Programming :: C++ Variable Type Followed By *?
Jul 1, 2010In C++ what does the suffix, "*" mean appended to a variable type, e.g., "char* variable1;"?
View 3 RepliesIn C++ what does the suffix, "*" mean appended to a variable type, e.g., "char* variable1;"?
View 3 Replieswhen i compile the device driver of led ,i get the erro like this:
[root@localhost led]# arm-linux-gcc -D__KERNEL__ -DMODULE -I /home/liumeng/lmldd
/linux-2.6.34.1/ -c -O -Wall led.c -o led.o
led.c:34: error: variable `GPIO_LED_ctl_ops' has initializer but incomplete type
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Its an example froom a book... and it does not work...
Code:
#include <stdio.h>
int main ( int argc, const char * argv[] ) {
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I'm trying to read content of file to variable and use this variable in for loop. The problem is, when I have c++ comment style in file - /*. Spaces in line are also interpreted as separated lines.
For example:
Code:
Changing $files to "$files" eliminate these problems but causes that whole content of variable is treated as one string (one execution of loop).
my script has a variable which comes in the form +00.00 +0.00 -00.00 or -0.00 (the numbers can be any in that form) for any that have a + symbol I need to remove the +, but if it has a - symbol it needs to stay.
i need to make a new variable with the string from the old variable btut without any plus sign. I have tried a lot of different ways with no success, each thing I tried either left the + or removed the entire string. I think this should work but doesn't
foo=+12.40
bar=${foo#+}
how I can search within a variable and assign the results to a new variable. I'll use the following as an example -
cars="Audi BMW Cadillac Chevy Dodge Ferrari Ford Mercedes"
list=`echo ${cars} | egrep -o '<A?+|<C+'`
with the echo command I get the following output assigned to list -
A
C
C
What I'd like to get for output is -
Audi
Cadillac
Chevy
how I could do this regardless of upper/lower case letters?
I am going to write a function which will do different operation base on the data type of the input parameter.
I am using C (Pure C, not C++).
The problem is that I do not know how to get the data type of the input parameter in C Language.
Can anyone tell me how to do this.
I'm trying to compile a program and it gives me the following:
I checked cmath-util.h:46 and cmath-util.h:48:
I'm not a C person, and the author is unavailable so far.
If I want to use that result to be saved in a variable, which type would it be in script? For clearing: let variable x and destination path is y/z
in prog.sh:
x=du -hb /y/z
echo $x
Q1: What type of x?
Q2: What option instead of -hb to presedent the size in kib?
included shell script inside c program, and i wanted to assign the value of c variable to shell variable..Can any one please suggest me how to do it?
View 8 Replies View RelatedThis loop is part of a bash script which takes multiple arguments.
Code:
for ((i=1;i<=$number;++i)) ; do
offset=$(($i+5))
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I am trying to generic way to convert the string datatype to other primitive data type. To achieve, i used Template . But i getting error and couldn't resolve the issue and error reported is also clueless.
Code
====
#include <vector>
#include <iostream>
#include <string>
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with my "if" statement? It's probably just a bracket or something stupid missing, but I cant get the variable "type" to add the line when its selected:
clear
read -p "Please Enter Printer Name : " name
read -p "Please Enter Printer IP : " IP
read -p "Please Enter Printer Description : " des
read -p "Please Enter Printer Location : " loc
read -p "Please Enter Printer Class : " clas
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i want to pass variable in mysql qyery in c programming
View 1 Replies View RelatedI have beat this enough and don't get what should have been a very simple thing to do. I build a variable;
Code:
CLIST=java,lua,python,php,perl,ruby,tcl
CLIST will be used by another bash script but I need to replace the commas with a space. I
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How would I go about defining a variable from a document name. Example:document01.doc I want to take the 01 and set X to equal integer 1.
View 1 Replies View RelatedI need to replace JAVA_OPTS= with JAVA_OPTS=<some_value>.I need to give "" value at the end of the replacement. I have tried with the following but it is not working: sed -e "s|JAVA_OPTS= |JAVA_OPTS=<some_value>"
View 2 Replies View RelatedI have been searching most of today and am stuck on getting a variable into an awk portion of my bash script. I have this working:
Code:
#!/bin/sh
SRC=/var/log/mail.log
DEST=/var/www/output/myFile.txt
VAR=userName@myDomain.tld
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Can awk take a shell variable? Or do I have to do something completely different?
Following is the way I saw a variable initialized in C
Code:
static const unsigned int rtl8139_rx_config =
RxCfgRcv64K |
(RX_FIFO_THRESH << RxCfgFIFOShift) |
(RX_DMA_BURST << RxCfgDMAShift);
on following link
[URL]
I have initialized variables in past but above initialization I could not understand what is it?
problem statement:
pattern_search="Exam Name"
sed -n "/$pattern_search/,/hello/"p tmp5 | awk '{if ( $4 != 0 && $4 ~ /[0-9]+.*[0-9]*/ ) print "$pattern_search" " " $0 }'
"tmp5" is a file. this is printing output as
$pattern_search value1
i.e value of $pattern_search is not getting substituted. i am expecting output as
Exam Name value1
how shall I print each variable separately using a generalized form. I tried writing the following within a for loop...Code:echo $(echo a$(echo $i)$(echo $j))which did yield no result. So what shall I write??
View 3 Replies View RelatedI have the following input:
Code:
Event 1............................................................
full_name: JENNY_JENNINGS genre: f
age: 32
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But as you can see in the input, in the 2nd "Event", the line containing "age" is not present, but in the output my code is printing the 1rst age value twice. The correct output should be blank in the age field for 2nd line in the output like this:
Code:
full_name|genre|age|code
JENNY_JENNINGS|f|32|15a
JOHN_JOHNSON|m||23c
MARY_JEAN|f|25|11d
What is wrong in my code? how can I fix it? * I�m using ubuntu 10.10
How are environment variable set in tcl? I tried "set $env(MYVAR) xxxx" but it didn't work.
View 1 Replies View Relatedi'm trying to execute a shell script, i'm trying to use the values in an array for use in a sed command:
sed -n '/Sales ID: ${array[$i]}/,/Totals:/p'
that command creates empty files. so my guess is that its not recognizing the array as an array but as text?
how would i be able to utilize the array in the command? i got it, didnt think that if i doubled up the single quotes that it would work, but this worked:
sed -n '/Sales ID: '${array[$i]'}/,/Totals:/p'
I have a directory file capturing script, the variable is fine with in the loop but gone after the loop is done:
Code:
DIR="/usb/sdb1/media/music/"
i=1
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It compiles fine, but gets stuck in the loop. z never increments. I was using a for loop originally but had the same problem so I decided to try a while loop.
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I am about to move my scripts to the next generation level, so I need some help I am stuck in varying my variable names in a loop. For example:
for user in ben dorothy mike pat
do
[ -r /home/$user ] && let "$user"check=1 || let "$user"check=0
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Just a simple BASH for loop to read the file path from a text file (clean.txt) echo the variable for debug purposes, and scp it to a server I have using port 50 for SSH.
I've already formatted the entries in clean.txt to handle spaces correctly, using sed replacement.
Example from the clean.txt file:
Code:
/MP3/NAS000000001/Barenaked Ladies/Barenaked Ladies - Barenaked For The Holidays/20 Auld Lang Syne.mp3
/MP3/NAS000000001/Barenaked Ladies/Barenaked Ladies - Barenaked For The Holidays/14 Deck the Stills.mp3
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This is probably a very easy thing to do, but I don't know how: I'd like to export an env't variable, and then use its reference in a Bash script
Code:
I am trying to create a script to be used on RHEL server. If I replace the $t with a number, the script works. If I try add a variable or the $1, the script doesn?t work (returns all processes even if less than the $t value). I thought that it may be treating it as a literal, but I wasn?t sure of the conversion.
t=$1
echo $t
lcnt=`ps -eo pid,ppid,rss,vsize,pcpu,pmem,cmd -ww --sort=pid | awk '{if ($6 > $t) print
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