre- invocation and passed to the post- invocation.I know that something similar to my quest is done with the 'pid' but how to do it in the 'standard' way. Happily there can't be multiple dpkg instances running concurrently (prevented by dpkg?) so I don't have to worry about that issue.
Q1. What is the 'standard' way of passing parameters about?
Code: Select allsnapper -c etc create -t pre -p   (which 'prints' the parameter (int) to pass to the following invocation)
snapper -c etc create -t post --pre-number <parameter> in place of the two etckeeper calls.
Q2. How do I pick up the 'printed' output of the 'pre' call? I think it's just a 'get' from the stream but perhaps I've missed something.?
I am trying following script can I do this or is there a way to do find and replace the replacing word is dynamic input by user
echo -n "Enter name:"
read RP_USER
sed 's/text1/$RP_USER/' /home/user/file1 > /home/user/file2
I am new to bash scripting. I want to know whether i can pass one variable to another. For example $1 represent argument1. Now if i want to get the argument 1 like USER="1" now i want $ of $USER to execute $1 so what should i do..
View 2 Replies View RelatedHow can I pass xml data from memory or a variable to xmllint that expects a file as input? Or does xmllint have the capabilities to read from stin or a variable?
View 4 Replies View RelatedI have a file with around 1000 IP addresses in it and I need to be able to ssh into each one of them, run a single command, and then exit. I already know the ssh command I want to run and it looks like this:
Code:
shpass -p [password] ssh -p 10022 -o StrictHostKeyChecking=no root@[ip variable] 'reboot'
(I know shpass is not good to use and keys are the correct way but I don't have any other options in this scenario.) if these ip addresses were in a .csv file, by themselves with no other information, how would I create a script to do the above command to each ip until the end of the file?
I cannot for the life of me get this little (simple) script I wrote to work. Here is the entire script:
Code:
#!/bin/bash
ASPECT=`mediainfo $1 |grep "Display aspect ratio" |cut -d : -f 2`
HEIGHT=`echo "320 / $ASPECT" |bc`
SIZE=`echo 320x$HEIGHT`
[code]......
An input filename ($1) is fed into mediainfo, which by the use of grep and cut spits out a single number which is the aspect ratio. This is then divided by bc into 320, which gives the desired height dimension for the file that I want ffmpeg to create for me. Finally, ffmpeg runs using the calculated dimensions... Basically, it's the passing of the $ASPECT variable to bc that seems to fail. It looks like bc won't read the output from the mediainfo line... It always crashes out with:
Code:
(standard_in) 1: illegal character: ^M I've tried doing something even simpler like this to debug by just trying it to display the calculation on the screen:
Code:
#!/bin/bash
ASPECT=`mediainfo $1 |grep "Display aspect ratio" |cut -d : -f 2`
HEIGHT=`echo "320 / $ASPECT" |bc`
echo $HEIGHT
and it does the same, so it's definitely bc that won't accept the output from mediainfo.
I want to know is there some more efficient way of passing a pointer to a local variable as a parameter to a function in x86 asm? Right now I have to move the base pointer to a temp register, subtract from the register and pass that, like this (assuming a local var at esp-4):
Code:
mov eax, ebp
sub eax, 4
push eax
Is there a better way?
I'm having some trouble this morning to send a SQL query to our Oracle DB server in PHP. When I try to pass my value "OF/110246801A01" as variable it tell's me "Warning: oci_bind_by_name(): ORA-01036: illegal variable name/number"
PHP Code:
$ociO ='OF/110246801A01';
$selectAllFieldsFromOf=oci_parse($conn,"SELECT*FROMMFGOPEWHEREMFGNUM_0LIKE':ociOf' ");
oci_bind_by_name($selectAllFieldsFromOf,":ociOf",$ociOf,15);
$resultQuery =oci_execute($selectAllFieldsFromOf);
if(!$resultQuery){
$e = oci_error($selectAllFieldsFromOf);
return trigger_error(htmlentities($e['message'],ENT_QUOTES),E_USER_ERROR);
[Code]....
I have installed FC13 on my laptop and set it up as a development server. Here is my issue when passing variable from one page to the next it gets lost. My PHP includes work DB connect string works from the include.
View 1 Replies View RelatedSay, i have an imaginary std library function, which I want to call.
Code:
void std_lib_func(ObjectType *param);
Now in my c++ program, I have a main() function, and I will like to call a customized function (which will in turn call the std lib function) from the main function, as below:
Code:
int main()
{
ObjectType *aobj;
customized_func(aobj);
}
[Code]...
I tried the below but get an error that the std lib function is expecting a ObjectType* param, not aobj. How should I work this out.
Code:
void customized_func(ObjectType aobj)
How can I to pass a perl variable into html input tag? For example, If a have got a cgi script:
Quote:
use CGI;
use DBI;
my $owner = $cgi->param('owner');
[code]....
How can I to pass $owner variable?
I'm trying to implement an assert function similar to:[url]
However, I'm having trouble with file existence testing when the file name has a space in it.
I have distilled the problem down to the following:
This code works as expected, printing 'yes' if '~/test file' exists, and no if not.
Code:
However, this code gives an error.
Code:
The error:
Code:
Which tells me that it is splitting ["~/test file"] into ["~/test] and [file"]. Why? Is there a way around this?
Note that if you simply use a file path without a space, both cases work perfectly. Is this a BASH bug possibly? I just can't understand why the first would work, but the second wouldn't.
I want pass a variable at compile time.
for example in x.c
int global_var = POSITION;
How can I send this POSITION at compile time. ie like # make POSITION=10 Is it possible?
"While ; do ; done" is very convenient for SH coding. However sometimes you may be annoyed by your computed variable within the "while do done" type loop. What to do how to pass it out of the loop to the outside of the bash code? A solution is to write it into the /tmp or on the disk... and to call it back after. - not elegant... really not... Anyone would know a trick another alternative that would look nicer?
Code:
# Count file total size
TOTAL_SIZE=0
LISTOFFILES=`cat "$HOME/.fvwmoscfg/fvwmburnerlist.lst"`
echo "$LISTOFFILES" | while read i ; do
SIZE=`du -bs $i | cut -f 1`
TOTAL_SIZE=`expr $SIZE + $TOTAL_SIZE`
echo "$TOTAL_SIZE" > "$HOME/.fvwmoscfg/fvwmburnerlisttotalsize.lst"
done
TOTAL_SIZE=`cat $HOME/.fvwmoscfg/fvwmburnerlisttotalsize.lst`
echo "The total size of all files and folders is : $TOTAL_SIZE"
I am writing a script to get hardware information of a particular UNIX machine. To do this, I ftp a shell script (commands to get h/w information) to the target machine and then use SSH to remote the remote script.With FTP, I can pass a password accepted as input the shell script. How can I pass the same password to SSH ? This is because I do not want the user to enter the password twice.
View 5 Replies View RelatedI am calling another executable in my application (C programing) using "system" command
which is user interactive program. now i want to pass those args in system command only.
system(" executable ");
Executable will expect 1,2 or 3.
1 is to continue
2 for do changes in settings
3 exit from application
how to pass these in to system command
how to pass an array as a command line argument in a shell script?
View 5 Replies View RelatedOn our server we have a certain directory, say /storage, that contains many large files. They are all compressed (gzip). Many of our users are not computer-savvy, and so when one of these files is needed, they will copy it to their own directory. Consequently, we have multiple terabytes of duplicate data. I'd like to enforce an alias whereby if someone tries to use cp on a file from /storage, they will instead create a symbolic link. My idea was something like:
alias cp='cp.storage'
File cp.storage:#!/bin/sh
truePath=$(readlink -f "$1")
[code]....
The conditional checks whether the file being copied begins with "/storage". The problem with this is that if someone wanted to use cp with any options on a file not in /storage, those options would be obliterated. Can someone guide me as to a good way to accomplish this? Either a way to get the options from cp into cp.storage, or another approach not using alias this way. Everyone will be using bash.
how to use QGLviewer. I want to give my program a file name as a command line argument. All of the sample programs I find have a main.cpp file like this:
Quote:
#include <QApplication>
#include "window.h"
int main(int argc, char *argv[])
[code]....
Then the Window class, which is derived from QGLViewer, does all the program's actual work. If I want access to argc and argv, for example, to open and read a file that's passed as an argument, what would handle that? Is there a built-in way to get the arg variables to the window class, or do I need to just write a loadfile function and pass them?
suppose i store the history number of a command say :
1004 cat file
Then now i want to run it like : !1004 but by using a variable.
command=1004
!$command
i am getting errors like :
command=1004command
I am very new to shell scripting.How does one pass a command-line parameter to a shell script?for the below program
#/bin/bash
mount -t cifs -o user=ramkannan,password=Linux123@ //10.200.1.125/ramkannan /MT
cd /MT/test
date=`/bin/date "+\%Y-\%m-\%d-\%H-\%M-\%S"`
mysqldump -uroot -pram2@ employeedb > $date.sql
gzip $date.sql
I want to pass parameter for everything,i tried in google and did but iam getting error while passing parameter to all
#/bin/bash
mount -t cifs -o user=$1,password=$2 //10.200.1.125/ramkannan /MT
cd /MT/test
date=`/bin/date "+\%Y-\%m-\%d-\%H-\%M-\%S"`
mysqldump -uroot -pram2@ employeedb > $date.sql
gzip $date.sql
i was getting error while passing parameter to all.
I just decided I'd give Google Chrome a try. Installed it via the google repository and it went fine.
However, every now and then it just vanishes from my menu and it can't be found again, also the command in the terminal can't find anything.
So, what's left is to reinstall it, and during reinstall it doesn't even whine about already being installed.
Anybody else with this matter? I am running 64-bit Squeeze.
I've got 2 problems:1. How can I use the find command to search for devices files?2. I need to find all files thaare 6 months (or more) old and that have a size of 2 Mo or more. What would the code look like?Oh and also, how can I use the cat command to insert text in a file?
View 2 Replies View RelatedHere is my example code that doesn't work:
find $HOME -type d -name "$WHATEVER" -exec rm -rfv {} ';'
$HOME works ofcourse. it's $WHATEVER that -name doesn't honor. Has to be a variable. I really don't see a way around it because $WHATEVER could be any number of things depending on the circumstance. I've also tried other things:
find $HOME -type d -name '${WHATEVER}' -exec rm -rfv {} ';'
Using backticks will process $WHATEVER but it tries to execute it as a command instead of processing it as an argument to -name....
i'm trying to execute a shell script, i'm trying to use the values in an array for use in a sed command:
sed -n '/Sales ID: ${array[$i]}/,/Totals:/p'
that command creates empty files. so my guess is that its not recognizing the array as an array but as text?
how would i be able to utilize the array in the command? i got it, didnt think that if i doubled up the single quotes that it would work, but this worked:
sed -n '/Sales ID: '${array[$i]'}/,/Totals:/p'
I can print a specific line of a file with:$ sed -n '20p' myFileHow can I store it in a variable (in a shell script)?(I wasn't successful with "myVar=sed -n '20p' myFile" for example)
View 2 Replies View RelatedI need to create a zip file of jpg and bmp files. The zip file is named after the first file it finds which ends with .dat. Here is my script:
Code:
DAT_FILE= `find . -maxdepth 1 -iname "*.dat" | head -1 | sed 's/..(.*)..../1/'`
(cd pics; find . ( -name "*.bmp" -o -name "*.jpg" ) -print | zip ../$DAT_FILE -@ )
BTW my sed command cut off the first two chars and last four chars since find will return the filename is the form of "./filename.dat" and I just want to extract filename. When I run this script, it creates a zip file named ".zip". How do I fix this so the zip file is named after my dat file?
Code:
ls Again the command can be stored in a variable and then executed. Like
Code:
var=ls
&var
The above two codes are the same. The problem occurs when we try to pipeline it. Consider the following problem:
Code:
ls | grep *
works fine...but when we try to store it in a variable and run the command there is an error.
Code:
var="ls|grep *"
$var
how to store this kind of commands in a variable?
I have a file that contains 5 fields and anothen one with two I want to take the value from user and search file1 and if the value exists then write in file2 to the $2 to the line that $1=value
file 1
1:fsdfsd:g:33:fsdf
2:yytgdcf:a:3:sgd
3:tttt:g:67:yujhggfg
[code].....