Ubuntu :: Scripts In Bash And Perl - Users Hasn't Been Able To Login
Jul 29, 2011
I've been asked to do certain jobs doing scripts in bash and perl. So this time they asked me to check which users hasn't been able to loggin. DONE with Code: lasb Now they asked me to show how many times all the users have input certain Bash Commands like
Code: Ls Cd pwd I was wondering if there was a command of something that could show me how many times those commands has been used, I already know I can see all input with Code: history Sorry I'm really new to this, been working with this for a couple of weeks, and its really interesting.
i have a NIS master server and 4 NIS clients. out of 4 nis clients two are acting as login servers ie users will login and do all their stuffs and the remaining two are application servers. But sometimes users login into applications servers and started doing all their developer's job. i want to allow only a limited number of users tointo this application users not all the users who are all part of the nis domain.all the systems are running RHEL 5.4 on hp's proliant x86_64 based servers. Please advice me how should i proceed? enabling ip tables is not possible in my environment.
I need to control daemons like dhcp/bind from within a perl script. I could run the script as root to restart/stop/start the daemons however, this is not good for security.
What are the ways of controlling processes within perl as different users?
I wanted to run bash and perl scripts which requires SU privileges by clicking on dektop Terminal window opens and closes fast without knowing what happened.
scripts work on terminal window by telling
sudo perl file.pl sudo bash file.sh Perl has this header #!/usr/bin/env perl
[Code]....
How can I run them with desktop shortcuts with SU privilege so, the terminal will not close after execution?
should not the scripts work without telling perl or bash,
I've set up password-less login for user1 on a Ubuntu machine to login automatically into a Fedora box using the publickey authentication method. Everything is working smoothly. Now, there is a user2 on Fedora but he does not have an account on Ubuntu.
I tried to login as user2 from Ubuntu to but got the following error :
Code:
Predictably neither scp or sftp work either. I have several questions as a result.
1.Is the SSH server rejecting user2 login because I am inadvertently using user1 keys (as I am logged in as user1) ?
2. Do I need to have a user2 account on Ubuntu and public/private key authentication setup with Fedora for user2 to be able to login ?
3. Is there a method I can use to password login as user2 from Ubuntu to Fedora (even though there is no user2 account on Ubuntu) AND still keep password-less login for user1 or do I have to have password-less login for both ?
At present the only way to access the user2 account from Ubuntu is to SSH using the user1 account and then su to user2.
I wrote this script for bash & perl. If you run it in bash it should work. It changes title - (uuid) kernel - initrd ... to title - uuid UUID=the_uuid... kernel - initrd .... When I wrote it I replaced end of lines by . It's the second $block definition. But now I need to repair it, because I will work with the 1st $block definition. That is not to exclude end of lines, but leave it be untouched. Now when you escape the second $block definition, the code does not work. What I have to do to repair it working with multiline input data?
I wanted to run bash and perl scripts which requires SU privileges by clicking on desktop Terminal window opens and closes fast without knowing what happened.
scripts work on terminal window by telling sudo perl file.pl sudo bash file.sh
Perl has this header #!/usr/bin/env perl or #!usr/bin/perl -w
Bash has header #!/bin/bash
How can I run them with desktop shortcuts with SU privilege so, the terminal will not close after execution? Should not the scripts work without telling perl or bash, since they have the header?
I've been trying to figure out a way to more easily color text in Perl like I do on Bash on a Linux box. In bash, what I'll do is set color variables up to equal the escape sequence, then echo out with escape seqeunces to print it exactly how I want it. Typically I'll want a character or a word in a different color, not the whole line. For example
echo -n -e "My face is turning ${RED}red${UNCOLOR} like a lobster." In Perl with the term::ANSIColor module, it seems to just do a line. Am I being dense? Is there a way that I can do it like I do it in BASH that's fairly easy to read after the fact?
I've recently inherited a bunch of files at a new job and am trying to figure out some of the problems that have constantly popped up. The one i'm getting a huge headache with results from a bash script that is supposed to change a date format from a client populated txt field to one we want defined a certain way. Everything in the script works fine, except that one function. Below is the line i'm trying to manipulate, with date examples.
The one caveat is that the first date is non-static and changes daily. It is, however, always the current date. If it helps, the second date will always be a year away from the first date.My idea was to pull the current date via perl's DATE function, but...how to do it, and calculate a year away without throwing the rest of the bash script off? Any help would be appreciated. I'm sure it's a simple solution but i know absolutely nothing about these scripts and how they were written.
This pretend to be a script for rename a lot of files automatically. So I put the list of files in an array named @lista. But, as you can see, at the end of the command I use a sed filter to print out a backslash for those files that have spaces in their names, so the path for those files could be rightly interpreted.
But there's no way I could print a backslash. It works well when I use the Perl's sed substitution s///, but I need every path in the array to be fixed.
I'd like to add that the bash command works perfectly well alone. I mean outside the Perl script.
I'm writing a bash script that executes a few perl scripts. One of the perl scripts that I need to execute requires two arguments with it. The arguments are stored in a txt file, each line contains a hostname and its corresponding IP address separated by a ":" (colon), the txt file looks like this below:
[Code]...
I'm not sure if it's the best way to accomplish this but here it goes. In the bash file, let's call it getHosts.sh, I create an array and assign each line of the file to an element in that array. I then think I need to create a new array where I take the hostname (which is before the ":") separate it from its IP address and place the IP address on a new line just below the hostname (this way I can reference to it like $hostNames[$x] would be the hostname, and $hostNames[$x+1] would be its IP address). So the new array would now look like this below:
I wanted to find and replace a string from a perl file. I have written a script in bash which runs the following command.
perl -pi -e "s/$findstring/$replacestring/" testfile where as $findstring = print F_WC_TMP"$line "; and $replaceString = $line = join ' ', split ' ', $line; print F_WC_TMP"$line ";
But when I am running the above command, i think it is replacing the $findstring with the above mentioned string and hence it contains a $line, it is looking for the variable $line and not finding the exact string. I am confused about how to search for a string that contains $ in it and replace it with another $string.
I am trying to fix a perl script, and I really suck at perl. But I think this problem will be easy for people who know it.
The problem is, I have an old setup script someone wrote many years ago. It fails if the standard shell is dash and not bash. The only way I've gotten it to work is to point /bin/sh to bash. I looked thru the script and it uses "system" many places, and I think that's the problem.
I searched for it and found this link:url
My plan is to include this function:
Code: sub system_bash { my @args = ( "bash", "-c", shift ); system(@args); } Then I could simply change all calls to system into system_bash and it should work?
The parameter to the system calls is usually some variable. What if the parameter is a list already? Do I need to test for it somehow, and if it's a list, prepend "bash" and "-c" to the list? How do I do that?
In the script there are lots of places like this:
my $error = system($cmd); if ($error) { die/warn "some error message"; }
Shouldn't there be a return in the system_bash function?
I'm not sure if this is best done in Perl or Bash. I'm thinking surely someone else has created something close to what I'm looking for. The results of the script would be that someone would kick off "linux_hosts.sh" r whatever you want to call it, then a top "folder" of options (with hosts contained within each of these top menu choices), then, based on which number corresponds to that top level, they're presented with a set of linux hosts that are relevant to that top level name. Example:
$ linux_hosts.sh 1. VMware hosts 4. Private Domain 2. ESX servers 5. Red Hat boxes
installed Ubuntu Server Edition and I've found that my first user has a bash history and I can turn on a coloured prompt by editing my .bashrc etc but new users don't have that!I did : useradd -d /home/newb -m newbpasswd newband the correct looking .bashrc file appears to be in /home/newb but it is being ignore by bash when logged in as newb. Instead I am presented with just a dollar prompt instead of "newb@server"how can I sort out my users with proper prompts?
I have started using Ubuntu and I have to add a large number of users, over a thousand, using a Bash Script. I also have to give them a password. Do you create a text file first.
I want to execute a bash script that switches user and then executes a series of commands. None of this users have root privileges. I guess I have to edit the sudoers file to give user1 (the user executing the script) privileges to be able to log as user2 with no password prompt. I've been looking for this example but I haven't found any.
I have a CentOS dedicated server running ProFTP. I have created user accounts which are meant for FTP access only but the users cannot connect to the FTP unless their shell access is /bin/bash
Here is an example line that is outputted when I use this command:
This user can access the FTP fine, but he can also access SSH which I don't want to allow him to do. If I set his shell access to /bin/false then he can't connect to the FTP.
What can I use in instead of /bin/bash to allow FTP but don't allow SSH?
I was asked to list passwordless or locked accounts in a fedora system. As far as I know, fedora or RH dont allow passwordless accounts (the system locks the account Edit: ... unless you set passwd -d :-P ), so I might show info about locked accounts.
I am totally aware that I could do a grep or an awk searching for "!!" or "", but my people is asking me to check against passwd -S (which prints info of accounts). The thing, is that in Solaris you can check with passwd -a -s all the users, but in Linux I couldnt find anything similar. what approach do you reccomend for passing, say , the list of users ( like the output of awk searching only user names) to the command passwd -S one by one?
A Tomcat server is installed under user A. Now I am going to write a script which will start this Tomcat server. And this script can be executed from other users (from there account). And if other user run this script, the process ID should be of user A, so that user A can start or stop this process any time. This means, at the beginning of the script I have set the process ID as user A. How to do this?
Meaning when I turn on the computer, it automatically logs into the family account; and they never need to enter any passwords.Second, under System -> Administration -> Users and Groups (users-admin from terminal) there is a "Don't ask for password on login" option (toggle) which is desirable for this family account. However, I have never seen this option enabled, but always grayed out. Is there any way to enable this option?In short, I want:1) For the family account never to require a password on login.2) Automatically log into the family account on boot.
I have a fair number of users created for running processes (apache, oracle, etc) and they appear in the login screen when I boot. Is there a way to not display them?
