General :: SED Expression Does Not Work
Aug 25, 2011
I want to use sed to comment out a certain command in a js file. The command is called processLoad(..). I came up with expression below but it doesn't do what I expect it to do. The computer that I am on belongs to my provider, so I do not know the version of linux that is running on the machine.
[added:]
sed -r -i 's_^([ ]+processLoad.*)$_//1_' test.txt
I hope to replace a line:
processLoad('mystr');
into
// processLoad('mystr')
I figured out that '/' as substitute separation character would pose problems with the // as comments, so I choose _ as substitute separation character.
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Oct 6, 2010
I want to translate this .fdi clause
Quote:
<match key="info.product" string="PS/2 Generic Mouse">
<merge key="input.x11_options.EmulateWheel" type="string">true</merge>
<merge key="input.x11_options.EmulateWheelButton" type="string">2</merge>[code].....
into its Xorg equivalent. What does it look like?
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Sep 2, 2010
I am trying myself on regular expressions. A read on [URL]/regex.htm) that {x} means search X times preceding character. So, why is this :
Code:
wstation~> echo '123456789' | grep [0-9][0-9][0-9]
123456789 # MATCH !! I have 3 numbers in a row.
[code]...
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Jun 29, 2010
how do I get this regular expression to work in an if/else statement? This is just a little script for learning BASH. don't be too harsh.
This script will test if a certain number of files with 1-4 in their filename exist and print their filename. An error message will be printed if not.
#
for i in `ls file[1-9]`
do
if [[ "$i" == *1-4 ]] ; then
echo "This file, $i, ends in a number between 1-4"
else
echo "Error, this file, $i, does not end with a number between 1-4"
fi
done
I get this error. ./file_test.sh: 13: [[: not found
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Oct 13, 2010
I'm writing a Perl script to find an old key in a file and replace it with a new codefirst the program should find the old key in the input file. here is the way I used in my script. but it doesn't work.May you please let me know what is wrong and how I can correct it?the key is stored in the file in the following format:
PHP Code:
Key=("1234567" , someOtherVrable)
I want 1234567
[code]...
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Feb 3, 2010
I was doing an exercise on Learning Perl, 3rd edition. (exercise chapter 10 btw) The problem asks to create a program that generates a random number and asks the user to guess. It should tell the user if the guess is lower or higher and exit if the user types either exit or quit. My code is the following:
Code:
#! /usr/bin/perl
$correct = int(1+rand 100);
[code]....
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Jan 21, 2010
On my server, logs are saved in log.gz format. I want to know what regular expression should i use to search both oracle and a particular IP, say 1.2.3.4 in a single log line ?
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Feb 20, 2010
sed -i 's/EXTRAVERSION =/EXTRAVERSION = -$(date +%D)/g' file would search in the file, file for the string: 'EXTRAVERSION =', and change every instance it finds to 'EXTRAVERSION = -02/20/2010'. BUT IT DOESN'T.It changes it to 'EXTRAVERSION = $(date +%D)', literally. I've tried single and double quotes in almost every possible configuration. Is there any way to tell sed that one desires the command output, not the literal text?
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Oct 22, 2009
I have two type of lines in a text file example
Code:
x.junk(a,b,YAHOO);
y.junk(c,d);
I want to search and replace the second type of line with the first type i.e. with YAHOO included, so that I have
Code:
x.junk(a,b,YAHOO);
y.junk(c,d,YAHOO);
I am trying to use
Code:
:%s/(.*).junk((.*),(.*)^<YAHOO>);/1.junk(2,3,YAHOO);/
In the above code ^<YAHOO> search is not working (I want lines "except YAHOO"). I know that [^ab] will work for "except a,b" characters. How can I say "except word" in regular expressions?
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Feb 3, 2011
I am trying the execute the following
#!/usr/bin/python
import os
os.system("sed -e 's#^(.*) (.*)0http://12#' t2.txt > t3.txt")
os.system("cat t3.txt | sort | uniq -c | sort -rn | head > t4.txt")
But I receive the following error message.
sed: -e expression #1, char 27: unterminated `s' command
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Nov 23, 2010
I just want to grep for a n digit number followed by M alphabet. Generally for a three digit number i can give grep [0-9][0-9][0-9]M , but if the digits are increasing it is tough to represent them.
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Nov 17, 2010
Quote:
#!/bin/sh
for i in {1..10}
do
for j in {1..50}
[code]....
The first echo generates something like: abc.de.fgh The second echo generates:
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Apr 1, 2011
so I have a perl script that contains an array like this:@hostNames = (ABC123R:192.168.1.1, CBA321CBP:192.168.1.2, ZYX987R:192.168.1.3, etc firstelement"ABC123R:192.168.1.1":ABC123R is the hostname and 192.168.1.1 is it's IPaddress.I am trying to write a regular expression that will split the element with a '-' wherever there is a LETTER next to a NUMBER, like so:ABC-123-R:192.168.1.1I tried this expression below but am struggling with using regex for slightly complicated matching criteria:
for ($x = 0; $x < scalar(@hostNames); $x++)
{
$hostNames[$x] = split /([A-Z][0-9])/, "-"
[code]....
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Feb 15, 2010
What I want to achieve is, if I have following in my file:
x y
X z
I should be able to find the pair, x Y and replace it with x a. So, basically I want to search for case sensitive 'x' but search and replace case insensitive 'y'. How should I do it? Can this be achieved with 'sed' command?
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Jul 7, 2010
I'm attempting to search through a rather large assortment of html files created in Word using 'save as html'. what I'm trying to do is find and delete these tags (they're causing browsers to display black diamonds with white question marks):
<span style='mso-spacerun:yes'> </span> Tags contain from 1 to 4 spaces between opening and closing. I get positive results from this:
grep <span style='mso-spacerun:yes'> filename.html but once I attempt to tell it to match any number of characters up until the next '>' symbol, it tells me I'm using an invalid regex: grep <span style='mso-spacerun:yes'>[^>]+> filename.html
I've been nose-deep in regex tutorials for the past day or so, and I'm still not understanding why this doesn't work. If I put the pattern (without backslashes) into a separate file and use `grep -f patternfile filename.html`, I get no error but no matches either. So far as I can figure, the above regex boils down to:
Match the string "<span style='mso-spacerun:yes'>", followed by any number of characters that are not a ">", followed by a ">". If someone could tell me where I'm going wrong with this,
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May 28, 2010
I'm trying to math all class references in a C++ file using grep with regular expression. I'm trying to know if a specific include is usuless or not, so I have to know if there is a refence in cpp. I wrote this RE that searches for a reference from class ABCZ, but unfortunately it isn't working as I espected:
grep -E '^[^(/*)(//)].*[^a-zA-Z]ABCZ[]*[*(<:;,{& ]'
^[^(/*)(//)] don't math comments in the begging of the line ( // or /* )
.* followed by any character
[^a-zA-Z] do not accept any caracter before the one I'm searching (like defABCZ)
[]* any white space (I can have something like ABCZ var; )
[*(<:;,{& ] followed by ( * < : ; , & { (I cant get #define "ABCZ.h" or ABCZdef for example)
Well, I can get patterns like this:
class Test: public ABCZ{
class Test: public ABCZ {
class Test : public ABCZ<T>
[code].....
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Dec 13, 2010
I have this..
RewriteRule ^(apes|ape)/(.*)$ $2?fh=$1 [L,QSA]
I only want to match the directories ape/ and apes/ but I think it is matching any directory that ends in "ape" or "apes" or maybe does it match any string containing those characters in any order? I am not great at regex, and have read alot, but still not sure if I understand this correctly.
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Oct 26, 2009
I've got a list of files that I've copied from my terminal and pasted into gedit and into OO.o writer. Since the files are all created by gedit, in each case there is both file and file~. I want to get rid of all the 'file~' lines. I thought I could do search and replace using *~, but this doesn't work.
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Jan 8, 2011
How would I use a unix grep regular expression to find any two capital letters side by side and how would I find an expected comma in an expected spot?
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Sep 7, 2010
I have 4 Linux machines with cluster.My target is to find all kind of IP address (xxx.xxx.xxx.xxx) in every file in the linux system remark: need to scan each file in the linux system and verify if the file include IP address if yes need to print the IP as the following
more /etc/inet/file.example1
182.23.2.4
255.255.0.0
10.10.1.1
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Nov 30, 2010
I've found the following script to copy files specified by a find output into a target directory.Code:find $SOURCE -name "*.avi" | xargs -i cp -v {} $TARGETWhat exactly does the colored expression mean? Does it refer to an array?
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Jun 7, 2011
This line if [[ $hamachi_reachable = true && $lan_reachable = true ]]; then is always evaluating to true. I gave two ips that are not valid, so that both variables would become false yet the whole expression is evaluating as true. With that set -x in there, I get this output.
Where am I going wrong?
Code:
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May 7, 2011
I've spent most of the evening browsing the web, trying many things I've found on various forums, but nothing seems to work.
I have a test.txt file containing many lines like the following ones :
...
<insert_random_text>228.00 €<insert_more_random_text>
<insert_random_text>17.50 €<insert_more_random_text>
<insert_random_text>1238.13 €<insert_more_random_text>
...
And I want to extract :
...
228.00
17.50
1238.13
...
There is always one occurrence of € in each line. I want the numeric value that precedes this € occurrence. The random text (before and after) may contain numbers too, so the € may be important to parse, in order to correctly identify the number to return. The last character that precedes the number to extract is always a ">" (coming from an HTML tag).
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Jan 2, 2010
I'm working with javascript and trying to replace all instances of a Roman character in a string with nothing. How do I assign var reg to all Roman characters? In UTF8, capital letter A is U0041 and at the other end, small z is UFF5A.
So, I'd like to do something like:
var reg = u0041 - UFF5A;
str1 = str.replace(reg, '');
I think you get the idea. I have no idea if that can be done. The idea is to take this string (for example): str = make a door-to-door[house-to-house] visit / ring every doorbell." And take out all the Roman characters and define it as str1. And then take out all the Korean characters (u1100-uFFDC) and define it as str2. In fact, a WAY more useful thing to do would be to replace the instance of this: [u1100-uFFDC]+" "+[u0041-UFF5A] with [u1100-uFFDC]+","+[u0041-UFF5A] so that the output would be a .csv file.
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Mar 16, 2011
i cant use regular expression in replace function. I want to do this
a = ' Bad boy'
b = a.replace("b[aA]d", '')
Ofcourse this is a simple example for my query. Its not working so shall i assume regex dont work with replace function ?
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May 27, 2009
I need to use sed to edit a file that contains just one line. This should be pretty simple, but I've googled and can't seem to figure it out. I need to match everything from a certain string up until the first comma in the line. There are multiple commas in the line and my matching pattern is matching up until the last comma, not the first.
Here is what I'm trying:
As you can see it is matching up until the last comma. Seems like the .* is matching any character including the other commas. The output from this that I am hoping to achieve:
How can I get the regular expression to match from asdf: up until the first comma?
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Feb 11, 2010
My console fu is a bit lacking, as it seems that I can't figure out how to uninstall all packages containing a certain expression.
I tried: apt-get remove *expression*
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May 15, 2010
I'm writing a loganalysis application and wanted to grab apache log records between two certain dates. Assume that a date is formated as such: 22/Dec/2009:00:19 (day/month/year:hour:minute) Currently, I'm using a regular expression to replace the month name with its numeric value, remove the separators, so the above date is converted to: 221220090019 making a date comparison trivial.. but.. Running a regex on each record for large files, say, one containing a quarter million records, is extremely costly.. is there any other method not involving regex substitution? here's the function doing the convertion/comparison
[Code]...
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May 3, 2010
I found such simple example of awk
Code:
awk '
BEGIN { a = "1abc 2def"
b = gensub(/(.+) (.+)/, "\2 \1", "g", a)
print b }'
However I don't understand why the regular expresion in parentheses doesn't work how I woud expect. If I delete the .+ so it does the same.
Code:
awk '
BEGIN { a = "1abc 2def"
b = gensub(/() ()/, "\2 \1", "g", a)
print b }'
I wanted to use a regular expression in parantheses like ([/+[]()]) to get the specific letters.
Code:
awk '
BEGIN { a = "1abc 2def"
b = gensub(/([/+[]()])/, "//\1", "g", a)
print b }'
But why the regexp in () isn't working
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Apr 30, 2011
I remember reading that using sed, you can do this with parentheses: s/abc(something)def/(something)else/g I can't find an explanation of how to do something like this with Awk. Say you have this in an HTML file, where (number) stands for a one or two-digit number:
<sup>(number)</sup>
And you want to change that to this:
<a name="(number)t" href="#(number)b"><sup>(number)</sup></a>
How would this be possible? Would you have to use sed?
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