I have many files in a folder for example
Kiran.txt
Kiran1.txt
Kiran221.txt
Kiran144.txt
Time.csv
[Code]...
From this directory, I want to know how I could use grep to display files based on part of their filename - for example those starting with "Account" or those ending in ".sh".
I have a single directory of pairs of files, with the pairs sharing a string as the beginning of the filename:
SF1-27F1492R-clone01_T3_A18_001.ab1
SF1-27F1492R-clone01_T7_A20_002.ab1
SF1-27F1492R-clone02_T3_A19_003.ab1
SF1-27F1492R-clone02_T7_A21_004.ab1
...etc
I need to create a subdirectory for each pair then move the pair into the subdirectory.
I accomplished the first step using:
$find /foo -name '*T3*' -exec mkdir '{}.wrk' ;
I can use a regex to designate the pair and associate the directory, but how do I use regex in a path as the output of a move command?
I am trying to do a find/grep/wc command to find matching files, print the filename and then the word count of a specific pattern per file. Here is my best (non-working) attempt so far:
wc `find . ( -name "*.as" -o -name "*.mxml" ) -exec grep -H HeightResizableList {}` ;
I have a file with joker character patterns:
./include/*
./src/*
etc.
From the current directory I would like to recursively get the list of files that do not match these patterns.
I'm currently trying to organize a media server so that things will be in some kind of logical order rather than the current setup of dumping everything of a certain content type into a single folder. However, the size and diversity of content within these disorganized folders precludes me doing things manually. Does anyone know of a program or script that could sort the files into folders based on part of a filename
View 7 Replies View RelatedI would like to remove a part from wiz_khalifa-black_&_yellow-(82_bpm).mp3
The part to be removed is -(*_bpm)
so that makes wiz_khalifa-black_&_yellow.mp3
Also a problem is that sometimes multiple "(" occur in a filename (wiz_khalifa-black_&_yellow-(remix)-(82_bpm)), so how can i only remove from the last "("
I have just re transcoded a bunch of avi's. to tell the new ones from the old ones I put '[xvid]' at the end of all the new avi's. but now I have deleated the old avi's I want to remove the [xvid] part of the file name. This is what I have so far
Code:
#!/bin/bash
for name in *.avi
do
newname=`echo "$name" | tr -d [xvid]`
[Code]...
Is there a way, preferably in python or BASH, to rename files from a list? for instance, track1.mp3, track2.mp3 should be renamed to the names stored in a file listing song names. I have tried to loop a variable through directory listing and renamed them, only to find that filenames with spaces can't be assigned to a variable as a whole. To solve the problem above, I have tried the read command in BASH, which enables the program reading line by line from a list. However, It was failed to pipe the results from directory listing to the read command.
View 14 Replies View RelatedI am using wget to download files from a HTTPS site.My command goes as below. I have used * as wildcard to denote anything can be there between underscore and ".". Please advise on how to solve this./usr/sfw/bin/wget --no-check-certificate --user=LTSTSSB --password=pass -O temp.txt https://234.123.432.33:444/Reporting/File-To-Get_*.xml
View 1 Replies View RelatedI have a very large directory with probably millions of small files in it. It's taking forever to run ls on the directory.
Is there an easy script that I can run to split the directory into smaller ones, based on the prefixes of the filenames. My goal is to wind up with something similar to what the Debian archives' pool directory looks like.
I am working on the script parsing specific message "TEST" from multiple file. The log file name looks like:
N3.2009-11-26-03-05-02.console.log.tar.gz
N4.2009-11-29-00-25-03.console.log.tar.gz
N6.2009-12-01-10-05-02.console.log.tar.gz
I am using the following command:
zgrep -a --text "TEST" * | awk -F"[ .,]" '{sub(".*:","",$6); sub(",.*","",$7); print $1,$6,$7,$10}
and getting
N3 2009-11-25 20:12:57 TEST
N4 2009-11-28 10:42:18 TEST
N6 2009-12-01 10:00:24 TEST
If I only want to search the log file after 2009-11-29, what shall I change the command?
possible to rename a list of files in batch in order to maintain the last part of them, then purge a central section and then again maintain the extension?I.E.:
Code:
file01.qwertyuiop.txt
file02.asdfghjklmnbvzxcqwertyuiop.txt
[code]....
I've got a directory with thousands of files and I want to delete those that contain specific text.When I try:Code: ls | grep -l "specific text" * | xargs rm I get the error: Code: /bin/grep: Argument list too long Is there an easy way to get around this without having to move files into seperate folders and processing them in batches? I found an article on getting around this problem, but I'm kind of new to Linux and don't know how to apply this to my specific problem.
View 3 Replies View RelatedIf I have files named like this:
abc_one.c
egx_two.c
tsf_two.c
[code]...
We have a large number of devices on our LAN with the mac prefix of 00:60:60. We want to assign these addresses from a separate address pool. I've created two classes, one to match 00:60:60 and another that I want to contain any other device. When i try to start the server I get:
/etc/dhcp3/dhcpd.conf line 33: boolean expression expected
match if not binary-to-ascii(16,8,":",substring(hardware, 1, 3))
^#this carrot should be under the last parenthesis#
Configuration file errors encountered -- exiting
Here is the relevant section of /etc/dhcp3/dhcpd.conf
class "006060" {
match if binary-to-ascii(16,8,":",substring(hardware, 1, 3)) = "00:60:60";
}
[Code].....
I've tried a few variations on that line. I've spent days trying to find any examples of "match if not" and haven't found anything. I assume it's going to be something to do with parenthesis/quote placement. Oh and this is ISC DHCP Server V3.0.4.
Since I'm not building a specific piece of software but a shell script, I hope this is in the right forum. At work, we use RHEL for the basic system but have Windows clients attached as well. On the Win side, there's a program that I'm trying to duplicate on the Linux side. Because of established procedures, I can't change the way files are named so please don't suggest I do that (my boss would not be happy). We have files stored on an NFS share we manipulate on either side.
The program is used to copy files from one directory to another, based on the filenames. The first two characters of the filename are ignored (they're for human-readable sorting purposes only), the next four characters are the time, and then all characters after that are ignored. The time is read and the file gets copied at that time. (This was all done in VC++ many years ago, and nobody knows where the source code is.) For example, a file named 2d0730abcd.txt would be copied from the source directory to the destination directory at 7:30am.
It seems to me that it should be fairly straightforward to build a shell script on the Linux side to do the same thing, but darned if I can figure out which magical combination of commands to use. Would the shell script end up creating a giant pile of AT commands?
I am interested in the following problem: given a string (pattern) find a regexp which match this pattern.
I will need this for a developing of an idea 'pattern based filtration'.
I have a requirement to list files using find command My folder contains below list of files with out extention.I have a requirement to exclude only ABC.123.* type files and list others. Even though files having MNO contains this pattern i should not exclude. Even if file ends with .txt or .doc it should not be excluded. That is ABC.123.1234.txt should not be excluded.But I am not getting what is required. Can any one please let me know if I am doing wrong any where. As per my requirement I cannot use grep, -regex, or -regex attributes to find command.
View 7 Replies View RelatedHow can I remove all .swp files in all of my subdirectories under Linux?
View 4 Replies View RelatedIf I wanted to copy all *.so files from src to dst I'd do:
cp src/*.so dst
However, I want to copy all *.so files from src and it's subdirs into dst.
I'm trying to do something very basic in bash. It's a kind of cross-reference matching between 2 files. I have a file1.txt. It's like this:
Code:
item1
item3
item4
...
I Have a file2.txt. It's like this:
Code:
item1 "Properties of item1"
item2 "Properties of item2"
item3 "Properties of item3"
item4 "Properties of item4"
item5 "Properties of item5"
...
My goal is to print out the lines in file2 that contains lines present in file1. I do:
Code:
for i in $(cat file1.txt); do grep $i file2.txt; done but I get no output. Will someone please tell me where am I mistaking?
I have 2 massive duplicate dirs of the same format as below:
dir1
subdir1
file1
subdir2
file1
subdir3
file1
...
Dir2 is the same, but it has some newer files of the same name. I want to copy all file1's from Dir2 to the same name and folders in dir1. So basically something like:
cp -pr bkpDir1/*/*-big.gif Dir2/*/*-big.gif
This works for singular cases:
cp -pr bkpDir1/uniquesubdir/*-big.gif Dir2/uniquesubdir/*-big.gif
But not for wildcards:
cp -pr bkpDir1/subdir*/*-big.gif Dir2/subdir*/*-big.gif
Anyway the aim is to do the first cp above, I have tried a few options using find. In trying to show an example stumbled upon a way that worked, while in dir2:
find */*-big.gif | xargs -i cp -rp {} ../dir1/{}
Sure there are better ways also...
I am writing a shell script that finds all files named <myFile> in a directory <dir> or any of its subdirectories, recursively. I also need to take care of symbolic links that may form cycles, to avoid infinite loops. I am not supposed to use find command for the same
I started writing the code but got stuck. I thought using recursion may be a smart way, but its not working.
Code:
#!/bin/sh
findFiles()
{
thisDIR=$1
#cd $thisDIR
code....
$ uname -a
Linux a 2.6.35.10-74.fc14.i686.PAE #1 SMP Thu Dec 23 16:10:47 UTC 2010 i686 i686 i386 GNU/Linux
$ lsb_release -a
LSB Version: :core-4.0-ia32:core-4.0-noarch
[Code].....
How can I set a pattern that will output a filename equal to the original filename? E.g.
something.mp3 → something.ogg
And why isn't this implemented in SoundConverter?
PS: {Filename} doesn't work.
I'm searching within Java files for some occurrence of a phrase:
find . -name '*.java' | xargs grep -l 'string'
How do I change this command to print to the shell all of the lines which contain a match?
What is the best and simplest way to compare two directory structures without actually comparing the data in files. This works fine:
diff -qr dir1 dir2
But it's really slow because it's comparing files too. Is there a switch for diff or another simple cli tool to do this?
I run 5GBFree.com a free hosting site. As you can imagine, it gets quite a few people signing up to abuse the service.Recently I've found a LOT of people setting up sites with a particular script that floods forums and IRC chat rooms. The names of the files are as follows:
peindom1.php
peindom2.php
peindom3.php
peindom4.php
Is there a command I can run to remove files with these filenames ANYWHERE on the server (so basically, a command to go through all folders on the server and remove instances of that name
What is the difference between filename and ./filename? Under what circumstances is one preferred to the other?
View 5 Replies View RelatedI just did an update on my Debian system and it was very long. I'd like to know now, after the upgrades have already been applied, which packages were upgraded and which were not.
View 2 Replies View RelatedI loaded a distro (which does not seem relevant) onto my laptop and used it for a while. Applications did whatever they do creating and saving files. I know that I have images and documents and videos and music and such on the laptop among other non-distro data files. Is there a simple (straightforward) way to identify which files on disk are NOT part of the installed distro? I know how to use find. I know that find lets me locate files based on some date-time-stamp. I know, too, that I can use any selected file as a benchmark date-time instead of some specific command line string.
For example:
Code:
Find files whose modification date is before (or after) the date(s) associated with the file /path/foo.bar.
Is there any one file that I could use to peg the distro install date? Can I get that date from somewhere else like a file system details?