I have to write a script which would search the IP adesseses in a given directory.
Below is my command.
Code:
grep -HwrnI --exclude=*.log '[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}.[0-9]{1,3}' *|grep -v '/.svn/'
I have to exclude the following from search resluts.
1. Comments
a. Can be starting with /, * or #...
b. Cane be between a line
EX: some text... #comment1
I am trying to compare a list of patterns from one file and grep them against another file and print out only the unique patterns. Unfortunately these files are so large that they have yet to run to completion. Here's the command that I used:
Code: grep -L -f file_one.txt file_two.txt > output.output Here's some example data:
Code:
>FQ4HLCS01BMR4N
>FQ4HLCS01BZNV6
>FQ4HLCS01B40PB
>FQ4HLCS01BT43K
>FQ4HLCS01CB736
>FQ4HLCS01BU3UM
>FQ4HLCS01BBIFQ
how to increase efficiency or use another command?
I want to traverse a directory and get a list of files that contain a set of patterns. I assumed I could use grep for this, but I having trouble getting grep to only return files that match ALL patterns. Here's what I've come up with so far:
Code:
grep --recursive --file=searchpatterns.txt --files-with-matches somedirectory/*
However, this gives me a list of files that match ANY of the patterns in the searchpatterns.txt file. I want to match ALL of the patterns. I've looked through the man page, but can't find anything that allows me to change the "OR" to "AND" for multiple patterns.
I have a file that goes like this:
I need to grep the lines between pattern 1 and pattern 2 and not the lines following pattern 2. Cannot use grep -A(num), as there are varying number of lines following pattern 1. Also, used awk one-liners, but results are erroneous.
I am interested in using the grep method in the shell of my CentOS machine to obtain patterns from a file and use them to search through another file and highlight the patterns found. For example:
pattern file:
one
two
three
test file:
AAAAAAAAAAAAAAAAAAAAAoneAAAAAAAAAAAAAAAAthreeAAAAAAAAAAAA
I would like to take a file looking like...
uid=user1,ou=People,dc=company,dc=com
uid=user2,ou=People,dc=company,dc=com
uid=user3,ou=People,dc=company,dc=com
[Code]...
How can I use grep to search for line with either 'res' or 'rep'? i try "grep -e res|rep" or gre -e "rep|rep" but that does not work.
View 3 Replies View RelatedI have done this before but i cant really recall now
I have a text file and i want to grep the word "interface" and 10 lines following it. I think there was some switch like grep -A or something ?
I have a list of words that I want to grep in many files to see which ones have it and which ones dont. in the text file I have all the words listed line by line, ex: list.txt:
check
try this
word1
word2
open space
list ..
I want to grep each line one by one. like I want it to
grep "check" *.log
grep "try this" *.log
grep "word1" *.log .. etc how can I do this?
and maybe write the output to a file.
how to update a series of values from multiple grep commands outputs to be appended to a single row of a csv file? Work on a linux envir. The values from grep output will be numeric values.
Output sold look like:
1,3,4,5,7,0,5
Each of these values will be odtained from multiple grep commands piped with wc -l Is it possible to update a single row of a csv file if so pleas ehelp me with the command to be used to redirect the output into the csv file
I'm working on setting multiple switches in grep.
Here's an example of how to run my script:
would (should) produce the results of this:
Right now i have some code to catch the inputs, using a variable "z":
Code:
Then:
Code:
I'm almost positive that the problem is in the bolded line above (for one thing, it always leaves off the initial "-e"). So basically i want a string that gives me "-e input" and concatenates as many times as necessary.
I want grep multiple files:
let abc.1.abc.2,abc.3,abc.4
I use grep <pattern> abc.* to read the files. But here grep read files in the order of 1,2,3,4 . I want to to grep the files in reverse order like 1st the abc.4 file will be read and abc.1 file will be last.
Is this possible ?
Awk varying patterns to different file?
[Code]...
What I want to do is when the records have identical $3 i.e. same gene:blabla, I want to put them in a file with $3.out (P.S. along with the lines below it) I tried grepping out $3 first separately onto a file, and then taking each line in that file as a pattern and pulling out records using awk. Somehow I faced probs with pulling out onto $3.out
I have a huge binary log file. There are lets say 4 id's that I want to find in a log file. I know that those 4 id's will be present in the log file and I also know in what order they will be present. I want to find 1st id from the log then 2nd id and then third id and so on..
Simple/inefficient solution is: Loop through the id's and then grep in the log file. Problem with this solution is for each id grep will search from the beginning of the file.
Better/efficient solution would be: Sine I know the order in which id's will be present in the log file. Loop through id's, grep 1st id and then move on to grep 2nd id and so on...this way I can grep all id's in one pass. Is this solution possible ?
I have 500000 + values to find in log files and I have to find efficient solution for it.
i have a problem about deleting a line from a text file which contains two specific patterns. i am using "sed -i "/$name/ d" peop.txt" but i must use one more variable which is surname.
"
burak:ak:3242:2342:dsa@a.com
gokhan:an:432:4234:da@a.com
"
and this is the code of text file. and the second question when i use "/$name/ d" it deletes not only the names which are macthing with $name but also all words that contain $name. so how can i fix these problems_?
I am trying to exclude 2 directories with find and pass it into cpio. I have tried
Code:
find . -depth -path '.evolution' -prune -o -path '.gconf' -prune -o -print|cpio -aov > /media/caca/full$date
./.gconf/apps/evolution/memos/%gconf.xml
./.gconf/apps/evolution/memos
[Code]....
I have a file with joker character patterns:
./include/*
./src/*
etc.
From the current directory I would like to recursively get the list of files that do not match these patterns.
I'm trying to use sed to search for a certain 'primary' pattern that may exist on several lines, with each primary pattern followed by an --unknown-- number of 'secondary' patterns.The lines containing the pattern start with: test(header_name)On that same line is an arbitrary number of strings that come after it.I want to move those strings over to their own lines so that they each are preceded by their own test(header_name).e.g. Original file (mytest.txt):
apples
test("Type1", "hat", "cat", "dog", "house");
bananas
[code]....
I want to replace a pattern with other pattern in a textfile. But there are two same patterns,but I need two change only the second occurence. EG:
Text file is
aaaa=1
bbbb=2
cccc=3
dddd=4
[code]....
Now I want to change aaaa=x into some other entry.
Just trying to set up a new backup using tar, but there are a few things I dont want to include. Using --exclude I can exclude sub-directories, but how do I exclude specific files in a subdirectory that are (for instance) executables or have a specific extension?
View 5 Replies View RelatedAt present in my server the log folder was filled up and causing memory issue. So I am planning to write a script in such a way that the files which are older than 30 days will be deleted and also need to find the files which were not compressed and need to compress this file. Compression will exclude if the file was created on the same day.
View 12 Replies View RelatedIn Midnight Commander, is it possible to exclude some directories/patterns/... when doing search? (M-?) I'm specifically interested in skipping the .hg subdirectory.
View 1 Replies View RelatedI want to search file excluding the NFS ...find / -mount -name 'filename' restricts the search only in the root disc partition,but the file can be in other partitions alsoIs there any way to exclude the NFS only.
View 2 Replies View RelatedI know I can do find . -type f, but that includes binary file and I couldn't find a way to exclude them with find
View 4 Replies View RelatedI need to kind of grep within grep. My input file would be something like:
[Code]....
and I need to find the first occurrence of hello before MY PATTERN (hello 9008 in this case), so the output should be:
[Code]....
I remember using some dos program that would scan text files for particular words/patterns. It had an ncurses-like interface and if I'm not wrong its name was "Concord". Is there anything like that on linux? The main functionality was as follows:
1. support for regular expressions
2. print lines containing a particular word or pattern (highlighting it) and printing the surrounding lines.
3. print lines containing a particular word or pattern only if another pattern occurs within N words to the left/right.
The second point is easy to achieve in grep. The 3rd one could be done in awk. The problem is that as much fun as it would be to put it all together and embellish with some nice ncurses interface(eg. with dialog), I don't want to reinvent the wheel. Besides, I have just relocated and have been waiting for my phone line welcome pack for almost 2 weeks now (ie. no internet apart from work and mobile phone), which makes it difficult for me to get anything done.
I have a file that I need to scan and output data between Number and End containing string 123.
Number 1:
6
7
123
1
End
I am trying to delete any blank lines within two patterns e.g.
Address: 53 HIGH STREET Cred Id :
MYTOWN
MYCOUNTY
MM12 6MM
Pay Method : Crossed Cheque
The start of my pattern is "Cred Id" and the end is "Pay Method" and I want to delete the blank lines between county and post code. I did find the code below but it doesn't seem to change anything:
sed -ne '/Cred Id/,/Pay Method/!bp' -e '/^$/b' -e -e p ll.out
I can get it to print just the range I'm interested in by doing sed -ne '/Cred Id/,/Pay Method/p'.
I have spent the last hour searching for a solution to this, but I can't get it to work. Here is what I am trying to do:
I have directories for different months in one folder. So for example Code: ../folder/Jan/
../folder/Aug/
etc. Some of the folders have a dot in front of the month as so: Code: ../folder/.Sep/
../folder/.Oct/
[Code].....
I am trying to find all the csv files EXCEPT those in a folder that has a dot. For example I want all the csv files in ../folder/Jan/ but I want none in ../folder/.Oct/.
I also want to exclude all the files in the /Aug/ folder that represent days 10-31.
Here is what I have so far: Code: find /some_path/folder/ ( ! -name "Aug[10-31]*.csv" ! -path "/.*/" -name "*.csv" ) | more This command lists all the .csv files except those in the /Aug/ files. So it just ignores the /Aug/ folder completely but lists every other .csv file.
I'm trying to compress with zip for linux utility a file
Is need to be done (example):
But I would like that in the zip file there is only one file: source.file instead the whole directory path /usr, /src,... and the file.
I can't move up to the directory /usr/src/ to execute the command.
I must do this from / directory.
If this possible? I Windows systems even if I do the zip C:directory1directory2source.zip C:directory1directory2source.file, it does what I need: a Zip in directory2 with just the file source.file.
I've been looking up the man page for zip, but did not find anything useful, tried, -j, -D with no success.