Programming :: Variable Not Incrementing In C
Sep 10, 2010It compiles fine, but gets stuck in the loop. z never increments. I was using a for loop originally but had the same problem so I decided to try a while loop.
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It compiles fine, but gets stuck in the loop. z never increments. I was using a for loop originally but had the same problem so I decided to try a while loop.
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Say I have a file as
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It would be great, if i could issue a command (Vi/Bash/awk, ...) in order to obtain
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So, the "replace string" should be replaced by another string containing the counter of replacement.
I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
my script has a variable which comes in the form +00.00 +0.00 -00.00 or -0.00 (the numbers can be any in that form) for any that have a + symbol I need to remove the +, but if it has a - symbol it needs to stay.
i need to make a new variable with the string from the old variable btut without any plus sign. I have tried a lot of different ways with no success, each thing I tried either left the + or removed the entire string. I think this should work but doesn't
foo=+12.40
bar=${foo#+}
how I can search within a variable and assign the results to a new variable. I'll use the following as an example -
cars="Audi BMW Cadillac Chevy Dodge Ferrari Ford Mercedes"
list=`echo ${cars} | egrep -o '<A?+|<C+'`
with the echo command I get the following output assigned to list -
A
C
C
What I'd like to get for output is -
Audi
Cadillac
Chevy
how I could do this regardless of upper/lower case letters?
included shell script inside c program, and i wanted to assign the value of c variable to shell variable..Can any one please suggest me how to do it?
View 8 Replies View RelatedThis loop is part of a bash script which takes multiple arguments.
Code:
for ((i=1;i<=$number;++i)) ; do
offset=$(($i+5))
[code]...
ch[1]=0; ch[2]=0; ch[3]=0; ch[4]=0; ch[5]=0; ch[6]=0; ch[7]=0; ch[8]=0; ch[9]=0; ch[10]=0;ch[11]=0; ch[12]=0; ch[13]=0; ch[14]=0; ch[15]=0 ch[16]=0; ch[17]=0; ch[18]=0; ch[19]=10; ch[20]=0;
I have an array ch and I want to increment each element in my array for the following if statement. I'm not sure I have the right array increment syntax but I have tried it in different ways ant it doesn't seem to work.
I tried ch[$1]++, ch[$1]+1, ch[$1++], ch[$1]+=1, ch[$1]=ch[$1]+1 none of these seem to work.
# while loop reading from read.txt for check list 1 - 15
for i in `seq 15`
do
a=`grep "${cl[$i]}" $file`
status=$?
if [[ $status = 0 ]];
then
echo -n -e "1 "
let ch[$i+1]
let k++
else
echo -n -e "0 "
fi
done
for l in `seq 20`
do
echo -n -e "${ch[$l]} "
done
Is there any way in cvs to check in a change without incrementing the revision number?
I know you can specify the revision number, but I'm under the impression that if you specify a revision that exists, it increments .1 to the right.
So if current revision is 1.2 and i specify -r 1.2 it will make the revision 1.2.1
i want to pass variable in mysql qyery in c programming
View 1 Replies View RelatedI have beat this enough and don't get what should have been a very simple thing to do. I build a variable;
Code:
CLIST=java,lua,python,php,perl,ruby,tcl
CLIST will be used by another bash script but I need to replace the commas with a space. I
[code]...
How would I go about defining a variable from a document name. Example:document01.doc I want to take the 01 and set X to equal integer 1.
View 1 Replies View RelatedI need to replace JAVA_OPTS= with JAVA_OPTS=<some_value>.I need to give "" value at the end of the replacement. I have tried with the following but it is not working: sed -e "s|JAVA_OPTS= |JAVA_OPTS=<some_value>"
View 2 Replies View RelatedI have been searching most of today and am stuck on getting a variable into an awk portion of my bash script. I have this working:
Code:
#!/bin/sh
SRC=/var/log/mail.log
DEST=/var/www/output/myFile.txt
VAR=userName@myDomain.tld
[code]....
Can awk take a shell variable? Or do I have to do something completely different?
In C++ what does the suffix, "*" mean appended to a variable type, e.g., "char* variable1;"?
View 3 Replies View RelatedFollowing is the way I saw a variable initialized in C
Code:
static const unsigned int rtl8139_rx_config =
RxCfgRcv64K |
(RX_FIFO_THRESH << RxCfgFIFOShift) |
(RX_DMA_BURST << RxCfgDMAShift);
on following link
[URL]
I have initialized variables in past but above initialization I could not understand what is it?
problem statement:
pattern_search="Exam Name"
sed -n "/$pattern_search/,/hello/"p tmp5 | awk '{if ( $4 != 0 && $4 ~ /[0-9]+.*[0-9]*/ ) print "$pattern_search" " " $0 }'
"tmp5" is a file. this is printing output as
$pattern_search value1
i.e value of $pattern_search is not getting substituted. i am expecting output as
Exam Name value1
how shall I print each variable separately using a generalized form. I tried writing the following within a for loop...Code:echo $(echo a$(echo $i)$(echo $j))which did yield no result. So what shall I write??
View 3 Replies View RelatedI have the following input:
Code:
Event 1............................................................
full_name: JENNY_JENNINGS genre: f
age: 32
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But as you can see in the input, in the 2nd "Event", the line containing "age" is not present, but in the output my code is printing the 1rst age value twice. The correct output should be blank in the age field for 2nd line in the output like this:
Code:
full_name|genre|age|code
JENNY_JENNINGS|f|32|15a
JOHN_JOHNSON|m||23c
MARY_JEAN|f|25|11d
What is wrong in my code? how can I fix it? * I�m using ubuntu 10.10
How are environment variable set in tcl? I tried "set $env(MYVAR) xxxx" but it didn't work.
View 1 Replies View Relatedi'm trying to execute a shell script, i'm trying to use the values in an array for use in a sed command:
sed -n '/Sales ID: ${array[$i]}/,/Totals:/p'
that command creates empty files. so my guess is that its not recognizing the array as an array but as text?
how would i be able to utilize the array in the command? i got it, didnt think that if i doubled up the single quotes that it would work, but this worked:
sed -n '/Sales ID: '${array[$i]'}/,/Totals:/p'
I have a directory file capturing script, the variable is fine with in the loop but gone after the loop is done:
Code:
DIR="/usb/sdb1/media/music/"
i=1
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I am about to move my scripts to the next generation level, so I need some help I am stuck in varying my variable names in a loop. For example:
for user in ben dorothy mike pat
do
[ -r /home/$user ] && let "$user"check=1 || let "$user"check=0
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Just a simple BASH for loop to read the file path from a text file (clean.txt) echo the variable for debug purposes, and scp it to a server I have using port 50 for SSH.
I've already formatted the entries in clean.txt to handle spaces correctly, using sed replacement.
Example from the clean.txt file:
Code:
/MP3/NAS000000001/Barenaked Ladies/Barenaked Ladies - Barenaked For The Holidays/20 Auld Lang Syne.mp3
/MP3/NAS000000001/Barenaked Ladies/Barenaked Ladies - Barenaked For The Holidays/14 Deck the Stills.mp3
[Code]....
This is probably a very easy thing to do, but I don't know how: I'd like to export an env't variable, and then use its reference in a Bash script
Code:
I am trying to create a script to be used on RHEL server. If I replace the $t with a number, the script works. If I try add a variable or the $1, the script doesn?t work (returns all processes even if less than the $t value). I thought that it may be treating it as a literal, but I wasn?t sure of the conversion.
t=$1
echo $t
lcnt=`ps -eo pid,ppid,rss,vsize,pcpu,pmem,cmd -ww --sort=pid | awk '{if ($6 > $t) print
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I am trying to write a script which can read the names of all folders within a given folder into separate variables. In effect, if a folder contains a folder "Folder1", "Folder2", "Folder3", the script would read those names into variables such as:
Variable1 = "Folder1"
Variable2 = "Folder2"
Variable3 = "Folder3"
I have tried fiddling with the find . command, but without any success.
I am new to linux scripting, but I have programming experience. I need to save the UUID for /dev/sda1 as a variable, lets call it id. I am sure there is a way to do this with the awk and blkid commands, but I do not know any of this well enough yet to figure it out and after a couple of hours of reading I am still lost as to exactly how I would put this together. I need to save the uuid as a variable so that I can run an if statement with it
if [ -f /media/$id/file ]
then
echo "copy successful"
else
echo "oh crap!"
honestly all I need the uuid for but I cant check this by doing the same if with /dev/sda1/file so I need to be able to save the uuid into a variable
I want to write a c program with some shell scripts.Now For a simple C program. I am Setting a variable called val2 in bash, now I want to use bash variable val2 in C code. How do I do that?The above doesn't work (coz its spawning a different memory space and when shell script ends the variable dies with it as per my research but how do I keep them in same memory space)Also Is there any Good reference where they teach how to integrate C and Bash Together?
View 5 Replies View RelatedI need to pass variable from sc1.sh to sc2.sh and update the value of the passed variable in sc2.sh and then return the updated value of the variable from sc2.sh to sc1.sh.
View 7 Replies View Related